Is a script called somewhere - linux

On one of my linux servers I have a script that performs some controls.
Is there a way of finding out where this script is called? This can be in
another script, cobol program, crontab, ...
Opening every one of them will take a very long time.

If you can modify the script, put in a ps line to get the parent pid, ps again and grep for the parent pid to get the command, then log to file.
Come back in a week or so and you should have the command that is triggering your script. In case it's something nested, you may want to recurse or similar.
To do this without modifying the script, you'll need a watcher script/program that checks for access to the script file or calls ps every so often. However, if you have that kind of access, just modifying the script is probably easier.
Edit: Apparently the commands to get the parent pid and command for it, without repeatedly calling ps, look something like:
ps -p $$ -o ppid=
cat /proc/<pid>/cmdline
(from jweyrich's answer here)

Grep for it:
grep -lr yourscript /etc /opt/anotherlikleydir
failing that, search the whole system : grep -lr yourscript /
Edit:
failing that, search in binaries too: grep -lar yourscript /
failing that, the script is either executed by a logged in user or a scripted remote login... if that's the case, try peachykeen's approach and edit the script... and why not dump a ps axf to a log too.

Related

How to log every single command executed from shell script

I am trying to find a way to record every single command that is executed by any user on the system.
Things that I have came across earlier.
It is possible to view shell commands executed from the terminal using ~/.bashrc_history file.
There is a catch here, It logs only those commands which were executed interactively from bash shell/terminal.
This solves one of my problems. But in addition to it, I would like to log those commands also which were executed as a part of the shell script.
Note: I don't have control over shell script. Therefore, adding verbose mode like #!/bin/bash -xe is not possible.
However, this can be assumed that I have root access as a system administrator.
Eg: I have another user that has access to the system. And he runs the following shell script using from his account.
#!/bin/sh
nmap google.com
and run as "$ sh script.sh"
Now, What I want is "nmap google.com" command should be logged somewhere once this file is executed.
Thanks in advance. Even a small help is appreciated.
Edit: I would like to clarify that users are unaware that they are being monitored. So I need a solution something at system level(may be agent running with root). I cannot depend on user to log suspicious activity. Of-course everyone will avoid such tricks to put blame on someone else if they do something fishy or wrong
I am aware that you were asking for Bash and Shell scripting and tagged your question accordingly, but in respect to your requirements
Record every single command that is executed by any user on the system
Users are unaware that they are being monitored
A solution something at system level
I am under the assumption that you are looking for Audit Logging.
So you may take advantage from articles like
Log all commands run by Admins on production servers
Log every command executed by a User
You can run the script in this way:
execute bash (it will override the shebang)
ts to prefix every lines
logs both in terminal and files
bash -x script.sh |& ts | tee -a /tmp/$(date +%F).log
You may ask the other user to create an alias.
Edit:
You may also add this into /etc/profile (sourced when users login)
exec > >(tee -a /tmp/$(date +%F).log)
Do it also for error output if needed. Keep it splited.

Get PID in bash file with open screen

I am a beginner in bash programming. I want to obtain PIDs from processes, in order to use trap and kill to receive and send signals to a program in the same file.
In particular, I start the program opening a screen in this way:
screen -d -m "start program"
process_id=`/bin/ps -fu $USER| grep "program" | grep -v "grep" | awk '{print $2}'`
The variable process_id contains two PIDs, not one. If I run without a screen, I don't have this issue (anyway, I have to open the screen).
Does anyone have solutions to this problem?
Another question: If I write
screen -d -m "start program">log
the log file isn't printed. Any suggestions?
For your first question, pgrep(or process grep) is what you are looking for.
For instance, the following will return a list of PIDs of all bash processes running.
preg bash
And if you read the docs:
-signal
Defines the signal to send to each matched process. Either the numeric or the symbolic signal name can be used.
Second question, you could either use the -LogFile flag if your version of screen supports it. Or specify the log file in your .screenrc configuration file.
This has already been answered.
Edit:
If you can't access the user's home directory where the configuration file .screenrc is usually put, you could change the $SCREENRC environment variable to explicitly set to an alternative path for it.

Is there a way to get an output from already running program?

I am trying to write a script that starts rtmpsrv and waits for some output from it. rtmpsrv gives the desirable output and continues running, but the script is waiting for a termination of rtmpsrv. How do I gain access to the output of rtmpsrv without stopping it?
Well, I'm not familiar with rtmpsrv, but unless necessary you should wait for it to finish. However, you can probably redirect its output to a file, and then grep the file to see if it contains the string you are looking for.
(fictional code... you can expect syntax hell, just want to give you an idea)
nohup rtmpsrv >log.rtmpsrv 2>&1 &
...
while :; do
if ! result=$(grep "your desired line" log.rtmpsrv); then
echo "success: found $result"
break
fi
done
Note: the if constructs should work as per http://www.tldp.org/LDP/Bash-Beginners-Guide/html/sect_07_01.html - just to have nicer code, as #Charles Duffy suggested.
The most simple way is this:
rtmpsrv > logfile &
Then you can search logfile for the text that you're looking for. Meanwhile, rtmpsrv will do it's thing, completely unaware of your script.
This question contains examples how to wait in your script for a certain pattern to appear in the logfile (so you don't have to search it again and again): Do a tail -F until matching a pattern
Note: If you start the rtmpsrv process in the script and the script terminates, it will probably kill the rtmpsrv process. To avoid that use nohup.
Just attach to the process using gdb -p <pid> where the pid is the process id of your script.
You can find the pid of your running script by doing smth like this ps ax | grep <My Script's Name>
http://etbe.coker.com.au/2008/02/27/redirecting-output-from-a-running-process/

When does I/O redirection occur relative to the execution of commands in the Linux shell?

