Reading the documentation, I'm led to believe Google Docs should be able to handle if-statements in the following format (straight from the documentation):
IF(test, then_value, otherwise_value)
So, as a test, I try the following:
=IF(2>1, 2, 1)
This should obviously print 2 since two will always be greater than one. However, this throws me an error. So, I try the following instead:
=IF(1=1, 1, 1)
This also gives me an error.
Obviously I'm doing something wrong here, unless Google stopped supporting if-statements in their docs. Can anyone help?
Google has obviously changed this without changing the proper documentation. According to the documentation, as of writing this, the correct way to do this is as in my question:
=IF(2>1, 2, 1)
However, if you start writing "=IF" in Google Drive, a popup guides you in the correct direction, and it seems they have changed the syntax to:
=IF(2>1; 2; 1)
Note the use of semicolons instead of commas. That's it.
Related
I'm studying how to work with data right now and so I'm following along with a tutorial for working with Time Series data. Among the first things he does is read_csv on the file path and then use squeeze=True to read it as a Series. Unfortunately (and as you probably know), squeeze has been depricated from read_csv.
I've been reading documentation to figure out how to read a csv as a series, and everything I try fails. The documentation itself says to use pd.read_csv('filename').squeeze('columns') , but, when I check the type afterward, it is always still a Dataframe.
I've looked up various other methods online, but none of them seem to work. I'm doing this on a Jupyter Notebook using Python3 (which the tutorial uses as well).
If anyone has any insights into why I cannot change the type in this way, I would appreciate it. I'm not sure if I've misunderstood the tutorial altogether or if I'm not understanding the documentation.
I do literally type .squeeze("columns") when I write this out because when I write a column name or index, it fails completely. Am I doing that correctly? Is this the correct method or am I missing a better method?
Thanks for the help!
shampoo = pd.read_csv('shampoo_with_exog.csv',index_col= [0], parse_dates=True).squeeze("columns")
I would start with this...
#Change the the stuff between the '' to the entire file path of where your csv is located.
df = pd.read_csv(r'c:\user\documents\shampoo_with_exog.csv')
To start this will name your dataframe as df which is kind of the unspoken industry standard the same as pd for pandas.
Additionally, this will allow you to use a "raw" (the r) string which makes it easier to insert directories into your python code.
Once you are are able to successfully run this you can simply put df in a separate cell in jupyter. This will show you what your data looks like from your CSV. Once you have done all that you can start manipulating your data. While you can use the fancy stuff in pd.read_csv() I mostly just try to get the data and manipulate it from the code itself. Obviously there are reasons not to only do a pd.read_csv but as you progress you can start adding things here and there. I almost never use squeeze although I'm sure there will be those here to comment stating how "essential" it is for whatever the specific case might be.
there is this method I used the other day and I have forgotten the details, which in we used a syntax like this:
f=//command//(x,'sin(x)');
something like this.
im not sure if the syntax is fully correct, or what the right command is. but after this we could simply ask for the f(x) value like this:
x= 0;
y= f(x);
and then the results were y=0;
What you are asking for is usually not recommendable. Please check if a simple anonymous function also fits your requirements:
f=#(x)(sin(x))
In case you really need to evaluate from a string:
f=str2func('#(x)sin(x)')
I would advice against the second option unless absolutely required, it can lead to hard to debug errors.
well I found the answer myself and it was "inline" command; :)
f=inline('sin(x+y+z)','x','y','z');
you can add as much variables as needed too.
I'm trying to output a template variable inside the if statement in ModX, but it gives no output.
I have multiple pages with links to articles and the point is to only output template variable content on the first page but not the others.
// This gives no output:
[[!#get.page:is=`1`:or:is=``:then=`[[*content]]`:else=``]
// This outputs "yes" on the first page and "no" on others:
[[!#get.page:is=`1`:or:is=``:then=`yes`:else=`no`]]
I've even tried this, but it still does not give any output. I guess the problem is not about the output modifier:
[[!#get.page:is=`1`:or:is=``:then=`[[*content]]`:else=`[[*content]]`]
I'm using ModX Revo 2.7.0
Any help is appreciated, thanks in advance!
Actually in your case missing a double closing angle bracket "]]"
[[!#get.page:is=`1`:or:is=``:then=`[[*content]]`:else=``]]
The `or:is=` is matching against an empty state. Unless that is intentional you should be able to remove it. Also, the `:else=`` is the default state, so, you don't need that either.
The following should work and you'll have cleaner code:
[[!#get.page:is=`1`:then=`[[*content]]`]]
This is driving me mad at the moment, if anyone can help it would be much appreciated!! This is simple enough in Java, but when called from groovy I cannot get multiple gbc properties defined in a single constraint.
I have read on a couple of old posts on the net that GridBagConstraints properties such as gridx etc can be added as follows from here.
code snippet of interest:
label(text:'Username', constraints:gbc(gridx:0,gridy:0,gridwidth:2))
However this won't work for me and I didn't expect it to as the syntax appears to be from years ago so I assume an old API. (error message below when I try the above)
Caught: java.lang.IllegalArgumentException: cannot add to layout: constraint must be a string (or null)
I can't see how this could work as as surely the format needs to be:
GridBagConstraints gbc = new GridBagConstraints()
label("Username: ", constraints:gbc.gridx=0)
The two lines of code above run, but then I have the problem that I can't add more than one entry in the 'constraints:' section, and obviously I need to add 'gridy=0' etc.
Has anybody got any solution on how this should work?
Thanks
Taylor.
I'm creating a macro that opens a file that everyone has on their computer and in order to do so must know the person's username / work ID.
To get the person's work ID I've tried using the following:
sso = IIf(InStr(Application.OperatingSystem, "Windows") = 1, Environ("UserName"), _
'MacScript("(user name as string)"))
Running this on windows returns an error because of the Macscript (I think) and I'd assume the same would happen vice versa, even though the error part of the IIF is never actually accessed I'm guessing seeing as the whole line is executed this is why there is a problem, thus On Error Resume Next would not really help here.
I know this can be easily overcome by just using an if and else statement but I just want to know if I'm right / why this problem occurs and if there are any other more sophisticated ways of achieving what I want.
Thanks
The IIF function evaluates both the true and false parts, or rather it attempts to do so. There is no short-circuit. Your assumption about why it's failing (and also that you can't use an OERN) is correct. You may take a look at conditional compilation logic, if certain parts of your code will not compile on Windows (or Mac, respectively).
http://msdn.microsoft.com/en-us/library/aa240847(v=vs.60).aspx