What happens with Win32 IO Completion Port and synchronous appearing IO? - io

According to http://support.microsoft.com/kb/156932 calls to ReadFile can appear synchronous if certain conditions are met. For example if the target file is NTFS compressed. The article does not say anything about what happens if the file handle is accociated to an IOCP.
So what happens in this case when the file handle is associated with an IOCP? Will i still receive IO completion packets for this request or will the request carried out completely synchronous?
If so, i have to put the whole ReadFile call in a worker thread. The thread that issues the ReadFile call initially is not allowed to block. The reason i am considering IOCP is because putting the ReadFile call into a worker thread means a context switch to the worker thread which then blocks immediatly after on ReadFile.

Any overlapped operation that completes with ERROR_SUCCESS OR with ERROR_IO_PENDING will generate a completion packet. See tip 4 of this knowledge base article.
This assumes that you haven't enabled FILE_SKIP_COMPLETION_PORT_ON_SUCCESS on the handle in question, using SetFileCompletionNotificationModes(). If you HAVE enabled FILE_SKIP_COMPLETION_PORT_ON_SUCCESS then operations that complete with ERROR_SUCCESS will NOT generate a completion packet and you should do completion processing at the point where you issued the overlapped operation.

Related

Can two callbacks execute the code at the same time(Parrallely) or not?

I am doing an IO wait operation inside a for loop now the thing is when all of the operations terminates I want to send the response to the server. Now I was just wondering that suppose two IO operation terminates exactly at the same time now can they execute code at the same time(parallel) or will they execute serially?
As far as I know, as Node is Concurrent but not the Parallel language so I don't think they will execute at the same time.
node.js runs Javascript with a single thread. That means that two pieces of Javascript can never be running at the exact same moment.
node.js processes I/O completion using an event queue. That means when an I/O operation completes, it places an event in the event queue and when that event gets to the front of the event queue and the JS interpreter has finished whatever else it was doing, then it will pull that event from the event queue and call the callback associated with it.
Because of this process, even if two I/O operations finish at basically the same moment, one of them will put its completion event into the event queue before the other (access to the event queue internally is likely controlled by a mutex so one will get the mutex before the other) and that one's completion callback will get into the event queue first and then called before the other. The two completion callbacks will not run at the exact same time.
Keep in mind that more than one piece of Javascript can be "in flight" or "in process" at the same time if it contains non-blocking I/O operations or other asynchronous operations. This is because when you "wait" for an asynchronous operation to complete in Javscript, you return control back to the system and you then resume processing only when your completion callback is called. While the JS interpreter is waiting for an asynchronous I/O operation to complete and the associated callback to be called, then other Javascript can run. But, there's still only one piece of Javascript actually ever running at a time.
As far as I know, as Node is Concurrent but not the Parallel language so I don't think they will execute at the same time.
Yes, that's correct. That's not exactly how I'd describe it since "concurrent" and "parallel" don't have strict technical definitions, but based on what I think you mean by them, that is correct.
you can use Promise.all :
let promises = [];
for(...)
{
promises.push(somePromise); // somePromise represents your IO operation
}
Promise.all(promises).then((results) => { // here you send the response }
You don't have to worry about the execution order.
Node.js is designed to be single thread. So basically there is no way that 'two IO operation terminates exactly at the same time' could happen. They will just finish one by one.

thread with a forever loop with one inherently asynch operation

I'm trying to understand the semantics of async/await in an infinitely looping worker thread started inside a windows service. I'm a newbie at this so give me some leeway here, I'm trying to understand the concept.
The worker thread will loop forever (until the service is stopped) and it processes an external queue resource (in this case a SQL Server Service Broker queue).
The worker thread uses config data which could be changed while the service is running by receiving commands on the main service thread via some kind of IPC. Ideally the worker thread should process those config changes while waiting for the external queue messages to be received. Reading from service broker is inherently asynchronous, you literally issue a "waitfor receive" TSQL statement with a receive timeout.
But I don't quite understand the flow of control I'd need to use to do that.
Let's say I used a concurrentQueue to pass config change messages from the main thread to the worker thread. Then, if I did something like...
void ProcessBrokerMessages() {
foreach (BrokerMessage m in ReadBrokerQueue()) {
ProcessMessage(m);
}
}
// ... inside the worker thread:
while (!serviceStopped) {
foreach (configChange in configChangeConcurrentQueue) {
processConfigChange(configChange);
}
ProcessBrokerMessages();
}
...then the foreach loop to process config changes and the broker processing function need to "take turns" to run. Specifically, the config-change-processing loop won't run while the potentially-long-running broker receive command is running.
My understanding is that simply turning the ProcessBrokerMessages() into an async method doesn't help me in this case (or I don't understand what will happen). To me, with my lack of understanding, the most intuitive interpretation seems to be that when I hit the async call it would go off and do its thing, and execution would continue with a restart of the outer while loop... but that would mean the loop would also execute the ProcessBrokerMessages() function over and over even though it's already running from the invocation in the previous loop, which I don't want.
As far as I know this is not what would happen, though I only "know" that because I've read something along those lines. I don't really understand it.
Arguably the existing flow of control (ie, without the async call) is OK... if config changes affect ProcessBrokerMessages() function (which they can) then the config can't be changed while the function is running anyway. But that seems like it's a point specific to this particular example. I can imagine a case where config changes are changing something else that the thread does, unrelated to the ProcessBrokerMessages() call.
Can someone improve my understanding here? What's the right way to have
a block of code which loops over multiple statements
where one (or some) but not all of those statements are asynchronous
and the async operation should only ever be executing once at a time
but execution should keep looping through the rest of the statements while the single instance of the async operation runs
and the async method should be called again in the loop if the previous invocation has completed
It seems like I could use a BackgroundWorker to run the receive statement, which flips a flag when its job is done, but it also seems weird to me to create a thread specifically for processing the external resource and then, within that thread, create a BackgroundWorker to actually do that job.
You could use a CancelationToken. Most async functions accept one as a parameter, and they cancel the call (the returned Task actually) if the token is signaled. SqlCommand.ExecuteReaderAsync (which you're likely using to issue the WAITFOR RECEIVE is no different. So:
Have a cancellation token passed to the 'execution' thread.
The settings monitor (the one responding to IPC) also has a reference to the token
When a config change occurs, the monitoring makes the config change and then signals the token
the execution thread aborts any pending WAITFOR (or any pending processing in the message processing loop actually, you should use the cancellation token everywhere). any transaction is aborted and rolled back
restart the execution thread, with new cancellation token. It will use the new config
So in this particular case I decided to go with a simpler shared state solution. This is of course a less sound solution in principle, but since there's not a lot of shared state involved, and since the overall application isn't very complicated, it seemed forgivable.
My implementation here is to use locking, but have writes to the config from the service main thread wrapped up in a Task.Run(). The reader doesn't bother with a Task since the reader is already in its own thread.