On my desktop, there is only one file,its name is "file1.txt",then I execute shell script like this:
$ find . -name "*.txt" > file2.txt
After that, I run the other shell script like this:
$ cat file2.txt
Its output is:
./file1.txt
./file2.txt
So it looks like that the execution of find command is behind the creat of file “file2.txt", Am I right?
You are correct; the I/O redirection takes place before the find command is executed, so the file file2.txt already exists (but is empty) when the find command is running. Therefore, the output of the find command will include file2.txt.
It makes sense if you think about it. The redirection has to be done before find executes. You can't have it writing to the terminal first and then going to the file, even if there was a mechanism that allowed that.
You are right: the shell opens the output file first, creating it. Then it creates a subprocess with fork. The shell then closes the file and waits for the child to return. The child process calls dup or dup2 to open the output file with file descriptor 1, and only then it executes the command with one of the functions of the exec family.

How to restart background php process? (how to get pid)

I'm a PHP developer, and know very little about shell scripting... So I appreciate any help here.
I have four php scripts that I need running in the background on my server. I can launch them just fine - they work just fine - and I can kill them by looking up their PID.
The problem is I need my script to, from time to time, kill the processes and restart them, as they maintain long standing HTTP requests that sometimes are ended by the other side.
But I don't know how to write a command that'll find these processes and kill them without looking up the PID manually.
We'll start with one launch command :
/usr/local/php5/bin/php -f /home/path/to/php_script.php > /dev/null &
Is there a way to "assign" a PID so it's always the same? or give the process a name? and how would I go about writing that new command?
Thank you!
Nope, you can't "assign" the process PID; instead, you should do as "real" daemons do: make your script save its own PID in some file, and then read it from that file when you need to kill.
Alternative would be to use something like supervisor, that handles all that for you in a quite nice way.
Update - supervisor configuration
Since I mentioned supervisor, I'm also posting here a short supervisor configuration file that should do the job.
[program:yourscriptname]
command=/usr/local/php5/bin/php -f /home/path/to/php_script.php
Have a look here for more configuration options.
Then you can use it like this:
# supervisorctl status
to show the process(es) status.
# supervisorctl start yourscriptname
to start your script
# supervisorctl stop yourscriptname
to stop your script
Update - real world supervisor configuration example
First of all, make sure you have this in your /etc/supervisor/supervisord.conf.
[include]
files = /etc/supervisor/conf.d/*.conf
if not, just add those two lines and
mkdir /etc/supervisor/conf.d/
Then, create a configurtion file for each process you want to launch:
/etc/supervisor/conf.d/script1.conf
[program:script1]
command=/usr/local/php5/bin/php -f /home/path/to/php_script.php
stdout_logfile=/var/log/script1.log
stderr_logfile=/var/log/script1-error.log
/etc/supervisor/conf.d/script2.conf
[program:script2]
command=/usr/local/php5/bin/php -f /home/path/to/php_script2.php
stdout_logfile=/var/log/script2.log
stderr_logfile=/var/log/script2-error.log
...etc, etc.. for all your scripts.
(note that you don't need the trailing & as supervisor will handle all the daemonization thing for you; in fact you shouldn't execute programs that are self-daemonizing inside supervisor).
Then you can start 'em all with:
supervisorctl start all
or just one with something like:
supervisorctl start script1
Starting supervisor from php
Of course, you can start/stop the supervisor-controlled processes using the two commands above, even from inside a script.
Remember however that you'll need root privileges, and it's quite risky to allow eg. a web page to execute commands as root on the server..
If that's the case, I recommend you have a look at the instructions on how to run supervisor as a normal user (I never did that, but you should be able to run it as the www-data user too..).
The canonical way to solve this is to have the process write its PID into a file in a known location, and then any utility scripts can look up the file, read the PID, and manipulate that process. Add a command line argument to the script that gives the name of the PID file to write to.
A work around to this would be to use ps aux, this will show all of the processes with the command that called them. This presumes of course that the 4 scripts are different files, or can be uniquely identified by the command that called them. Pipe that through a grep and you're all set ps aux | grep runningscript.php
OK! so this has been a headache and a half for my who knows NOTHING about shell/bash whatever scripting...
#redShadow 's response would had been perfect, except my hosting provider will not give me access to the /etc/supervisor/ directory. as he said, you must be root - and even using sudo was an admin wouldn't let me make any chances there...
Here's what I came up with:
kill -9 `ps -ef | grep php | grep -v grep | awk '{print $2}'`
because the only types of commands I was executing showed up in the top command as php this command loops thru running processes, finds the php commands and their corresponding PIDs and KILLS them! woot!!
What I do is have my script check for a file that I name "run.txt". If it does not
exist, they exit. Then just br renaming that (empty) file, I can stop all my scripts.

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