1 aaa bbb aaa
2 aaa ccccccccc aaa
3 aaa xx aaa
How to replace the second aaa to yyy for each line
1 aaa bbb yyy
2 aaa ccccccccc yyy
3 aaa xx yyy
Issuing the following command will solve your problem.
:%s/\(aaa.\{-}\)aaa/\1yyy/g
Another way would be with \zs and \ze, which mark the beginning and end of a match in a pattern. So you could do:
:%s/aaa.*\zsaaa\ze/yyy
In other words, find "aaa" followed by anything and then another "aaa", and replace that with "yyy".
If you have three "aaa"s on a line, this won't work, though, and you should use \{-} instead of *. (See :h non-greedy)
Related
I'm trying to sort a file but I can't get the results I want.
I have this file :
742550111 aaa aaa aaa aaa aaa 2008 3 1 1
5816470687 aa a dissertation for the 933 2 2 2
Each field is separated by a tabulation, and I would like to sort on the second column.
When I try sort test.txt -t\t -k 2, the output is the same as in the file.
But the output I want to have is :
5816470687 aa a dissertation for the 933 2 2 2
742550111 aaa aaa aaa aaa aaa 2008 3 1 1
I think that's because sort ignores the spaces between the words.
So I tried with this command : LC_ALL=C sort test.txt -t\t -k 2, but it still doesn't work.
Do you have any ideas ?
Bash replaces $'\t' with a real tab:
LC_ALL=C sort file -t $'\t' -k 2
Output:
5816470687 aa a dissertation for the 933 2 2 2
742550111 aaa aaa aaa aaa aaa 2008 3 1 1
My requirement is to get the count based on the field.
For example:
AAA 1234
AAA 111
...
AAA 112
BBB 123
BBB 123
...
BBB 333
CCC 333
Output should be:
AAA 2000
BBB 300
CCC 1
I am using the Sort card:
SORT FIELDS=(1,3,CH,A)
OUTFIL REMOVECC,NODETAIL,
SECTIONS=(1,3,TRAILER3=(1,3,X,COUNT=(M10,LENGTH=10)))
But I need the count to be left justified. Currently the count is displaying with leading spaces.
How can I make these count results left justified?
Let's say I have below text.
aaaaaaa
aaaaaaa
bbb
bbb
bbb
ccccccccccccc
ddddd
ddddd
Is there a way to modify the text as the following.
1 aaaaaaa
1 aaaaaaa
2 bbb
2 bbb
2 bbb
3 ccccccccccccc
4 ddddd
4 ddddd
You could use something like this in awk:
$ awk '{print ($0!=p?++i:i),$0;p=$0}' file
1 aaaaaaa
1 aaaaaaa
2 bbb
2 bbb
2 bbb
3 ccccccccccccc
4 ddddd
4 ddddd
i is incremented whenever the current line differs from the previous line. p holds the value of the previous line, $0.
Alternatively, as suggested by JID:
awk '$0!=p{p=$0;i++}{print i,$0}' file
When the current line differs from p, replace p and increment i. See the comments for discussion of the pros and cons of either approach :)
A further contribution (and even shorter!) by NeronLeVelu
$ awk '{print i+=($0!=p),p=$0}' file
This version performs the addition assignment and basic assignment within the print statement. This works because the return value of each assignment is the value that has been assigned.
As pointed out in the comments, if the first line of the file is empty, the behaviour changes slightly. Assuming that the first line should always begin with a 1, the following block can be added to the start of any of the one-liners:
NR==1{p=$0;i=1}
i.e. on the first line, initialise p to the contents of the line (empty or not) and i to 1. Thanks to Wintermute for this suggestion.
Is there a way to delete the whole line if it contains specific word using sed? i.e.
I have the following:
aaa bbb ccc
qqq fff yyy
ooo rrr ttt
kkk ccc www
I want to delete lines that contain 'ccc' and leave other lines intact. In this example the output would be:
qqq fff yyy
ooo rrr ttt
All this using sed. Any hints?
sed -n '/ccc/!p'
or
sed '/ccc/d'
I have some strings like below:
ffffffffcfdeee^dddcdeffffffffdddcecffffc^cbcb^cb`cdaba`eeeeeefeba[NNZZcccYccaccBBBBBBBBBBBBBBBBBBBBBB
eedeedffcc^bb^bccccbadddba^cc^e`eeedddda`deca_^^\```a```^b^`I^aa^bb^`_b\a^b```Y_\`b^`aba`cM[SS\ZY^BBB
Each string may (or may not) end with a stretch of trailing B of varied length.
I'm just wondering if we can simply use Bash code to remove the B stretch?
You could try something like
sed 's/\(.\)B*$/\1/' file
Input
aaa BBBBB
aaa BBBBB cccc
aaa bbb ccc BBBBBBB
Output
aaa
aaa BBBBB cccc
aaa bbb ccc
just with bash
shopt -s extglob
str="a.zxn;lqwyerpyqgha;lsdnBBBBB"
str=${str%%+(B)}
echo $str # ==> a.zxn;lqwyerpyqgha;lsdn
This might work for you:
sed 's/B*$//' file