How do you get text from a textView in Haskell?
I am not sure I am doing it right. The only "get" function I could find in the TextView class is textViewGetBuffer which evaluates to an IO TextBuffer, not a string.
I am trying to get the string value of the IO TextBuffer using textBufferGetText :: self -> TextIter -> TextIter -> Bool -> String, but cannot figure out what to specify as the TextIter values.
The TextIter values specify the start and end of the range to get text, but when I looked up the TextIter datatype it did not specify any value constructors I could use.
name = textBufferGetText (textViewGetBuffer txtView) start end True
Any suggestions/help would be greatly appreciated.
(Disclaimer: I don't know how to use GTK in Haskell and I can't install it on this machine, so I can't test this)
Looking at the documentation, there are several methods to get a TextIter value from a TextBufferClass. The ones you're probably interested in are the textBufferGetStartIter and textBufferGetEndIter, which each take a TextBufferClass and return IO TextIter, so you could write a function something like
textViewGetValue :: TextViewClass self => self -> IO String
textViewGetValue tv = do
buf <- textViewGetBuffer tv
start <- textBufferGetStartIter buf
end <- textBufferGetEndIter buf
value <- textBufferGetText buf start end True
return value
which should work. Technically, the last two lines could just be textBufferGetText buf start end True, but I think this makes it a bit more clear what is happening.
EDIT: I should say that I found these methods in Graphics.UI.Gtk.Multiline.TextView, Graphics.UI.Gtk.Multiline.TextBuffer, and Graphics.UI.Gtk.Multiline.TextIter, so you may have to import those as well. But I don't know what all is already in your namespace.
Related
I have a program I'm trying to create of a one line text editor
I've come to a bit of a wall at this point.
I have a list of letters called left and one called right
perhaps in a function or a do list how can I set left to left ++ char where char is a user inputted char. I understand it's not possible to modify lists but can I redefine them?
If this pseudo code helps
left = "hello"
in = get user input
left = left ++ in
Thanks in advance
This is what the State Monad is for. The link should help (it points to a tutorial). Your example would then become:
type Line = State String ()
addInput :: String -> Line
addInput inp = do
left <- get
put $ left ++ inp
runState (addInput <user input>) "hello"
This does, however, require getting to know monads a bit. Follow the examples in the link.
I need to create a function that basically works like this :
insert_char("string" 'x') outputs "sxtxrxixnxg".
So here is my reasoning :
Create a list with every single character in the string :
let inserer_car(s, c) =
let l = ref [] in
for i = 0 to string.length(s) - 1 do
l := s.[i] :: !l
done;
Then, I want to use List.map to turn it into a list like ['s', 'x', 't', 'x' etc.].
However, I don't really know how to create my function to use with map. Any help would be appreciated!
I'm a beginner in programming and especially in ocaml! so feel free to assume I'm absolutely ignorant.
If you were using Core, you could write it like this:
open Core.Std
let insert_char s c =
String.to_list s
|> (fun l -> List.intersperse l c)
|> String.of_char_list
Or, equivalently:
let insert_char s c =
let chars = String.to_list s in
let interspersed_chars = List.intersperse chars c in
String.of_char_list interspersed_chars
This is just straightforward use of existing librariies. If you want the implementation of List.intersperse, you can find it here. It's quite simple.
A map function creates a copy of a structure with different contents. For lists, this means that List.map f list has the same length as list. So, this won't work for you. Your problem requires the full power of a fold.
(You could also solve the problem imperatively, but in my opinion the reason to study OCaml is to learn about functional programming.)
Let's say you're going to use List.fold_left. Then the call looks like this:
let result = List.fold_left myfun [] !l
Your function myfun has the type char list -> char -> char list. In essence, its first parameter is the result you've built so far and its second parameter is the next character of the input list !l. The result should be what you get when you add the new character to the list you have so far.
At the end you'll need to convert a list of characters back to a string.
I have a recursive function working within the scope of strictly defined interface, so I can't change the function signatures.
The code compiles fine, and even runs fines without error. My problem is that it's a large result set, so it's very hard to test if there is a semantic error.
