I'm trying to figure out how to dt or df the last occurrence of a character in a string.
For example, let's say I have the following line:
foo not.relevant.text.bar
If I f df. I expectedly get foo relevant.text.bar but I would like to get foo bar. Using f 3df. is not an option as I don't know how many of that character will be in the string. Additionally, I may want to get foo .bar (f 3dt.), or if the line ends with a dot, I may want to get foo .. I want to always find the last one regardless of how many there are.
Is this possible without a regex? I suppose I could use a regex but I was hoping there was a simple vim command that I'm missing. I find myself trying to do something like this often.
one way without using regex, without counting "dot" (could be other letters)... see if others have better way..
foo[I]not.relevant.text.bar ([I] is cursor)
you could try:
lmm$T.d`m
or in this format, may look better?
lmm$T.d`m
this will do the job. you could create a mapping if you use that often.
EDIT
I add a GIF animation to show it works. :)
note
I typed #= in normal mode after moving my cursor to the right starting point (by f(space)), to display the keys I pressed in command line.
You can use my JumpToLastOccurrence plugin. It provides ,f / ,F / ,t / ,T commands that do just that.
I would use f df...
It is not necessarily shorter to type, but I find it easier to use "repeat last command" than counting in advance the number of word/sentence I want to delete.
Then you can adjust the number of . you type to adjust the length of the string you want to delete.
For your example: ET.dB
foo not.relevant.text.bar
And it works, as long as the cursor is anywhere within the text following "foo".
Strip Path from Path+Filename: ET/dB
I use it for stripping a pathname of all but the trailing filename.
Strip the path from /some/long/path/filename.ext leaving only the filename.
Just as long as:
The cursor is anywhere within the bold word
There are no spaces in that word
E Go to the end (since there are no spaces - also works if not the last thing on the line)
T/ Find the last / (stop just after it, so it will be deleted, as well)
dB Delete to the beginning of the word
In visual mode:
$F.d^
The $ goes to the end of the current line, F searches backward for a period and d^ deletes till the beginning of the line.
Related
I'm new into vim, I have hug text file as follow:
ZK792.6,ZK792.6(let-60),cel-miR-62(18),0.239
UTR3,IV:11688688-11688716,0.0670782
ZC449.3b,ZC449.3(ZC449.3),cel-miR-62(18),0.514
UTR3,X:5020692-5020720,0.355907
First, I would like to get delete all rows with even numbers (2,4,6...).
Second, I would like to remove (18) from entire file. as a example:
cel-miR-62(18) would be cel-miR-62.
Third: How can I get delete all parentheses including it's inside?
Would someone help me with this?
For the first one:
:g/[02468]\>/d
where :g matches all lines by the regex between the slashes and runs d (delete line) on the matching lines. The regex is quite easy to read, the only interesting symbol there is perhaps the \>, which matches end of a word.
For the second question:
:%s/\V(18)//g
where % is the specification meaning "all lines of the file", s is the substitute command, \V sets the "very nomagic" mode of regexes (not sure what your default is, you might not need this) and the final g makes vim substitute all occurrences on each line (with an empty string, the one between slashes). Make sure that :set gdefault? prints nogdefault (the default setting of gdefault), otherwise, drop the final g from the substitute command.
To remove every even line (or every other line):
:g/^/+d
To remove every instance of (18):
:%s/(18)//g
Remove all the parenthetical content:
:%s/(.\\{-})//g
Note: the pattern in third answer is a non-greedy match.
Let's say I have the following line of code:
something:somethingElse:anotherThing:woahYetAnotherThing
And I want to replace each : with a ; except the first one, such that the line looks like this:
something:somethingElse;anotherThing;woahYetAnotherThing
Is there a way to do this with the :[range]s/[search]/[replace]/[options] command without using the c option to confirm each replace operation?
As far as I can tell, the smallest range that s acts on is a single line. If this is true, then what is the fastest way to do the above task?
I'm fairly new to vim myself; I think you're right about range being lines-only (not 100% certain), but for this specific example you might try replacing all of the instances with a global flag, and then putting back the first one by omitting the global -- something like :s/:/;/g|s/;/:/.
