Use shell to load in variables to replace placeholders - linux

I have a problem where my config files contents are placed within my deployment script because they get their settings from my setting.sh file. This causes my deployment script to be very large a bloated.
I was wondering if it would be possible in bash to do something like this
setting.sh
USER="Tom"
log.conf
log=/$PLACEHOLDER_USER/full.log
deployment.sh
#!/bin/bash
# Pull in settings file
. ./settings.sh
# Link config to right location
ln -s /home/log.conf /home/logging/log.conf
# Write variables on top of placeholder variables in the file
for $PLACEHOLDER_* in /home/logging/log.conf
do
(Replace $PLACEHOLDER_<VARAIBLE> with $VARIABLE)
done
I want this to work for any variable found in the config file which starts with $placeholder_
This process would allow me to move a generic config file from my repository and then add the proper variables from my setting file on top of the placeholder variables in the config.
I'm stuck on how I can get this to actually work using my deployment.sh.

This small script will read all variable lines from settings.sh and replace the PLACEHOLDER_xxx in file for each. Does this help you?
while IFS== read variable value
do
sed -i "s/\$PLACEHOLDER_$variable/$value/g" file
done < settings.sh

#!/usr/local/env bash
set -x
ln -s /home/log.conf /home/logging/log.conf
while read user
do
usertmp=$(echo "${user}" | sed s'#USER=\"##' \
sed s'#"$##')
user="${usertemp}"
log="${user}"/full.log
done < setting.sh
I don't really understand the rest of what you're trying to do, I will confess, but this will hopefully give you the idea. Use read.

Related

Running a Script to change a wp-config file DB Name

I teach students how to fix wordpress sites and I would like to write a script that looks at what information they have in their wp-config.php and add a single letter or number to the database name.
For example the line is such
define('DB_NAME', 'cpanelUser_NameofDB');
I would like to add a number or a line to the end of NameofDB
I can use this to isolate the cpanelUser_NameofDB
grep -i 'DB_NAME' wp-config.php | cut -d"'" -f4
but I'm not sure how to add information, nor if this is the correct script I should run to get there. I would also like it to not matter what the name of the database is since it will be ran on multiple sites. I'm sure I could use regex but I'm not too versed in that and would not know where to start. Help please!
You can use WP CLI on the server:
Go to the website root:
cd /var/www/mysite.com/htdocs
...and list all the wp-config values:
wp config list
...or set the value you need to change:
sudo wp config set DB_NAME put_my_custom_db_name_here --allow-root
See more WP CONFIG features here:
https://developer.wordpress.org/cli/commands/config/
You can use sed for this purpose to fix this line:
#!/bin/bash
id=34
sed -i "s/^.*DB_NAME.*$/define('DB_NAME', 'cpanelUser_NameofDB${id}');/" wp-config.php
flag -i means that we do change in file directly.
Alternatively you can make template file and generate new file while sed works on stdin and stdout
#!/bin/bash
id=34
cat wp-config.php-template| sed "s/^.*DB_NAME.*$/define('DB_NAME', 'cpanelUser_NameofDB${id}');/" > wp-config.php.$id

