I want to find if a string contains another string in Pig. I found that there is a built-in index function, but it only searches for characters not strings.
Is there any other alternative?
You can use this :
X = FILTER A BY (f1 matches '.*the_word_you're_looking_for.*');
More information here : http://pig.apache.org/docs/r0.10.0/basic.html#comparison
Related
I'm trying to replace a specific values in a long string. Is it possible to do this with replace function in python?
a snipit of the string is:
'rh':0, 'rp':0, 't':'b.nan','rh':1, 'rp':1, 't':'b.nan'
my snipit string should look like
'rh':0, 'rp':0, 't':b.nan,'rh':1, 'rp':1, 't':b.nan
i'm trying to replace the 'b.nan' to b.nan but it doesn't work.
The code i'm using:
a.replace("'b.nan'", "b.nan")
You can index strings like arrays:
string = "hello"
print(string[1])
this prints 'e'
You could try finding the index and then replacing it as such
I want to find a specific string within a string.
For example, let's say I have the string
string = "username:quantopia;password:blabla
How can I then find quantopia?
I am using python 3.
Update: I am sorry I did not mention what I try before..
string.split('username:',1)[1].split(';',1)[0]
But this look very bad and not efficient, I was hoping for something better.
Just use regex as such:
import re
username = re.search("username:(.*);password", "username:quantopia;password:blabla").group(1)
print("username:", username)
This will output quantopia.
In this expression "username:(.*);password" you are saying "give me everything from username: to ;password" So this is why you're getting quantopia. This might as well be ":(.*);" as it will output the same thing in this case.
The simple solution is:
string = "username:quantopia;password:blabla"
username = "username"
if username in string:
# do work.
You might be better to just use split to create a dictionary so you dont need to use multiple regex to extract different parts of data sets. The below will split stirng into key value pairs then split key value pairs then pass the list of lists to dict to create a dictionary.
string = "username:quantopia;password:blabla"
data = dict([pairs.split(':') for pairs in string.split(';')])
print(f'username is "{data["username"]}" and password is "{data["password"]}"')
OUTPUT
username is "quantopia" and password is "blabla"
Do we have any methods in mel to check string contained in some another String or not.
For Example:
I had String like "mel".
I had Another String like "melcode".
Do we have any idea how to check the String "mel" is available in String "melcode".
num indexOf(str inputString1, str inputString2)
if the return value is -1 then inputString1 does not contain inputString2
As mentioned in Is there any possible way to filter movelets using mel from another movlet?
Hi Jaya Sankar, you can use indexOf which returns -1 if the first input String does not contain the second input String. There are also startsWith and endsWith as methods.
I have strings which looks like this [NAME LASTNAME/NAME.LAST#emailaddress/123456678]. What I want to do is parse strings which have the same format as shown above so I only get NAME LASTNAME. My psuedo idea is find the index of the first instance of /, then strip from index 1 to that index of / we found. I want this as a VBScript.
Your way should work. You can also Split() your string on / and just grab the first element of the resulting array:
Const SOME_STRING = "John Doe/John.Doe#example.com/12345678"
WScript.Echo Split(SOME_STRING, "/")(0)
Output:
John Doe
Edit, with respect to comments.
If your string contains the [, you can still Split(). Just use Mid() to grab the first element starting at character position 2:
Const SOME_STRING = "[John Doe/John.Doe#example.com/12345678]"
WScript.Echo Mid(Split(SOME_STRING, "/")(0), 2)
Your idea is good here, you should also need to grab index for "[".This will make script robust and flexible here.Below code will always return strings placed between first occurrence of "[" and "/".
var = "[John Doe/John.Doe#example.com/12345678]"
WScript.Echo Mid(var, (InStr(var,"[")+1),InStr(var,"/")-InStr(var,"[")-1)
In Lua, in want to get captures from a string containing a specific substring. E.g. in the string
test = "<item>foo</item> <item>bar</item>"
I want to get items containing "a", which in this case would be "bar". I tried this:
print(string.find(test, "<item>(.-a.-)</item>"))
but the result is:
1 34 foo</item> <item>bar
So .- is more greedy than I expected. What would be the correct pattern?
Try print(string.find(test, "<item>([^<]-a.-)</item>")).