Note: if the line contains a ; before the first : then this will not work.
Here you go...
:%s/\(:.*\):/\1;/|&|&|&|&
This is a simple regex substitute that takes care of one single not-the-first :.
The & command repeats the last substitute.
The | syntax separates multiple commands on one line. So, each substitute is repeated as many times as there are |& things.
Here is how you could use a single keystroke to do what you want (by mapping capital Q):
map Q :s/:/;/g\|:s/;/:<Enter>j
Every time you press Q the current line will be modified and the cursor will move to the next line.
In other words, you could just keep hitting Q multiple times to edit each successive line.
Explanation:
This will operate globally on the current line:
:s/:/;/g
This will switch the first semi-colon back to a colon:
:s/;/:
The answer by #AlliedEnvy combines these into one statement.
My map command assigns #AlliedEnvy's answer to the capital Q character.
Another approach (what I would probably do if I only had to do this once):
f:;r;;.
Then you can repeatedly press ;. until you reach the end of the line.
(Your choice to replace a semi-colon makes this somewhat comfusing)
Explanation:
f: - go to the first colon
; - go to the next colon (repeat in-line search)
r; - replace the current character with a semi-colon
; - repeat the last in-line search (again)
. - repeat the last command (replace current character with a semi-colon)
Long story short:
fx - moves to the next occurrence of x on the current line
; repeats the last inline search
While the other answers work well for this particular case, here's a more general solution:
Create a visual selection starting from the second element to the end of the line. Then, limit the substitution to the visual area by including \%V:
:'<,'>s/\%V:/;/g
Alternatively, you can use the vis.vim plugin
:'<,'>B s/:/;/g
It happens sometimes that I have to look into various log and trace files on Windows and generally I use for the purpose VIM.
My problem though is that I still can't find any analog of grep -v inside of VIM: find in the buffer a line not matching given regular expression. E.g. log file is filled with lines which somewhere in a middle contain phrase all is ok and I need to find first line which doesn't contain all is ok.
I can write a custom function for that, yet at the moment that seems to be an overkill and likely to be slower than a native solution.
Is there any easy way to do it in VIM?
I believe if you simply want to have your cursor end up at the first non-matching line you can use visual as the command in your global command. So:
:v/pattern/visual
will leave your cursor at the first non-matching line. Or:
:g/pattern/visual
will leave your cursor at the first matching line.
you can use negative look-behind operator #<!
e.g. to find all lines not containing "a", use /\v^.+(^.*a.*$)#<!$
(\v just causes some operators like ( and #<! not to must have been backslash escaped)
the simpler method is to delete all lines matching or not matching the pattern (:g/PATTERN/d or :g!/PATTERN/d respectively)
I'm often in your case, so to "clean" the logs files I use :
:g/all is ok/d
Your grep -v can be achieved with
:v/error/d
Which will remove all lines which does not contain error.
It's probably already too late, but I think that this should be said somewhere.
Vim (since version about 7.4) comes with a plugin called LogiPat, which makes searching for lines which don't contain some string really easy. So using this plugin finding the lines not containing all is ok is done like this:
:LogiPat !"all is ok"
And then you can jump between the matching (or in this case not matching) lines with n and N.
You can also use logical operations like & and | to join different strings in one pattern:
:LP !("foo"|"bar")&"baz"
LP is shorthand for LogiPat, and this command will search for lines that contain the word baz and don't contain neither foo nor bar.
I just managed a somewhat klutzy procedure using the "g" command:
:%g!/search/p
This says to print out the non-matching lines... not sure if that worked, but it did end up with the cursor positioned on the first non-matching line.
(substitute some other string for "search", of course)
You can search with following line and press n to jump to the first non-matching line
^\(.*all is ok\)\#!.*$
Breakdown of operators:
^ -> means start of the line
\( and \) -> To match a whole string multiple times, it must be grouped into one item. This is done by putting "\(" before it and "\)" after it.
\#! -> Matches with zero width if the preceding atom does NOT match at the current position.
.* -> Matches any character repeated 1 or more times
$ -> end of the line
Here is sample animation how it works. For simplicity I searched for word apple.
