I am wondering if it is possible to keep assigned values in ghci when a module is reloaded?
For example i assign a value in ghci:
ghci> let x = 1
or
ghci> x <- getLine
After entering :r to reload an existing module x is not in scope anymore. Is it generally possible to keep the assignment available, like for example in the Python interpreter? (this is really convenient...)
Even tho that actually each line in ghci represents a function that is (monadically) bound to the next one I am still wondering if maintaining that state is possible.
I'm not aware of any way of doing this.
The trouble is that you could have some variable bound to a value of a certain type, edit the source to remove that type, and hit reload. Now you have a variable of a type that no longer exists.
Still, you would think it shouldn't be too hard to detect that, and discard just the variables that don't make sense any more. (The really fun part is presumably when a type still exists but has a different number of fields now, or something like that...)
Related
I'm restricting myself the use of prebuilt-in functions for training purposes. I have recoded length as count and it works.
I have a search funtion that simply returns a value at index in a list when given an index and a list. It works completly fine. It throws an error when the index is too large.
search [] _ = error "index too large"
search (a:_) 0 = a
search (_:a) b = search a (b - 1)
Now, I want a safeSearch function that return Nothing if the index is too large of if the list is empty. So I've simply done this.
safeSearch :: [a] -> Int -> Maybe a
safeSearch a b
| b < 0 || b >= count a = Nothing
| otherwise = Just (search a b)
And it works! ... as long as you don't try it on an empty list. Even with an index too large for the list length.
main = print(safeSearch [] 5)
This crashes and I really can't find any way around it.
Even though I don't think my second line is usefull (because if the list is empty, its count is 0 so we drop in the first guard and it should return Nothing?) its not working. Removing it does not solve the problem.
Here's the compile-time error.
main.hs:91:8: error:
* Ambiguous type variable `a0' arising from a use of `print'
prevents the constraint `(Show a0)' from being solved.
Probable fix: use a type annotation to specify what `a0' should be.
These potential instances exist:
instance Show Ordering -- Defined in `GHC.Show'
instance Show Integer -- Defined in `GHC.Show'
instance Show a => Show (Maybe a) -- Defined in `GHC.Show'
...plus 22 others
...plus 13 instances involving out-of-scope types
(use -fprint-potential-instances to see them all)
* In the expression: print (safeSearch [] 5)
In an equation for `main': main = print (safeSearch [] 5)
|
91 | main = print(safeSearch [] 5)
| ^^^^^^^^^^^^^^^^^^^^^^
exit status 1
Any idea? Something I'm missing or even completly going wrong? A concept I need to understand deeper?
The problem is a compile error. That means it isn't actually running your code and hitting your error "index too large" call; the compiler is rejecting your code before it can even try to run it. So you're looking in the wrong place if you're trying to change the code to avoid that.
What's actually happening is that safeSearch [] 5 is returning a value of type Maybe a, where a is the type of the elements in the list. But you didn't include any elements in the list, so there is nothing at all to decide what that type a is.
Your function safeSearch can work for any type, so that's actually fine. But you also try to print the Maybe a value. Using print requires a Show instance, and the instance for Maybe a requires there to also be a Show instance for a. Because there is nothing saying what type a is, the compiler has no way of finding the appropriate Show instance for it, so it has to abort compilation with an error.
The most straightforward way to solve it is to add a type annotation (either of the list, or the Maybe a value resulting from safeSearch). Something like this:
main = print (safeSearch ([] :: [Int]) 5)
(This is what the error message is talking about when it says an ambiguous type variable is preventing a Show constraint from being solved, and that the probable fix is to add a type annotation)
Note that this sort of issue is rarely a problem in "real" code. Normally if you have a list processed into another structure with a related type, you will have other code that does something with the elements or the result, or that produced the list (which isn't always empty). You wouldn't normally write a program that does nothing but process an always-empty list and print the result, except for these kinds of quick tests. So normally, when there is that other code as well, there will be enough context for the compiler to deduce the type of your empty list, and the extra type annotations will not be needed. So this kind of extra type annotation is not usually considered a serious burden that needs to be avoided, because they are hardly ever needed in "real" code. You just code as you want, and on the occassion that a compile error makes your realise you need an annotation you simply add it and move on.
