So I've stupidly designed a list of recent articles, all is good with the world BUT the first 2 entries html are markedly different then the remainder of entries.
I am yet to turn a line of code so any advice anyone an offer is greatly appreciated.
Simplistically the ul would look like:
<li class="1of2"> /* It's number 1 – give it a class to identify it as special */
<h1>{title}</h1>
<p>{short_desc}</p>
</li>
<li class="1of2"> /* It's number 2 – give it a class to identify it as special */
<h1>{title}</h1>
<p>{short_desc}</p>
</li>
<li> /* It's not number 1 or 2 – ie. every other item, NO class per se */
<h1>{title}</h1>
<p>{short_desc}</p>
</li>
If you imagine a 3 column grid for all entries but the first 2 entries are 1.5 columns each. Bit of a noodle scratch going on here, any thoughts gratefully voted upon.
PS. I will be using Stash if that helps !
Just output the class name based on the value of {count}. I've output the whole opening <li> tag here to keep it simple but you could just output the class attribute or class name itself.
{if count<=2}
<li class="special">
{if:else}
<li>
{/if}
<h1>{title}</h1>
... etc.
</li>
Incidentally, I don't think you can have class names that begin with a number.
Here's how I would do it if you want each of the first 2 to have a unique class name:
<li{if count<=2}class="top{count}"{/if}>
that will output
<li class="top1">...
<li class="top2">...
<li>...
If you want the first 2 items to have the same class:
<li{if count<=2}class="whateveryouwant"{/if}>
which will output
<li class="whateveryouwant">...
<li class="whateveryouwant">...
<li>...
Couldn't you do {if count == "1|2"}class="whatever"{/if} ?
Seems you are asking for two unique classes, one for the first entry and one for the second entry. In that case, this will work:
{if count == 1}
<li class="first">
<h1>{title}</h1>
<p>{short_desc}</p>
</li>
{if:else if count == "2"}
<li class="second">
<h1>{title}</h1>
<p>{short_desc}</p>
</li>
{if:else}
<li>
<h1>{title}</h1>
<p>{short_desc}</p>
</li>
{/if}
Also, class names that start with a number will not validate.
You could do it with simple conditionals as well if there is no "other" class that would then require the if:else part of the conditional:
<li{if count == "1"} class="first"{/if}{if count == "2"} class="second"{/if}">
<h1>{title}</h1>
<p>{short_desc}</p>
</li>
This assumes you don't have any other differences, such as different custom fields in one option versus the other, which MediaGirl's suggestion would handle more elegantly. If the only difference between them is class assignment, this is another alternative.
Related
Prestashop option to hide unavailable attributes on product page doesn't work when attribute groups are used, for example color and size (for clothing shops).
I need to keep showing all possible combinations, but grey out (or strikethrough) the combinations with no stock.
Like this:
I tried several things.
In Prestashop 1.6 the following piece of code worked to apply css class (.out-of-stock-float-left) to unavailable combinations:
{elseif $group.group_type == 'radio'}
<ul id="group_{$id_attribute_group}">
{foreach from=$group.attributes key=id_attribute item=group_attribute}
{if {$group.attributes_quantity[{$id_attribute|intval}]} > 1} <!-- product in stock -->
<li class="input-container float-left">
<input class="input-radio" type="radio" data-product-attribute="{$id_attribute_group}"
name="group[{$id_attribute_group}]"
value="{$id_attribute}"{if $group_attribute.selected} checked="checked"{/if}>
<span class="radio-label">{$group_attribute.name}</span>
</li>
{else} <!-- product out of stock -->
<li class="input-container out-of-stock-float-left">
<input class="input-radio" type="radio" data-product-attribute="{$id_attribute_group}"
name="group[{$id_attribute_group}]"
value="{$id_attribute}"{if $group_attribute.selected} checked="checked"{/if}>
<span class="radio-label">{$group_attribute.name}</span>
</li>
{/if}
{/foreach}
</ul>
{/if}
When changing combinations there is an ajax request. I don't know how to grey out combinations with no stock and make them not clickable.
Thanks
I just got into Scrapy & I’m aware this is a Noob question but How do I add an attribute to specify specific pagination link?
here is the html with the element I’m targeting.
`<div class="pagination">
<a rel="prev" href="/collections/all?page=1" class="fa fa-chevron-left prev pagination-icon"></a>
<ul>
<li class="pagination-icon">
1
</li>
<li class="pagination-icon pagination-icon--current">
2
</li>
<li class="pagination-icon">
3
</li>
<li class="pagination-icon">
4
</li>
<li class="pagination-icon pagination-icon--current">
…
</li>
<li class="pagination-icon">
50
</li>
</ul>
I Need to follow the link in this line
<a rel="next" href="/collections/all?page=3" class="fa fa-chevron-right next pagination-icon"></a>
Here is my scrapy code
next_page = response.css('div.pagination a::attr(href)').extract_first()
if next_page is not None:
yield response.follow(next_page, callback=self.parse)
What’s happening is its following this link instead of the other one because it is the first one in the class “pagination”
<a rel="prev" href="/collections/all?page=1" class="fa fa-chevron-left prev pagination-icon"></a>
I can see 2 differences between the attributes of the 2 links, both in the class “pagination”
Rel attribute is different, I need the one with “next”
Class attribute is different, I need “fa fa-chevron-right next pagination-icon”
I’m pretty sure I can get the correct link by specifying one of the 2 attributes listed above in my css selector. I tried using the following CSS selectors but none worked.
div.pagination a.fa fa-chevron-right next pagination-icon a::attr(href) does not work
a.fa fa-chevron-right next pagination-icon a::attr(href) does not work
a.fa fa-chevron-right next pagination-icon::attr(href) does not work
How can I achieve my goal? Why do none of the CSS selectors I tried work?
