how to scale the element by keeping the fixed position in svg - svg

i want to scale the below element in fixed position.
<path id="container_svg_rectsymbol1" fill="red" stroke-width="1" stroke="Gray" d="M 73.1111111111111 -71.75 L 83.1111111111111 -71.75 L 83.1111111111111 -61.75 L 73.1111111111111 -61.75 L 73.1111111111111 -71.75" transform="scale(1)"/>
when am start scaling it moves from one location to another location. i don't want to move the object i just want to enlarge the size of object.
i have referred following link.
http://commons.oreilly.com/wiki/index.php/SVG_Essentials/Transforming_the_Coordinate_System
how to do fixed scaling ?
i want to animate the element i.e enlarge the size in fixed position. i have implemented in following way. but it sill moves the element from origin. please refer below code.
var box = element.getBBox();
var scaleVal=null, x=null, y=null;
$(element).animate(
{
scale: 1,
centerX:box.x+(4*transX),
centerY:box.y+(4*transY)
},
{
duration: 4000,
step: function(now,fx) {
if (fx.prop == "scale") {
scaleVal = now;
} else if (fx.prop == "centerX") {
x = now;
} else if (fx.prop == "centerY") {
y = now;
}
if(!sf.util.isNullOrUndefined(scaleVal) && !sf.util.isNullOrUndefined(x) && !sf.util.isNullOrUndefined(y)) {
$(element).attr("transform", "translate("+(-x*(scaleVal-1))+","+(-y*(scaleVal-1))+")scale(" + scaleVal + ")");
}
}
)
referred the below link for scaling in centered point.
http://commons.oreilly.com/wiki/index.php/SVG_Essentials/Transforming_the_Coordinate_System
but it still starts from origin and enlarges the element.
Thanks,
Siva

Scaling is centred on the origin (0, 0), so if your shape is not centred on (0, 0) it will appear to move. To fix this first translate your shape so it is centred on the origin, then scale it, then translate it back:
transform="translate(78.11 -66.75) scale(2) translate(-78.11 66.75)"
Note that the transformations are done in reverse order.
You could simplify things by creating a shape centred on the origin to start with and then scaling and transforming it.
<path id="container_svg_rectsymbol1" fill="red" stroke="Gray" d="M -5 -5 v10 h10 v-10 h-10" transform="translate(78.11 -66.75) scale(3)"/>
You could also convert the transform into matrix, which would be more efficient:
<path opacity="0.5" fill="red" stroke-width="1" stroke="Gray" d="M -5 -5 v10 h10 v-10 h-10" transform="matrix(3 0 0 3 78.11 -66.75)"/>
[EDIT] To use jQuery animate, this should work (scaling from 0 to 1 over 4 seconds):
var box = element.getBBox();
var cx = box.x + box.width/2;
var cy = box.y + box.height/2;
$(element).animate(
{ scale: 1 },
{ duration: 4000,
step: function(now, fx) {
scaleVal = now;
$(element).attr("transform", "translate(" + cx + " " + cy + ") scale(" + scaleVal + ") translate(" + (-cx) + " " + (-cy) + ")");
}
}
);

OK, now that I have reread your question, it seems that you want to use transform="scale()" and encountering the mysterious "move" also, which is confusing for most beginners learning SVG (me included).
Scaling is measured from the origin(0,0), hence if the object is at location (50,-100), when applying scale(2), the object location is doubled to (50*2, -100*2) => (100, -200). Hence you need to correct this by translate(-50,100).
Using matrix() would be the next area to explore as it is quite intuitive. The above example would require matrix(2 0 0 2 -50 100) to scale and move it back to original. Also with matrix() code, you can perform flip() and mirror() easily with the 2nd and 3rd field. Again you have to translate the length and/or width of object for these two transformation.

Related

How to know the m or M point of path from all of points in svg?(use raphael.js)

