Assume I have a block of data in Excel 2010, 100 rows by 3 columns.
Column C contains some duplicates, say it starts off as
1, 1, 1, 2, 3, 4, 5, ..... , 97, 98
Using VBA, I would like to remove the duplicate rows so I am left with 98 rows and 3 columns.
1, 2, 3, ..... , 97, 98
I know there is a button in Excel 2010 to do that but it inteferes with the rest of my code subsequently and gives incorrect results.
Furthermore, I would like to do it in arrays, then paste the results on the worksheet, rather than methods such as Application.Worksheetfunction.countif(.....
So something like:
Dim myarray() as Variant
myarray=cells(1,1).Currentregion.value
Dim a as Long
For a=1 to Ubound(myarray,1)
'something here to
Next a
I answered a similar question. Here is the code I used:
Dim dict As Object
Dim rowCount As Long
Dim strVal As String
Set dict = CreateObject("Scripting.Dictionary")
rowCount = Sheet1.Range("A1").CurrentRegion.Rows.Count
'you can change the loop condition to iterate through the array rows instead
Do While rowCount > 1
strVal = Sheet1.Cells(rowCount, 1).Value2
If dict.exists(strVal) Then
Sheet1.Rows(rowCount).EntireRow.Delete
Else
'if doing this with an array, then add code in the Else block
' to assign values from this row to the array of unique values
dict.Add strVal, 0
End If
rowCount = rowCount - 1
Loop
Set dict = Nothing
If you want to use an array, then loop through the elements with the same conditional (if/else) statements. If the item doesn't exist in the dictionary, then you can add it to the dictionary and add the row values to another array.
Honestly, I think the most efficient way is to adapt code you'd get from the macro recorder. You can perform the above function in one line:
Sheet1.UsedRange.RemoveDuplicates Columns:=3, Header:=xlYes
Function eliminateDuplicate(poArr As Variant) As Variant
Dim poArrNoDup()
dupArrIndex = -1
For i = LBound(poArr) To UBound(poArr)
dupBool = False
For j = LBound(poArr) To i
If poArr(i) = poArr(j) And Not i = j Then
dupBool = True
End If
Next j
If dupBool = False Then
dupArrIndex = dupArrIndex + 1
ReDim Preserve poArrNoDup(dupArrIndex)
poArrNoDup(dupArrIndex) = poArr(i)
End If
Next i
eliminateDuplicate = poArrNoDup
End Function
Simple function to remove duplicates from a 1D array
Private Function DeDupeArray(vArray As Variant) As Variant
Dim oDict As Object, i As Long
Set oDict = CreateObject("Scripting.Dictionary")
For i = LBound(vArray) To UBound(vArray)
oDict(vArray(i)) = True
Next
DeDupeArray = oDict.keys()
End Function
Edit:
With stdVBA (a library largely maintained by myself) you can use:
uniqueValues = stdEnumerator.CreateFromArray(myArray).Unique().AsArray()
An improvement on #RBILLC and #radoslav006 answers, this version searches the array with the duplicates removed for existing values so it searchs less values to find a duplicate.
