I am trying to perform some operations over some data, but they are not working and I need to find a way to ignore those cells which don´t meet all the requirements.
Basically, I have a column where some cells have text + numbers in their content and other have only text. I search inside all of them and split TEXT in one column and NUMBER in another one. Then, I run a macro to find the matching text to each one in other column.
But when I try to split TEXT from NUMBERS, I search for the first "(", cause my number format is (10.10.10), but if it is not found, the cell value appears: #VALUE! (ok, it is expected cause the character was not found). Here is the problem: if I run my macro over "#VALUE! it crashs and don´t finish its execution.
I have tried to use
On Error GoTo
in my macro code, but for some reason it doesn´t not handle the "Run time error: Type Mismatch".
For contadorOr = 2 To colO
For contadorDes = 2 To colA
On Error GoTo cont
If InStr(1, Cells(contadorDes, colunaDestino).Value, Cells(contadorOr, colunaOrigem).Value) Then
If InStr(1, Cells(contadorOr, colunaOrigem + 4).Value, Cells(contadorDes, colunaDestino + 1).Value) Then
Cells(contadorOr, colunaOrigem + 5).Value = "Mesma versão"
End If
Exit For
End If
Next contadorDes
cont: Next contadorOr
Any suggestions? I can think of ignoring this error (when it´s happen, my variable contadorOr is incremented and go to no next value) or any way to avoid #VALUE! returned by my functions, but haven´t had success doing that.
Thanks in advance.
Instead of using error handling options you could check if cell which you are going to check/process doesn't return error. This is quite simple as presented below:
If IsError(Cells(contadorDes, colunaDestino).Value) Then
'to do anything if there is error
'usually...do nothing
Else
'do what you want if there is no error
End if
Related
I am trying to remove duplicate values except the first one.
My solution to this was to conditionally format all duplicates, then, working backwards, clear contents of the formatted cells. This would mean that the first one will stop being formatted once all duplicates are removed.
What I have been trying:
For i = LaC To 5 Step -1
LR = ws.Cells(Rows.Count, LaC).End(xlUp).Row
For j = 2 To LR
cond = (ws.Cells(j, i).DisplayFormat.Interior.ColourIndex.Value)
If cond = 22 Then
ws.Cells(j, i).ClearContents
End If
Next
Next
Basically, if I try ws.Cells(j, i).DisplayFormat.Interior.ColourIndex in the immediate window, it returns 22.
However, if I try this code, I get error:
Object doesn't support this property or method (Error 438)
Any assistance would be greatly appreciated.
If it is not necessary to use VBA you can get rid of duplicates in the GUI via “Data” → “Data Tools” → “Remove Duplicates”. Or, in current versions of Excel O365, you can use the UNIQUE-function like this
UNIQUE(A:A)
assuming your source data is in row A. This will keep up with changing data.
Check this line more carefully:
cond = (ws.Cells(j, i).DisplayFormat.Interior.ColourIndex.Value)
ColorIndex is a Property, not an Object. As such, ColorIndex.Value will return an error. Note that you haven't included the .Value when testing in the Immediate Window, and it works as expected:
?ws.Cells(j, i).DisplayFormat.Interior.ColourIndex 'This will work
?ws.Cells(j, i).DisplayFormat.Interior.ColourIndex.Value 'This will err
Also, there is no need for you to put it in brackets, either:
cond = ws.Cells(j, i).DisplayFormat.Interior.ColourIndex
Ans: I was writing Colour instead of Color.
I am rather new at programming, and while learning Python also started experimenting with Excel VBA. I have an issue with the last one.
I have some large Excel sheets and tried to validate that data in specific columns matches data on another sheet in certain columns as they will be supposed to relate to each other by these values (and will be connected by a third value). To make this a bit more difficult, both of these columns may contain more than one value separated by "|". So, I have split these values in a list and I try to iterate through them to make sure all these values are set correctly, the connection will work fine.
All is fine as long as all is fine :) I have however an issue where there are two values in one of those columns and only one in the other. I would like this discrepancy to be noted on a sheet and then proceed to the next item.
The way that seemed to be applicable for me is to use "On Error GoTo ErrHandler", then note error on another sheet, and then user Resume to proceed.
Here is what I came up with:
For h = 0 To UBound(Split1())
For j = 1 To GetMaxRow("SpecificSheet", A)
On Error GoTo ErrHandler:
If Sheets("SpecificSheet").Cells(j, 1).Value = Split1(h) And Sheets("SpecificSheet").Cells(j, 2).Value = Split2(h) Then
DependencyOk = DependencyOk + 1
End If
Next j
Next h
ErrProceed:
Also ErrHandler is:
ErrHandler:
Sheets("Issues").Cells(x, 1) = "IssueDescription"
GoTo ErrProceed
It stops at line 2 with Subscript out of range for Split2(h) rather than moving on to ErrHandler and then ErrProceed. I have the feeling this must be something very obvious but I am just unable to get this working, and I am not able to find other way (like a try/except) in Excel VBA.