My primary question is: In a sequence of function calls A to B to A to B to breaking condition, considering the same original Map is passed to all functions until breaking condition, and that some functions only return an Integer, would an insert on a Map in a function that only returns an Integer still be reflected once control is returned to the first function?
primaryFunc :: SuperType -> MyMap -> (Integer, MyMap)
primaryFunc (SubType1 a) mapInstance = do
let returnInt = func1 a mapInstance
(returnInt, mapInstance)
primaryFunc (SubType2 c) mapInstance = do
let returnInt = primaryFunc_nonprefix_SuperType c mapInstance
let returnSuperType = (Const returnInt)
let returnTable = H.insert c returnSuperType mapInstance
(returnInt, returnTable)
primaryFunc (ConstSubType d) mapInstance = do
let returnInt = d
(returnInt, mapInstance)
func1 :: SubType1 -> MyMap -> Integer
func1 oe vt = do
--do stuff with input and map data to get return int
returnInt = primaryFunc
returnInt
func2 :: SubType2 -> MyMap -> Integer
func2 pe vt = do
--do stuff with input and map data to get return int
returnInt = primaryFunc
returnInt
Your question is almost impossibly dense and ambiguous, but it should be possible to answer what you term your "primary" question from the simplest first principles of Haskell:
No Haskell function updates a value (e.g. a map). At most it can return a modified copy of its input.
Outside of the IO monad, no function can have side effects. No function can affect the value of any variable assigned before it was called; all it can do is return a value.
So if you pass a map as a parameter to a function, nothing the function does can alter your existing reference to that value. If you want an updated value, you can only get that from the output of a function to which you have passed the original value as input. New value, new reference.
Because of this, you should have absolute clarity at any depth within your web of functions about which value you are working with. Knowing this, you should be able to answer your own question. Frankly, this is such a fundamental characteristic of Haskell that I am perplexed that you even need to ask.
If a function only returns an integer, then any operations you perform on any values made available to the function can only affect the output - that is, the integer value returned. Nothing done within the function can affect anything else (short of causing the whole program to crash).
So if function A has a reference to a map and it passes this value to function B which returns an int, nothing function B does can affect A's copy of the map. If function B were allowed to secretly alter A's copy of the map, that would be a side effect. Side effects are not allowed.
You need to understand that Haskell does not have variables as you understand them. It has immutable values, references to immutable values and functions (which take inputs and return new outputs). Functions do not have variables which are in scope for other functions which might alter those variables on the fly. That cannot happen.
As an aside, not only does the code you posted show that you do not understand the basics of Haskell syntax, the question you asked shows that you haven't understood the primary characteristics of Haskell as a language. Not only are these fundamentals things which can be understood before having learned any syntax, they are things you need to know to make sense of the syntax.
If you have a deadline, meet it using a tool you do understand. Then go learn Haskell properly.
In addition, you will find that
an insert on a Map in a function that only returns an Integer
is nearly impossible to express. Yes, you can technically do it like in
insert k v map `seq` 42 -- force an insert and throw away the result
but if you think that, for example:
let done = insert k v map in 42
does anything with the map, you're probably wrong.
In no case, however, is the original map altered.
I have an assignment which is to create a calculator program in Haskell. For example, users will be able to use the calculator by command lines like:
>var cola =5; //define a random variable
>cola*2+1;
(print 11)
>var pepsi = 10
>coca > pepsi;
(print false)
>def coke(x,y) = x+y; //define a random function
>coke(cola,pepsi);
(print 15)
//and actually it's more complicated than above
I have no clue how to program this in Haskell. All I can think of right now is to read the command line as a String, parse it into an array of tokens. Maybe go through the array, detect keywords such "var", "def" then call functions var, def which store variables/functions in a List or something like that. But then how do I store data so that I can use them later in my computation?
Also am I on the right track because I am actually very confused what to do next? :(
*In addition, I am not allowed to use Parsec!*
It looks like you have two distinct kinds of input: declarations (creating new variables and functions) and expressions (calculating things).
You should first define some data structures so you can work out what sort of things you are going to be dealing with. Something like:
data Command = Define Definition | Calculate Expression | Quit
type Name = String
data Definition = DefVar Name Expression | DefFunc Name [Name] Expression
-- ^ alternatively, implement variables as zero-argument functions
-- and merge these cases
data Expression = Var Name | Add Expression Expression | -- ... other stuff
type Environment = [Definition]
To start off with, just parse (tokenise and then parse the tokens, perhaps) the stuff into a Command, and then decide what to do with it.
Expressions are comparatively easy. You assume you already have all the definitions you need (an Environment) and then just look up any variables or do additions or whatever.
Definitions are a bit trickier. Once you've decided what new definition to make, you need to add it to the environment. How exactly you do this depends on how exactly you iterate through the lines, but you'll need to pass the new environment back from the interpreter to the thing which fetches the next line and runs the interpreter on it. Something like:
main :: IO ()
main = mainLoop emptyEnv
where
emptyEnv = []
mainLoop :: Environment -> IO ()
mainLoop env = do
str <- getLine
case parseCommnad str of
Nothing -> do
putStrLn "parse failed!"
mainLoop env
Just Quit -> do
return ()
Just (Define d) -> do
mainLoop (d : env)
Just (Calculate e) -> do
putStrLn (calc env e)
mainLoop env
-- the real meat:
parseCommand :: String -> Maybe Command
calc :: Environment -> Expression -> String -- or Integer or some other appropriate type
calc will need to look stuff up in the environment you create as you go along, so you'll probably also need a function for finding which Definition corresponds to a given Name (or complaining that there isn't one).