Public Function RemoveDuplicatesFromArray(sourceArray As Variant)
Dim duplicateFound As Boolean
Dim arrayIndex As Integer, i As Integer, j As Integer
Dim deduplicatedArray() As Variant
arrayIndex = -1
deduplicatedArray = Array(1)
For i = LBound(sourceArray) To UBound(sourceArray)
duplicateFound = False
For j = LBound(deduplicatedArray) To UBound(deduplicatedArray)
If sourceArray(i) = deduplicatedArray(j) Then
duplicateFound = True
Exit For
End If
Next j
If duplicateFound = False Then
arrayIndex = arrayIndex + 1
ReDim Preserve deduplicatedArray(arrayIndex)
deduplicatedArray(arrayIndex) = sourceArray(i)
End If
Next i
RemoveDuplicatesFromArray = deduplicatedArray
End Function
Here's another approach for working with an array:
Sub tester()
Dim arr, arrout
arr = Range("A1").CurrentRegion.Value 'collect the input array
arrout = UniqueRows(arr) 'get only unique rows
Range("H1").Resize(UBound(arrout, 1), UBound(arrout, 2)).Value = arrout
End Sub
Function UniqueRows(arrIn As Variant) As Variant
Dim keys, rw As Long, col As Long, k, sep, arrout
Dim dict As Object, lbr As Long, lbc As Long, ubr As Long, ubc As Long, rwOut As Long
Set dict = CreateObject("scripting.dictionary")
'input array bounds
lbr = LBound(arrIn, 1)
ubr = UBound(arrIn, 1)
lbc = LBound(arrIn, 2)
ubc = UBound(arrIn, 2)
ReDim keys(lbr To ubr)
'First pass:collect all the row "keys" in an array
' and unique keys in a dictionary
For rw = lbr To ubr
k = "": sep = ""
For col = lbc To ubc
k = k & sep & arrIn(rw, col)
sep = Chr(0)
Next col
keys(rw) = k 'collect key for this row
dict(k) = True 'just collecting unique keys
Next rw
'Resize output array to # of unique rows
ReDim arrout(lbr To dict.Count + (lbr - 1), lbc To ubc)
rwOut = lbr
'Second pass: copy each unique row to the output array
For rw = lbr To ubr
If dict(keys(rw)) Then 'not yet output?
For col = lbc To ubc 'copying this row over to output...
arrout(rwOut, col) = arrIn(rw, col)
Next col
rwOut = rwOut + 1 'increment output "row"
dict(keys(rw)) = False 'flag this key as copied
End If
Next rw
UniqueRows = arrout
End Function
Answer from #RBILLC could be easily improved by adding an Exit For inside internal loop:
Function eliminateDuplicate(poArr As Variant) As Variant
Dim poArrNoDup()
dupArrIndex = -1
For i = LBound(poArr) To UBound(poArr)
dupBool = False
For j = LBound(poArr) To i
If poArr(i) = poArr(j) And Not i = j Then
dupBool = True
Exit For
End If
Next j
If dupBool = False Then
dupArrIndex = dupArrIndex + 1
ReDim Preserve poArrNoDup(dupArrIndex)
poArrNoDup(dupArrIndex) = poArr(i)
End If
Next i
eliminateDuplicate = poArrNoDup
End Function
I think this is really a case for using excel's native functions, at least for the initial array acquisition, and I don't think there's any simpler way to do it. This sub will output the unique values starting in column 5. I assumed that the target range was empty, so if it's not, change r and c.
Sub testUniques()
Dim arr, r As Long, c As Long, h As Long, w As Long
Dim this As Worksheet: Set this = ActiveSheet
arr = Application.Unique(this.Cells(1, 1).CurrentRegion)
r = 1
c = 5
h = UBound(arr, 1) - 1
w = UBound(arr, 2) - 1
this.Range(this.Cells(r, c), this.Cells(r + h, c + w)) = arr
End Sub
I know this is old, but here's something I used to copy duplicate values to another range so that I could see them quickly to establish data integrity for a database I was standing up from various spreadsheets. To make the procedure delete the duplicates it would be as simple as replacing the dupRng lines with Cell.Delete Shift:=xlToLeft or something to that effect.
I haven't tested that personally, but it should work.
Sub PartCompare()
Dim partRng As Range, partArr() As Variant, i As Integer
Dim Cell As Range, lrow As Integer
lrow = ThisWorkbook.Worksheets("Sheet1").Cells(Rows.Count, 1).End(xlUp).Row
i = 0
Set partRng = ThisWorkbook.Worksheets("Sheet1").Range(Cells(1, 1), Cells(lrow, 1))
For Each Cell In partRng.Cells
ReDim Preserve partArr(i)
partArr(i) = Cell.Value
i = i + 1
Next
Dim dupRng As Range, j As Integer, x As Integer, c As Integer
Set dupRng = ThisWorkbook.Worksheets("Sheet1").Range("D1")
x = 0
c = 1
For Each Cell In partRng.Cells
For j = c To UBound(partArr)
If partArr(j) = Cell.Value Then
dupRng.Offset(x, 0).Value = Cell.Value
dupRng.Offset(x, 1).Value = Cell.Address()
x = x + 1
Exit For
End If
Next j
c = c + 1
Next Cell
End Sub
Remove duplicates (plus related row items) from array
As OP wanted a VBA solution close to RemoveDuplicates, I demonstrate an array approach using a â–ºdictionary to get not the unique items per se (dict.keys), but the related row indices of first occurrencies (dict.items).
