I want to show a circle around only invalid data.
i have done the complete steps shown in this link
But this circle shown is very big and covers the entire cell.
I want a small circle only covering the data not the entire cell's width.
Data validation is a built in Excel functionality. It checks whole cell value.
So it is not possible, using Data validation, to accomplish what your trying.
It MAY BE POSSIBLE using VBA, shapes, events and (hard) parsing character rendering. In your place, I would be glad with this very big circles!!! :)
I agree with #LS_dev. See this MS Article about changing data validation for printing. Try modifying it to loop through all your data validation and change the width and height.
You can probably do it with this part of the code by changing the width and height:
If Not c.Validation.Value Then
Set o = ActiveSheet.Shapes.AddShape(msoShapeOval, _
c.Left - 2, c.Top - 2, c.Width + 4, c.Height + 4)
o.Fill.Visible = msoFalse
o.Line.ForeColor.SchemeColor = 10
o.Line.Weight = 1.25
Related
I have a building a set of stencil shapes and I need the text to display below the shape. I am using custom formulas to generate the text, and as such the volume of text changes from use case to use case.
What I have come across is using the Text Transform set of properties, and I have tried the following with success for a single line of text:
TxtWidth = TEXTWIDTH(TheText)
TxtPinX = Width * 0.5
TxtLocPinX = TxtWidth * 0.5
TxtHeight = Height * 0
TxtPinY = Height * -0.2
TxtLocPinY = TxtHieght * 0.5
TxtAngle = 0 deg
The problem arises when there is more than a single line of text to display -> the text appears 'half above (inside) and half below' the bottom the shape.
I would like to place all the text, regardless of how many lines there are, underneath the shape.
What I have tried is to set the TxtPinY = some formula different from above eg/ Height * -(TxtHeight). This seems to always result in an 'error in formula'.
I am sure that this is something simple that I am missing, but I cannot figure it out.
Can anybody point me in the right direction?
Cheers and thanks for taking a look at this,
The Frog
You could try the TEXTHEIGHT function to get around this. Specify a reasonable maximum text widht as a second parameter for it:
TxtHeight = TEXTHEIGHT(TheText,100)
TxtPinY = 0
TxtLocPinY = TxtHeight
You can use the code provided with the stencil available in this post:
http://visguy.com/vgforum/index.php?topic=7461.msg31490#msg31490
I am using Apache POI SXSSF to generate xlsx document. The document uses Times New Roman sizes 9 and 11, and the default cell width and height have been changed. The question is how to calculate the height of the merged cells so that all the text fits (the height of the cell must be dynamically set according to the given text)? The server running the application does not have a display, and this code is running in the IBM Integration Bus.
The solution from How to get the needed height of a multi line rich-text field (any font, any font size) having defined width using Java? is not suitable. The server running the application is missing a display and the string int ppi = java.awt.Toolkit.getDefaultToolkit().getScreenResolution(); returns an exception, and manually picking the ppi value is also not possible. If there is a display, everything works correctly.
And is there any way to use the "align center selection" function somehow?
I found that centering a selection gives a similar result as merging multiple cells horizontally, but I couldn't find an answer anywhere on how to use this in Apache POI. As a result, experimentally, I found out that in order to achieve this effect, you need to do the following things:
Create CellStyle; specify setWrapText(true) and setAlignment(HorizontalAlignment.CENTER_SELECTION) for it
Apply the style created in step 1 to all cells that need to be merged
Specify the value in the first cell
Code example:
Font font = wb.createFont(); // where wb - is SXSSFWorkbook object
font.setFontName("Times New Roman");
font.setFontHeightInPoints((short) 11);
CellStyle style = wb.createCellStyle();
style.setFont(font);
style.setWrapText(true);
style.setAlignment(HorizontalAlignment.CENTER_SELECTION);
for (int i = 0; i <= endCellNum - firstCellNum; i++){ // where endCellNum - number of last cell of selection and firstCellNum is number of first cell of selection
Cell cell = curRow.createCell(firstCellNum + i);
cell.setCellStyle(cs);
if (i == 0){
firstCell = cell;
}
}
firstCell.setCellValue(value);
I have an existing Excel file I need to work with. It contains a line graph where measurement results are plotted. All the referencing is done via names. The graph is called "ChartResult".
Obviously Excel discriminates the graph area (the "outer") and the plot area (the "inner") where the graph is plotted. Please correct me if I'm wrong, also learning the preferred english nomenclature would be of great help.
My goal is to print the (page containing the) table so that the division/auxiliary lines have a specific distance from each other. My thinking was that if I define the scale of the axis (the max and min values) and define a size of the graph I would acheive this goal.
However in Excel I can only type in the size of the whole graph area, which is the outer thing, so not helpful when I want to define the size of the graph, the inner thing.
I started using VBA to acheive this but haven't been succesful:
Sub Groesse_eingeben()
ActiveSheet.ChartObjects("ChartResult").Activate
ActiveChart.SeriesCollection(1).Select
ActiveChart.PlotArea.Select
Selection.Left = 0
Selection.Top = 0
Selection.Width = 200
Selection.Height = 200
End Sub
This code is changing the size an position of the graph but not to what I expected it to be. Is the input of Selection.XY in pixels or mm? I naively assumed mm but my graph becomes smaller than 200x200 mm, around 60x60 mm.
Thank you!
