JavaFX does not provide a CENTER value for Side so I am trying to center the X and Y Axis by translation:
scanXAxis.setTranslateY(0.5*scanYAxis.getBoundsInParent().getHeight()); // xAxis initially on TOP
scanYAxis.setTranslateX(0.5*scanXAxis.getBoundsInParent().getWidth()); // yAxis initially on LEFT
The result I am getting however are axes crossing at a point that depends on the scene's size instead of (0,0) i.e I can get them crossed at the origin by manually resizing the scene. This is exaclty the reverse of what I am striving for.
Any help would be greatly appreciated!
Cheers
I am using the Axis and I think the design is not friendly. I can't set the axis upside down or right to the left. I used axis.rotate but I have to hack the code for the layout of the contentPlot. Also, the axis can only be set to the left, right, top or bottom. But I want some flexibility, e.g. when I implement parallel coordinates, I can't put it to the place I really want to put it. So I am thinking I have to write my own axis class instead.
Related
I am using three.js and created a basic scene with a few meshses rendered with some basic lighting . My torus geometry was previously pointy with few polygons but I was able to smooth it out by adding more segments but now I would like to straighten the lines out in my cube. They seem jaggy. In the pic I am including my render on the left seems a lot jaggier then the example I am following on the right. I have even set width and height segments to very large values (200). Any Ideas why the aliasing/jagginess?My render on left, example on right
Is it possible to have the vtkAxesActor small in a corner of the window?
Here is a image of what I currently got and what I would like to have. The colorful axes are the standard axesActor. But I would like the axes in a corner of the window and only there (bottom left in black). They shouldn't move around the window when the view is rotated. Only around their origin.
Is this possible? And if yes, how?
A possible solution is to put the vtkAxesActor into an orientation widget:
widget = vtk.vtkOrientationMarkerWidget()
widget.SetOrientationMarker(axisActor)
widget.SetInteractor(interactor)
widget.SetViewport(0, 0, size, size)
widget.InteractiveOff()
widget.EnabledOn()
The vtkAxesActor location is functional and it's location has a purpose. The anchor point of the AxesActor is the anchor point of the model. This provides context of where any transformations or translations would be calculated from.
Unfortunately the example of the axisActor in the corner you have proposed would only provide context of the orientation of the model and so not part of the standard options.
XYPlot vertex points positioned towards the edge of the grid gets cut off and only show the half of the point inside the grid. Can I make it so the whole point is shown?
You just need to add some padding to the grid like this:
plot.getGraphWidget().setGridPaddingLeft(PixelUtils.dpToPix(5));
you'll probably also want to do the same on the right to keep things symmetrical.
Following Quote from this source:
http://www.cambridgeincolour.com/tutorials/image-projections.htm
Equirectangular image projections map the latitude and longitude
coordinates of a spherical globe directly onto horizontal and vertical
coordinates of a grid, where this grid is roughly twice as wide as it
is tall.
I have a 13312 px width and 6656 pixel height Panorama picture. It's a equirectangular projection of a room and have a 2:1 ratio.
I use following formular to calculate the xPosition:
var xPosition = ( panorama.width / 360 ) * azimuth
Azimuth = Phi = Heading = Angle to the left or right
How do I project this now on a 1366x768px browser screen?
I think my results are wrong, because it's not on the point where it should be.. it could be because the sphere has a distortion on the left and right:
Is there any formular to calculate the position with attention to the distortion and scale it to fit on the browser screen? I looked many (MANY) sources to find a solution for this, but they always just say that equirectangular are just lat and long.. they don't consider the distortion.
Last question: To find a special solution, I tryed to put a plane on the circle and expanded the line which shows the alpha angle. I though with Phytagoras I could find the position.. but this didn't worked either.. maybe I did something wrong? Is this the way even possible or am I doing it wrong?
edit
THIS is what I'm actually looking for: http://othree.github.io/360-panorama/three-2d/
The black grid in the background. What is the name of this? For what do I have to google or look for? When you start the 2D Panorama, if you want to get the coordinations of the top right corner of the window, what do you have to do?
The whole calculation problem was about to create a Google Streetview similiar view from a 2:1 equirectangular image. We already found a solution for this with a great help from Martin Matysiak (https://github.com/marmat | Google).
It's been a while so I can't give a direct answer to what the main solution is, but I can provide a URL to an AddOn Martin wrote for adding the custom Markers that we actually were trying to make.
You can follow https://github.com/marmat/google-maps-api-addons and look for yourself. In the end it helped a lot to solve the main problem and let us continue with our main Framework for Google Business Tours.
If you follow the link in the threejs demo you included, it would take you to the source code.
particularly look at:
https://github.com/mrdoob/three.js/blob/dev/examples/webgl_panorama_equirectangular.html
and
https://github.com/mrdoob/three.js/blob/dev/src/geometries/SphereBufferGeometry.js
not sure if there is distortion though. The distortion comes from the fact that the texture is mapped to the sphere, and the sphere is rendered in 3D (openGL).
I'm using Raphael to draw rectangles. Whoo-hoo!
Is there a way to right align contents of an SVG file?
Not just text, but shapes as well?
I can do the math and get the computed x value, but I'm looking for the lazy-simple solution.
Thank you.
There isn't. Unlike normal web pages where the window is resized and the content flows into it, when a Raphael paper is resized, there is no sort of flow, so aligning is irrelevant. Instead of setting align=right, you just set the right edge to be the same position you set the width of the paper to be. If you enlarge the paper, you can scale the contents with a single operation. Once you've set the position of the right edge, you've essentially set the align position. You don't need to re-set all edge values when the paper changes size, you just scale everything with one command. Hope that helps