mansa, amit, janani ,[rakesh]
aruna,mahesh,,prathiksha
This is my input.
I need a shell script or a awk command that gives me output in following manner
mansa
amit
janani
rakesh
aruna
mahesh
prathiksha
The script should remove all ,'s brackets.
I tried this
awk -F "\[\][,]+" '{for(i=1;i<=NF;i++){print $i}}'
but its printing one extra line after each record.
Easier with grep:
$ grep -o '[a-z]\+' file
mansa
amit
janani
rakesh
aruna
mahesh
prathiksha
Another option might be tr:
tr -cs '[:alpha:]' '[\n*]' < file
Although it would create empty lines if there is leading whitespace, which could then be filtered out:
tr -cs '[:alpha:]' '[\n*]' < file | awk NF
Assuming you only want to remove square brackets and split the items from within comma delimeters, you could use the following:
perl -pe 's/,+/,/g ; s/[\[\]]//g ; s/\s*,\s*/\n/g' foo.txt
The reason I recommend this approach is in the event that your named values have numbers in them or other non-alpha characters you may want to preserve.
The perl expression above contains 3 regular expressions. First part reduces multiple commas into one (to avoid empty values between commas. The second part removes the square braces. The third part splits values by replacing commas (with whitespace on either left or right) with newlines.
Output would be as follows:
mansa
amit
janani
rakesh
aruna
mahesh
prathiksha
Related
I have data in variable like json -
v={k1:v1,k2:v2,k3:v3,k4:v4,k5:v5,k6:v6,k7:v7,k8:v8};
where key and value could be any values.
I need to split this into multiple lines after every 10 character..which i did by
echo "${v}" | sed -r 's/.{10}/&\n/g'
This does the split as per sed . But now i need to make sure split should happen only after comma character found after every 10 characters...so that out put should have meaningful lines ..
output should be ..
k1:v1,k2:v2,
.....
Whole idea is not break lines in between
Thanks
You may use
sed -r 's/.{10}[^,]*,/&\n/g'
See the sed demo online.
The .{10}[^,]*, pattern matches
.{10} - any 10 chars
[^,]* - 0 or more chars other than ,
, - a comma.
The &\n replacement pattern replaces with the whole match (&) and appends a newline to it.
If actually you just want to add a newline after every 2nd comma then that's this in GNU sed and some other seds:
$ echo "$v" | sed 's/,[^,]*,/&\n/g'
k1:v1,k2:v2,
k3:v3,k4:v4,
k5:v5,k6:v6,
k7:v7,k8:v8
or this for portability across all seds in all shells:
sed 's/,[^,]*,/&\
/g'
or this using any awk:
awk '{gsub(/,[^,]*,/,"&\n")}1'
Sorry and thanks for feed back here is the expected output-
{k1:v1,k2:v2,
k3:v3,k4:v4,
k5:v5,k6:v6,
k7:v7,k8:v8}
Rule should be look for first 10 characters then first comma when found add a new line after that pattern.
Wiktor code snippt does this actually. However , i am happy to see to achieve this with other ways. Thanks all.
I would like to display the last word in these lines I tried to look for example the word value but no answer, so I thought to look for the words between quotes but my file contains other words between quotes that I have I need not actually want to display the values of the select tag knowing that my html file is.
grep '*' hosts.html | awk '{print $NF}'
For example:
value='www.visit-tunisia.com'>www.visit-tunisia.com
value='www.watania1.tn'>www.watania1.tn
value='www.watania2.tn'>www.watania2.tn
I would have
www.visit-tunisia.com
www.watania1.tn
www.watania2.tn
You need to set the field separator to > you do this with the -F option:
$ awk -F'>' '{print $NF}' hosts.html
www.visit-tunisia.com
www.watania1.tn
www.watania2.tn
Note: I'm not sure what you are trying to achieve by grep '*' hosts.html?