Chris
System:
Microsoft® Excel® 2016 MSO (Version 2204 Build 16.0.15128.20128)
Win10 Pro 21H2
Update:
Ok, the input size is points. But how to specify the exact size of the graph?
On the screenshot there are two dotted borders: One, the inner, is the actual size of the visible graph the other is the size of the graph object. To cause more confusion: Both are within the graph area, which I called "outer" area above :)
How can I input the exact numbers for the actual visible graph?
You can control the outer width of the chart (ChartObject) with the .Width property, and the inner width of the chart with the .Chart.PlotArea.Width property.
Here is a sub that takes a chart and widths as inputs, and updates the chart:
Private Sub SetChartWidths(Ch As ChartObject, OuterWidth As Long, InnerWidth As Long)
' Set the outer width of the chart
Ch.Width = OuterWidth
' Set the inner width (plot area width)
Ch.Chart.PlotArea.Width = InnerWidth
End Sub
EDIT START
And here is how you can use the sub:
Private Sub UseSubroutine()
' Store the chart object in a variable
Dim LineChart As ChartObject
Set LineChart = ThisWorkbook.Sheets("Sheet1").ChartObjects(1)
' Run the sub
SetChartWidths Ch:=LineChart, OuterWidth:=200, InnerWidth:=150
End Sub
If you're having trouble using the SetChartWidths sub, and it is in a different Module than the code you're calling it from, you can remove the Private from the front to change the Scope of the sub.
EDIT END
As for what widths to use, that will be up to you.
So column width is done using cell width on all cells in one column ike this:
from docx import Document
from docx.shared import Cm
file = /path/to/file/
doc = Document(file)
table = doc.add_table(4,2)
for cell in table.columns[0].cells:
cell.width = Cm(1.85)
however, the row height is done using rows, but I can't remember how I did it last week.
Now I managed to find a way to reference the rows in a table, but can't seem to get back to that way. It is possible to change the height by using the add_row method, but you can't create a table with no rows, so the the top row will always be the default height, which about 1.6cms.
There is a way to access paragraphs without using add_paragraph, does anyone know how to access the rows without using the add_row method because it was that that I used to set row height in a table as a default.
I have tried this but it doesn't work:
row = table.rows
row.height = Cm(0.7)
but although this does not give an error, it also has no effect on the height.
table.rows is a collection, in particular a sequence, so you need to access each row separately:
for row in table.rows:
row.height = Cm(0.7)
Also check out row.height_rule for some related behaviors you have access to:
https://python-docx.readthedocs.io/en/latest/api/table.html#row-objects
When you assign to table.rows.height, it just adds a .height instance attribute that does nothing. It's one of the side-effects of a dynamic language like Python that you encounter a mysterious behavior like this. It goes away as you gain more experience though, at least it has for me :)
Some additional information:
The answer here is correct, but this will give a minimum row height. Using WD_ROW_HEIGHT_RULE.EXACTLY will fix the cell height to the set row height ignoring the contents of the cell, this can result in cropping of the text in an undesirable way.
para = table.cell(0,0).add_paragrph('some text')
SOLUTION:
add_paragraph actually adds a blank line above the text.
Use the following instead to avoid using add_paragraph:
table.cell(0,0).paragraphs[0].text = 'some text'
or using add_run can make it easier to also work with the text:
run = table.cell(0,0).paragraphs[0].add_run('some text')
run.bold = True
I want to put a transparent label on top of a sheet in Excel, so that I can take advantage of the MouseMove event of the label to "draw cells" (aka change their fill color and so on) by mouse click / drag / etc. - since I can't do that on the cells per se.
Now everything works just fine, except that I can't make the label transparent at runtime (aka in VBA) ... while by doing exactly the same thing in Design Mode works as expected. Specifically, I have the code (more or less):
Dim MapLabel As OLEObject
On Error Resume Next
Sheet2.OLEObjects("MapLabel").Delete
Set MapLabel = Sheet2.OLEObjects.Add("Forms.Label.1")
MapLabel.name = "MapLabel"
MapLabel.Placement = xlMoveAndSize
MapLabel.Object.Caption = ""
' Problem line below
MapLabel.Object.BackStyle = fmBackStyleTransparent
' Problem line above
MapLabel.Left = Sheet2.cells(2, 6).Left
MapLabel.Top = Sheet2.cells(2, 6).Top
MapLabel.Width = Sheet2.cells(2,6).Width * 10
MapLabel.Height = Sheet2.cells(2,6).Height * 10
So, in words, I first delete the label named 'MapLabel', then recreate it (the above code goes into a "init" Sub). All the code lines except the one marked produce the desired result. The marked one does set the BackStyle property of the label to fmBackStyleTransparent ... but it doesn't actually make the label transparent. This is frustrating, because it's the same approach that works flawlessly at design time!
Do you have a solution to this? I read about solving similar problems by declaring the label as MsForms.Label or as Control, but the sheet object doesn't have those properties, plus, there are far more label properties which can be set using the OLEObject than with the help of MsForms.Label or Control.
All you need to do after this line:
MapLabel.Object.BackStyle = fmBackStyleTransparent
put this line:
ActiveSheet.Shapes(MapLabel.Name).Fill.Transparency = 1
I hope I helped.
P.S. If you need explanation i will edit my answer.
I had the same problem as you but in Word. The solution for me was to do the following:
In design mode:
Right click on the object
Navigate to Switch to automatic form/Image > Wrapping > In front of the text
Add an empty picture to your label