Got formulas for figuring my differences between date periods in days as follows:
=IF(F7="","0",DAYS360(F6,F7)+1)
This gives the days result for each period that I am interested in, but I then need to add each period of days together and subtract them from a current date (like doing service computation). The issue is that I need to do this second calculation within a 360-day calendar as well. If I just try to do a days360() formula with one value being the current date and the other being the total number of days that I need to backtrack, then the "original" date that it comes up with is drastically off.
This seems to be the equivalent of the difference between NETWORKDAYS and WORKDAY functions. The former counts working days between two dates, the latter adds working days to a date, you essentially want the WORKDAY equivalent for DAYS360, which I don't think exists.
You can manipulate DAYS360, though, e.g. with a date in A2 and number of days to subtract (in 360 day mode) in B2 you can use this formula for the date
=A2-B2-MATCH(B2,INDEX(DAYS360(A2-B2-ROW(INDIRECT("1:"&CEILING(B2/30,1))),A2),0),0)
Related
So i have been playing with Excel for a while, and one thing led to another, i wanted to try this: How would i calculate the instances of dates (such as below) in one sheet
And count which of those dates fall under the 30/60/90 day period (such as below) I'm looking to see if i could have a final tally up the number of instances of dates which fall below 30/60/90 days to the current date in another sheet.
Using the table example gave that i would know that 2 dates fall under the 30/60 days period, and one fell under the 90 days period
Is there a solution to my predicament?
Edit: More accurate question
Use nested IF() function.
=IF(TODAY()-B2<=30,30,IF(TODAY()-B2<=60,60,IF(TODAY()-B2<=90,90,"Other period")))
Or try IFS() if you have Excel-365.
=IFS(TODAY()-B2<=30,30,TODAY()-B2<=60,60,TODAY()-B2<=90,90)
Another option is-
=XLOOKUP(TODAY()-B2,{30,60,90},{30,60,90},"Other Period",1)
You could try:
Formula in E2:
=SUMPRODUCT(--(CEILING(D$6-B$2:B$6,30)=D2))
I have a set of dates, in total 7 periods spanning 6 months each with corresponding calculation factor.
I will have user input of period for which they'd want the calculation to be done, which can fall within one of the 6 months periods or encompass between two or more such periods wholly or partially.
Illustration:
The preset periods:
User input:
I've obtained decimal value (monthly basis) of the periods input by the user for calculation. For first instance (see user input), the decimal value for the period 01-01-2015 to 29-04-2015 will be 3.97 on monthly basis. The calculation for that period would be like:
n*3.97*113%
For the second instance, the decimal value for the period 30-04-2015 to 30-06-2015 would be 2.03, which would be used to do calculation at 113% and then the result will be added to the calculation done at 119% using the decimal value 5.65 for the period 01-07-2015 to 20-12-2015:
(n*2.03*113%)+(n*5.65*119)
Think I can handle the breaking up of periods since the revision event is bi-annual on particular dates but advice regards to that is welcome. More importantly, I need help tracing the preset calculation factor (say 132%) corresponding to the period input by the user as illustrated above. Is it feasible?
I will use the standard approach for finding the overlap between two dates and will split the task into three parts as in my answer to this recent question.
(1) The first part is finding the overlap between the user's range of dates and one or more revision periods in whole months and will need an array formula. I have chosen to use the Datedif function 1 to get the difference in months between the beginning and end of the overlaps. If there is no overlap, the start date fed in to Datedif will be after the end date, and it will return an error which can be trapped by Iferror. If the user's dates start in A2 and B2, this gives in C2:
=SUM(IFERROR((DATEDIF(IF(K$2:K$8>A2,K$2:K$8,A2),IF(L$2:L$8<B2,L$2:L$8,B2),"m")+1)*M$2:M$8,0))
which has to be entered as an array formula using CtrlShiftEnter
The above result includes the first and last months entered by the user even if they are incomplete months. It's then necessary to subtract any missing days in the first and last months.
(2) Missing days in first month as a fraction of the number of days in that month in D2:
=SUMIFS($M$2:$M$8,$K$2:$K$8,"<="&A2,$L$2:$L$8,">="&A2)*(A2-EOMONTH(A2,-1)-1)/(EOMONTH(A2,0)-EOMONTH(A2,-1))
A noted by OP, this could also have been done using sumproduct, vlookup or index/match.
(3) Missing days in last month as a fraction of days in that month in E2:
=SUMIFS($M$2:$M$8,$K$2:$K$8,"<="&B2,$L$2:$L$8,">="&B2)*(EOMONTH(B2,0)-B2)/(EOMONTH(B2,0)-EOMONTH(B2,-1))
The total is just (1)-(2)-(3) or
=C2-D2-E2
I have put the results of OP's two examples for comparison in H2 and H3: my results agree with them in the first 3 significant figures.
n*3.97*113%
(n*2.03*113%)+(n*5.65*119)
In all cases I have set n=1 and ignored the fact that the rate is a percentage.
This shows how the results would be calculated manually:
1 Pros of using Datedif:
(1) Works across year boundaries unlike just using Month function.
(2) Works conveniently with Iferror to identify non-matching date ranges.
Cons of using Datedif:
(1) It is an undocumented function and may be withdrawn in future.
(2) In this particular case, all date calculations are within the same year so Month would be useable.
I'm stuck creating a formula that will calculate days before the end of the month then adjust to make sure it is a business day. For example: 30 days before 6/30/2015 is 5/31/2015 which is a Sunday. I need that to adjust to the Friday before.
I'm working on finding the due dates of a number of documents that are due a certain number of days before another date. For example: documents are due 30 days before the last day of the month. However, the number of days varies and the due date needs to fall on a business day (Monday-Friday). Sometimes it's 30 days, sometimes it's 60 days, sometimes it's 30 calendar days + 5 business days, etc.
