I have some ISO 11785 RFID animal tags which are programmed with a number and also have a number written on them. The two numbers are matched through a text file which was sent with the RFID tags. The problem is that the numbers returned by the RFID reader don't match the numbers in the file. I would like someone to help me determine how the tag numbers have been converted to be put in the file. The RFID tag returns a number with manufacturer code followed by a unique animal code.
Here is a sample of the data:
RFID Tag | RFID Response From Tag
8000F580076C2BA9 | 982 000124529577
8000F580076C2C34 | 982 000124529716
8000F580076C2C32 | 982 000124529714
8000F580076C2DD4 | 982 000124530132
8000F580076C2BDC | 982 000124529628
Can anyone suggest what I should do to the number on the left to get to the number on the right? I have tried converting from hex to decimal but that doesn't seem to work.
Edit
It turns out if I take the last 7 characters of hex then they become the animal ID, the F58 translates to the 3982 which can be worked around to get me the 982 part. I think I should be able to work from this but thought I would leave the post anyway in case someone else has the same problem.
The field encoding is defined by the ISO standard.
bits
1 Animal flag
2-4 retag counter
5-9 user information
10-15 reserved
16 additional data flag
17-26 country/manufacturer code (982 is Allflex)
27-64 unique ID
Related
I used cantools python package to decode canbus message. I used a dbc file created by me for testing. I copied a sample file. When I use can id like 419358976, I get error. But for smaller can ids like 350, it works. Does cantools fail for extended frame ids? how do I get this working?
my code which is failing for extended id's is as follows:
db = cantools.database.load_file('.\\src\\test\\resources\\j1939.dbc')
print(db.decode_message(419358976,b'\xff\xff\xff\xc0\x0c\xff\xff\xff'))
error: cantools.database.errors.Error: Standard frame id 0x18fee900 is more than 11 bits in message EEC1.
I found the answer for my question. The can id like 419358976 is an extended id. So to map that id to the id in the dbc file, I need to add another 32 bit hex number 8000 0000 to the hex can id. Then convert that result hex number to decimal and use it as the id field in the dbc file. It works perfectly after. The above error message is gone after
I'm looking for a way to shorten a sentence (a text of few lines) to produce a "readable" (not too long) file name.
The application scenario is a chatbot where user can submit a media, say a video, with some paired description text (a caption). The application would assign to the video a readable file name, to retrieve afterward the video by his file name.
Imagine a video paired with a more or less long text description of the scene, like by example:
const videoDescription = 'beautiful yellow flowers on foreground, with a background with countryside meadows and many cows'
How could I shorten the description above with a "suitable" short file name?
Ok, I could just give the sentence as a name, maybe something a bit sanitized, like:
const videoFileName = 'beautiful_yellow_flowers_on_foreground_with_a_background_with_countryside_meadows_and_many_cows.MP4'
but in that way I could exceed the 255 limit of file name size (e.g. on Linux)
Any idea for a shortener algo?
Maybe I could build the shortened filename with word abbreviations?
Maybe I could remove from sentence articles, prepositions, etc.?
BTW, a minor issue: I'm working with Italian language, so a bit of chars sanitize is required to produce good filenames.
Last but not least, I'd looking for JavaScript/Node.js code
You can check if the length is larger than 255 and shorten if necessary. You should also check for duplicates and append -1, -2 and so on if necessary.
let filename='some_flowers_on_foreground_with_a_background_with_countryside_meadows_and_few_cows.MP4'
if(filename.length>255)
filename=filename.slice(0,255-4)+'.MP4'
I am attempting to encode the EPC of a GS1 RFID using ZPL statements on a Zebra 410R printer.
First, consider the following ZPL :
^FD51,0,6,111111,2,33,444^FS
What I am attempting to do, is replace the 444 with a value stored in a field number (^FN).
^XA
^DFE:RFID^FS
^RB96,8,3,3,20,24,10,28
^RFW,E
^FD51,0,6,111111,2,33,^FN11"Enter Barcode"^FS
^XZ
So, How do I replace the '444' portion of the field data with the value stored in the field number (^FN11) ?
Thank you in advance.
Well, maybe a little bit too late, but to anyone, who may have the same question - DF is a pair command, you need to pair it with XF. DF is Download format - here you use the varible ( FD, FN). XF is Recall Format - here you declare the variables.
So, your code just miss the definition of variable, here is the whole code:
Your code:
^XA
^DFR:RFID^FS
^RB96,8,3,3,20,24,10,28
^RFW,E
^FD51,0,6,111111,2,33,^FN11"Enter Barcode"^FS
^XZ
^XA
^XFR:RFID
^FN11^FN444^FS
^XZ
I'm working right now on a symfony2 web app and I need to generate automatically and randomly pin-code composed by 6 alphanumeric characters example:
14gkf8
kfgh88
this code will be sent by mail to the use, that's how he will connect to the platform.
anyone have an idea how to make it or there is maybe a ready tool to do it ? thank you
You can generate random codes with the following code:
substr(bin2hex(openssl_random_pseudo_bytes(100)), 0, 6)
Online demo.
openssl_random_pseudo_bytes() will generate random binary data, bin2hex() will transform this binary data as hexadecimal data (e.g. 5c3aa…e55) and substr(…, 0, 6) will keep only the 6 first characters. Since hexadecimal uses values from 0 to 9 and a to f, there is 16 different characters available at each position, so it gives 16^6 = 16,777,216 possibilities (with 0 to 9 and a to z it's 36^6 = 2,176,782,336, only ± 130 times more). If the user doesn't need to type the key, you can use more characters, for example with 12 characters you have many more possibilities: 16^12 = 2,814×10¹⁴.
You can use uniqid() to generate a unique alphanumeric string
I am having a 512*512 types of file its a x*y type of file . now we are having 512 files of this type . these 512 files are like the z-axis if we have 100 files of this type then our total vertices are 512*512*100 , in this way I have to read a file is there any algorithm to read files arranged this type and putting into a single 2-d text file.
2-d text file will be like this
000 001 010 011 100 101 110 111 ,in this way we go on printing from the 3-d text file into a single 2-d text file
Is there any way to do that if anyone know please let me know that. any tutorial or any code
Sudhanshu
p.s : if you need any other information about my question you tell me.
Okay, I'm going to parse it this way:
You have some files of Type XY:
Each one has a 512*512 table.
You have Z of these files.
You want to turn it into a new type of file, with a 512*512*512 table.
I'll assume that:
You know how to perform basic file I/O.
You know how to parse your existing file (it has a known delimiter for row/column).
It's surprisingly easy: concatenate the files. You know the length, so you know that every 2^18 entries (or 2^9 rows) represents a X-Y plane at an integer Z-location.
If you're worried about the size changing, then go ahead and choose a new delimiter to represent a new Z-index.