If you do this kind of quick check in GHCi rather than writing a full program with a main function, then you also would not have needed the extra type annotation. This is because GHCi has the ExtendedDefaultRules language extension turned on by default. The "default rules" are conditions when GHC will choose a type for you instead of throwing an "ambiguous type" error. The normal default rules are pretty strict, and really only designed for defaulting numeric constraints (like Num a or Real a, etc). They do not apply to your original example. The "extended default rules" apply more often to avoid needing lots of type signatures in the interactive interpreter (since there you enter one line at a time, instead of the compiler being able to see the full module to infer types from usage). In this case entering print (safeSearch [] 5) at the interpreter prompt will work because it defaults the returned type to Maybe (), and it just so happens that printing Nothing :: Maybe () produces the same output as it would if it had correctly guessed the type you actually meant.
But in almost any real program, defaulting a type variable to () will be a stupid thing to do that makes things work less, so I do not recommend getting into the habit of enabling ExtendedDefaultRules in an actual module. Just add the type annotation, or do quick checks in the interpreter instead of in a module.
What you've written works great for any real-world use case. It only fails when someone writes print (safeSearch [] x) - a literal empty list, with no context to tell what result type is expected. It works fine if they pass in a nonempty list, or a list expression that happens to evaluate to an empty list, or if they use the result in a way that lets type inference figure out what was intended.
Further, there is really no way to write the function so that it works when passed a contextless empty list. The burden to make the types clear is necessarily placed on call sites, not the definition. The comments on your question have already shown how to do this; you only have to be that explicit when you're calling your function in a way that's obviously useless.
Is it possible to instruct GHC compiler to require that a specific value in code has invalid type, without ever using this value?
A contrived example is:
data Box a = Num a => Box a
goodBoxSample :: Box Int
goodBoxSample = Box 1
-- below definition and binding are expected to fail compilation
badBoxSample :: Box String
badBoxSample = Box "foo"
Is there a way to inform the compiler that badBoxSample is expected to fail (e.g. with some pragma, rather than commenting it out as a known bad sample), so that the code compiles only if badBoxSample fails to type-check?
The motivation here is the same as for writing a test (in some other language) with the code that is required to throw exception for the test case to pass.
Not possible. You're basically asking for a way to prove that there's no instance Num String, but Haskell operates under the open-world assumption, which means that someone could always declare such an instance.
Somebody posted a very helpful answer here, but before I managed to accept it was removed... Thank you anyway, and here it is for the reference:
https://hackage.haskell.org/package/generic-lens-2.0.0.0/docs/Data-Generics-Product-Fields.html
In short, the goal of testing failing types can be achieved with doctest, in the way the linked library does it.
In a Haskell source file, I can write
a = 1
and I had the impression that I have to write the same in GHCi as
let a = 1
, for a = 1 in GHCi gives a parse error on =.
Now, if I write
a = 1
a = 2
in a source file, I will get an error about Multiple declaration of a, but it is OK to write in GHCi:
let a = 1
let a = 2
Can someone help clarify the difference between the two styles?
Successive let "statements" in the interactive interpreter are really the equivalent of nested let expressions. They behave as if there is an implied in following the assignment, and the rest of the interpreter session comprises the body of the let. That is
>>> let a = 1
>>> let a = 1
>>> print a
is the same as
let a = 1 in
let a = 1 in
print a
There is a key difference in Haskell in having two definitions of the same name and identical scopes, and having two definitions of the same name in nested scopes. GHCi vs modules in a file isn't really related to the underlying concept here, but those situations do lead you to encounter problems if you're not familiar with it.
A let-expression (and a let-statement in a do block) creates a set of bindings with the same scope, not just a single binding. For example, as an expression:
let a = True
a = False
in a
Or with braces and semicolons (more convenient to paste into GHCi without turning on multi-line mode):
let { a = True; a = False} in a
This will fail, whether in a module or in GHCi. There cannot be a single variable a that is both True and False, and there can't be two separate variables named a in the same scope (or it would be impossible to know which one was being referred to by the source text a).
