Where I work I don't get paid overtime, but I accrue holiday days for the overtime I work. I have the following spreadsheet which calculates how much overtime I've done and totals it in D15.
Now I want to calculate how many days this is, based on 8 hours per day. In D16, I've done =D15/8 and formatted it as h.mm \d\a\y\s, but this shows as 2.26 days instead of 2.4375 days.
What is the correct formula to use in D16?
Note to reader: this question led to multiple solutions some of which were discussed in the comments. Here is a summary of the solution found.
First solution
=(HOUR(D15)+MINUTE(D15)/60)/8
Explanation
Dates and time in Excel are stored as serial numbers, so 19:30 is actually 0.8125.
So, if you divide it by 8, you will get 0.1015625.
This latter value is worth 2.26 days
OP's version (thanks to Danny Becket (OP)) - see the comments below.
This solution now handles hours > 24.
=((DAY(D20)*24)+HOUR(D20)+(MINUTE(D20)/60))/8
or better (credits to Barry Houdini):
=((INT(D20)*24)+HOUR(D20)+(MINUTE(D20)/60))/8
The former formula has a limitation for large values, perhaps not relevant here but if D20 is 800:00 then you get the wrong answer (7 days rather than 100 days). This is probably because DAY function is giving you calendar day which will "reset" at 31, best to use INT in place of DAY.
Another easily understandable version
Divide by the length of the day as a time value:
=D15/"8:00"
More easily changed if length of workday changes
Enter:
in B3 8:3
in C3 16:3
in D3 =IF(B3<C3,C3-B3-1/3,2/3-B3+C3)
Select B3:D3, format as hh:mm and copy down as far as required.
Sum ColumnD and append *3 to the formula, but format as Number.
Add data by overwriting cells in ColumnB and/or ColumnC as required (defaults do not add to total).
Copes with overtime up to next regular start time (ie including past midnight, new serial number). 1/3 because standard working day is 8 hours (24 hours is unity for date serial counter). B3 and C3 could be hard coded but (i) there is no need and (ii) allows more flexibility. If to readily identify non standard start/finish could use conditional formatting.
Does not address weekend overtime but could easily be adapted to do so (eg add column, flag weekend day with 8 in that extra column then add that 8 [1/3] to the finish time).
Make sure that D15 has a number format of [h]:mm
then have D16 as =sum(D15/"8:00") should work fine
thats what i have tracking my annual leave, I work 37h pw with a leave day being classed as 7h24m or a half day of leave as "3:42"
I have leave taken as a cumulative figure assigned as [h]:mm in cell K2 of my spreadsheet
then I have K3=SUM(K2/"7:24") for days taken formatted as a general number
you may also need to change the date datum in excel to the 1904 date system http://support.microsoft.com/kb/182247/en-gb
to get this to work (only a problem if you have negative time as I do when calculating flex hours)
Related
I made a worksheet covering meal expenses for a set period of time (01-08-2020 until 31-08-2020.)
The company will pay up to 75kr, Monday-Friday.
The list covers expenses 7 days a week, If the amount is greater than 75 on Monday-Friday, I have to pay the extra expenses. (This I have figured out correctly). Saturday and Sunday I have to pay fully.
So my question is, how can I sum this and exclude Saturday and Sunday?
Attempt 1:
I tried this formula (Norwegian excel. Summerhvis = SUMIF. Lørdag = Saturday):
=SUMMERHVIS(B2:B32,"<>lørdag", G2:G32)
It seems to be partly correct however, I miss Sunday, how can I add Sunday to this equation?
Attempt 2:
I used this formula:
=SUMMERHVIS(B2:B32,B2:B6,G2:G32)
It gave the correct answer but the answer was layered in 5 rows. I then summed this in P8.
Where I want the answer is in G32. So in G32 I wrote =p8.
It must be an easier way of doing this?