Iterate through files in a directory, create output files, linux

I am trying to iterate through every file in a specific directory (called sequences), and perform two functions on each file. I know that the functions (the 'blastp' and 'cat' lines) work, since I can run them on individual files. Ordinarily I would have a specific file name as the query, output, etc., but I'm trying to use a variable so the loop can work through many files.
(Disclaimer: I am new to coding.) I believe that I am running into serious problems with trying to use my file names within my functions. As it is, my code will execute, but it creates a bunch of extra unintended files. This is what I intend for my script to do:
Line 1: Iterate through every file in my "sequences" directory. (All of which end with ".fa", if that is helpful.)
Line 3: Recognize the filename as a variable. (I know, I know, I think I've done this horribly wrong.)
Line 4: Run the blastp function using the file name as the argument for the "query" flag, always use "database.faa" as the argument for the "db" flag, and output the result in a new file that is has the same name as the initial file, but with ".txt" at the end.
Line 5: Output parts of the output file from line 4 into a new file that has the same name as the initial file, but with "_top_hits.txt" at the end.
for sequence in ./sequences/{.,}*;
do
echo "$sequence";
blastp -query $sequence -db database.faa -out ${sequence}.txt -evalue 1e-10 -outfmt 7
cat ${sequence}.txt | awk '/hits found/{getline;print}' | grep -v "#">${sequence}_top_hits.txt
done
When I ran this code, it gave me six new files derived from each file in the directory (and they were all in the same directory - I'd prefer to have them all in their own folders. How can I do that?). They were all empty. Their suffixes were, ".txt", ".txt.txt", ".txt_top_hits.txt", "_top_hits.txt", "_top_hits.txt.txt", and "_top_hits.txt_top_hits.txt".
If I can provide any further information to clarify anything, please let me know.
If you're only interested in *.fa files I would limit your input to only those matching files like this:
for sequence in sequences/*.fa;
do
I can propose you the following improvements:
for fasta_file in ./sequences/*.fa # ";" is not necessary if you already have a new line for your "do"
do
# ${variable%something} is the part of $variable
# before the string "something"
# basename path/to/file is the name of the file
# without the full path
# $(some command) allows you to use the result of the command as a string
# Combining the above, we can form a string based on our fasta file
# This string can be useful to name stuff in a clean manner later
sequence_name=$(basename ${fasta_file%.fa})
echo ${sequence_name}
# Create a directory for the results for this sequence
# -p option avoids a failure in case the directory already exists
mkdir -p ${sequence_name}
# Define the name of the file for the results
# (including our previously created directory in its path)
blast_results=${sequence_name}/${sequence_name}_blast.txt
blastp -query ${fasta_file} -db database.faa \
-out ${blast_results} \
-evalue 1e-10 -outfmt 7
# Define a file name for the top hits
top_hits=${sequence_name}/${sequence_name}_top_hits.txt
# alternatively, using "%"
#top_hits=${blast_results%_blast.txt}_top_hits.txt
# No need to cat: awk can take a file as argument
awk '/hits found/{getline;print}' ${blast_results} \
| grep -v "#" > ${sequence_name}_top_hits.txt
done
I made more intermediate variables, with (hopefully) meaningful names.
I used \ to escape line ends and allow putting commands in several lines.
I hope this improves code readability.
I haven't tested. There may be typos.
You should be using *.fa if you only want files with a .fa ending. Additionally, if you want to redirect your output to new folders you need to create those directories somewhere using
mkdir 'folder_name'
then you need to redirect your -o outputs to those files, something like this
'command' -o /path/to/output/folder
To help you test this script out, you can run each line one by one to test them. You need to make sure each line works by itself before combining.
One last thing, be careful with your use of colons, it should look something like this:
for filename in *.fa; do 'command'; done

Common "include" file between shell and makefile

I've created an (makefiles oriented) include file which contains some variables defined to be used on by others makefiles.
# this is myinclude/makevars file
MY_FOLDER:=$(ROOT_FOLDER)/my/folder
ANOTHER_FOLDER:=$(MY_FOLDER)/another/folder
MY_LIB:=$(ANOTHER_FOLDER)/lib
this "include file" works just great if I include it in other makefiles:
include myinclude/makevars
but would be cool if I might include it in some shell script too!.
Currently I've created another file (myinclude/shellvars) very similar but "shell" oriented:
# this is myinclude/shellvars file
MY_FOLDER=$ROOT_FOLDER/my/folder
ANOTHER_FOLDER=$MY_FOLDER/another/folder
MY_LIB=$ANOTHER_FOLDER/lib
clearly by including this in my (shell) scripts anything works but I have a duplicated file with (semantically) the same info!
any idea to have this two files "merged" into one (myinclude/makevars and myinclude/shellvars) ? any special syntax?
any help is clearly appreciated!
-- kasper!
Try this:
eval "$(cat makevars.inc | tr -d '(:)')"
echo "$MY_LIB"
This loads the text of the target include file into memory, erases all colons and parentheses from it and then executes the result.

