I'm newbie on linux issues and before asking here I googled it however I couldnt find a clue about grep --exclude.So I wonder what does the line below ?? Thanks in advance
grep --exclude=\*.svn\* -r REVISION 1.0.0.8/*1.0.0.8.config > 1.0.0.8-REVISION.txt
SOLVED BY MYSELF
search REVISION on "1.0.0.8/*1.0.0.8.config" file exluding .svn file and send output to 1.0.0.8-Revision.txt
To grep through a directory while excluding various file types (in your example anything prefixed with .svn ) you probably want to do the following:
grep -r "SOMETHING" --exclude="*.svn*" /path/to/directory > 1.0.0.8-REVISION.txt 2>&1
This will grep through all files within a directory recursively, then post the matches to a file called 1.0.0.8-REVISION.txt which is located relative to where you are currently searching.
If you provide more information abut exactly what you're trying to grep/find I can update my answer with something that will work exactly for your case.
you can find grep on man pages here.
what exclude does:
--exclude=PATTERN:
Recurse in directories skip file matching PATTERN.
your command will search, recursively, in all directories, skipping file pattern "*.svn*" and searching for file pattern "1.0.0.8/*1.0.0.8.config > 1.0.0.8-REVISION.txt"
Related
I have already followed this query # (How to replace a string in multiple files in linux command line).
My question is rather an extension of the same.
I want to check only specific file extensions in the subfolders also but not every file extension.
What I have already tried:
grep -rli 'old-word' * | xargs -i# sed -i 's/old-word/new-word/g' #
My problem: It is changing in every other file format as well. I want to search and replace only in one file extension.
Please add another answer where I can change the entire line of a file as well not just one word.
Thanks in advance.
Simplest solution is to use complex grep command:
grep -rli --include="*.html" --include=".json" 'old-word' *
The disadvantage of this solution. Is that you do not have clear control which files are scanned.
Better suggesting to tune a find command to locate your desired files.
Using RegExp filtering option -regex to filter file names.
So you verify the correct files are scanned.
Than feed the find command result to grep scanning list.
Example:
Assuming you are looking for file extensions txt pdf html .
Assuming your search path begins in /home/user/data
find /home/user/data -regex ".*\.\(html\|txt\|pdf\)$"
Once you have located your files. It is possible to grep match each file from the the above find command:
grep -rli 'old-word' $( find /home/user/data -regex ".*\.\(html\|txt\|pdf\)$" )
If I have two strings, for example "class" and "btn", what is the linux command that would allow me to search for these two strings in the entire directory.
To be more specific, lets say I have directory that contains few folders with bunch of .php files. My goal is to be able to search throughout those .php files so that it prints out only files that contain "class" and "btn" in one line. Hopefully this clarifies things better.
Thanks,
I normally use the following to search for strings inside my source codes. It searches for string and shows the exact line number where that text appears. Very helpful for searching string in source code files. You can always pipes the output to another grep and filter outputs.
grep -rn "text_to_search" directory_name/
example:
$ grep -rn "angular" menuapp
$ grep -rn "angular" menuapp | grep some_other_string
output would be:
menuapp/public/javascripts/angular.min.js:251://# sourceMappingURL=angular.min.js.map
menuapp/public/javascripts/app.js:1:var app = angular.module("menuApp", []);
grep -r /path/to/directory 'class|btn'
grep is used to search a string in a file. With the -r flag, it searches recursively all files in a directory.
Or, alternatively using the find command to "identify" the files to be searched instead of using grep in recursive mode:
find /path/to/your/directory -type f -exec grep "text_to_search" {} \+;
How to rename files without changing extension in Linux \
102221.pdf to 102221_name.pdf
This is what you want I think:
for x in *; do mv "$x" "${x%.*}_name.${x##*.}"; done
${x%.*} will give the name of the file without extention
${x##*.} will extract the extentions
ls * | sed -r 'p;s/\.pdf$/_name\.pdf/g' | xargs -n2 mv
list all the files with ls and pipe the output to sed. sed replaces .pdf with _name.pdf and outputs both the original file name and the new file name to xargs with will call mv with the 2 parameters.
you can also use the rename command which is simpler
rename 's/\.pdf$/_name\.pdf/g' ./*
The regex pattern remains the same though
well i am not so good in linux.. but still found a working answer for you.. hope it will solve ur purpose..
check the given link.. you might need a light weighted tool called as jhead mainly its to get the header information about the file link created date and time and other.. you can find the information which suits you..
Answer
https://superuser.com/questions/90057/linux-rename-file-but-keep-extension
jhead
http://www.sentex.net/~mwandel/jhead/
This is not exactly the easiest one to explain in a title.
