sed command inserting text - bash - linux

I am exploring sed function
what I have here is a simple text file shown below
Id,fruit name and quantity. now I want to add the amount of the fruit behind the quantity of each fruit respectively
fruit.txt
1,apple
2,banana
how to make it become like this.
expected output
first input of sed command
my textfile(fruit.txt) will become like this
1,apple,50
2,banana,40

Use sed like this:
sed -i -r 's/(apple)(,[0-9]*)?$/\1,10/'
sed -i -r 's/(apple)(,[0-9]*)?$/\1,20/'
sed -i -r 's/(apple)(,[0-9]*)?$/\1,30/'

use awk:
awk -F, -v OFS="," '/apple/{$3="whatever"}7' file
but if you don't have gnu awk 4.1, you have to do this to write back to the file:
awk -F, -v OFS="," '/apple/{$3="whatever"}7' file >~/foo.tmp && mv ~/foo.tmp file

Related

How do you change column names to lowercase with linux and store the file as it is?

I am trying to change the column names to lowercase in a csv file. I found the code to do that online but I dont know how to replace the old column names(uppercase) with new column names(lowercase) in the original file. I did something like this:
$cat head -n1 xxx.csv | tr "[A-Z]" "[a-z]"
But it simply just prints out the column names in lowercase, which is not enough for me.
I tried to add sed -i but it did not do any good. Thanks!!
Using awk (readability winner) :
concise way:
awk 'NR==1{print tolower($0);next}1' file.csv
or using ternary operator:
awk '{print (NR==1) ? tolower($0): $0}' file.csv
or using if/else statements:
awk '{if (NR==1) {print tolower($0)} else {print $0}}' file.csv
To change the file for real:
awk 'NR==1{print tolower($0);next}1' file.csv | tee /tmp/temp
mv /tmp/temp file.csv
For your information, sed using the in place edit switch -i do the same: it use a temporary file under the hood.
You can check this by using :
strace -f -s 800 sed -i'' '...' file
Using perl:
perl -i -pe '$_=lc() if $.==1' file.csv
It replace the file on the fly with -i switch
You can use sed to tell it to replace the first line with all lower-case and then print the rest as-is:
sed '1s/.*/\L&/' ./xxx.csv
Redirect the output or use -i to do an in-place edit.
Proof of Concept
$ echo -e "COL1,COL2,COL3\nFoO,bAr,baZ" | sed '1s/.*/\L&/'
col1,col2,col3
FoO,bAr,baZ

Search A and replace B in A|B in shell scripting/SED/AWK

I have a text file with layout as:
tableName1|counterVariable1
tableName2|counterVariable2
I want to replace the counterVariable1 with some other variable say counterVariableNew.
How can I accomplish this?
I have tried various SED/AWK approaches, closest one is mentioned below:
cat $fileName | grep -w $tableName | sed -i 's/$tableName\|counterVariable/$tableName\|counterVariableNew'
But all the 3 commands are not merging properly, please help!
Your script is an example of [ useless use of cat ]. But the key point here is to escape the pipe delimiter which has a special meaning(it stands for OR) when used with awk FS. So below script should do
# cat 42000479
tableName1|counterVariable1
tableName2|counterVariable2
tableName3|counterVariable2
# awk -F\| '$1=="tableName2"{$2="counterVariableNew"}1' 42000479
tableName1|counterVariable1
tableName2 counterVariableNew
tableName3|counterVariable2
An alternate way of doing the same stuff is below
# awk -v FS='|' '$1=="tableName2"{$2="counterVariableNew"}1' 42000479
Stuff inside the single quote will not be expanded.
awk -F'|' -v OFS='|' '/tableName1/ {$2="counterVariableNew"}1' file
tableName1|counterVariableNew
tableName2|counterVariable2
This will search for A (tableName1) and replace B (counterVariable1) to counterVariableNew.
Or by using sed :
sed -r '/tableName1/ s/(^.*\|)(.*)/\1counterVariableNew/g' file
tableName1|counterVariableNew
tableName2|counterVariable2
For word bounded search: Enclose the pattern inside \< and \> .
sed -r '/\<tableName1\>/ s/(^.*\|)(.*)/\1counterVariableNew/g' file
awk -F'|' -v OFS='|' '/\<tableName1\>/ {$2="counterVariableNew"}1' file