Interpreting the comment liberally, you have input lines which might contain:
value='www.visit-tunisia.com'>www.visit-tunisia.com
value='www.watania1.tn'>www.watania1.tn
value='www.watania2.tn'>www.watania2.tn
and you would like the names which are repeated on a line as the output:
www.visit-tunisia.com
www.watania1.tn
www.watania2.tn
This can be done using sed and capturing parentheses.
sed -n -e "s/.*'\([^']*\)'.*\1.*/\1/p"
The -n says "don't print unless I say to do so". The s///p command prints if the substitute works. The pattern looks for a stream of 'anything' (.*), a single quote, captures what's inside up to the next single quote ('\([^']*\)') followed by any text, the captured text (the first \1), and anything. The replacement text is what was captured (the second \1).
Example:
$ cat data
www and wotnot
value='www.visit-tunisia.com'>www.visit-tunisia.com
blah
value='www.watania1.tn'>www.watania1.tn
hooplah
value='www.watania2.tn'>www.watania2.tn
if 'nothing' is required, nothing will be done.
$ sed -n -e "s/.*'\([^']*\)'.*\1.*/\1/p" data
www.visit-tunisia.com
www.watania1.tn
www.watania2.tn
nothing
$
Clearly, you can refine the [^']* part of the match if you want to. I used double quotes around the expression since the pattern matches on single quotes. Life is trickier if you need to allow both single and double quotes; at that point, I'd put the script into a file and run sed -f script data to make life easier.
sed 's/.*>\(.*\)/\1/g' your_file
I have a file containing many lines, and I want to display only the first word of each line with the Linux commands.
How can I do that?
You can use awk:
awk '{print $1}' your_file
This will "print" the first column ($1) in your_file.
Try doing this using grep :
grep -Eo '^[^ ]+' file
try doing this with coreutils cut :
cut -d' ' -f1 file
I see there are already answers. But you can also do this with sed:
sed 's/ .*//' fileName
The above solutions seem to fit your specific case. For a more general application of your question, consider that words are generally defined as being separated by whitespace, but not necessarily space characters specifically. Columns in your file may be tab-separated, for example, or even separated by a mixture of tabs and spaces.
The previous examples are all useful for finding space-separated words, while only the awk example also finds words separated by other whitespace characters (and in fact this turns out to be rather difficult to do uniformly across various sed/grep versions). You may also want to explicitly skip empty lines, by amending the awk statement thus:
awk '{if ($1 !="") print $1}' your_file
If you are also concerned about the possibility of empty fields, i.e., lines that begin with whitespace, then a more robust solution would be in order. I'm not adept enough with awk to produce a one-liner for such cases, but a short python script that does the trick might look like:
>>> import re
>>> for line in open('your_file'):
... words = re.split(r'\s', line)
... if words and words[0]:
... print words[0]
...or on Windows (if you have GnuWin32 grep) :
grep -Eo "^[^ ]+" file
I'm stumped with how to remove a portion of a string that has forward slashes and question marks in it.
Example: /diag/PeerManager/list?deviceid=RXMWANT8WFYJNF7K6DXXXJLJVN
and I need the output to be RXMWANT8WFYJNF7K6DXXXJLJVN
I've tried tr and sed but tr removes some of the characters I need in the output. sed is giving me trouble because of the forward slashes.
What's a quick method to remove the /diag/PeerManager/list?deviceid= portion of my string?
thanks!
echo "/diag/PeerManager/list?deviceid=RXMWANT8WFYJNF7K6DXXXJLJVN" | sed -n 's:/[a-zA-Z]/[a-zA-Z]/[a-zA-Z]?[a-zA-Z]=::p'
This should do the trick. I chose the colon as the delimiter as it will not cause any issues with the forward slash. This makes a lot of assumptions about the type of input it will be receiving, specifically that it will only contain three backslashes with lower and uppercase letters between them, a series of letters ending in a question mark, another series of letters ending in an equals sign. This then removes those items and prints the remaining characters (your device id).
This worked for me:
sed 's/.*deviceid=\([^&]*\).*/\1/'
Example:
$ echo '/diag/PeerManager/list?deviceid=RXMWANT8WFYJNF7K6DXXXJLJVN' | sed 's/.*deviceid=\([^&]*\).*/\1/'
RXMWANT8WFYJNF7K6DXXXJLJVN
This is not the most robust solution, but if you have a fixed set of input that will never change, it's probably good enough.