I have an svg picture like this, with M and m in the path. I use raphael.js to calculate. I can get all the points by calling Raphael.getTotalLength(path), but how can I know from which point is the path behind m.
I want to know all the absolute coordinate points of the inner border of the svg, so that I can get a data format similar to the following [[points of the outer border], [points of the inner border]].
This is how I achieved it. I can get all the points, but I can’t distinguish which are the points of the inner frame and which are the points of the outer frame.
import Raphael from 'raphael';
function getPoints(path) {
let points = [];
for (let i = 0; i < Raphael.getTotalLength(path); i += step_point) {
const point = Raphael.getPointAtLength(path, i);
points.push(point);
}
}
This is the svg content:
<svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 120 120">
<path
d="M72.8525 8.0439c-.405 0-.816.022-1.222.064-4.973.523-8.939 4.112-10.048 8.833-.73-.028-1.453-.043-2.162-.043-5.453 0-10.307.814-14.464 2.423-1.988-3.703-5.849-6.071-10.173-6.071-.973 0-1.949.124-2.899.37-2.994.773-5.508 2.667-7.078 5.331-1.571 2.664-2.01 5.781-1.236 8.775.772 2.986 2.693 5.506 5.301 7.052-1.056 2.419-1.535 4.533-1.814 6.02-.623 3.314-2.519 13.398 5.355 20.728 3.209 2.988 6.672 4.84 10.937 5.8-3.558 4.888-7.226 11.138-8.02 16.945-.349 2.543-.027 4.749.956 6.576l-.149.355c-.034.081-.062.165-.085.25-.315 1.166-.025 2.398.778 3.295.672.754 1.639 1.187 2.649 1.187.044 0 .088-.001.131-.002.27.406.626.758 1.053 1.029.518.33 1.109.519 1.719.55l-1.044 4.167c-.571 2.283.813 4.636 3.086 5.245l10.106 2.708c.372.1.753.15 1.132.15 1.299 0 2.521-.582 3.351-1.595.825-1.008 1.151-2.32.894-3.6-.013-.064-.007-.13.016-.189l1.1-2.829 3.729 6.22c.78 1.3 2.206 2.109 3.723 2.109.759 0 1.509-.202 2.168-.582l9.061-5.232c1.308-.756 2.119-2.108 2.167-3.619.03-.959-.249-1.873-.779-2.627.6-.052 1.175-.255 1.679-.595.42-.283.766-.644 1.024-1.058h.035c1.047 0 2.037-.459 2.713-1.259.778-.92 1.035-2.16.687-3.318-.025-.084-.056-.166-.092-.246l-.158-.35c.933-1.854 1.194-4.068.777-6.6-1.181-7.17-6.763-14.845-10.84-19.646 1.556-.529 3.061-1.122 4.547-1.793 6.708-3.027 9.062-8.913 9.395-11.913.346-3.113-.969-9.08-2.01-12.015-1.056-2.977-3.244-8.332-6.599-12.674 1.647-2.29 2.406-5.105 2.106-7.957-.621-5.911-5.566-10.369-11.503-10.369m0 2c4.84 0 8.997 3.657 9.514 8.578.312 2.97-.769 5.764-2.716 7.735 4.039 4.59 6.48 11.006 7.313 13.355 1.049 2.957 2.192 8.566 1.908 11.126-.285 2.56-2.435 7.696-8.23 10.311-2.229 1.006-4.658 1.897-7.363 2.639.216.171.429.348.617.556 3.231 3.599 10.589 12.513 11.888 20.392.453 2.753-.065 4.727-1.052 6.153l.583 1.294c.149.498.04 1.049-.299 1.451-.296.349-.728.55-1.186.55-.367 0-.722-.13-1.002-.367-.127-.107-.234-.231-.32-.372l-.182-.406c-.053.03-.108.056-.161.085l.17 1.142c.01.521-.245 1.023-.682 1.318-.258.174-.558.266-.867.266-.518 0-.999-.256-1.288-.685-.093-.138-.163-.287-.208-.447l-.078-.525s0 .001-.001.001c-.092.021-.184.022-.277.035-.125.259-.314.488-.566.645-.247.154-.531.235-.82.235-.22 0-.427-.055-.621-.14l1.058 2.404c.18.409.472.758.845 1.006 1.444.961 1.377 3.104-.126 3.973l-9.061 5.23c-.368.213-.77.315-1.168.315-.795 0-1.57-.407-2.008-1.137l-4.403-7.347c-.752-.015-1.524-.056-2.306-.11l-1.698 4.368c-.163.417-.202.87-.114 1.309.3 1.49-.864 2.801-2.284 2.801-.201 0-.407-.026-.614-.082l-10.106-2.708c-1.234-.33-1.974-1.589-1.664-2.827l1.907-7.612c-.062-.027-.127-.044-.185-.077-.256-.151-.451-.374-.584-.631-.092-.01-.185-.009-.278-.027 0 0-.001 0-.001-.001l-.065.532c-.04.159-.105.309-.193.448-.287.45-.777.72-1.312.72-.294 0-.582-.084-.832-.243-.444-.283-.713-.777-.717-1.298l.139-1.147c-.054-.027-.11-.052-.163-.081l-.174.415c-.082.142-.184.268-.307.377-.285.254-.652.395-1.034.395-.441 0-.864-.19-1.158-.519-.35-.392-.474-.939-.339-1.441l.548-1.311c-1.026-1.397-1.598-3.356-1.219-6.121.917-6.699 6.151-14.247 9.637-18.644-4.885-.547-9.142-2.083-13.173-5.836-6.746-6.28-5.521-14.805-4.752-18.894.384-2.041 1.039-4.558 2.526-7.33-2.881-1.035-5.218-3.424-6.041-6.612-1.324-5.122 1.756-10.347 6.877-11.67.802-.207 1.607-.306 2.399-.306 4.097 0 7.844 2.654 9.119 6.698 5.236-2.473 11.057-3.05 15.518-3.05 1.264 0 2.419.047 3.42.109 0 0 .169.006.449.024.281-4.587 3.828-8.437 8.55-8.934.34-.035.678-.053 1.013-.053"
fill="#F00" stroke="#000" />
</svg>
I really look forward to your answers, thank you!
As I mentioned elsewhere. You can split on M. If for some reason this doesn't make sense (as you mentioned multiple 'm's) as you say "behind m", then you need to amend your question to be more precise about where the split would be, if this is part of a more generic issue.
So we can split the string on "m"
var match = new RegExp("(^[^m]*)(.*)", "").exec(path);
And get the last point of the first path part...
var point = Raphael.getPointAtLength(match[1], p.getTotalLength(match[1]));
Then add the final point to the first path...
var p2 = r.path("M" + point.x + "," + point.y + match[2]).attr('stroke','blue')
And I've amended getPoints()...
function getPoints(path) {
let points = [];
let step_point = 10;
for (let i = 0; i < path.getTotalLength(); i += step_point) {
const point = path.getPointAtLength(i);
points.push(point);
}
return points;
}
And get the sets of points...
console.log(getPoints(p1));
console.log(getPoints(p2));
jsfiddle showing different colours for outer/inner and it dumps in the console the two sets of points.

