Round numbers based on ending digit in Excel - excel-formula

I need a formula in excel to round my price list.
Last digit of my price ends with
0-1-2 = 9 (Example: if price is $50-$51-$52 will be $49)(subtracts)
3 = 4 (Example: if price is $53 will become $54)(add 1)
4 = 4 (Example: if price is $54 will be the same $54)
5 = 5 (Example: if price is $55 will be the same $55)
6-7-8 = 9 (Example: if price is $56-$57-$58 will be $59)(adds)
9 = 9 (Example: if price is $59 will be the same $59)
My price starts from $8 to $1,106.
Thanks and I appreciate your help.

Assuming a price in cell P1:
=P1+CHOOSE(MOD(P1,10)+1,-1,-2,-3,1,0,0,3,2,1,0)
The MOD(x, y) function returns the remainder of x/y, so MOD(x, 10) gets you the last digit by itself.
The CHOOSE(i, c1, c2, c3, c4, ... ) function returns the item ci based on the given index i.
Add one to the result of the MOD() function to get an index between 1 and 10, and then use the index values to adjust the price according to your spec.

Related

Excel formula help - I have 14/28 day readings averaged per day which need to be recorded as daily readings

Dates when the data was read are shown on the date column on the left, then worked out a value per day shown in ET/DAY column.
To analyze monthly data etc etc I want daily data so every day has the ET/DAY value between the dates it was read and inserted in the et/day column.
I have entered in manually what I want in blue but need a formula to do this as too long to do all manually
You can do this with MATCH. With an ascending list, if you give the magic number 1 as the third parameter, it will show the last row number with a smaller or equal number.
Here it's matched 17 with 15 in column A and the result is 2, for row 2:
A
B
C
1
10
=MATCH(17,A:A,1) = 2
2
15
3
20
So for your data, you can match the daily dates with the column on the left, and feed the row number into INDEX to look up from the ET/Day column.
A
B
C
D
E
1
Date
ET/Day
Daily
ET/Day
2
05/Jan/1995
05/Jan/1995
=Index(B:B, Match(#D:D,A:A,1)) = #N/A
3
19/Jan/1995
3.00
06/Jan/1995
=Index(B:B, Match(#D:D,A:A,1)) = 3.00
4
02/Feb/1995
5.41
07/Jan/1995
=Index(B:B, Match(#D:D,A:A,1)) = 3.00
5
...
...
6
19/Jan/1995
=Index(B:B, Match(#D:D,A:A,1)) = 3.00
7
20/Jan/1995
=Index(B:B, Match(#D:D,A:A,1)) = 5.41
There's an inconsistency here with the 05 Jan rate but it should be good after that.

Excel formatting without VBA

So I have some results which may or may not have totals. In this case food. Each food is given an amount and a weight total. I have information below the results however which I do not want to shift. I would use a table however, if I hide rows, it shifts items up. If I sort the rows, the name of the food with no results will still show. Any idea how I could reformat my results into food with results only in a new referenced cell? I'm trying to automate this with no button pressing, and without using macro's/vba's. I could use something like =IF(ISBLANK(B21),"noResults",A21) but how could i list them all like my example blelow?
a1 b1 c1
Amount Weight
x Apples 5 10
x Oranges
x Peaches 6 10
x Lemons 2 10
x Tomatos
x Avacados 3 10
x
x
x xxxxdon't shift or move xxxxxxxxx
TO:
x g1 h1 i1
x Amount Weight
x Apples 5 10
x Peaches 6 10
x Lemons 2 10
x Avacados 3 10
x
xxxxxxxxdon't shift or move xxxxxxxxx
If you can add an ID column to the foods, you could do the following using the SMALL() function:
=IF(D3<>"",B3,"")
=IFERROR(SMALL($F$3:$F$8,ROW(C1)),"")
=VLOOKUP(H3,$B$3:$F$8,2,FALSE)
To Explain Further
The SMALL() function takes an array of numbers and will return the 1st smallest, 2nd smallest, or whatever smallest number you specify. Because this example only has Food names, I had to add an ID column (column B) to get an array of numbers.
Since we only want to view rows with data (amount & weight), I added another column ID Formula (column F) to only display the ID if the column has data.
Now that we are only displaying ID's with data, we can use the SMALL() function to get the 1st smallest ID still showing, then the 2nd smallest ID still showing, and so on... notice that I used the ROW() function to get 1,2,3...
Lastly, I used a simple VLOOKUP() to add in the Food, Amount, and Weight for the respective ID's.