I've been able to calculate 30 days + 5 business days with the following formula:
=workday(start_date-30,-5)
Any ideas how to adjust this so that I can just have the due date be 30 calendar days before a certain date but also always be a business day?
Using WORKDAY you can use a formula like this:
=WORKDAY(A1+B1+1,-1)
where A1 is your start date and B1 the number of days to add.
You probably need to write a macro function or maybe some nested IF statements in your cell's formula.
Take a look at http://www.mrexcel.com/forum/excel-questions/481558-round-date-nearest-workday.html
That solution moves forward to the nearest workday, but the principle is sound: just subtract instead of add.
This sounds simple but I have been pulling my hair out trying to figure out a solution. Any help before I go bald would be great.
I need a formula which is able to
calculate the duration in (days, hrs, mins) between two date\time values (eg 05/12/2012 5:30 PM and say 07/12/2012 5:45 PM);
excluding weekends and holidays.
I would like the result of the formula to read as follows "e.g 2 Days 0 Hrs and 15 Mins".
Thanks
Link to sample workbook
You can use NETWORKDAYS and NETWORKDAYS.INTL to achieve this
A bit of manipulation is required as these return net whole days:
Use these functions to calculate the number of non workdays, then subtract from the difference between start and end dates
=E3-D3-(NETWORKDAYS.INTL(D3,E3,"0000000")-NETWORKDAYS(D3,E3,$A$16:$A$24))
This returns the working day difference, where 1.0 = 1 day
NETWORKDAYS.INTL(D3,E3,"0000000") calculates whole days between the two dates (no weekends, no holidays)
NETWORKDAYS(D3,E3,"0000000",$A$16:$A$24) calculates whole working days days between the two dates (Sat/Sun weekends, holidays as per your list in $A$16:$A$24)
Difference in non-working days between the two dates.
E3-D3 is time between start and end date/times (1.0 = 1 day)
Use custom number formatting to display thye result in the format you require
d "Days" h "Hours" mm "Mins"
Note: this format won't work for negative values, you will need an alternative for when end date is before start date.
The following formula works like a treat with no additional formatting or manipulation.
To make it more stable I have turned all the holiday dates for UK 2012/13 into ‘Excel Serial Number’ format and placed them in an array bracket.
Replacing the "D5" in the formula with your cell reference for your course or metric "End Date" and "E5" with your course or Metric for "Completion Date".
=IF(E5<D5,"-"&TEXT(D5-E5,"h:mm"),NETWORKDAYS(D5,E5,({40910,41005,41008,41036,41064,41065,41148,41268,41269,41275,41362,41365,41400,41421,41512,41633,41634}))-1-(MOD(E5,1)<MOD(D5,1))&" days "&TEXT(E5-D5,"h:mm"))
Where I work I don't get paid overtime, but I accrue holiday days for the overtime I work. I have the following spreadsheet which calculates how much overtime I've done and totals it in D15.
Now I want to calculate how many days this is, based on 8 hours per day. In D16, I've done =D15/8 and formatted it as h.mm \d\a\y\s, but this shows as 2.26 days instead of 2.4375 days.
What is the correct formula to use in D16?
Note to reader: this question led to multiple solutions some of which were discussed in the comments. Here is a summary of the solution found.
First solution
=(HOUR(D15)+MINUTE(D15)/60)/8
Explanation
Dates and time in Excel are stored as serial numbers, so 19:30 is actually 0.8125.
So, if you divide it by 8, you will get 0.1015625.
This latter value is worth 2.26 days
OP's version (thanks to Danny Becket (OP)) - see the comments below.
This solution now handles hours > 24.
=((DAY(D20)*24)+HOUR(D20)+(MINUTE(D20)/60))/8
or better (credits to Barry Houdini):
=((INT(D20)*24)+HOUR(D20)+(MINUTE(D20)/60))/8
The former formula has a limitation for large values, perhaps not relevant here but if D20 is 800:00 then you get the wrong answer (7 days rather than 100 days). This is probably because DAY function is giving you calendar day which will "reset" at 31, best to use INT in place of DAY.
Another easily understandable version
Divide by the length of the day as a time value:
=D15/"8:00"
More easily changed if length of workday changes
Enter:
in B3 8:3
in C3 16:3
in D3 =IF(B3<C3,C3-B3-1/3,2/3-B3+C3)
Select B3:D3, format as hh:mm and copy down as far as required.
Sum ColumnD and append *3 to the formula, but format as Number.
Add data by overwriting cells in ColumnB and/or ColumnC as required (defaults do not add to total).
Copes with overtime up to next regular start time (ie including past midnight, new serial number). 1/3 because standard working day is 8 hours (24 hours is unity for date serial counter). B3 and C3 could be hard coded but (i) there is no need and (ii) allows more flexibility. If to readily identify non standard start/finish could use conditional formatting.
Does not address weekend overtime but could easily be adapted to do so (eg add column, flag weekend day with 8 in that extra column then add that 8 [1/3] to the finish time).
Make sure that D15 has a number format of [h]:mm
then have D16 as =sum(D15/"8:00") should work fine
thats what i have tracking my annual leave, I work 37h pw with a leave day being classed as 7h24m or a half day of leave as "3:42"
I have leave taken as a cumulative figure assigned as [h]:mm in cell K2 of my spreadsheet
then I have K3=SUM(K2/"7:24") for days taken formatted as a general number
you may also need to change the date datum in excel to the 1904 date system http://support.microsoft.com/kb/182247/en-gb
to get this to work (only a problem if you have negative time as I do when calculating flex hours)