How can I get a rect with just two of the corners rounded? [duplicate]

I have the following SVG:
<svg>
<g>
<path id="k9ffd8001" d="M64.5 45.5 82.5 45.5 82.5 64.5 64.5 64.5 z" stroke="#808600" stroke-width="0" transform="rotate(0 0 0)" stroke-linecap="square" stroke-linejoin="round" fill-opacity="1" stroke-opacity="1" fill="#a0a700"></path>
<path id="kb8000001" d="M64.5 45.5 82.5 45.5 82.5 64.5 64.5 64.5 z" stroke="#808600" stroke-width="0" transform="rotate(0 0 0)" stroke-linecap="square" stroke-linejoin="round" fill-opacity="1" stroke-opacity="1" fill="url(#k9ffb0001)"></path>
</g>
</svg>
I want to get a CSS-like border-top-right-radius and border-top-bottom-radius effect.
How can I achieve that rounded corner effect?
Here is how you can create a rounded rectangle with SVG Path:
<path d="M100,100 h200 a20,20 0 0 1 20,20 v200 a20,20 0 0 1 -20,20 h-200 a20,20 0 0 1 -20,-20 v-200 a20,20 0 0 1 20,-20 z" />
Explanation
m100,100: move to point(100,100)
h200: draw a 200px horizontal line from where we are
a20,20 0 0 1 20,20: draw an arc with 20px X radius, 20px Y radius, clockwise, to a point with 20px difference in X and Y axis
v200: draw a 200px vertical line from where we are
a20,20 0 0 1 -20,20: draw an arc with 20px X and Y radius, clockwise, to a point with -20px difference in X and 20px difference in Y axis
h-200: draw a -200px horizontal line from where we are
a20,20 0 0 1 -20,-20: draw an arc with 20px X and Y radius, clockwise, to a point with -20px difference in X and -20px difference in Y axis
v-200: draw a -200px vertical line from where we are
a20,20 0 0 1 20,-20: draw an arc with 20px X and Y radius, clockwise, to a point with 20px difference in X and -20px difference in Y axis
z: close the path
<svg width="440" height="440">
<path d="M100,100 h200 a20,20 0 0 1 20,20 v200 a20,20 0 0 1 -20,20 h-200 a20,20 0 0 1 -20,-20 v-200 a20,20 0 0 1 20,-20 z" fill="none" stroke="black" stroke-width="3" />
</svg>
Not sure why nobody posted an actual SVG answer. Here is an SVG rectangle with rounded corners (radius 3) on the top:
<path d="M0,0 L0,27 A3,3 0 0,0 3,30 L7,30 A3,3 0 0,0 10,27 L10,0 Z" />
This is a Move To (M), Line To (L), Arc To (A), Line To (L), Arc To (A), Line To (L), Close Path (Z).
The comma-delimited numbers are absolute coordinates. The arcs are defined with additional parameters specifying the radius and type of arc. This could also be accomplished with relative coordinates (use lower-case letters for L and A).
The complete reference for those commands is on the W3C SVG Paths page, and additional reference material on SVG paths can be found in this article.
As referenced in my answer to Applying rounded corners to paths/polygons, I have written a routine in javascript for generically rounding corners of SVG paths, with examples, here: http://plnkr.co/edit/kGnGGyoOCKil02k04snu.
It will work independently from any stroke effects you may have. To use, include the rounding.js file from the Plnkr and call the function like so:
roundPathCorners(pathString, radius, useFractionalRadius)
The result will be the rounded path.
The results look like this:
You have explicitly set your stroke-linejoin to round but your stroke-width to 0, so of course you're not going to see rounded corners if you have no stroke to round.
Here's a modified example with rounded corners made through strokes:
http://jsfiddle.net/8uxqK/1/
<path d="M64.5 45.5 82.5 45.5 82.5 64.5 64.5 64.5 z"
stroke-width="5"
stroke-linejoin="round"
stroke="#808600"
fill="#a0a700" />
Otherwise—if you need an actual rounded shape fill and not just a rounded fatty stroke—you must do what #Jlange says and make an actual rounded shape.
I'd also consider using a plain old <rect> which provides the rx and ry attributes
MDN SVG docs <- note the second drawn rect element
I've happened upon this problem today myself and managed to solve it by writing a small JavaScript function.
From what I can tell, there is no easy way to give a path element in an SVG rounded corners except if you only need the borders to be rounded, in which case the (CSS) attributes stroke, stroke-width and most importantly stroke-linejoin="round" are perfectly sufficient.
However, in my case I used a path object to create custom shapes with n corners that are filled out with a certain color and don't have visible borders, much like this:
I managed to write a quick function that takes an array of coordinates for an SVG path and returns the finished path string to put in the d attribute of the path html element. The resulting shape will then look something like this:
Here is the function:
/**
* Creates a coordinate path for the Path SVG element with rounded corners
* #param pathCoords - An array of coordinates in the form [{x: Number, y: Number}, ...]
*/
function createRoundedPathString(pathCoords) {
const path = [];
const curveRadius = 3;
// Reset indexes, so there are no gaps
pathCoords = pathCoords.slice();
for (let i = 0; i < pathCoords.length; i++) {