CountifS + multiple criteria + distinct count

I'm looking for a formula calculating : distinct Count + multiple criteria
Countifs() does it but do not includes distinct count...
Here is an example.
I have a table on which I want to count the number of distinct items (column item) satisfying multiple conditions one column A and B : A>2 and B<5.
Image description here
Line Item ColA ColB
1 QQQ 3 4
2 QQQ 3 3
3 QQQ 5 4
4 TTT 4 4
5 TTT 2 3
6 TTT 0 1
7 XXX 1 2
8 XXX 5 3
9 zzz 1 9
Countifs works this way : COUNTIFS([ColumnA], criteria A, [ColumnB], criteria B)
COUNTIFS([ColumnA], > 2 , [ColumnB], < 5)
Returns : lines 1,2,4,5,8 => Count = 5
How can I add a distinct count function based on the Item Column ? :
lines 1,2 are on a unique item QQQ
lines 4,5 are on a unique item TTT
Line 8 is on a unique item XXX
Returns Count = 3
How can I count 3 ?!
Thanks
You can download the excel file # Excel file
Newer versions of Excel allow for this problem to be solved in a (relatively) more simple way. It certainly is easier to follow and understand, conceptually.
First, filter the table based on multiple criteria (join multiple with the *):
=FILTER(Table,(Table[Column A]>2)*(Table[Column B]<5))
Then, grab the "Item" column with INDEX:
=INDEX(FILTER(Table,(Table[Column A]>2)*(Table[Column B]<5)),,2)
Next, filter for unique entries:
=UNIQUE(INDEX(FILTER(Table,(Table[Column A]>2)*(Table[Column B]<5)),,2))
Finally, perform a count:
=COUNTA(UNIQUE(INDEX(FILTER(Table,(Table[Column A]>2)*(Table[Column B]<5)),,2)))
Ugly formula, but it works.
=SUM(((FREQUENCY(IF(C2:C10>2,1,0)*IF(D2:D10<5,1,0)*(COUNTIF(B2:B10,">"&B2:B10)+1),ROW(B2:B10)-ROW(B2)))*(ROW(B2:B11)-ROW(B2))>0)*1)
I'll start with the criteria IFS:
IF(C2:C10>2,1,0)*IF(D2:D10<5,1,0)
Gives an array of 1s and 0s for the rows that satisfy both criteria. ARRAY = {1;1;1;1;0;0;0;1;0} for your example.
Where B2:B10 is the Item column, the countif formula:
COUNTIF(B2:B10,">"&B2:B10)
returns {6;6;6;3;3;3;1;1;0} where the number equals the number of item values in B2:B10 alphabetically less than the tested item value.
QQQ goes to 6 [3"TTT", 2"XXX", 1"zzz"]
TTT goes to 3 [2"XXX", 1"zzz"]
XXX goes to 1 [1"zzz"]
zzz goes to 0 [0 less than "zzz"]
Need to add 1 to this array to make sure there are no 0 values:
{7;7;7;4;4;4;2;2;1}.
So when multiplying the criteria, and the countif statement:
(IF(C2:C10>2,1,0)*IF(D2:D10<5,1,0)*(COUNTIF(B2:B10,">"&B2:B10)+1)
You get ARRAY = {7;7;7;4;0;0;0;2;0}.
FREQUENCY(ARRAY,ROW(B2:B10)-ROW(B2))
ROW(B2:B10)-ROW(B2) sets the frequency bins to {0;1;2;3;4;5;6;7;8}. So the output of the frequency formula is {4;0;1;0;1;0;0;3;0;0} where the last 0 is for all values greater than 8.
((ROW(B2:B11)-ROW(B2)>0)*1) equals {0;1;1;1;1;1;1;1;1;1}. Multiplying ARRAY by this removes the 0 count at the start: ARRAY = {0;0;1;0;1;0;0;3;0;0}. [NOTE: B11 is lowest item column cell+1 because of the added array value from the frequency formula for values over 8]
(ARRAY)>0)*1 = {0;0;1;0;1;0;0;1;0;0}
SUM this = 3.
ctrl + shift + enter, because it's an array formula.
cmd + shift + enter for mac.
You could try this:
=SUMPRODUCT(1/COUNTIF(B2:B10,B2:B10))
Credit where credit due, however ... I found it over here:
https://exceljet.net/formula/count-unique-values-in-a-range-with-countif

