I want to run a program every 5th mins between 9:15am and 3:30pm.
5 * * * MON-FRI
seems to run the program every 5 mins (as expected) but its critical to run it only after 9:15
You must create several records in cron to accomplish what you want:
15,20,25,30,35,40,45,50,55 9 * * MON-FRI /path/to/program
*/5 10-14 * * MON-FRI /path/to/program
0,5,10,15,20,25,30 15 * * MON-FRI /path/to/program
The other way is to incorporate the logic in you program
Talking about programming way this is sample shell script which will check if you are between Monday and Friday and between 9:15 and 15:30
date +"$u %H %M"|awk '{t=$2*60+$3; if ($1>=1 && $1<6 && t>=555 && t<=930) print 1; else print 0;}'
This command will print 1 if you are in to the interval of run the things and 0 if you are outside. And then you need to run the script every 5 minutes:
*/5 * * * * /path/to/program
I need to run cron job every hour at first minute
I have already tried the following :
1> 0 * * * * ? *
2> 0 */1 * * * ? *
Unfortunately I did not get correct results
I need the job to start at first minute for every hour as the following :
0:01
1:01
2:01
3:01
4:01
.
.
23:01
end
Every hour at minutes 1
0 1 0/1 ? * * *
ref Cron Expression Generator
I need to set a cronjob to run a bash script every 5 minutes, starting at 9:30am until 4:00pm.
I have the following but, it's not quite right...
Cronjob:
*/5 9-16 * * * /path/to/directory/job.sh > /path/to/log/file/job.log 2>&1
What you have there is a line that will run the command every five minutes between 09:00 and 16:55 (all ranges here are inclusive).
What you're trying to achieve can be done relatively simply with three separate crontab lines:
30-59/5 9 * * * /path/to/directory/job.sh > /path/to/log/file/job.log 2>&1
*/5 10-15 * * * /path/to/directory/job.sh > /path/to/log/file/job.log 2>&1
0 16 * * * /path/to/directory/job.sh > /path/to/log/file/job.log 2>&1
The first handles the case between 09:30 and 09:55, the second every five minutes between 10:00 and 15:55, and the final one the single job at 16:00.
Cron doesn't have a syntax for expressing that directly, so you'll need 3 separate lines: one for 9:30-9:55, one for 10:00-15:55, and one for 16:00.
I think this is correct:
30-55/5 9 * * * <command>
*/5 10-15 * * * <command>
0 16 * * * <command>
im writing more bash backup scripts but have a little problem.
on the 1st of each month i run server1.sh to do a full backup.
every other day i run server2.sh which looks at server1 backup and performs an incremental backup based on this full backup.
thats all great.
my first problem is how can i tell server2.sh to NOT run on the 1st of each month as server1.sh will be running this day.
to run these scripts im using crontab.
example cron
0 1 * * server1.sh
2 * * * server2.sh
so far i have this script using an if but its not fully working yet
#!/bin/bash
LinkDest=/home/backup/website/full
r_date=$(date "+%d-%m-%y")
f_date=$(date +%F)
c_date=$(date +%d)
servers=("123.123.78.90" "123.123.78.91" "123.123.78.92" "123.123.78.93" "123.123.78.94" "123.123.78.95" "cluster")
if [ $c_date -eq 01 ]
then
echo "Backup Skipped 1st of Month"
exit 0
else
for j in "${servers[#]}"
do
echo "server:/data/backup/$j /home/backup/website/$j"
rsync -avz --link-dest=$LinkDest root#123.123.78.90:/data/backup/"$j" /home/backup/website/$f_date --bwlimit=10000 --log-file=/logs/rsync_"$j"_"$r_date".log
fi
done
This is the format of cron expression:
# Minute Hour Day of Month Month Day of Week Command
# (0-59) (0-23) (1-31) (1-12 or Jan-Dec) (0-6 or Sun-Sat)
0 2 12 * * /usr/bin/find
Given your question, you can use following cron expression:
All days except first day of the month for run server2.sh: 0 0 2-31 * *
Only first day of month for run server1.sh: 0 0 1 * *
You have to define minute and hour at which run your script. So replace first two 0 0 with your own values. For example:
20 3 2-31 * *
20 3 1 * *
To run your scripts at 3.20 AM.
Hope this help!
i want to execute a script twice daily at 00:00 and 13:30 so i write :
0,30 0,13 * * *
it seems wrong for me, because like this, the script will fire at 00:00 , 00:30 , 13:00 and 13:30. Any idea ?
Try this-: 00 01,13 * * *
it will run at 1 A.M and 1 P.M
You can't do what you want in one entry, since the two minute definitions will apply for both hour definitions (as you've identified).
The solution is (unfortunately) use two cron entries. One for 00:00 and one for 13:30.
An alternative is perhaps to execute one script at 00:00. That script would execute your original script, then wait 13.5 hours and then execute that script again. It would be easy to do via a simple sleep command, but I think it's unintuitive, and I'm not sure how cron manages such long running processes (what happens if you edit the crontab - does it kill a spawned job etc.)
You CAN NOT do that with cron on a single line.
You have to create 2 separate lines like so:
# Will run "YourCommand" at 00:00 every day of every months
#Min Hours D of the M Month D of the Week Command
0 0 * * * YourCommand
# Will run "YourCommand" at 13:30 every day of every months
30 13 * * * YourCommand
Or, as a single line, you can run a command every x hours, like so:
# Will run "YourCommand" every 12 hours
0 */12 * * * YourCommand
or
# Will run "YourCommand" at 1am and 1pm every day
0 1,13 * * * YourCommand arg1 arg2
Try this out: 0 6,18 * * *
it will run at minute 0 past hour 6 and 18
Or you can try it out on cronguru
try ...
00,30 00,13 * * * [ `date +%H%M` == 1330 ] || [ `date +%H%M` == 0000 ] && logger "its time"
Try this out:
0 1,13 * * *
What the above code means:
Cron will run at minute 0 past hour 1 and 13
Sharing a screenshot from crontab.guru
30 0,13 * * * somecommand.sh
This is just purely an example, but you will see that this is a cron entry that will run at 0:30AM and then 1:30PM (13 is 1 in military time). Just comma separate the hours, or comma separate whatever section of the cron.
try this,
0 10 9/12 ? * *
At second :00, at minute :10, every 12 hours starting at 09am, of every day
Try this, Only if you have the same minutes for each schedule. This will run your job twice a day at 1:00 & 13:00
0 1,13 * * *
You can try quickly more variations here: https://crontab.guru/