You can use SUMPRODUCT and the WEEKDAY function:
=SUMPRODUCT((WEEKDAY(A2:A32,3)<5)*G2:G32)
According to the Microsoft function translator, this might be, in Norwegian:
=SUMMERPRODUKT((UKEDAG(A2:A32;3)<5)*G2:G32)
If you really want to use SUMIF and your text days, one way would be (in English):
=SUM(SUMIF(B2:B32,{"Monday";"Tuesday";"Wednesday";"Thursday";"Friday"},G2:G32)),
or, if your weekday days are in b4:b8:
=SUM(SUMIF(B2:B32,$B$4:$B$8,G2:G32))
but I'd advise against it as it would only work in the language of the text days of the week. Also, I note your days of the week don't seem to match up with what the days of the week were in the US. For example, here 1 Aug 2020 was a Saturday, so another possible cause for error (unless I am not understanding the dates correctly).
The above is the same as summing five separate SUMIF equations, each for a desired day of the week.
I'm trying to figure out a way to create an excel spreadsheet that will allow me to keep track of how many hours I've earned per each paid holiday my company offers, then keep track of how many hours I've used and what's remaining. But I'm unsure how to calculate this properly.
I could easily do the math my self as it's a simple lay out, but I'm trying to find a way that will just let me enter the numbers for earned and used and walk away from anything else.
What I'm trying to do is the follow:
Have multiple sections. In the first section it'll be my holidays. So in like Column A, working down I'd have New Years, Memorial Day, July 4th, etc. Column B working down would be time earned. But this would be labeled in each cell as "8 Hrs" or "4 hrs". Column C would be time used in the same format "4 hrs" "8 hrs". Then Column D would simple be hours remaining.
Now in the second section I'd have holiday hours earned, which is 2 weeks. Not too sure how to lay it out, and then I still have my sick days, but not sure if I should include that in section 2 or not with the vacation time.
I'd like a way to be able to simply Calculate B2 - C2 = D2. So 8 Hrs - 4 Hrs = 4 Hrs (to show 4 Hrs remaining for each line item.)
Problem is I'm unsure how to calculate remaining time simply because of the Hrs suffix. And with that I also can't calculate total time still remaining, both for holiday hours earn and vacation/sick hours.
Yes, it's easier for me to track it as 8 Hrs rather than 1 day, etc.
Any advice on how to formulate this. Or if anyone knows of a premade template that fits this type of scenario, that I could then just take and integrate into my own spreadsheet.
Sorry if this is confusing in any way.
Also, As I'm no excel wizard, unsure if this is relevant or not, but I'm using Excel 2016, as part of the Office suite.
Another option is to just leave the number as it is and label the column accordingly. Do you really need to see "hrs" in every cell when you know you are tracking hours?
Use a custom number format of,
[>1]0 \H\r\s;[=1]0 \H\r_);0 \H\r\s;[Red]#
... and treat all hours as integers.
As requested, I have included a simplified screenshot that illustrates the issue.
As you can see, I subtracted the two dates and formatted it as "h:mm:ss". Why doesn't this give you the total amount of hours that have passed between the two dates? Is there a better way to do this? There is a great answer below, but I am trying to figure out why doing the way illustrated in this screenshot doesn't work.
END OF EDIT
I am aware that similar questions have been answered here, but for whatever reason this is not working for me at all.
I have two columns: one is a date, one is the time.
As you can see from the currently highlighted cell, the "time" column is actually stored as date with the time included. In column H, I have the date stored as a serial code so that the decimal number refers to a month, day, year, hour, minute, and second. When I subtract the serial code that refers to 2/16/2016 3:20:01 PM from the serial code that refers to refers to 2/14/2016 1:20:01 PM and format that cell as "h:mm", I am getting 2:00. Why?????
I have been hacking away at this for a while and this is supposed to be stupid easy and it's not working. Any help is greatly appreciated so I can move on to more important things.
It does work. Just take the difference between the two dates, format the cell containing the difference as Number, and then use one of the following formulas to get the units you want. I will assume that:
A1 has the value 2/16/2016 3:20:01 PM
B1 has the value 2/14/2016 1:20:01 PM
Into C1 enter A1 - B1, and format it as Number
If you want the difference as days, leave C1 as is.