// 1. Get current coord and the next two (startpoint, cornerpoint, endpoint) to calculate rounded curve
const c2Index = ((i + 1) > pathCoords.length - 1) ? (i + 1) % pathCoords.length : i + 1;
const c3Index = ((i + 2) > pathCoords.length - 1) ? (i + 2) % pathCoords.length : i + 2;
const c1 = pathCoords[i];
const c2 = pathCoords[c2Index];
const c3 = pathCoords[c3Index];
// 2. For each 3 coords, enter two new path commands: Line to start of curve, bezier curve around corner.
// Calculate curvePoint c1 -> c2
const c1c2Distance = Math.sqrt(Math.pow(c1.x - c2.x, 2) + Math.pow(c1.y - c2.y, 2));
const c1c2DistanceRatio = (c1c2Distance - curveRadius) / c1c2Distance;
const c1c2CurvePoint = [
((1 - c1c2DistanceRatio) * c1.x + c1c2DistanceRatio * c2.x).toFixed(1),
((1 - c1c2DistanceRatio) * c1.y + c1c2DistanceRatio * c2.y).toFixed(1)
];
// Calculate curvePoint c2 -> c3
const c2c3Distance = Math.sqrt(Math.pow(c2.x - c3.x, 2) + Math.pow(c2.y - c3.y, 2));
const c2c3DistanceRatio = curveRadius / c2c3Distance;
const c2c3CurvePoint = [
((1 - c2c3DistanceRatio) * c2.x + c2c3DistanceRatio * c3.x).toFixed(1),
((1 - c2c3DistanceRatio) * c2.y + c2c3DistanceRatio * c3.y).toFixed(1)
];
// If at last coord of polygon, also save that as starting point
if (i === pathCoords.length - 1) {
path.unshift('M' + c2c3CurvePoint.join(','));
}
// Line to start of curve (L endcoord)
path.push('L' + c1c2CurvePoint.join(','));
// Bezier line around curve (Q controlcoord endcoord)
path.push('Q' + c2.x + ',' + c2.y + ',' + c2c3CurvePoint.join(','));
}
// Logically connect path to starting point again (shouldn't be necessary as path ends there anyway, but seems cleaner)
path.push('Z');
return path.join(' ');
}
You can determine the rounding strength by setting the curveRadius variable at the top. The default is 3 for a 100x100 (viewport) coordinate system, but depending on the size of your SVG, you may need to adjust this.
For my case I need to radius begin and end of path:
With stroke-linecap: round; I change it to what I want:
This question is the first result for Googling "svg rounded corners path". Phrogz suggestion to use stroke has some limitations (namely, that I cannot use stroke for other purposes, and that the dimensions have to be corrected for the stroke width).
Jlange suggestion to use a curve is better, but not very concrete. I ended up using quadratic Bézier curves for drawing rounded corners. Consider this picture of a corner marked with a blue dot and two red points on adjacent edges:
The two lines could be made with the L command. To turn this sharp corner into a rounded corner, start drawing a curve from the left red point (use M x,y to move to that point). Now a quadratic Bézier curve has just a single control point which you must set on the blue point. Set the end of the curve at the right red point. As the tangent at the two red points are in the direction of the previous lines, you will see a fluent transition, "rounded corners".
Now to continue the shape after the rounded corner, a straight line in a Bézier curve can be achieved by setting the control point between on the line between the two corners.
To help me with determining the path, I wrote this Python script that accepts edges and a radius. Vector math makes this actually very easy. The resulting image from the output:
#!/usr/bin/env python
# Given some vectors and a border-radius, output a SVG path with rounded
# corners.
#
# Copyright (C) Peter Wu <peter#lekensteyn.nl>
from math import sqrt
class Vector(object):
def __init__(self, x, y):
self.x = x
self.y = y
def sub(self, vec):
return Vector(self.x - vec.x, self.y - vec.y)
def add(self, vec):
return Vector(self.x + vec.x, self.y + vec.y)
def scale(self, n):
return Vector(self.x * n, self.y * n)
def length(self):
return sqrt(self.x**2 + self.y**2)
def normal(self):
length = self.length()
return Vector(self.x / length, self.y / length)
def __str__(self):
x = round(self.x, 2)
y = round(self.y, 2)
return '{},{}'.format(x, y)
# A line from vec_from to vec_to
def line(vec_from, vec_to):
half_vec = vec_from.add(vec_to.sub(vec_from).scale(.5))
return '{} {}'.format(half_vec, vec_to)
# Adds 'n' units to vec_from pointing in direction vec_to
def vecDir(vec_from, vec_to, n):
return vec_from.add(vec_to.sub(vec_from).normal().scale(n))
# Draws a line, but skips 'r' units from the begin and end
def lineR(vec_from, vec_to, r):
vec = vec_to.sub(vec_from).normal().scale(r)
return line(vec_from.add(vec), vec_to.sub(vec))
# An edge in vec_from, to vec_to with radius r
def edge(vec_from, vec_to, r):
v = vecDir(vec_from, vec_to, r)
return '{} {}'.format(vec_from, v)
# Hard-coded border-radius and vectors
r = 5
a = Vector( 0, 60)
b = Vector(100, 0)
c = Vector(100, 200)
d = Vector( 0, 200 - 60)
path = []
# Start below top-left edge
path.append('M {} Q'.format(a.add(Vector(0, r))))
# top-left edge...
path.append(edge(a, b, r))
path.append(lineR(a, b, r))
path.append(edge(b, c, r))