Obtaining file names from directory in Bash

I am trying to create a zsh script to test my project. The teacher supplied us with some input files and expected output files. I need to diff the output files from myExecutable with the expected output files.
Question: Does $iF contain a string in the following code or some kind of bash reference to the file?
#!/bin/bash
inputFiles=~/project/tests/input/*
outputFiles=~/project/tests/output
for iF in $inputFiles
do
./myExecutable $iF > $outputFiles/$iF.out
done
Note:
Any tips in fulfilling my objectives would be nice. I am new to shell scripting and I am using the following websites to quickly write the script (since I have to focus on the project development and not wasting time on extra stuff):
Grammar for bash language
Begginer guide for bash
As your code is, $iF contains full path of file as a string.
N.B: Don't use for iF in $inputFiles
use for iF in ~/project/tests/input/* instead. Otherwise your code will fail if path contains spaces or newlines.
If you need to diff the files you can do another for loop on your output files. Grab just the file name with the basename command and then put that all together in a diff and output to a ".diff" file using the ">" operator to redirect standard out.
Then diff each one with the expected file, something like:
expectedOutput=~/<some path here>
diffFiles=~/<some path>
for oF in ~/project/tests/output/* ; do
file=`basename ${oF}`
diff $oF "${expectedOutput}/${file}" > "${diffFiles}/${file}.diff"
done

how to print the ouput/error to a text file?

I'm trying to redirect(?) my standard error/output to a text file.
I did my research, but for some reason the online answers are not working for me.
What am I doing wrong?
cd /home/user1/lists/
for dir in $(ls)
do
(
echo | $dir > /root/user1/$dir" "log.txt
) > /root/Desktop/Logs/Update.log
done
I also tried
2> /root/Desktop/Logs/Update.log
1> /root/Desktop/Logs/Update.log
&> /root/Desktop/Logs/Update.log
None of these work for me :(
Help please!
Try this for the basics:
echo hello >> log.txt 2>&1
Could be read as: echo the word hello, redirecting and appending STDOUT to the file log.txt. STDERR (file descriptor 2) is redirected to wherever STDOUT is being pointed. Note that STDOUT is the default and thus there is no "1" in front of the ">>". Works on the current line only.
To redirect and append all output and error of all commands in a script, put this line near the top. It will be in effect for the length of the script instead of doing it on each line:
exec >>log.txt 2>&1
If you are trying to obtain a list of the files in /home/user1/lists, you do not need a loop at all:
ls /home/usr1/lists/ >Update.log
If you are attempting to run every file in the directory as an executable with a newline as its input, and collect the output from all these programs in Update.log, try this:
for file in /home/user1/lists/*; do
echo | "$file"
done >Update.log
(Notice how we avoid the useless use of ls and how there is no redirection inside the loop.)
If you want to create an empty file called *.log.txt for each file in the directory, you would do
for file in /home/user1/lists/*; do
touch "$(basename "$file")"log.txt
done
(Using basename to obtain the file name without the directory part avoids the cd but you could do it the other way around. Generally, we tend to avoid changing the directory in scripts, so that the tool can be run from anywhere and generate output in the current directory.)
If you want to create a file containing a single newline, regardless of whether it already exists or not,
for file in /home/user1/lists/*; do
echo >"$(basename "$file")"log.txt
done
In your original program, you redirect the echo inside the loop, which means that the redirection after done will not receive any output at all, so the created file will be empty.
These are somewhat wild guesses at what you might actually be trying to accomplish, but should hopefully help nudge you slightly in the right direction. (This should properly be a comment, I suppose, but it's way too long and complex.)

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