You can iterate through the non-matches using g and a null substitution:
:g!/pattern/s/^//c
If you reply "n" each time you wont even mark the file as changed.
You need ctrl-C to escape from the circle (or keep going to bottom of file).
My previous question seems to be a bit ambiguous, I will rephrase it:
I have a file like this:
copythis abc
replacethis1 xyz
qwerty replacethis2
hasfshd replacethis3 fslfs
And so on...
NOTE: replacethis1, replacethis2, replacethis3, ... could be any words
How do I replace "replacethis1","replacethis2","replacethis3",.. word by "copythis" word by using minimum vim commands.
One way I can do is by these steps:
delete "replacethis1","replacethis2","replacethis3",.. by using 'dw'
copy "copythis" using 'yw'
move cursor to where "replacethis1" was and do 'p'; move cursor to where "replacethis2" was and do 'p' and so on...
Is there a better way to do this in VIM (using less number of vim commands)?
Since you changed your question, I'd do it this way:
Move to the first "replacethis1" and type cw (change word), then type "copythis" manually.
Move to the next "replacethis", hit . (repeat last operation)
Move to the next "replacethis", hit .,
and so on, and so on.
If "copythis" is a small word, I think this is the best solution.
The digit needs to be included, and there could be more than one instance per line:
:%s/replacethis\d/copythis/g
Given that "replacethis[1-3]" can be arbitrary unrelated words, the quickest/simplest way to do this globally would be:
:%s/replacethis1\|replacethis2\|replacethis3/copythis/g
(Note that you need to use \| to get the pipes to function as "or". Otherwise, vim will look for the literal | character.)
I've been struggling with this for a long time too, I think I just worked out the cleanest way:
Use whichever command is cleanest to put copythis into register r:
/copythis
"rye
Then go to the replacement and replace it with the contents of r:
/replacethis
cw<CTRL-R>r<ESC>
Then you can just n.n.n.n.n.n.n. for the rest of them, or if they're wildly different just go to the beginning of each and hit .
The key is replacing and pasting in one step so you can use . later.
:%s/copythis/replacethis/g
To replace all occurrences of copythis with replacethis. Or you can specify a range of line numbers like:
:8,10 s/copythis/replacethis/g
Note, the /g on the end will tell it to replace all occurrences. If you leave that off it will just do the first one.
create this mapping:
:map z cwcopythis^[
( ^[ is the escape character, you can type it in vim using Ctrl+V Ctrl+[ )
go to each word you want to replace and press z
if u need to do essentially the same action multiple times - swap 1st word of one line with second word of the next line, I say you could record a macro and call it whenever you need to
Have you tried string replacement?
%s/replacethis/copythis
A host of other parameters are possible to fine-tune the replacement. Dive into the Vim help for more details. Some more examples here.
You can remap e.g. the m key in normal mode to delete the word under the cursor and paste the buffer: :nnoremap m "_diwP.
Then you can just copy the desired word, move the cursor anywhere onto the to-be-replaced word and type m.
EDIT: Mapping to m is a bad idea since it is used to mark locations. But you can use e.g. ; anyway.
I am using Vim to read through a lot of C and Perl code containing many single letter variable names.
It would be nice to have some command to change the name of a variable to something more meaningful while I’m in the process of reading the code, so that I could read the rest of it faster.
Is there some command in Vim which could let me do this quickly?
I don’t think regexes would work because:
the same single letter name might have different purposes in different scoping blocks; and
the same combination of letters could be part of another longer variable name, a string literal, or a comment.
Are there any known solutions?
The following is how to rename a variable which is defined in the current scope {}.
Move your cursor to the variable usage. Press gd. Which means - move cursor to the definition.
Now Press [{ - this will bring you to the scope begin.
Press V - will turn on Visual Line selection.
Press % - will jump to the opposite } thus will select the whole scope.
Press :s/ - start of the substitute command.
<C-R>/ - will insert pattern that match variable name (that name you were on before pressing gd).
/newname/gc<CR> - will initiate search and replace with confirmation on every match.
Now you have to record a macros or even better - map a key.