path.append(lineR(b, c, r))
path.append(edge(c, d, r))
path.append(lineR(c, d, r))
path.append(edge(d, a, r))
path.append(lineR(d, a, r))
# Show results that can be pushed into a <path d="..." />
for part in path:
print(part)
Here are some paths for tabs:
https://codepen.io/mochime/pen/VxxzMW
<!-- left tab -->
<div>
<svg width="60" height="60">
<path d="M10,10
a10 10 0 0 1 10 -10
h 50
v 47
h -50
a10 10 0 0 1 -10 -10
z"
fill="#ff3600"></path>
</svg>
</div>
<!-- right tab -->
<div>
<svg width="60" height="60">
<path d="M10 0
h 40
a10 10 0 0 1 10 10
v 27
a10 10 0 0 1 -10 10
h -40
z"
fill="#ff3600"></path>
</svg>
</div>
<!-- tab tab :) -->
<div>
<svg width="60" height="60">
<path d="M10,40
v -30
a10 10 0 0 1 10 -10
h 30
a10 10 0 0 1 10 10
v 30
z"
fill="#ff3600"></path>
</svg>
</div>
The other answers explained the mechanics. I especially liked hossein-maktoobian's answer.
The paths in the pen do the brunt of the work, the values can be modified to suite whatever desired dimensions.
This basically does the same as Mvins answer, but is a more compressed down and simplified version. It works by going back the distance of the radius of the lines adjacent to the corner and connecting both ends with a bezier curve whose control point is at the original corner point.
function createRoundedPath(coords, radius, close) {
let path = ""
const length = coords.length + (close ? 1 : -1)
for (let i = 0; i < length; i++) {
const a = coords[i % coords.length]
const b = coords[(i + 1) % coords.length]
const t = Math.min(radius / Math.hypot(b.x - a.x, b.y - a.y), 0.5)
if (i > 0) path += `Q${a.x},${a.y} ${a.x * (1 - t) + b.x * t},${a.y * (1 - t) + b.y * t}`
if (!close && i == 0) path += `M${a.x},${a.y}`
else if (i == 0) path += `M${a.x * (1 - t) + b.x * t},${a.y * (1 - t) + b.y * t}`
if (!close && i == length - 1) path += `L${b.x},${b.y}`
else if (i < length - 1) path += `L${a.x * t + b.x * (1 - t)},${a.y * t + b.y * (1 - t)}`
}
if (close) path += "Z"
return path
}
Here’s a piece of react code to generate rectangles with different corner radiuses:
const Rect = ({width, height, tl, tr, br, bl}) => {
const top = width - tl - tr;
const right = height - tr - br;
const bottom = width - br - bl;
const left = height - bl - tl;
const d = `
M${tl},0
h${top}
a${tr},${tr} 0 0 1 ${tr},${tr}
v${right}
a${br},${br} 0 0 1 -${br},${br}
h-${bottom}
a${bl},${bl} 0 0 1 -${bl},-${bl}
v-${left}
a${tl},${tl} 0 0 1 ${tl},-${tl}
z
`;
return (
<svg width={width} height={height}>
<path d={d} fill="black" />
</svg>
);
};
ReactDOM.render(
<Rect width={200} height={100} tl={20} tr={0} br={20} bl={60} />,
document.querySelector('#app'),
);
https://jsfiddle.net/v1Ljpxh7/
Just to simplify implementing answer of #hmak.me, here's a commented piece of React code to generate rounded rectangles.
const Rect = ({width, height, round, strokeWidth}) => {
// overhang over given width and height that we get due to stroke width
const s = strokeWidth / 2;
// how many pixels do we need to cut from vertical and horizontal parts
// due to rounded corners and stroke width
const over = 2 * round + strokeWidth;
// lengths of straight lines
const w = width - over;
const h = height - over;
// beware that extra spaces will not be minified
// they are added for clarity
const d = `
M${round + s},${s}
h${w}
a${round},${round} 0 0 1 ${round},${round}
v${h}
a${round},${round} 0 0 1 -${round},${round}
h-${w}
a${round},${round} 0 0 1 -${round},-${round}
v-${h}
a${round},${round} 0 0 1 ${round},-${round}
z
`;
return (
<svg width={width} height={height}>
<path d={d} fill="none" stroke="black" strokeWidth={strokeWidth} />
</svg>
);
};
ReactDOM.render(
<Rect width={64} height={32} strokeWidth={2} round={4} />,
document.querySelector('#app'),
);
Jsfiddle link.
I wrote this little typescript function so I can dynamically create the path for a complex rounded rectangle that function similar to a div with border-radius.
export function roundedRectPath(
x: number,
y: number,
width: number,
height: number,
bevel: [number, number, number, number] = [3, 3, 3, 3]
): string {
return "M" + x + "," + y
+ `m 0 ${bevel[0]}`
+ `q 0 -${bevel[0]} ${bevel[0]} -${bevel[0]}`
+ `l ${width - bevel[0] - bevel[1]} 0`
+ `q ${bevel[1]} 0 ${bevel[1]} ${bevel[1]}`
+ `l 0 ${height - bevel[1] - bevel[2]}`
+ `q 0 ${bevel[2]} -${bevel[2]} ${bevel[2]}`
+ `l -${width - bevel[2] - bevel[3]} 0`
+ `q -${bevel[3]} 0 -${bevel[3]} -${bevel[3]}`
+ `z`;
}
I found a solution but it is a bit hacky so it may not always work. I found that if you have an arc (A or a) with really small values it forces it to create a curve in one spot thus forming a rounded comer...
<svg viewBox="0 0 1 0.6" stroke="black" fill="grey" style="stroke-width:0.05px;">
<path d="M0.7 0.2 L0.1 0.1 A0.0001 0.0001 0 0 0 0.099 0.101 L0.5 0.5Z"></path>
</svg>
You are using a path element, why don't you just give the path a curve? See here for how to make curves using path elements: http://www.w3.org/TR/SVG/paths.html#PathDataCurveCommands