These are used to retain the whole row data via procedure LeaveUniques profiting from the advanced possibilities of the â–ºApplication.Index() function - c.f. Some peculiarities of the the Application.Index function
Example Call
Sub ExampleCall()
'[0]define range and assign data to 1-based 2-dim datafield
With Sheet1 ' << reference to your project's sheet Code(Name)
Dim lastRow: lastRow = .Cells(.Rows.Count, "C").End(xlUp).Row
Dim rng: Set rng = .Range("C2:E" & lastRow)
End With
Dim data: data = rng ' assign data to 2-dim datafield
'[1]get uniques (column 1) and remove duplicate rows
LeaveUniques data ' << call procedure LeaveUniques (c.f. RemoveDuplicates)
'[2]overwrite original range
rng.Clear
rng.Resize(UBound(data), UBound(data, 2)) = data
End Sub
Procedure LeaveUniques
Sub LeaveUniques(ByRef data As Variant, Optional ByVal colNum As Long = 1)
'Purpose: procedure removes duplicates of given column number in entire array
data = Application.Index(data, uniqueRowIndices(data, colNum), nColIndices(UBound(data, 2)))
End Sub
Help functions to LeaveUniques
Function uniqueRowIndices(data, Optional ByVal colNum As Long = 1)
'Purpose: return data index numbers referring to uniques
'a) set late bound dictionary to memory
Dim dict As Object
Set dict = CreateObject("Scripting.Dictionary")
'b) slice e.g. first data column (colNum = 1)
Dim colData
colData = Application.Index(data, 0, colNum)
'c) fill dictionary with uniques referring to first occurencies
Dim i As Long
For i = 1 To UBound(colData)
If Not dict.exists(dict(colData(i, 1))) Then dict(colData(i, 1)) = i
Next
'd) return 2-dim array of valid unique 1-based index numbers
uniqueRowIndices = Application.Transpose(dict.items)
End Function
Function nColIndices(ByVal n As Long)
'Purpose: return "flat" array of n column indices, e.g. for n = 3 ~> Array(1, 2, 3)
nColIndices = Application.Transpose(Evaluate("row(1:" & n & ")"))
End Function
Related
I want to remove predefined parts of the strings in the following table and save the values in an array. For some reason I get an error stating that I'm outside of the index. The lengths of the strings in the table can vary.
Sub New_1()
Dim i, j, k As Integer
Dim Endings As Variant
k = 0
Endings = Array("/A", "/BB", "/CCC", "/DDDD", "/EEEEE")
Dim ArrayValues() As Variant
With Worksheets("table1")
Dim lastRow As Long: lastRow = .Cells(.Rows.Count, 1).End(xlUp).Row
ReDim ArrayValues(lastRow)
For i = lastRow To 1 Step -1
For j = 0 To UBound(Endings)
ArrayValues(k) = Replace(.Range("A" & i), Endings(j), "")
k = k + 1
Next j
Next i
End With
End Sub
You're getting out of bounds because your ArrValues is filled up after not even 3 iterations of your "i" since you're adding up your k every j iterations
If you want an array of the cleaned up cells do this instead:
Sub New_1()
Dim i As Integer, j As Integer, k As Integer
Dim Endings As Variant
Dim ArrayValues() As Variant
Dim lastRow As Long
Endings = Array("/A", "/BB", "/CCC", "/DDDD", "/EEEEE")
With Worksheets("Blad6")
lastRow = .Cells(.Rows.Count, 1).End(xlUp).Row
ReDim ArrayValues(1 To lastRow) 'Then you don't have an empty ArrayValues(0)
For i = lastRow To 1 Step -1
For j = 0 To UBound(Endings)
If j = 0 Then
ArrayValues(i) = Replace(.Range("A" & i), Endings(j), "")
Else
ArrayValues(i) = Replace(ArrayValues(i), Endings(j), "")
End If
Next j
Next i
'Use Array here
End With
End Sub
If your intent is to create an array in which everything after the / is removed, this might be simpler, using the Split function; and also faster by storing the data to be split in a VBA array, in iterating through that array instead of the worksheet cells.