Here are the final mappings:
" For local replace
nnoremap gr gd[{V%::s/<C-R>///gc<left><left><left>
" For global replace
nnoremap gR gD:%s/<C-R>///gc<left><left><left>
Put this to your .vimrc or just execute.
After this pressing gr on the local variable will bring you to :s command where you simply should enter new_variable_name and press Enter.
I know it's an old question, and #mykola-golubyev's way obviously IS the best answer for the particular case in the OP question (which, I assume is going through obfuscated code where you're likely to have multiple blocks with same var names); but with the question name like that many people coming here from google searches probably look for less situation-specific ways to rename variables in VIM -- and those can be more concise
I'm surprised no one suggested this way:
* :s// NEWNAME /gc
The * is the same as gn - search the next occurrence of the word under the cursor AND make it the last searched pattern; you can then omit the search pattern in the substitute command and VIM will assume that last one is the pattern to search for.
For small amounts of var copies, here's an even quicker one:
* cw NEWNAME <esc> then repeat n. for other occurrences
* is search for occurrences, cw is change word, n goes to the next occurrence of the last searched term and . repeats the last command (which is now change word to NEWNAME)
(Credits for me knowing all this go to #doomedbunnies on Reddit)
Another cool trick: (credits to #nobe4)
* cgn NEWNAME <esc> then repeat . for other occurrences
cgn is "change whatever is the result of (find next occurrence)". Now that this is the last command, you don't need the n to go to the next occurrence, so fewer strokes again, and, more importantly, no need to alternate n and .. But, obviously, this one has the drawback of not having a way to skip an occurrence.
Here are some benefits of these over other similar approaches, or language-specific plugins with refactoring support:
no command mapping, no fiddling with .vimrc(or init.vim), so you can use it in any VIM copy you come across (e.g. a quick task on some VPS or your friend's machine where configuring VIM your way would defeat the purpose of 'quick')
using * or gn for word selection is very quick -- just one keystroke (well, let's say 1.5)
using * or gn makes sure you don't get any matches inside other words, just as :%s/<C-R>//gc does. Beats typing the :%s/\<OLDNAME\>/NEWNAME/gc by hand: I personally tend to forget to use the \< things to limit matches to whole words only.
Not using a scope will only result in a few extra strokes of n to skip unwanted matches -- probably even fewer than the extra strokes needed to limit the scope to a certain code block. Under normal circumstances, your variables are most likely somewhat localised to a certain code block anyway.
AFAIK, there is no actual refactoring support in VIM. When doing a rename with the intent of a refactor I usually take the following precautions:
Limit the scope of the change my using marks.
When entering the regex, bracket the name with \< and >. This will make it match an entire word which reduces the types of incorrect renames that will occur.
Don't do a multiline replace to reduce chances of a bad replace
Look through the code diff carefully if it's anything other than a small change.
My end change looks something like this
:'a,'bs/\<foo\>/bar
I would love to be wrong about there not being a refactoring tool for VIM but I haven't seen it.
Put this in your .vimrc
" Function to rename the variable under the cursor
function! Rnvar()
let word_to_replace = expand("<cword>")
let replacement = input("new name: ")
execute '%s/\(\W\)' . word_to_replace . '\(\W\)/\1' . replacement . '\2/gc'
endfunction
Call it with :call Rnvar()
expand("<cword>") gets the word under the cursor. The search string uses % for file-scope, and the \(\W\) patterns look for non-word characters at the boundary of the word to replace, and save them in variables \1 and \2 so as to be re-inserted in the replacement pattern.
You could use the 'c' modifier in the global search and replace that would ask you for confirmation for each replace. It would take longer but it might work for a non-humongous code file:
%s/\$var/\$foo/gc
The c stands for confirm.
In c, you may be able to make some progress using cscope. It makes an attempt at understanding syntax, so would have a chance of knowing when the letter was a variable.
If this is across multiple files, you may consider taking a look at sed. Use find to grab your files and xargs plus sed for a replace. Say you want to replace a with a_better_name in all files matching *.c, you could do
find . -name "*.c" | xargs sed -i -e 's/a/a_better_name/g'
Bear in mind that this will replace ALL occurrences of a, so you may want a more robust regex.