How to make a circle with SVG Path tag, using Arc attributes [duplicate]

Short question: using SVG path, we can draw 99.99% of a circle and it shows up, but when it is 99.99999999% of a circle, then the circle won't show up. How can it be fixed?
The following SVG path can draw 99.99% of a circle: (try it below and see if you see 4 arcs or only 2 arcs, but note that if it is IE, it is rendered in VML, not SVG, but have the similar issue)
var paper = Raphael(0, 0, 300, 800);
// Note that there are supposed to be 4 arcs drawn, but you may see only 1, 2, or 3 arcs depending on which browser you use
paper.path("M 100 100 a 50 50 0 1 0 35 85").attr({stroke: "#080", opacity: 1, "stroke-width" : 6}) // this is about 62.5% of a circle, and it shows on most any browsers
paper.path("M 100 210 a 50 50 0 1 0 0.0001 0").attr({stroke: "#080", opacity: 1, "stroke-width" : 6}) // this one won't show anything if it is IE 8's VML, but will show if it is Chrome or Firefox's SVG. On IE 8, it needs to be 0.01 to show
paper.path("M 100 320 a 50 50 0 1 0 0.0000001 0").attr({stroke: "#080", opacity: 1, "stroke-width" : 6}) // this one won't draw anything at all, unless you change the 0.0000001 to 0.0001 on Chrome or Firefox... Safari will show it though...
paper.path("M 100 430 a 50 50 0 1 0 0 0").attr({stroke: "#080", opacity: 1, "stroke-width" : 6}) // this is 100% of a circle... even Safari won't show it
<script src="https://cdnjs.cloudflare.com/ajax/libs/raphael/2.1.0/raphael-min.js"></script>
M 100 100 a 50 50 0 1 0 0.00001 0
But when it is 99.99999999% of a circle, then nothing will show at all?
M 100 100 a 50 50 0 1 0 0.00000001 0
And that's the same with 100% of a circle (it is still an arc, isn't it, just a very complete arc)
M 100 100 a 50 50 0 1 0 0 0
How can that be fixed? The reason is I use a function to draw a percentage of an arc, and if I need to "special case" a 99.9999% or 100% arc to use the circle function, that'd be kind of silly.
Again, a test case is above
(and if it is VML on IE 8, even the second circle won't show... you have to change it to 0.01)
Update:
This is because I am rendering an arc for a score in our system, so 3.3 points get 1/3 of a circle. 0.5 gets half a circle, and 9.9 points get 99% of a circle. But what if there are scores that are 9.99 in our system? Do I have to check whether it is close to 99.999% of a circle, and use an arc function or a circle function accordingly? Then what about a score of 9.9987? Which one to use? It is ridiculous to need to know what kind of scores will map to a "too complete circle" and switch to a circle function, and when it is "a certain 99.9%" of a circle or a 9.9987 score, then use the arc function.
I know it's a bit late in the game, but I remembered this question from when it was new and I had a similar dillemma, and I accidently found the "right" solution, if anyone is still looking for one:
<path
d="
M cx cy
m -r, 0
a r,r 0 1,0 (r * 2),0
a r,r 0 1,0 -(r * 2),0
"
/>
In other words, this:
<circle cx="100" cy="100" r="75" />
can be achieved as a path with this:
<path
d="
M 100, 100
m -75, 0
a 75,75 0 1,0 150,0
a 75,75 0 1,0 -150,0
"
/>
The trick is to have two arcs, the second one picking up where the first left off and using the negative diameter to get back to the original arc start point.
The reason it can't be done as a full circle in one arc (and I'm just speculating) is because you would be telling it to draw an arc from itself (let's say 150,150) to itself (150,150), which it renders as "oh, I'm already there, no arc necessary!".
The benefits of the solution I'm offering are:
it's easy to translate from a circle directly to a path, and
there is no overlap in the two arc lines (which may cause issues if you are using markers or patterns, etc). It's a clean continuous line, albeit drawn in two pieces.
None of this would matter if they would just allow textpaths to accept shapes. But I think they are avoiding that solution since shape elements like circle don't technically have a "start" point.
snippet demo:
circle, path {
fill: none;
stroke-width: 5;
stroke-opacity: .5;
}
circle {
stroke: red;
}
path {
stroke: yellow;
}
<?xml version="1.0" standalone="no"?>
<svg xmlns="http://www.w3.org/2000/svg" version="1.1"
width="220px" height="220px">
<circle cx="100" cy="100" r="75" />
<path
d="
M 100, 100
m -75, 0
a 75,75 0 1,0 150,0
a 75,75 0 1,0 -150,0
"
/>
</svg>
Update:
If you are using the path for a textPath reference and you are wanting the text to render on the outer edge of the arc, you would use the exact same method but change the sweep-flag from 0 to 1 so that it treats the outside of the path as the surface instead of the inside (think of 1,0 as someone sitting at the center and drawing a circle around themselves, while 1,1 as someone walking around the center at radius distance and dragging their chalk beside them, if that's any help). Here is the code as above but with the change:
<path
d="
M cx cy
m -r, 0
a r,r 0 1,1 (r * 2),0
a r,r 0 1,1 -(r * 2),0
"
/>
Same for XAML's arc. Just close the 99.99% arc with a Z and you've got a circle!
In reference to Anthony’s solution, here is a function to get the path:
function circlePath(cx, cy, r){
return 'M '+cx+' '+cy+' m -'+r+', 0 a '+r+','+r+' 0 1,0 '+(r*2)+',0 a '+r+','+r+' 0 1,0 -'+(r*2)+',0';
}
A totally different approach:
Instead of fiddling with paths to specify an arc in svg, you can also take a circle element and specify a stroke-dasharray, in pseudo code:
with $score between 0..1, and pi = 3.141592653589793238
$length = $score * 2 * pi * $r
$max = 7 * $r (i.e. well above 2*pi*r)
<circle r="$r" stroke-dasharray="$length $max" />
Its simplicity is the main advantage over the multiple-arc-path method (e.g. when scripting you only plug in one value and you're done for any arc length)
The arc starts at the rightmost point, and can be shifted around using a rotate transform.
Note: Firefox has an odd bug where rotations over 90 degrees or more are ignored. So to start the arc from the top, use:
<circle r="$r" transform="rotate(-89.9)" stroke-dasharray="$length $max" />
Building upon Anthony and Anton's answers I incorporated the ability to rotate the generated circle without affecting it's overall appearance. This is useful if you're using the path for an animation and you need to control where it begins.
function(cx, cy, r, deg){
var theta = deg*Math.PI/180,
dx = r*Math.cos(theta),
dy = -r*Math.sin(theta);
return "M "+cx+" "+cy+"m "+dx+","+dy+"a "+r+","+r+" 0 1,0 "+-2*dx+","+-2*dy+"a "+r+","+r+" 0 1,0 "+2*dx+","+2*dy;
}
i made a jsfiddle to do it in here:
function polarToCartesian(centerX, centerY, radius, angleInDegrees) {
var angleInRadians = (angleInDegrees-90) * Math.PI / 180.0;
return {
x: centerX + (radius * Math.cos(angleInRadians)),
y: centerY + (radius * Math.sin(angleInRadians))
};
}
function describeArc(x, y, radius, startAngle, endAngle){
var start = polarToCartesian(x, y, radius, endAngle);
var end = polarToCartesian(x, y, radius, startAngle);
var largeArcFlag = endAngle - startAngle <= 180 ? "0" : "1";
var d = [
"M", start.x, start.y,
"A", radius, radius, 0, largeArcFlag, 0, end.x, end.y
].join(" ");
return d;
}
console.log(describeArc(255,255,220,134,136))
link
all you need to do is to change the input of console.log and get the result in console
For those like me who were looking for an ellipse attributes to path conversion:
const ellipseAttrsToPath = (rx,cx,ry,cy) =>
`M${cx-rx},${cy}a${rx},${ry} 0 1,0 ${rx*2},0a${rx},${ry} 0 1,0 -${rx*2},0 Z`
Adobe Illustrator uses bezier curves like SVG, and for circles it creates four points. You can create a circle with two elliptical arc commands...but then for a circle in SVG I would use a <circle /> :)
Written as a function, it looks like this:
function getPath(cx,cy,r){
return "M" + cx + "," + cy + "m" + (-r) + ",0a" + r + "," + r + " 0 1,0 " + (r * 2) + ",0a" + r + "," + r + " 0 1,0 " + (-r * 2) + ",0";
}
It's a good idea that using two arc command to draw a full circle.
usually, I use ellipse or circle element to draw a full circle.
Another way would be to use two Cubic Bezier Curves. That's for iOS folks using pocketSVG which doesn't recognize svg arc parameter.
C x1 y1, x2 y2, x y (or c dx1 dy1, dx2 dy2, dx dy)
The last set of coordinates here (x,y) are where you want the line to end. The other two are control points. (x1,y1) is the control point for the start of your curve, and (x2,y2) for the end point of your curve.
<path d="M25,0 C60,0, 60,50, 25,50 C-10,50, -10,0, 25,0" />
These answers are much too complicated.
A simpler way to do this without creating two arcs or convert to different coordinate systems..
This assumes your canvas area has width w and height h.
`M${w*0.5 + radius},${h*0.5}
A${radius} ${radius} 0 1 0 ${w*0.5 + radius} ${h*0.5001}`
Just use the "long arc" flag, so the full flag is filled. Then make the arcs 99.9999% the full circle. Visually it is the same. Avoid the sweep flag by just starting the circle at the rightmost point in the circle (one radius directly horizontal from the center).

