Is there a way to delete the whole line if it contains specific word using sed? i.e.
I have the following:
aaa bbb ccc
qqq fff yyy
ooo rrr ttt
kkk ccc www
I want to delete lines that contain 'ccc' and leave other lines intact. In this example the output would be:
qqq fff yyy
ooo rrr ttt
All this using sed. Any hints?
sed -n '/ccc/!p'
or
sed '/ccc/d'
Related
Is it possible to remove multiple spaces from a text file and save the changes in the same file using awk or grep?
Input example:
aaa bbb ccc
ddd yyyy
Output I want:
aaa bbb ccc
ddd yyyy
Simply reset value of $1 to again $1 which will allow OFS to come into picture and will add proper spaces into lines.
awk '{$1=$1} 1' Input_file
EDIT: Since OP mentioned that what if we want to keep only starting spaces then try following.
awk '
match($0,/^ +/){
spaces=substr($0,RSTART,RLENGTH)
}
{
$1=$1
$1=spaces $1
spaces=""
}
1
' Input_file
Using sed
sed -i -E 's#[[:space:]]+# #g' < input file
For removing spaces at the start
sed -i -E 's#[[:space:]]+# #g; s#^ ##g' < input file
Demo:
$cat test.txt
aaa bbb ccc
ddd yyyy
Output I want:
aaa bbb ccc
ddd yyyy
$sed -i -E 's#[[:space:]]+# #g' test.txt
$cat test.txt
aaa bbb ccc
ddd yyyy
Output I want:
aaa bbb ccc
ddd yyyy
$
Row Actual Expected
1 AAA BBB
2 CCC CCC
3 DDD EEE
4 FFF GGG
5 HHH HHH
I want to compare actual and expected and store the difference in a file. Like
Row Actual Expected
1 AAA BBB
3 DDD EEE
4 FFF GGG
I have used awk -F, '{if ($2!=$3) {print $1,$2,$3}}' Sample.csv It will only compare Int values not String value
You can use AWK to do this
awk '{if($2!=$3) print $0}' oldfile > newfile
where
$2 and $3 are second and third columns
!= means second and third columns does not match
$0 means whole line
> newfile redirects to new file
I prefer an awk solution (can handle more fields and easier to understand), but you could use
sed -r '/\t([^ ]*)\t\1$/d' Sample.csv
Assuming the file uses tab or some other delimiter to separate the columns, then tsv-filter from eBay's TSV Utilities supports this type of field comparison directly. For the file above:
$ tsv-filter --header --ff-str-ne 2:3 file.tsv
Row Actual Expected
1 AAA BBB
3 DDD EEE
4 FFF GGG
The --ff-str-ne option compares two fields in a row for non-equal strings.
Disclaimer: I'm the author.
I want to merge specific line
Input :
AAA
BBB
CCC
DDD
EEE
AAA
BBB
DDD
CCC
EEE
Output Should be
AAA
BBB
CCC DDD
EEE
AAA
BBB
DDD
CCC EEE
I want to search CCC and merge next line with it.
I have tried with awk command but didn't get success
Use awk patterns, if the line matches /CCC/ then print the line with a space at the end and go on to the next line. Otherwise (1), print the line.
awk '/CCC/ { printf("%s ", $0); next } 1' file
Using sed:
sed '/CCC/ { N; s/\n/ / }' file
Using awk:
awk '{ ORS=(/CCC/ ? FS : RS) }1' file
1 aaa bbb aaa
2 aaa ccccccccc aaa
3 aaa xx aaa
How to replace the second aaa to yyy for each line
1 aaa bbb yyy
2 aaa ccccccccc yyy
3 aaa xx yyy
Issuing the following command will solve your problem.
:%s/\(aaa.\{-}\)aaa/\1yyy/g
Another way would be with \zs and \ze, which mark the beginning and end of a match in a pattern. So you could do:
:%s/aaa.*\zsaaa\ze/yyy
In other words, find "aaa" followed by anything and then another "aaa", and replace that with "yyy".
If you have three "aaa"s on a line, this won't work, though, and you should use \{-} instead of *. (See :h non-greedy)
I have some strings like below:
ffffffffcfdeee^dddcdeffffffffdddcecffffc^cbcb^cb`cdaba`eeeeeefeba[NNZZcccYccaccBBBBBBBBBBBBBBBBBBBBBB
eedeedffcc^bb^bccccbadddba^cc^e`eeedddda`deca_^^\```a```^b^`I^aa^bb^`_b\a^b```Y_\`b^`aba`cM[SS\ZY^BBB
Each string may (or may not) end with a stretch of trailing B of varied length.
I'm just wondering if we can simply use Bash code to remove the B stretch?
You could try something like
sed 's/\(.\)B*$/\1/' file
Input
aaa BBBBB
aaa BBBBB cccc
aaa bbb ccc BBBBBBB
Output
aaa
aaa BBBBB cccc
aaa bbb ccc
just with bash
shopt -s extglob
str="a.zxn;lqwyerpyqgha;lsdnBBBBB"
str=${str%%+(B)}
echo $str # ==> a.zxn;lqwyerpyqgha;lsdn
This might work for you:
sed 's/B*$//' file