The variables in a single binding set are all defined "at once"; the order they're written in is not relevant at all. You can see this because it's possible to define mututally-recursive bindings that all refer to each other, and couldn't possibly be defined one-at-a-time in any order:
λ let a = True : b
| b = False : a
| in take 10 a
[True,False,True,False,True,False,True,False,True,False]
it :: [Bool]
Here I've defined an infinite list of alternating True and False, and used it to come up with a finite result.
A Haskell module is a single scope, containing all the definitions in the file. Exactly as in a let-expression with multiple bindings, all the definitions "happen at once"1; they're only in a particular order because writing them down in a file inevitably introduces an order. So in a module this:
a = True
a = False
gives you an error, as you've seen.
In a do-block you have let-statements rather than let-expressions.2 These don't have an in part since they just scope over the entire rest of the do-block.3 GHCi commands are very like entering statements in an IO do-block, so you have the same option there, and that's what you're using in your example.
However your example has two let-bindings, not one. So there are two separate variables named a defined in two separate scopes.
Haskell doesn't care (almost ever) about the written order of different definitions, but it does care about the "nesting order" of nested scopes; the rule is that when you refer to a variable a, you get the inner-most definition of a whose scope contains the reference.4
As an aside, hiding an outer-scope name by reusing a name in an inner scope is known as shadowing (we say the inner definition shadows the outer one). It's a useful general programming term to know, since the concept comes up in many languages.
So it's not that the rules about when you can define a name twice are different in GHCi vs a module, its just that the different context makes different things easier.
If you want to put a bunch of definitions in a module, the easy thing to do is make them all top-level definitions, which all have the same scope (the whole module) and so you get an error if you use the same name twice. You have to work a bit more to nest the definitions.
In GHCi you're entering commands one-at-a-time, and it's more work to use multi-line commands or braces-and-semicolon style, so the easy thing when you want to enter several definitions is to use several let statements, and so you end up shadowing earlier definitions if you reuse names.5 You have to more deliberately try to actually enter multiple names in the same scope.
1 Or more accurately the bindings "just are" without any notion of "the time at which they happen" at all.
2 Or rather: you have let-statements as well as let-expressions, since statements are mostly made up of expressions and a let-expression is always valid as an expression.
3 You can see this as a general rule that later statements in a do-block are conceptually nested inside all earlier statements, since that's what they mean when you translate them to monadic operations; indeed let-statements are actually translated to let-expressions with the rest of the do-block inside the in part.
4 It's not ambiguous like two variables with the same name in the same scope would be, though it is impossible to refer to any further-out definitions.
5 And note that anything you've previously defined referring to the name before the shadowing will still behave exactly as it did before, referring to the previous name. This includes functions that return the value of the variable. It's easiest to understand shadowing as introducing a different variable that happens to have the same name as an earlier one, rather than trying to understand it as actually changing what the earlier variable name refers to.
I am new in Haskell, I noticed # has specific role when I was reading a code, someone knows what does exactly do?
# is used in pattern matching for keeping the binding to the whole thing.
Example:
In x#(a:as), x will refer to the entire list a:as.
In the above example, you can get the whole list via x instead of typing yourself a:as again.
If I have a Name in TemplateHaskell and want to find out the value of the variable that it names, provided that the variable is declared as a literal, can this be done?
var = "foo"
-- Can `contentsOf` be defined?
$((contentsOf . mkName $ "var") >>= guard . (== "foo"))
In theory, yes. In practice, no.
Finding out stuff about existing names is done using reify :: Name -> Q Info, and for a definition like that you would get back a VarI value, which includes a Maybe Dec field. This would seem to suggest that you might in some cases be able to get the syntax tree for the declaration of the variable, which would allow you to extract the literal, however current versions of GHC always returns Nothing in this field, so you're out of luck for a pure TH solution.
However, TH does allow arbitrary IO actions to be run, so you could potentially work around this by loading and parsing the module yourself using something like haskell-src-exts, however I suspect that would be more trouble than it's worth.