UPDATE:
Trying to clarify things a bit. The root of the issue is, that the Split2 list is shorter than Split1 - which is an issue with the input data and I'd like to capture this. I get the Split values from cells, where the values are separated by "|" characters:
CellValue = Sheets("SomeSheet").Cells(RowNumber, ColumNumber)
CellValueSplit() = Split(CellValue, "|")
And then iterate as:
For h = 0 To UBound(Split1())
So as Split1 moves on to the for example 3rd value, Split2 throws error and script stops. The best I was able to do so far was, that I let it proceed with the loop, but as this is a rather large sheet, it will fill the same error report ca. 200k times in this case, which I'd like to avoid. So I'd prefer it to proceed from after this loop once it hits out of range error, and proceed examining the next value.
Thank you for your help so far and in advance!
You have an issue with your syntax. The proper Error statement syntax is:
On Error GoTo <string>
On Error Resume Next
On Error GoTo 0
When using On Error GoTo <string> there is no ":" at the end. The ":" doesn't come into play until you create the target location. Example:
On Error GoTo Here
'// ---- Do something ---- //
Here:
'// ---- Handle the error ---- //
If you use On Error Resume Next, then you're telling the machine to ignore errors and proceed on to the next line of code.
When you useOn Error Return To 0, VBA will reset its error handling back to default. It's a good habit when using On Error Resume Next to insert On Error Return To 0 as soon as you no longer need it. On Error Resume Next has a real potential to break your code and make it behave strangely. Not to mention debugging can be a real nightmare. Check out the VBA manual from Microsoft for a more detailed explanation.
Finally, if your question is answered, you should mark it as answered.
vba-excelvbaexcel
The short and quick version is that VBA Error Handling Routine's only handle errors in the actual code execution, they do not fire when conditions expressed by the code are not met.
In your case, you do not need any error handling at all. In most cases it is actually best to avoid On Error GoTo .... There are cases where it's inevitable, but they are rare.
Try this IF THEN ELSE block:
If Sheets("SpecificSheet").Cells(j, 1).Value = Split1(h) And Sheets("SpecificSheet").Cells(j, 2).Value = Split2(h) Then
DependencyOk = DependencyOk + 1
Else
Sheets("Issues").Cells(x, 1) = "IssueDescription"
End If
Actually I have just found the issue. It was caused by a ":" left after an If statement a few rows earlier. I still don't really understand what it did, but I suggest not to reproduce it :)
I have scoured the web and this site looking for an answer on this, so I would really appreciate some help.
I'm creating a VBScript to do some modifications to a user-specified Excel spreadsheet. I have the first part of my script working fine, but the second part is driving me nuts. I need it to search the first column for a value and, if found, delete the row. Right now I'm not worrying about the deletion statement--I'm doing testing by seeing if I can get the For Each statement to run properly as well as the If Then statement. Here's the specific block of code:
For Each cell in objSheet.Columns("A:A").Cells
Set cell = objSheet.Columns("A:A").Cells
If cell.Value = "60802400040000" then
cell.font.bold = True
End If
Next
I have tried many variations of this and cannot find the right combination. Initially I was getting an "Object Required" messages, and after reading a number of posts, found that I needed to put in a Set statement for cell, which I did. Now I am getting a Mismatch Type error message.
The funny thing is, before I put in the Set statement, the code would execute, but it would throw the Object Required error when I closed the spreadsheet. After adding it, the error for the Type Mismatch pops up immediately.
Most examples I keep finding on the web are for VBA, and I try to modify them for VBS, which I don't know very well. Any assistance anyone can give me will be greatly appreciated.
You are redefining cell, cell is defined automatically in the For Each statement.
Delete this line
Set cell = objSheet.Columns("A:A").Cells
This is an example from Help, unfortunately Help doesn't have any examples that uses For Each, only For x = n to n and other means. For Each is the right thing to do.
Set r = Range("myRange")
For n = 1 To r.Rows.Count
If r.Cells(n, 1) = r.Cells(n + 1, 1) Then
MsgBox "Duplicate data in " & r.Cells(n + 1, 1).Address
End If
Next n
For vba to vbs, you have to create the object and use, as some objects are automatically available in VBA (like app object) - Set exceldoc = CreateObject("c:\blah\blah.xls) then to use Set r = exceldoc.worksheets(0).range("MyRange").
