I'm having trouble trying to use replace characters in MS excel. Help says * and ? can both replace characters, but if I try using them in IF, I don't get correct results.
For example:
A1="something"
=IF(A1="*mething";"yes";"no")
I always get no... How to use * correctly?
wildcards don't work with comparison operators like =
To achieve what you want you can use COUNTIF which does accept wildcards, i.e.
=IF(COUNTIF(A1;"*mething")>0;"yes";"no")
or RIGHT function like
=IF(RIGHT(A1;7)="mething";"yes";"no")
Wildcards cannot be used in this context. Use something like:
=IF(ISERROR(FIND("mething",A1)),"No","Yes")
Related
I am trying to formnulate a regex to get the ids from the below two strings examples:
/drugs/2/drug-19904-5106/magnesium-oxide-tablet/details
/drugs/2/drug-19906/magnesium-moxide-tablet/details
In the first case, I should get 19904-5106 and in the second case 19906.
So far I tried several, the closes I could get is [drugs/2/drug]-.*\d but would return g-19904-5106 and g-19907.
Please any help to get ride of the "g-"?
Thank you in advance.
When writing a regex expression, consider the patterns you see so that you can align it correctly. For example, if you know that your desired IDs always appear in something resembling ABCD-1234-5678 where 1234-5678 is the ID you want, then you can use that. If you also know that your IDs are always digits, then you can refine the search even more
For your example, using a regex string like
.+?-(\d+(?:-\d+)*)
should do the trick. In a python script that would look something like the following:
match = re.search(r'.+?-(\d+(?:-\d+)*)', my_string)
if match:
my_id = match.group(1)
The pattern may vary depending on the depth and complexity of your examples, but that works for both of the ones you provided
This is the closest I could find: \d+|.\d+-.\d+
There is one condition where I have to split my string in the manner that all the alphabetic characters should stay as one unit and everything else should be separated like the example shown below.
Example:
Some_var='12/1/20 Balance Brought Forward 150,585.80'
output_var=['12/1/20','Balance Brought Forward','150,585.80']
Yes, you could use some regex to get over this.
Some_var = '12/1/20 Balance Brought Forward 150,585.80'
match = re.split(r"([0-9\s\\\/\.,-]+|[a-zA-Z\s\\\/\.,-]+)", Some_var)
print(match)
You will get some extra spaces but you can trim that and you are good to go.
split isn't gonna cut it. You might wanna look into Regular Expressions (abbreviated regex) to accomplish this.
Here's a link to the Python docs: re module
As for a pattern, you could try using something like this:
([0-9\s\\\/\.,-]+|[a-zA-Z\s\\\/\.,-]+)
then trim each part of the output.
I'm using a IF AND statement to check a simple statement, for example A>B&BB, I get FALSE. How is that even possible?
My data sample:
It works both ways if I use AND(), but I prefer to use &.
You may "prefer to use &" but unfortunately this operator in Excel has a different meaning: string concatenation. If you dont want to use AND, you can use * instead; but you will need to parenthesize the terms.
=IF((A2>C2)*(C2<B2), TRUE, FALSE)
Use AND():
IF(AND(A2>C2,C2<B2),TRUE,FALSE)
Or as was written in comments you can use multiplication:
IF((A2>C2)*(C2<B2),TRUE,FALSE)
FYI - you don't need IF().
If you use AND(A2>C2,C2<B2) the result will be Boolean (TRUE/FALSE).
I have a parameter called Analyst group in this format :
[Dimension].[Analyst Group].&[Nl.Workplace.Foundation]
I want to pass this parameter to another report, to filter data. Its a multi value parameter. But the other report only accepts it in this format : [KanBan].[Analyst Group].&[Nl.Workplace.Foundation]
So im trying to isolate the "Nl.Workplace.Foundation", so i can do the following thing in the Go To Report parameter expression :="[KanBan].[Analyst Group].&["& --Isolated analyst group-- &"]" to create the desired format.
So what i need is to extract the part between .&[ and ]
But i really have no idea how to isolate that part of the string.
Found a solution! If i just use the Parameter.label instead of Parameter.value it automatically does what i want!
A different solution has been found, but I will still answer the initial question. It could help.
So what i need is to extract the part between .&[ and ]
You could use a regex.
This may not be the fastest way but it can handle most of the situations.
So let's assume you have a string containing:
[Dimension].[Analyst Group].&[Nl.Workplace.Foundation]
And you want to get the following string:
Nl.Workplace.Foundation
Just use the following expression:
=System.Text.RegularExpressions.Regex.Match("[Dimension].[Analyst Group].&[Nl.Workplace.Foundation]", "\.&\[(?<NWF>[^]]+)\]").Groups("NWF").Value
In the expression, replace the input string with your dynamic values, like for example:
=System.Text.RegularExpressions.Regex.Match(Fields!Dimension.Value & "." & Fields!AnalystGroup.Value, "\.&\[(?<NWF>[^]]+)\]").Groups("NWF").Value
I'm keeping the formula as simple as possible so that you can easily adapt it, with, say, handling the case where an input string will not have a match (with the above query it will return #Error).
You could do this by adding an IIF() or better, use a custom function that you can reuse in several places and will reduce the length of your expression.
I want to remove all the characters from a string expect whatever character is between a certain set of characters. So for example I have the input of Grade:2/2014-2015 and I want the output of just the grade, 2.
I'm thinking that I need to use the FIND function to grab whatever is between the : and the / , this also needs to work with double characters such 10 however I believe that it would work so long as the defining values with the FIND function are correct.
Unfortunately I am totally lost on this when using the FIND function however if there is another function that would work better I could probably figure it out myself if I knew what function.
It's not particularly elegant but =MID(A1,FIND(":",A1)+1,FIND("/",A1) - FIND(":",A1) - 1) would work.
MID takes start and length,FIND returns the index of a given character.
Edit:
As pointed out, "Grade:" is fixed length so the following would work just as well:
=MID(A1,7,FIND("/",A1) - 7)
You could use LEFT() to remove "Grade:"
And then use and then use LEFTB() to remove the year.
Look at this link here. This is the way I would go about it.
=SUBSTITUTE(SUBSTITUTE(C4, "Grade:", ""), "/2014-2015", "")
where C4 is the name of your cell.