SUMPRODUCT with a conditional with two ranges to calculate

To calculate a margin (JAN) I need to calculate:
sales(loja1)*margin(loja1)+sales(loja2)*margin(loja2)+sales(loja3)*margin(loja3)
/
(SUM(sales(loja1);sales(loja2);sales(loja3))
but I need to make this using a SUMPRODUCT. I tried:
=SUMPRODUCT((B3:B11="sales")*(C3:C11);(B3:B11="margin")*C3:C11))/SUMPRODUCT((B3:B11="sales")*(C3:C11))
but gave error!
When SUMPRODUCT is used to select cells within a range with text, the result for each evaluation will either be TRUE or FALSE. You will need to convert this to 1's or 0's by using '--' before the function so that when you multiply it by another range of cells, you will get the expected value
SUMPRODUCT Example: Sum of column B where column A is equal to 'Sales"
A B
1 | Sales 5
2 | Sales 6
3 | Margin 3
4 | Margin 2
Resulting Formula =SUMPRODUCT(--(A1:A4 = "Sales"),B1:B4)
How SUMPRODUCT works:
First, an array is returned that has True for each value in A1:A4 that equals "Sales", and False for each value that doesn't
Sales TRUE
Sales -> TRUE
Margin FALSE
Margin FALSE
Then the double negative converts TRUE to 1 and False to 0
1
1
0
0
Next, the first array (now the one with 1's and 0's) is multiplied by your second array (B1:B4) to get a new array
1st 2nd New Array
1 * 5 = 5
1 * 6 = 6
0 * 3 = 0
0 * 2 = 0
Finally all the values in the new array are summed to get your result (5+6+0+0 = 11)
Step 1:
For your scenario, you're going to need find the sales amount for each Location and multiply it by the margin for the corresponding location
location 1: sales * margin
=SUMPRODUCT(--(A3:A11="loja1"),--(B3:B11="venda"),(C3:C11)) * SUMPRODUCT(--(A3:A11="loja1"),--(B3:B11="margem"),(C3:C11))
You can do a similar formula for location 2 and 3 and then sum them all together.
Step: 2
To sum the sales for all locations, you can do a similar formula, again using the double negative, i.e. "--"
SUMPRODUCT(--(B3:B11="sales"),(C3:C11))
The resulting formula will be a bit long, but when you divide Step 1 by Step 2, you'll get the desired result

Excel nested IF formula

I want to set a formula that incorporates my school's attendance policy:
3 tardies = 1 unexcused absence
6 tardies = 2 unexcused absences
and so on
The cell must reference not only the cell with the Tardy count, but also the attendance worksheet in the same workbook, and must add the two values. For example, if the attendance page shows 1 unexcused absence and the tardy count shows 7 tardies, the formula needs to return 3.
This is what I've got:
=SUM(Attendance!O9+(IF(J4>=3,1,IF(J4>=6,2,IF(J4>=9,3,IF(J4>=12,4,))))))
It works for 4 tardies and 1 unexcused absence, but continues to return 2 for 7 tardies and 1 unexcused absence.
What am I missing?
Much easier than using If/Then:
=Attendance!O9+(Int(J4/3))
The Int function returns the floor integer of the calculation, J4/3. So, if J4 = 7, the result is 2. If J4=9, the result is 3, etc.
Your if statements are backwards you should check for bigger numbers first in this case otherwise the first if is always true. so 7 is falling true on >= 3 therefore you get 1 + 1 = 2
EDIT - a better way to do it would be to take your J4 divide it by 3 and return the value without the remainder
QUOTIENT(J4, 3)
The if part of your formula should be as follows
IF(J4<3,0,(IF(J4<6,1,(IF(J4<9,2,IF(J4<12,3,4))))))
Bear in mind that this formulae limits you to a maximum of 4 unexcused absences for tardies.
A better solution would be to use the QUOTIENT formula
= Attendance!O9 + QUOTIENT(J4,3)

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