Rotate rectangle around its own center in SVG

I have following piece of code :
<svg>
<defs>
<rect id = "myRect"
x = "10"
y = "10"
height = "120"
width = "120"
stroke-width = "2px"
stroke = "red"
fill = "blue" />
</defs>
<g transform = "translate(100,30)">
<use xlink:href = "#myRect" />
</g>
<g transform = "translate(100, 100) rotate(45 ? ?)">
<rect id = "myRect"
x = "10"
y = "10"
height = "120"
width = "120"
stroke-width = "2px"
stroke = "green"
fill = "yellow" />
</g>
</svg>
When I translate rectangle without rotation, it is working fine. But when I rotate it, I wanted to rotate it around its center axis point. What should I need to pass to rotate attribute?
You would have to set the center as the center of the filled element. Like this:
svg .rotate {
transform-box: fill-box;
transform-origin: center;
transform: rotate(45deg);
}
You just need to add half the width/height of the rectangle to get its centre.
<g transform = "translate(100, 100) rotate(45 60 60)">
See transform documentation of the rotate function for more information.
The accepted answer works if you are drawing the rectangle starting at point (0,0) which was the OP case. However for me it was not!
Here is what worked for me:
To get the rectangle coordinates i used $('#rectID').getBBox()
method, should return [rect-height , rect-width , rect-y , rect x ]
The center point is ( rect-x + (rect-width/2) , rect-y + (rect-height/2) )
Here is a snippet i used on the browser console:
var coord = $('#elemID')[0].getBBox();
coord.x + (coord.width/2) +' '+ coord.y + (coord.height/2)
origin
x = x + width / 2
y = y + height / 2
here
x is 10
y is 10
width is 120
height is 120
<g transform = "translate(100, 100) rotate(45 70 70)">
I know this is an old post but if there are people out there who are looking make the values modifiable outside the group element
const centerX=100;
const centerY=100;
const firstAngle=45;
const secondAngle=60;
const thirdAngle =60;
<g transform ={`translate(${centerX}, ${centerY}) rotate(${firstAngle} ${secondAngle},
${thirdAngle})`}>
Nothing you just need to write the following code with the element in javascript:
element.rotate(angle Degree);