Also you have to use constant values not names as vbscript can't look them up.
Nom_1 is the name of a cell in my worksheet, and is used in the following code.
Someimes that cell is left empty and I don't want the NormInv function to get called because it will return an error if the inputs are empty.
I get the error: Unable to get the NormInv property of the WorksheetFunction class
This leads me to believe my if statement is incorrect and it is allowing for the code to enter and execute even if Nom_1 is empty.
If Not IsEmpty(Nom_1) Then
internal_1 = Application.WorksheetFunction.NormInv(Rnd(), N_1, Std_1)
End If
Am I correctly checking if the cell is empty?
Just Expanding on Barranka's comment,
You need to make sure all cells with the names Nom_1 ,N_1,Std_1,internal_1 exist in the workbook
then use Range("Nom_1") instead of Nom_1
Sub MyNormInv()
If Not IsEmpty(Range("Nom_1")) Then
Range("internal_1") = Application.WorksheetFunction.NormInv(Rnd(), Range("N_1"), Range("Std_1"))
End If
End Sub
You could use
If Range(Nom_1).Value <> vbNullString Then
internal_1 = Application.WorksheetFunction.NormInv(Rnd(), N_1, Std_1)
End If
However, know that this will return False if you have a formula returning a zero length string in the cell. Even though the cell is not "empty" it will still be seen as blank because the value is "".
I have a VBA function within a spreadsheet which operates on another spreadsheet that is opened in an earlier stage of my macro. The macro used to work fine but just recently has started causing a 1004 error ("Unable to get RoundDown property of the WorksheetFunction class") when it runs.
I believe I understand what the error would be caused by (a problem running RoundDown) but I cannot see why it is getting triggered in my macro and the odd part is that when I go into Debug mode and step through the code in the VBE the error does not recur (despite nothing obviously changing).
Does anyone have a similar experience of this sort of error occuring inconsistently and know what I could do to resolve it?
I'm reasonably VBA/Excel-savvy, but any suggestions on further steps to diagnose it would be appreciated. I am wondering if there is some issue with the opened spreadsheet not being ready but I cannot see how.
The code is here. The error occurs on the line marked with a comment.
Public Function GetDatesA(sWorkbookname As String, sSheetname As String, sCell As String) As Variant
Dim vDateList() As Variant
Dim currentCell As Range
Dim n As Long
Set currentCell = Workbooks(sWorkbookname).Worksheets(sSheetname).Range(sCell)
n = 0
Do
If Trim(currentCell.Value) = "" Then
Exit Do
Else
ReDim Preserve vDateList(0 To 1, 0 To n)
vDateList(0, n) = WorksheetFunction.RoundDown(currentCell.Value, 0) 'error occcurs on this line
vDateList(1, n) = currentCell.Column
'Debug.Print currentCell.Value
End If
Set currentCell = currentCell.Offset(0, 1)
n = n + 1
Loop While currentCell.Column < XL_LAST_COLUMN
GetDatesA = vDateList
End Function
Other details are:
Excel version: 2010
File being opened resides locally on my C: drive; my macro is in a spreadsheet on the network
File format for both files is .xls (i.e. Excel 2003) - I don't have the option of changing this
Windows 7 (not that I think it would be relevant)
Two points I've tried already are:
Substitute a different worksheet function (e.g. Min(currentCell)) and that also causes the same problem
Having the file open already seems to stop the problem - I wonder if there is some way that the workbook which is being opened (rather than my main workbook with the macro in it) is not enabled for macros and this is interfering. But even if this is the cause I'm not sure how to get around it!
Any ideas?
This error occurs often when any argument passed to the worksheet function is not of the correct type or simply doesn't make sense.
For example, I've had this problem when calling WorksheetFunction.Asin with an argument bigger than 1. In your case, I'd guess currentCell.Value is a non-numeric value or one not according to your region settings regarding numbers.
Yes, the error message is really misguiding.
I got the "Unable to get * property of WorksheetFunction Class" error using Transpose, MMult,MDterm, and MInverse functions.
I was able to get my code to run by putting "Option Base 1" in the Declarations (before the actual code) section of the particular Module in the Editer.
Excel assumes "Option Base 0" which will add an extra row and column of empty cells. This will cause the error to occur and isn't immediately obvious to see.
I have come accross this before, and for me it was becase the criteria range made no sense, as Andre said above.
See example formula below:
.Cells(11, i).Formula = Application.WorksheetFunction.CountIfs(Sheets("Sheet1").Range("AC8:C" & n), "S")
Have a look at the Range... it makes no sense. Amended the range from "AC8:C" to "AC8:AC" and it will work perfectly