Some other decisions you should make:
What do I do when someone tries to redefine a variable?
What if I used one of those variables in the definition of a function? Do I evaluate a function definition when it is created or when it is used?
These questions may affect the design of the above program, but I'll leave it up to you to work out how.
First, you can learn a lot from this tutorial for haskell programming
You need to write your function in another doc with .hs
And you can load the file from you compiler and use all the function you create
For example
plus :: Int -> Int -- that mean the function just work with a number of type int and return Int
plus x y = x + y -- they receive x and y and do the operation
I am trying to use Parsec to parse something like this:
property :: CharParser SomeObject
property = do
name
parameters
value
return SomeObjectInstance { fill in records here }
I am implementing the iCalendar spec and on every like there is a name:parameters:value triplet, very much like the way that XML has a name:attributes:content triplet. Infact you could very easily convert an iCalendar into XML format (thought I can't really see the advantages).
My point is that the parameters do not have to come in any order at all and each paramater may have a different type. One parameter may be a string while the other is the numeric id of another element. They may share no similarity yet, in the end, I want to place them correctly in the right record fields for whatever 'SomeObjectInstance' that I wanted the parser to return. How do I go about doing this sort of thing (or can you point me to an example of where somebody had to parse data like this)?
Thankyou, I know that my question is probably a little confused but that reflects my level of understanding of what I need to do.
Edit: I was trying to avoid giving the expected output (because it is large, not because it is hidden) but here is an example of an input file (from wikipedia):
BEGIN:VCALENDAR
VERSION:2.0
PRODID:-//hacksw/handcal//NONSGML v1.0//EN
BEGIN:VEVENT
UID:uid1#example.com
DTSTAMP:19970714T170000Z
ORGANIZER;CN=John Doe:MAILTO:john.doe#example.com
DTSTART:19970714T170000Z
DTEND:19970715T035959Z
SUMMARY:Bastille Day Party
END:VEVENT
END:VCALENDAR
As you can see it contains one VEvent inside a VCalendar, I have made data structures that represent them here.
I am trying to write a parser that parses that type of file into my data structures and I am stuck on the bit where I need to handle properties coming in any order with any type; date, time, int, string, uid, ect. I hope that makes more sense without repeating the entire iCalendar spec.
Parsec has the Parsec.Perm module precisely to parse unordered but linear (i.e. at the same level in the syntax tree) elements such as attribute tags in XML files.
Unfortunately the Perm module is mostly undocumented. The best reference is the Parsing Permutation Phrases paper which the Haddock doc page refers to, but even that is largely a description of the technique rather than how to use it.
Ok, so between BEGIN:VEVENT and END:VEVENT, you have many key value pairs. So write a rule keyValuePair that returns (key, value). Now inside the rule for VEVENT you do many KeyValuePair to get a list of pairs. Once you've done that you use a fold to populate a VEVENT record with the given values. In the function you give to fold, you use pattern matching to find out in which field to store the value. As the starting value for the accumulator you use a VEvent record where the optional fields are set to Nothing. Example:
pairs <- many keyValuePairs
vevent = foldr f (VEvent {sequence = Nothing}) pairs
where f ("SUMMARY", v) ve = ve {summary = v}
f ("DSTART", v) ve = ve {dstart = read v}
...and so on. Do the same for the other components.
Edit: Here's some runnable example code for the fold:
data VEvent = VEvent {
summary :: String,
dstart :: String,
sequenceSt :: Maybe String
} deriving Show
vevent pairs = foldr f (VEvent {sequenceSt = Nothing}) pairs
where f ("SUMMARY", v) ve = ve {summary = v}
f ("DSTART", v) ve = ve {dstart = v}
f ("SEQUENCEST", v) ve = ve {sequenceSt = Just v}
main = do print $ vevent [("SUMMARY", "lala"), ("DSTART", "lulu")]
print $ vevent [("SUMMARY", "lala"), ("DSTART", "lulu"), ("SEQUENCEST", "lili")]
Output:
VEvent {summary = "lala", dstart = "lulu", sequenceSt = Nothing}
VEvent {summary = "lala", dstart = "lulu", sequenceSt = Just "lili"}
Note that this will produce a warning when compiled. To avoid the warning, initialize all non-optional fields to undefined explicitly.