If you want hours, use =24*(A1 - B1)
If you want minutes, use =24*60*(A1 - B1)
If you want seconds, use =24*60*60*(A1 - B1)
THE ANSWER TO THIS IS REALLY SILLY.
Below, you will find that Tim Biegeleisen provided an excellent answer to this question. I just wanted to further elaborate.
Sometimes having too many option for formatting can be a problem, which is what happened here.
When you subtract 2/14/2016 1:20:01 PM from 2/16/2016 3:20:01 PM and format it as h:mm:ss it only subtracts the hours portion and ignores days. You just have to somehow know that if you are trying to do what I'm trying to do, you have to format it as [h]:mm:ss and then it will calculate the total number of hours passed. The bracket around the "h" is the important part here. I hope this helps the next person who comes across this.
Got formulas for figuring my differences between date periods in days as follows:
=IF(F7="","0",DAYS360(F6,F7)+1)
This gives the days result for each period that I am interested in, but I then need to add each period of days together and subtract them from a current date (like doing service computation). The issue is that I need to do this second calculation within a 360-day calendar as well. If I just try to do a days360() formula with one value being the current date and the other being the total number of days that I need to backtrack, then the "original" date that it comes up with is drastically off.
This seems to be the equivalent of the difference between NETWORKDAYS and WORKDAY functions. The former counts working days between two dates, the latter adds working days to a date, you essentially want the WORKDAY equivalent for DAYS360, which I don't think exists.
You can manipulate DAYS360, though, e.g. with a date in A2 and number of days to subtract (in 360 day mode) in B2 you can use this formula for the date
=A2-B2-MATCH(B2,INDEX(DAYS360(A2-B2-ROW(INDIRECT("1:"&CEILING(B2/30,1))),A2),0),0)
This sounds simple but I have been pulling my hair out trying to figure out a solution. Any help before I go bald would be great.
I need a formula which is able to
calculate the duration in (days, hrs, mins) between two date\time values (eg 05/12/2012 5:30 PM and say 07/12/2012 5:45 PM);
excluding weekends and holidays.
I would like the result of the formula to read as follows "e.g 2 Days 0 Hrs and 15 Mins".
Thanks
Link to sample workbook
You can use NETWORKDAYS and NETWORKDAYS.INTL to achieve this
A bit of manipulation is required as these return net whole days:
Use these functions to calculate the number of non workdays, then subtract from the difference between start and end dates
=E3-D3-(NETWORKDAYS.INTL(D3,E3,"0000000")-NETWORKDAYS(D3,E3,$A$16:$A$24))
This returns the working day difference, where 1.0 = 1 day
NETWORKDAYS.INTL(D3,E3,"0000000") calculates whole days between the two dates (no weekends, no holidays)
NETWORKDAYS(D3,E3,"0000000",$A$16:$A$24) calculates whole working days days between the two dates (Sat/Sun weekends, holidays as per your list in $A$16:$A$24)
Difference in non-working days between the two dates.
E3-D3 is time between start and end date/times (1.0 = 1 day)
Use custom number formatting to display thye result in the format you require
d "Days" h "Hours" mm "Mins"
Note: this format won't work for negative values, you will need an alternative for when end date is before start date.
The following formula works like a treat with no additional formatting or manipulation.
To make it more stable I have turned all the holiday dates for UK 2012/13 into ‘Excel Serial Number’ format and placed them in an array bracket.
Replacing the "D5" in the formula with your cell reference for your course or metric "End Date" and "E5" with your course or Metric for "Completion Date".
=IF(E5<D5,"-"&TEXT(D5-E5,"h:mm"),NETWORKDAYS(D5,E5,({40910,41005,41008,41036,41064,41065,41148,41268,41269,41275,41362,41365,41400,41421,41512,41633,41634}))-1-(MOD(E5,1)<MOD(D5,1))&" days "&TEXT(E5-D5,"h:mm"))