Option Explicit
Sub New_1()
'in VBA, Long is marginally more efficient than Integer
Dim k As Long, v As Variant
Dim dataArr As Variant
Dim ArrayValues() As Variant
With Worksheets("SHEET7")
'faster to loop through VBA array than worksheet cells
'Note that this will be a 2D array with dimensions starting at 1, not 0
dataArr = Range(.Cells(1, 1), .Cells(.Rows.Count, 1).End(xlUp))
End With
'This might be simpler
ReDim ArrayValues(1 To UBound(dataArr, 1))
k = 0
For Each v In dataArr
k = k + 1
ArrayValues(k) = Split(v, "/")(0)
Next v
End Sub
I am looking to create a function that will take 2 ranges (of the same dimensions), and take the difference between the cell from one range and the corresponding cell in the other range, and then create a new range with all of the differences. Are there any obvious problems? If i select and crtl + sht + enter, the range fills with "#Value!"
This is what i have so far (assuming the ranges are 4 by 4s):
Function Compare_Ranges(range_1 As Range, range_2 As Range) As Range
Dim output_data As Range
Dim i As Integer
Dim j As Integer
Dim col As String
For i = 1 To 4 'looping through the columns
col = Col_Letter(i)
For j = 1 To 4 'looping through the rows
Set output_data(Col_Letter(i) & j) = range_1(Col_Letter(i) & j).Value - range_2(Col_Letter(i) & j).Value
Next j
Next i
Compare_Ranges = output_data
End Function
Where the function Col_Letter returns the correponding letter of the alphabet:
Function Col_Letter(lngCol As Integer) As String
Dim vArr
vArr = Split(Cells(1, lngCol).Address(True, False), "$")
Col_Letter = vArr(0)
End Function
Here is a version of your function that takes two ranges of the same size and returns an array with the same dimensions that holds the difference between each corresponding cell in the input ranges.
Function Compare_Ranges(range_1 As Range, range_2 As Range) As Variant
Dim output_data() As Variant
Dim c As Integer
Dim r As Integer
ReDim output_data(1 To range_1.Rows.Count, 1 To range_1.Columns.Count)
For c = 1 To UBound(output_data, 2) 'looping through the columns
For r = 1 To UBound(output_data, 1) 'looping through the rows
output_data(r, c) = range_1.Cells(r, c).Value - range_2.Cells(r, c).Value
Next
Next
Compare_Ranges = output_data
End Function
If you want to put this in a cell, you will need to press CTRL+ENTER after entiering the following in a cell:
=Compare_Ranges(A1:A7,B1:B7)
The function returns an array, so if you want to catch it's results by calling it in another sub procedure, you need the following"
Dim data as variant
data = Compare_Ranges(range("a1:a7"),range("b1:b7"))
I am not sure if I got this right but I hope at least will help you to get there. The function takes any two ranges and calculate the difference between them and store the result into an array.
Function Compare_Ranges(range_1 As Range, range_2 As Range, ByVal y As Long) As Variant
Dim j As Long
Dim col As String
Dim one As Object, two As Object, three As Variant
Set one = CreateObject("Scripting.Dictionary")
Set two = CreateObject("Scripting.Dictionary")
j = 0
For Each cell In range_1
one.Add Key:=j, Item:=cell.Value
j = j + 1
Next
j = 0
For Each cell In range_2
two.Add j, cell.Value
j = j + 1
Next
ReDim three(0 To j) As Variant
For i = 0 To j
three(i) = one(i) - two(i)
Next
Compare_Ranges = three(y)
End Function
Then you can use the code in the sub to populate them in any range you like.