Draw a hollow circle in SVG

I'm not sure how to approach drawing a hollow circle in SVG.
I would like a ring shape filled with a colour and then have a black outline.
The way I thought about doing it was have 2 circles, one with a smaller radius than the other. The problem is when I fill them, how do I make the smaller circle take the same fill colour as what it sits on?
Just use fill="none" and then only the stroke (outline) will be drawn.
<svg xmlns="http://www.w3.org/2000/svg" version="1.1">
<circle cx="100" cy="50" r="40" stroke="black" stroke-width="2" fill="none" />
</svg>
Or this if you want two colours:
<svg xmlns="http://www.w3.org/2000/svg" version="1.1">
<circle cx="100" cy="50" r="40" stroke="black" stroke-width="3" fill="none" />
<circle cx="100" cy="50" r="39" stroke="red" stroke-width="2" fill="none" />
</svg>
MDragon00's answer works, but the inner and outer circles are not perfectly aligned (e.g. centered).
I modified his approach a little, using 4 semi-circle arcs (2 outer and 2 inner in reversed direction) to get the alignment exactly right.
<svg width="100" height="100">
<path d="M 50 10 A 40 40 0 1 0 50 90 A 40 40 0 1 0 50 10 Z M 50 30 A 20 20 0 1 1 50 70 A 20 20 0 1 1 50 30 Z" fill="#0000dd" stroke="#00aaff" stroke-width="3" />
</svg>
<!--
Using this path definition as d:
M centerX (centerY-outerRadius)
A outerRadius outerRadius 0 1 0 centerX (centerY+outerRadius)
A outerRadius outerRadius 0 1 0 centerX (centerY-outerRadius)
Z
M centerX (centerY-innerRadius)
A innerRadius innerRadius 0 1 1 centerX (centerY+innerRadius)
A innerRadius innerRadius 0 1 1 centerX (centerY-innerRadius)
Z
-->
Thanks to Chasbeen, I figured out how to make a true ring/donut in SVG. Note that the outer circle actually isn't closed, which is only apparent when you use a stroke. Very useful when you have many concentric rings, especially if they're interactive (say, with CSS hover commands).
For the draw command...
M cx, cy // Move to center of ring
m 0, -outerRadius // Move to top of ring
a outerRadius, outerRadius, 0, 1, 0, 1, 0 // Draw outer arc, but don't close it
Z // default fill-rule:even-odd will help create the empty innards
m 0 outerRadius-innerRadius // Move to top point of inner radius
a innerRadius, innerRadius, 0, 1, 1, -1, 0 // Draw inner arc, but don't close it
Z // Close the inner ring. Actually will still work without, but inner ring will have one unit missing in stroke
JSFiddle - Contains several rings and CSS to simulate interactivity. Note the downside that there's a single pixel missing at the starting point (at the top), which is only there if you add a stroke on.
Edit:
Found this SO answer (and better yet, this answer) which describes how to get the empty innards in general
You can do this as per the SVG spec by using a path with two components and fill-rule="evenodd". The two components are semi-circular arcs which join to form a circle (in the "d" attribute below, they each end with a 'z'). The area inside the inner circle does not count as part of the shape, hence interactivity is good.
To decode the below a little, the "340 260" is the top middle of the outer circle, the "290 290" is the radius of the outer circle (twice), the "340 840" is the bottom middle of the outer circle, the "340 492" is the top middle of the inner circle, the "58 58" is the radius of the inner circle (twice) and the "340 608" is the bottom middle of the inner circle.
<svg viewBox="0 0 1000 1000" xmlns="http://www.w3.org/2000/svg">
<path fill-rule="evenodd" d="M340 260A290 290 0 0 1 340 840A290 290 0 0 1 340 260zM340 492A58 58 0 0 1 340 608A58 58 0 0 1 340 492z" stroke-width="4" stroke="rgb(0,0,0)" fill="rgb(0,0,255)">
<title>This will only display on the donut</title>
</path>
</svg>
This is the classic donut shape
I'm not sure if you are trying to achieve this with standard SVG or JavaScript that produces SVG
The objective can be achieved by including a relative "moveto" command in a single path definition
And click "donut holes" on the right side of the interactive examples.
At the very least you can see the path definition that made the red donut.
Here's a routine to create a bezier arc which is as close as makes no odds to a circle. You need four of them in a path for a complete circle.
BezierCurve BezierArc(double ox, double oy, double r, double thetaa, double thetab)
{
double theta;
double cpx[4];
double cpy[4];
int i;
int sign = 1;
while (thetaa > thetab)
thetab += 2 * Pi;
theta = thetab - thetaa;
if (theta > Pi)
{
theta = 2 * Pi - theta;
sign = -1;
}
cpx[0] = 1;
cpy[0] = 0;
cpx[1] = 1;
cpy[1] = 4.0 / 3.0 * tan(theta / 4);
cpx[2] = cos(theta) + cpy[1] * sin(theta);
cpy[2] = sin(theta) - cpy[1] * cos(theta);
cpx[3] = cos(theta);
cpy[3] = sin(theta);
cpy[1] *= sign;
cpy[2] *= sign;
cpy[3] *= sign;
for (i = 0; i < 4; i++)
{
double xp = cpx[i] * cos(thetaa) + cpy[i] * -sin(thetaa);
double yp = cpx[i] * sin(thetaa) + cpy[i] * cos(thetaa);
cpx[i] = xp;
cpy[i] = yp;
cpx[i] *= r;
cpy[i] *= r;
cpx[i] += ox;
cpy[i] += oy;
}
return BezierCurve({cpx[0], cpy[0]},{cpx[1], cpy[1]}, {cpx[2], cpy[2]}, {cpx[3], cpy[3]});
}

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