One way using awk, if there is only a single occurrence of an = on each line:
awk -F= '{ print $2 }' file.txt
Results:
RXMWANT8WFYJNF7K6DXXXJLJVN
Use Equals Sign as Field Delimiter
If you know that your GET query string will always have only one parameter (in this case, deviceid) then you can just use the equals sign as a field delimiter with the standard cut utility. For example:
$ echo '/diag/PeerManager/list?deviceid=RXMWANT8WFYJNF7K6DXXXJLJVN' |
cut -d= -f2-
RXMWANT8WFYJNF7K6DXXXJLJVN
How about:
$ echo /diag/PeerManager/list?deviceid=RXMWANT8WFYJNF7K6DXXXJLJVN | sed 's/^.*=//'
RXMWANT8WFYJNF7K6DXXXJLJVN
I need to edit a few text files (an output from sar) and convert them into CSV files.
I need to change every whitespace (maybe it's a tab between the numbers in the output) using sed or awk functions (an easy shell script in Linux).
Can anyone help me? Every command I used didn't change the file at all; I tried gsub.
tr ' ' ',' <input >output
Substitutes each space with a comma, if you need you can make a pass with the -s flag (squeeze repeats), that replaces each input sequence of a repeated character that is listed in SET1 (the blank space) with a single occurrence of that character.
Use of squeeze repeats used to after substitute tabs:
tr -s '\t' <input | tr '\t' ',' >output
Try something like:
sed 's/[:space:]+/,/g' orig.txt > modified.txt
The character class [:space:] will match all whitespace (spaces, tabs, etc.). If you just want to replace a single character, eg. just space, use that only.
EDIT: Actually [:space:] includes carriage return, so this may not do what you want. The following will replace tabs and spaces.
sed 's/[:blank:]+/,/g' orig.txt > modified.txt
as will
sed 's/[\t ]+/,/g' orig.txt > modified.txt
In all of this, you need to be careful that the items in your file that are separated by whitespace don't contain their own whitespace that you want to keep, eg. two words.
without looking at your input file, only a guess
awk '{$1=$1}1' OFS=","
redirect to another file and rename as needed
What about something like this :
cat texte.txt | sed -e 's/\s/,/g' > texte-new.txt
(Yes, with some useless catting and piping ; could also use < to read from the file directly, I suppose -- used cat first to output the content of the file, and only after, I added sed to my command-line)
EDIT : as #ghostdog74 pointed out in a comment, there's definitly no need for thet cat/pipe ; you can give the name of the file to sed :
sed -e 's/\s/,/g' texte.txt > texte-new.txt
If "texte.txt" is this way :
$ cat texte.txt
this is a text
in which I want to replace
spaces by commas
You'll get a "texte-new.txt" that'll look like this :
$ cat texte-new.txt
this,is,a,text
in,which,I,want,to,replace
spaces,by,commas
I wouldn't go just replacing the old file by the new one (could be done with sed -i, if I remember correctly ; and as #ghostdog74 said, this one would accept creating the backup on the fly) : keeping might be wise, as a security measure (even if it means having to rename it to something like "texte-backup.txt")
This command should work:
sed "s/\s/,/g" < infile.txt > outfile.txt
Note that you have to redirect the output to a new file. The input file is not changed in place.
sed can do this:
sed 's/[\t ]/,/g' input.file
That will send to the console,
sed -i 's/[\t ]/,/g' input.file
will edit the file in-place
Here's a Perl script which will edit the files in-place:
perl -i.bak -lpe 's/\s+/,/g' files*
Consecutive whitespace is converted to a single comma.
Each input file is moved to .bak
These command-line options are used:
-i.bak edit in-place and make .bak copies
-p loop around every line of the input file, automatically print the line
-l removes newlines before processing, and adds them back in afterwards
-e execute the perl code
If you want to replace an arbitrary sequence of blank characters (tab, space) with one comma, use the following:
sed 's/[\t ]+/,/g' input_file > output_file
or
sed -r 's/[[:blank:]]+/,/g' input_file > output_file
If some of your input lines include leading space characters which are redundant and don't need to be converted to commas, then first you need to get rid of them, and then convert the remaining blank characters to commas. For such case, use the following:
sed 's/ +//' input_file | sed 's/[\t ]+/,/g' > output_file
This worked for me.
sed -e 's/\s\+/,/g' input.txt >> output.csv