Sub result()
Dim one As Range, two As Range, three As Range
Dim j As Long
Set one = Worksheets("Sheet1").Range("A1:A4")
Set two = Worksheets("Sheet1").Range("B1:B4")
Set result = Worksheets("Sheet1").Range("D8:D11")
j = 0
For i = three.Row To ((result.Row + result.Rows.Count) - 1)
Worksheets("Sheet1").Cells(i, result.Column) = Compare_Ranges(one, two, j)
j = j + 1
Next
End Sub
having a hard time figuring out how to pivot a multi-column data set with duplicate rows into unique columns.
I have done research and found some VBA scripts to do this, but it is resulting in data missing when I do counts to confirm it pivoted correctly and ends up adding in duplicate columns (name/ rating year) over and over.
Anyone have any ideas? I'd do a pivot table, but I can't display the actual rating values in a pivot, only a sum/count/avg. etc...
You can do this easily in powerquery.
Highlight all your data, then insert>add table
data tab>get data from table
highlight right two columns>pivot columns
rating level as values
advanced options>don't aggregate
find and replace null with nothing
save and close
Pivot Data
The Code
Option Explicit
Sub pivotData()
' Define Source Range.
Dim rng As Range
Set rng = Range("A1").CurrentRegion
' Get unique values.
Dim prs As Variant
prs = getUniqueColumn1D(rng.Columns(1).Resize(rng.Rows.Count - 1).Offset(1))
Dim yrs As Variant
yrs = getUniqueColumn1D(rng.Columns(2).Resize(rng.Rows.Count - 1).Offset(1))
sort1D yrs
' Source Range to Source Array.
Dim Source As Variant
Source = rng.Value
' Define Target Array.
Dim Target As Variant
ReDim Target(1 To UBound(prs) - LBound(prs) + 2, _
1 To UBound(yrs) - LBound(yrs) + 2)
' Write from arrays to Target Array.
Target(1, 1) = Source(1, 1)
Dim n As Long
Dim i As Long
i = 1
For n = LBound(prs) To UBound(prs)
i = i + 1
Target(i, 1) = prs(n)
Next n
Dim j As Long
j = 1
For n = LBound(yrs) To UBound(yrs)
j = j + 1
Target(1, j) = yrs(n)
Next n
For n = 2 To UBound(Source, 1)
i = Application.Match(Source(n, 1), prs, 0) + 1
j = Application.Match(Source(n, 2), yrs, 0) + 1
Target(i, j) = Source(n, 3)
Next n
' Define Target Range.
Set rng = Range("E1").Resize(UBound(Target, 1), UBound(Target, 2))
' Write from Target Array to Target Range.
rng.Value = Target
' Inform user.
MsgBox "Data transferred.", vbInformation, "Success"
End Sub
' Returns the unique values from a column range.
Function getUniqueColumn1D(ColumnRange As Range, _
Optional ByVal Sorted As Boolean = False) _
As Variant
Dim Data As Variant
Data = ColumnRange.Columns(1).Value
With CreateObject("Scripting.Dictionary")
.CompareMode = vbTextCompare
Dim Key As Variant
Dim i As Long
For i = 1 To UBound(Data, 1)
Key = Data(i, 1)
If Not IsError(Key) And Not IsEmpty(Key) Then
.Item(Key) = Empty
End If
Next i
If .Count > 0 Then
getUniqueColumn1D = .Keys
End If
End With
End Function
' Sorts a 1D array only if it contains values of the same data type.
Sub sort1D(ByRef OneD As Variant, _
Optional ByVal Descending As Boolean = False)
With CreateObject("System.Collections.ArrayList")
Dim i As Long
For i = LBound(OneD) To UBound(OneD)
.Add OneD(i)
Next i
.Sort
If Descending Then
.Reverse
End If
OneD = .ToArray
End With
End Sub
I use the code hereunder to calculate max values as described in this post (vba max value of group of values). The code works great but once I have more than 65k lines I get a data type mismatch when trying to pase the array:
sht.Range(Cells(1, lColumn), Cells(last.Row, lColumn)).Value = Application.Index(groupsArray, , lColumn)
Could somebody help me to slice the array in chunks. I have tried to get it working myself but without any luck.