How to replace one or more consecutive symbols with one symbol in shell

I have a file containing consecutive symbols (as pipe "|") like
ANKRD54,LIAR,allergy,|||
ANKRD54,LIAR,asthma,||20447076||
ANKRD54,LIAR,autism,||||
ANKRD54,LIAR,cancer,|||
ANKRD54,LIAR,chronic_obstructive_pulmonary_disease,|||
ANKRD54,LIAR,dental_caries,||||
Now using shell or a sed command in shell is it possible to replace multiple pipe with one pipe like
ANKRD54,LIAR,allergy,|
ANKRD54,LIAR,asthma,|20447076|
ANKRD54,LIAR,autism,|
ANKRD54,LIAR,cancer,|
ANKRD54,LIAR,chronic_obstructive_pulmonary_disease,|
ANKRD54,LIAR,dental_caries,|
I guess the easiest way is use built-in commands: cat your_file | tr -s '|'
Pass your text to sed (e.g. via a pipe)
cat your_file | sed "s/|\+/|/g"
You can do that with a simple awk gsub as:-
awk -F"," -v OFS="," '{gsub(/[|]+/,"|",$4)}1' file
See it in action:-
$ cat file
ANKRD54,LIAR,allergy,|||
ANKRD54,LIAR,asthma,||20447076||
ANKRD54,LIAR,autism,||||
ANKRD54,LIAR,cancer,|||
ANKRD54,LIAR,chronic_obstructive_pulmonary_disease,|||
ANKRD54,LIAR,dental_caries,||||
$ awk -F"," -v OFS="," '{gsub(/[|]+/,"|",$4)}1' file
NKRD54,LIAR,allergy,|
ANKRD54,LIAR,asthma,|20447076|
ANKRD54,LIAR,autism,|
ANKRD54,LIAR,cancer,|
ANKRD54,LIAR,chronic_obstructive_pulmonary_disease,|
ANKRD54,LIAR,dental_caries,|

sed extract text between two patterns where second pattern may be either of one

I am trying to extract text between pattern1 (fixed) and pattern2 (this can be p2-1/p2-2).
can you please tell me how to achieve this in a single command?
A file starts with start and ends with either end or close
File1:
======
junktest
data
start
stackoverflow
sed
close
File2:
======
data2
start
stackoverflow
end
I can extract text from File1 with
sed -n "/start/,/close/p"
And from File2 with
sed -n "/start/,/end/p"
I need a single sed command to achieve both..
something like:
sed -n "/start/, /close or end /p"
Both GNU sed and BSD sed:
sed -nE '/start/,/close|end/p' file
This awk looks better
awk '/start/,/end|close/' file
sed -n -E "/Word1/,/Word2-1/p" | sed -n -E "/Word1/,/Word2-2/p"
Easy with awk:
$ awk '/start/{p=1}p{print}/end|close/{p=0}' file

How to delete lines from file with sed\awk?

I have file, with lines, contains ip with netmask
a.b.c.d/24
w.x.y.z/32
etc
How to delete delete specific row?
i'm using
sed -ie "s#a.b.c.d/24##g" %filname%
but after the removal is an empty string in file.
It should run inside a script, with ip as parameter and also work in freebsd under sh.
Sed solution
sed -i '/<pattern-to-match-with-proper-escape>/d' data.txt
-i option will change the original file.
Awk solution
awk '!/<pattern-to-match-with-proper-escape>/' data.txt
Using sed:
sed -i '\|a.b.c.d/24|d' file
Command line arg:
For the input being command line argument, say 1st argument($1):
sed -i "\|$1|d" file
Replace $1 with appropriate argument number as is your case.
You should use d (delete) not g. Also do not use s (replacement).
sed -ie '/a.b.c.d\/24/d' %filename%
In a script you should using it in this way
IP=$1
IPA=${IP////\\/}
sed -i /"${IPA}"/d %filename%
And the script parameter should be called in this way:
./script.sh a.b.c.d/24
perl -i -lne 'print unless(/a.b.c.d\/24/)' your_file
or in awk if you donot want to do inplace editing:
awk '$0!~/a.b.c.d\/24/' your_file

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