Make a counter in Python [closed] - python-3.x

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Closed 10 years ago.
I want to make a counter from 0 to 2.097152 sec with 1 µsec step.
I tried with time.sleep() but this is not the right solution
I use Python 3.x
Thank you for your help

You could have just searched for [python] range float
but anyways:
def msrange(start, stop, step=0.000001):
while start <= stop:
yield round(start, 6)
if start + step > stop:
yield stop
start += step
then you can:
for i in msrange(0, 0.00003):
print(i)
output:
0
1e-06
2e-06
3e-06
...
3e-05

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Closed 9 years ago.
I want to write a recursive method let's say "printVertical" that takes as input a positive integer and prints its digits in vertical.
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Homework? I'll try to guide you.
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i have done the correct and try again....
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---+-----
1 | 1
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Closed 10 years ago.
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