Sub FillGroupsMax()
Dim lColumn As Long
Dim sht As Worksheet
Dim groupsArray As Variant 'array with all group infomation
Dim groupsSeen As Variant 'array with group infomation already seen
Application.ScreenUpdating = False 'stop screen updating makes vba perform better
Set sht = ThisWorkbook.Worksheets("import")
Set last = sht.Range("A:A").Find("*", Cells(1, 1), searchdirection:=xlPrevious) 'last cell with value in column A
lColumn = sht.Cells(1, Columns.Count).End(xlToLeft).Column
groupsArray = sht.Range(Cells(1, 1), Cells(last.Row, lColumn))
'collect all the information on the Sheet into an array
'Improves performance by not visiting the sheet
For dRow = 2 To last.Row 'for each of the rows skipping header
'check if group as already been seen
If inArrayValue(Cells(dRow, 1).Value, groupsSeen) > 0 Then
'if it has been seen/calculated attribute value
'Cells(dRow, 4).Value = inArrayValue(Cells(dRow, 1).Value, groupsSeen)
groupsArray(dRow, lColumn) = inArrayValue(Cells(dRow, 1).Value, groupsSeen)
Else
'if it hasn't been seen then find max
'Cells(dRow, 4).Value = getMax(Cells(dRow, 1).Value, groupsArray)
groupsArray(dRow, lColumn) = getMax(Cells(dRow, 1).Value, groupsArray, lColumn)
'array construction from empty
If IsEmpty(groupsSeen) Then
ReDim groupsSeen(0)
'groupsSeen(0) = Array(Cells(dRow, 1).Value, Cells(dRow, 4).Value)
groupsSeen(0) = Array(groupsArray(dRow, 1), groupsArray(dRow, lColumn))
'attribute value to array
Else
ReDim Preserve groupsSeen(0 To UBound(groupsSeen) + 1)
groupsSeen(UBound(groupsSeen)) = Array(groupsArray(dRow, 1), groupsArray(dRow, lColumn))
End If
End If
Next
sht.Range(Cells(1, lColumn), Cells(last.Row, lColumn)).Value = Application.Index(groupsArray, , lColumn)
'reactivate Screen updating
Application.ScreenUpdating = True
End Sub
Function getMax(group As String, groupsArray As Variant, lColumn As Long) As Double
'for each in array
For n = 1 To UBound(groupsArray)
'if its the same group the Max we seen so far the record
If groupsArray(n, 1) = group And groupsArray(n, lColumn - 1) > maxSoFar Then
maxSoFar = groupsArray(n, lColumn - 1)
End If
Next
'set function value
getMax = maxSoFar
End Function
Function inArrayValue(group As String, groupsSeen As Variant) As Double
'set function value
inArrayValue = 0
'if array is empty then exit
If IsEmpty(groupsSeen) Then Exit Function
'for each in array
For n = 0 To UBound(groupsSeen)
'if we find the group
If groupsSeen(n)(0) = group Then
'set function value to the Max value already seen
inArrayValue = groupsSeen(n)(1)
'exit function earlier
Exit Function
End If
Next
End Function
You can write a helper function to use instead of Application.Index
Bonus - it will be much faster than using Index (>5x)
Sub Tester()
Dim arr, arrCol
arr = Range("A2:J80000").Value
arrCol = GetColumn(arr, 5) '<< get the fifth column
Range("L2").Resize(UBound(arrCol, 1), 1).Value = arrCol
End Sub
'extract a single column from a 1-based 2-D array
Function GetColumn(arr, colNumber)
Dim arrRet, i As Long
ReDim arrRet(1 To UBound(arr, 1), 1 To 1)
For i = 1 To UBound(arr, 1)
arrRet(i, 1) = arr(i, colNumber)
Next i
GetColumn = arrRet
End Function
EDIT - since QHarr asked about timing here's a basic example
Sub Tester()
Dim arr, arrCol, t, i as long
arr = Range("A2:J80000").Value
t = Timer
For i = 1 to 100
arrCol = GetColumn(arr, 5) '<< get the fifth column
Next i
Debug.print Timer - t '<<# of seconds for execution
End Sub
Below, whilst not as tidy as could be, is a way to process an array in chunks and Index to access a column and write out to the sheet.