You can't select multiple classes with a single dot. Either combine each of them with dots or go for this syntax "[class='fa fa-chevron-right next pagination-icon']". However, if any class out of them is generated dynamically then the selector will break.
Then try with this to see what happens.
response.css('div.pagination a[rel="next"]::attr(href)').extract_first()
I'm having trouble wrapping my head around how to create a dynamic menu with GWcode categories in ExpressionEngine. I would like the menu to go a certain depth only for current {segment_2} (parent) category and the rest of the parent categories to just stay a depth of 1.
For instance, if the url was: domain.com/products/medical-tables-cabinets/eta-classic-series/ it would output this:
<ul class="nav-menu">
<li>Power Tables</li>
<li class="active submenu">Medical Tables & Cabinets
<ul class="nav-submenu">
<li>ETA Alpha Series</li>
<li class="active submenu">ETA Classic Series
<ul class="nav-submenu">
<li>Entry A</li>
<li>Entry B</li>
<li>Entry C</li>
</ul>
</li>
<li>Style Line Cabinet Models</li>
<li>Echo Image Series</li>
<li>Bariatric Series</li>
<li>Family Practice</li>
<li>Treatment & Bedside Cabinets</li>
<li>Managed Care Quick Cabinets</li>
<li>Recovery Couches</li>
</ul>
</li>
<li>Pediatric Equipment</li>
<li>Medical Seating</li>
<li>Blood Drawing Chairs</li>
<li>Tubular Steel & Accessories</li>
<li>Physical Therapy Equipment</li>
<li>Kangoo by Clinton</li>
<li>Training Room Furnishings</li>
<li>Index by Model #</li>
<li>Clinton-Eco Tables</li>
</ul>
I got it working, but I still need to go a little deeper. Here is the basic concept:
{exp:gwcode_categories
channel="products"
style="linear"
}
{if depth1_start AND segment_2 != cat_url_title}
<li>{cat_name}</li>
{/if}
{if depth1_start AND segment_2 == cat_url_title}
<li class="active submenu">{cat_name}
<ul class="nav-submenu">
{/if}
{if depth == 2 AND segment_2 == parent_url_title}
<li{if segment_3 == cat_url_title} class="active"{/if}>{cat_name}</li>
{/if}
{if depth1_end AND segment_2 == parent_url_title}
</ul>
</li>
{/if}
{/exp:gwcode_categories}
In ExpressioneEngine, I'm creating a list with conditionals that is returning some strange behavior. The code below is part of a bigger set:
<li><h4>DERMATOLOGY</h4>
<ul>
{exp:channel:entries channel="specialist" dynamic="no" orderby="sp_order" sort="asc"}
{if sp_specialty == "sp_dermatology"}
<li>
<img src="{sp_headshot}" />
<p>{title}</p>
</li>
{/if}
{/exp:channel:entries}
</ul>
</li>
<li><h4>EMERGENCY AND CRITICAL CARE</h4>
<ul>
{exp:channel:entries channel="specialist" dynamic="no" orderby="sp_order" sort="asc"}
{if sp_specialty == "sp_emergency"}
<li class="{switch='one|two'}">
<img src="{sp_headshot}" />
<p>{title}</p>
</li>
{/if}
{/exp:channel:entries}
</ul>
</li>
What happens, in the case of EMERGENCY AND CRITICAL CARE, is that with the 5 entries I have under that, the classes are returned like this: two, one, one, one, two. Any suggestions on getting the behavior I need?
I see what you mean. The switch variable applies its logic to all entries returned by the entries loop - which is why you're seeing odd numbering in your rendered page - because it's applying them to entries returned by the loop that you are then applying conditionals to in order to do your grouping. You could use the search param to do some of that for you, returning only the entries you're looking for within each loop. Like this:
<li><h4>DERMATOLOGY</h4>
<ul>
{exp:channel:entries channel="specialist" search:sp_specialty="=sp_dermatology" dynamic="no" orderby="sp_order" sort="asc"}
<li>
<img src="{sp_headshot}" />
<p>{title}</p>
</li>
{/exp:channel:entries}
</ul>
</li>
<li><h4>EMERGENCY AND CRITICAL CARE</h4>
<ul>
{exp:channel:entries channel="specialist" search:sp_specialty="=sp_emergency" dynamic="no" orderby="sp_order" sort="asc"}
<li class="{switch='one|two'}">
<img src="{sp_headshot}" />
<p>{title}</p>
</li>
{/exp:channel:entries}
</ul>
</li>
This way each loop returns ONLY the matching items you're looking for, eliminating the need for the conditional and allowing the switch param to operate as it wants to - applying itself in alternating fashion to every returned entry from the loop.
Say I have this:
...
<li class='tab'>7</li>
<li class="tab">8</li>
...
...and I'd like to use Sparkup in my editor to add another say 6 tabs...so I run the sparkup command:
li.tab > a[href=#tab2-$]{$}*6
but it comes out all wrong,
<li class="tab">8</li>
<li class="tab">
1
2
3
...
</li>
My first thought was that my syntax should have been:
(li.tab > a[href=#tab2-$]{$})*6
But that did pretty much the same thing...except this time it didn't insert the second number:
<li class="tab">8</li>
<li class="tab">
$
$
$
...
</li>
Now the range problem (starting at 9 instead of 1) is just a minor annoyance, but what if I want it to repeat the li as well as the a tag?
And yes, before you go off about it, I am indeed aware that I could create all of this stuff just using a simple for loop; but that wasn't part of the question now was it?
You are almost there:
li.tab*6 > a[href=#tab2-$]{$}
You want to create 6 <li> so that's where you should put your multiplier.
No need to be defensive.