I have a file inputfile.txt that contains parts of filenames:
file1.abc
filed.def
fileq.lmn
This file is an input file that I need to use to find the full filenames of an actual directory. The ends of the filenames are different from case to case, but part of them is always the same.
I figured that I could grep text from the input file to the ls command in said directory (or the ls command to a simple text file), and then use awk to output my full desired result, but I'm having some trouble doing that.
file1.abc is read from the input file inputfile.txt
It's checked against the directory contents.
If the file exists, specific directories based on the filename are created.
(I'm also in a Busybox environment.. I don't have a lot at my disposal)
Something like this...
cat lscommandoutput.txt \
| awk -F: '{print("mkdir" system("grep $0"); inputfile.txt}' \
| /bin/sh
Thank you.
Edit: My apologies for not being clear on this.
The output should be the full filename of each line found in lscommandoutput.txt using the inputfile.txt to grep those specific lines.
If inputfile.txt contains:
file1.abc
filed.def
fileq.lmn
and lscommandoutput.txt contains:
file0.oba.ca-1.fil
file1.abc.de-1.fil
filed.def.com-2.fil
fileh.jkl.open-1.fil
fileq.lmn.he-2.fil
The extra lines that aren't contained in the inputfile.txt are ignored. The ones that are in the inputfile.txt have a directory created for them with the name that got grepped from lscommandoutput.txt.
/dir/dir2/file1.abc.de-1.fil/ <-- directory in which files can be placed in
/dir/dir2/filed.def.com-2.fil/
/dir/dir2/fileq.lmn.he-2.fil/
Hopefully that is a little bit clearer.
First, you win a useless use of cat award
Secondly, you've explained this really badly. If you can't describe the problem clearly in plain English it's not surprising you are having trouble turning it into a script or set of commands.
grep -f is a good way to get the directory names, but I don't understand what you want to do with them afterwards.
My problem now is using the outputted file with the one file I want to put the folders
Wut? What does "the one file I want to put the folders" mean? Where does the file come from? Is it the file named in inputlist.txt? Does it go in the directory that it matched?
If you just want to create the directories you can do:
fgrep -f ./inputfile.txt ./lscommandoutput.txt | xargs mkdir
N.B. you probably want fgrep so that the input strings aren't treated as regular expressions and regex metacharacters such as . are ignored.
Hello
I'm looking some script or program that use keywords or pattern search in files ex. php, html, etc and show where is this file
I use command cat /home/* | grep "keyword"
but i have too many folders and files and this command causes big uptime :/
I need this script to find fake websites (paypal, ebay, etc)
find /home -exec grep -s "keyword" {} \; -print
You don't really say what OS (and shell) you are using. You might want to retag your question to help us out.
Because you mention cat | ... , I am assuming you are using a Unix/Linux variant, so here are some pointers for looking at files. (bmargulies solution is good too).
I'm looking some script or program that use keywords or pattern search in files
grep is the basic program for searching files for text strings. Its usage is
grep [-options] 'search target' file1 file2 .... filen
(Note that 'search target' contains a space, if you don't surround spaces in your searchTarget with double or single quotes, you will have a minor error to debug.)
(Also note that 'search target' can use a wide range of wild-card characters, like .,?,+,,., and many more, that is beyond the scope of your question). ... anyway ...
As I guess you have discovered, you can only cram so many files at a time into the comand-line, even when using wild-card filename expansion. Unix/linux almost always have a utiltiyt that can help with that,
startDir=/home
find ${startDir} -print | xargs grep -l 'Search Target'
This, as one person will be happy to remind you, will require further enhancements if your filenames contain whitespace characters or newlines.
The options available for grep can vary wildly based on which OS you are using. If you're lucky, you type the following to get the man page for your local grep.
man grep
If you don't have your page buffer setup for a large size, you might need to do
man grep | page
so you can see the top of the 'document'. Press any key to advance to the next page and when you are at the end of the document, the last key press returns you to the command prompt.
Some options that most greps have that might be useful to you are
-i (ignore case)
-l (list filenames only (where txt is found)
There is also fgrep, which is usually interpretted to mean 'file' grep
becuase you can give it a file of search targets to scan for, and is used like
fgrep [-other_options] -f srchTargetsFile file1 file2 ... filen
I need this script to find fake websites (paypal, ebay, etc)
Final solution
you can make a srchFile like
paypal.fake.com
ebay.fake.com
etc.fake.com
and then combined with above, run the following
startDir=/home
find ${startDir} -print | xargs fgrep -il -f srchFile
Some greps require that the -fsrchFile be run together.
Now you are finding all files starting /home, searching with fgrep for paypay, ebay, etc in all files. The -l says it will ONLY print the filename where a match is found. You can remove the -l and then you will see the output of what is found, prepended with the filename.
IHTH.