I populated two columns (A:B) with data. Both had 132,000 rows, populated incrementally, with values from 1 to 132,000 in each column for my test run.
You can fiddle with cutOff to get the chunk size just below the point where the fail happens.
The code below is simply to demonstrate the principle of looping in batches, upto the set cutoff in each batch, until all rows have been processed.
Option Explicit
Public Sub WriteArrayToSheet()
Dim wb As Workbook
Dim ws As Worksheet
Set wb = ThisWorkbook
Set sht = wb.Worksheets("Sheet1") 'change as appropriate
Dim myArr() 'dynamic array
myArr = sht.Range("A1").CurrentRegion.Value 'you may want a more robust method
Dim cutOff As Long 'the max value - what ever it is before error occurs
cutOff = 1000
Dim totalRows As Long 'total rows in array read in from sheet
totalRows = UBound(myArr, 1)
Dim totalArraysNeeded As Long
'Determine how many lots of cutOff chunks there are in the total number of array rows
totalArraysNeeded = Application.WorksheetFunction.Ceiling(totalRows / cutOff, 1)
Dim rotations As Long 'number of times to loop original array to handle all rows
Dim rowCountTotal As Long
Dim rowCount As Long
Dim tempArr() 'this will hold the chunk of the original array
Dim rowCounter As Long
Dim lastRow As Long
Dim nextRow As Long
Dim i As Long
Dim j As Long
Dim numRows As Long
rotations = 1
Do While rotations < totalArraysNeeded
If rotations < totalArraysNeeded - 1 Then
ReDim tempArr(1 To cutOff, 1 To UBound(myArr, 2)) 'size chunk array
numRows = cutOff
Else
numRows = totalRows - rowCountTotal
ReDim tempArr(1 To numRows, 1 To UBound(myArr, 2)) 'size chunk array
End If
For i = 1 To numRows
rowCount = 1 'rows in this chunk looped
rowCountTotal = rowCountTotal + 1 'rows in original array looped
For j = LBound(myArr, 2) To UBound(myArr, 2)
tempArr(i, j) = myArr(rowCountTotal, j)
Next j
rowCount = rowCount + 1
Next i
With sht
lastRow = .Cells(.Rows.Count, "E").End(xlUp).Row 'Column where I am writing the sliced column out to
End With
If lastRow = 1 Then
nextRow = 1
Else
nextRow = lastRow + 1
End If
sht.Range("E" & nextRow).Resize(UBound(tempArr, 1), 1) = Application.Index(tempArr, , 1) 'write out to sheet
rotations = rotations + 1
Loop
End Sub
As #Tim suggested, the best way to slice a large array is use a loop to copy the column.
Though in your case, most of the processing time is spent on computing the maximum since your code is using a nested loop.
If you want to reduce significantly the processing time, then use a dictionary:
Sub Usage
GetMaxByGroupTo _
sourceGroups := ThisWorkbook.Range("Sheet1!A2:A100"), _
sourceValues := ThisWorkbook.Range("Sheet1!B2:B100"), _
target := ThisWorkbook.Range("Sheet1!C2")
End Sub
Sub GetMaxByGroupTo(sourceGroups As Range, sourceValues As Range, target As Range)
Dim dict As Object, groups(), values(), r As Long, max
Set dict = CreateObject("Scripting.Dictionary")
groups = sourceGroups.Value2
values = sourceValues.Value2
' store the maximum value of each group in a dictionary for an efficient lookup '
For r = Lbound(groups) to Ubound(groups)
max = dict(groups(r, 1))
If VarType(max) And values(r, 1) <= max Then Else dict(groups(r, 1)) = values(r, 1)
Next
' build and copy the result array to the sheet '
For r = Lbound(groups) to Ubound(groups)
values(r, 1) = dict(groups(r, 1))
Next
target.Resize(Ubound(groups), 1).Value2 = values
End Sub
I need to display two columns A and B listed in a combobox with unique values. So if two rows have the same A but not the same B, it is not a duplicate, both column need to be duplicate. I found a code that list one column (A) with unique values but I don't know how to add the column B.
There's a picture of my data and how I want to display it in my ComboBox.
Here's the code:
Private Sub UserForm_Initialize()
Dim Cell As Range
Dim col As Variant
Dim Descending As Boolean
Dim Entries As Collection
Dim Items As Variant
Dim index As Long
Dim j As Long
Dim RngBeg As Range
Dim RngEnd As Range
Dim row As Long
Dim Sorted As Boolean
Dim temp As Variant
Dim test As Variant
Dim Wks As Worksheet
Set Wks = ThisWorkbook.Worksheets("Sheet1")
Set RngBeg = Wks.Range("A3")
col = RngBeg.Column
Set RngEnd = Wks.Cells(Rows.Count, col).End(xlUp)
Set Entries = New Collection
ReDim Items(0)
For row = RngBeg.row To RngEnd.row
Set Cell = Wks.Cells(row, col)
On Error Resume Next
test = Entries(Cell.Text)
If Err = 5 Then
Entries.Add index, Cell.Text
Items(index) = Cell.Text
index = index + 1
ReDim Preserve Items(index)
End If
On Error GoTo 0
Next row
index = index - 1
Descending = False
ReDim Preserve Items(index)
Do
Sorted = True
For j = 0 To index - 1
If Descending Xor StrComp(Items(j), Items(j + 1), vbTextCompare) = 1 Then
temp = Items(j + 1)
Items(j + 1) = Items(j)
Items(j) = temp
Sorted = False
End If
Next j
index = index - 1
Loop Until Sorted Or index < 1
ComboBox1.List = Items
End Sub
Any clue? Thanks!
Try this code, please. It assumes that unique definition means pairs of values from the two columns, on the same row, to be unique:
Sub UnicTwoValInTwoColumns()
Dim sh As Worksheet, arr As Variant, arrFin As Variant, countD As Long
Dim lastRow As Long, i As Long, j As Long, k As Long, boolDupl As Boolean
Set sh = ActiveSheet 'use here your sheet
'supposing that last row in column A:A is the same in column B:B
'If not, the last row for B:B will be calculated and then the higher will be chosen:
lastRow = sh.Range("A" & Rows.Count).End(xlUp).Row
ReDim arrFin(1 To 2, 1 To lastRow) 'redim the final array for maximum possible number of elements
arr = sh.Range("A3:B" & lastRow).value 'pun in array the range to be analized
k = 1 'initialize the first array element number
For i = 1 To UBound(arr, 1) 'iterate between the array elements
boolDupl = False 'initialize the variable proving that the pair of data already in arrFin
For j = 1 To k 'iterate between the arrFin elements in order to check for duplicates
If arr(i, 1) & arr(i, 2) = arrFin(1, j) & arrFin(2, j) Then
boolDupl = True: Exit For 'if a duplicate is found the loop is exited
End If
Next j
If Not boolDupl Then 'load the arrFin only if a duplicate has not been found
arrFin(1, k) = arr(i, 1): arrFin(2, k) = arr(i, 2)
k = k + 1 'increment the (real) array number of elements
End If
Next
ReDim Preserve arrFin(1 To 2, 1 To k - 1) 'redim array at the real dimension (preserving values)
With Me.ComboBox1
.ColumnCount = 2 'be sure that combo has 2 columns to receive values
.List = WorksheetFunction.Transpose(arrFin) 'fill the combo with the array elements
End With
End Sub
You can paste the code in the form Initialize event, or let the Sub like it is, copy it in the form module and only call it from the event in discussion. I would suggest you to proceed in this las way. If you have (or will have) something else in the event, it would be simpler to identify a problem if it occurs, I think,