Serial Dispatch Queue with Asynchronous Blocks

Is there ever any reason to add blocks to a serial dispatch queue asynchronously as opposed to synchronously?
As I understand it a serial dispatch queue only starts executing the next task in the queue once the preceding task has completed executing. If this is the case, I can't see what you would you gain by submitting some blocks asynchronously - the act of submission may not block the thread (since it returns straight-away), but the task won't be executed until the last task finishes, so it seems to me that you don't really gain anything.
This question has been prompted by the following code - taken from a book chapter on design patterns. To prevent the underlying data array from being modified simultaneously by two separate threads, all modification tasks are added to a serial dispatch queue. But note that returnToPool adds tasks to this queue asynchronously, whereas getFromPool adds its tasks synchronously.
class Pool<T> {
private var data = [T]();
// Create a serial dispath queue
private let arrayQ = dispatch_queue_create("arrayQ", DISPATCH_QUEUE_SERIAL);
private let semaphore:dispatch_semaphore_t;
init(items:[T]) {
data.reserveCapacity(data.count);
for item in items {
data.append(item);
}
semaphore = dispatch_semaphore_create(items.count);
}
func getFromPool() -> T? {
var result:T?;
if (dispatch_semaphore_wait(semaphore, DISPATCH_TIME_FOREVER) == 0) {
dispatch_sync(arrayQ, {() in
result = self.data.removeAtIndex(0);
})
}
return result;
}
func returnToPool(item:T) {
dispatch_async(arrayQ, {() in
self.data.append(item);
dispatch_semaphore_signal(self.semaphore);
});
}
}
Because there's no need to make the caller of returnToPool() block. It could perhaps continue on doing other useful work.
The thread which called returnToPool() is presumably not just working with this pool. It presumably has other stuff it could be doing. That stuff could be done simultaneously with the work in the asynchronously-submitted task.
Typical modern computers have multiple CPU cores, so a design like this improves the chances that CPU cores are utilized efficiently and useful work is completed sooner. The question isn't whether tasks submitted to the serial queue operate simultaneously — they can't because of the nature of serial queues — it's whether other work can be done simultaneously.
Yes, there are reasons why you'd add tasks to serial queue asynchronously. It's actually extremely common.
The most common example would be when you're doing something in the background and want to update the UI. You'll often dispatch that UI update asynchronously back to the main queue (which is a serial queue). That way the background thread doesn't have to wait for the main thread to perform its UI update, but rather it can carry on processing in the background.
Another common example is as you've demonstrated, when using a GCD queue to synchronize interaction with some object. If you're dealing with immutable objects, you can dispatch these updates asynchronously to this synchronization queue (i.e. why have the current thread wait, but rather instead let it carry on). You'll do reads synchronously (because you're obviously going to wait until you get the synchronized value back), but writes can be done asynchronously.
(You actually see this latter example frequently implemented with the "reader-writer" pattern and a custom concurrent queue, where reads are performed synchronously on concurrent queue with dispatch_sync, but writes are performed asynchronously with barrier with dispatch_barrier_async. But the idea is equally applicable to serial queues, too.)
The choice of synchronous v asynchronous dispatch has nothing to do with whether the destination queue is serial or concurrent. It's simply a question of whether you have to block the current queue until that other one finishes its task or not.
Regarding your code sample code, that is correct. The getFromPool should dispatch synchronously (because you have to wait for the synchronization queue to actually return the value), but returnToPool can safely dispatch asynchronously. Obviously, I'm wary of seeing code waiting for semaphores if that might be called from the main thread (so make sure you don't call getFromPool from the main thread!), but with that one caveat, this code should achieve the desired purpose, offering reasonably efficient synchronization of this pool object, but with a getFromPool that will block if the pool is empty until something is added to the pool.

Asynchronous IO: How does the thread get contacted after IO is complete?

So on an asynchronous framework such as Node or Netty, a worker thread can be given an IO job, which it initiates along with a callback. Then it returns and picks up a different task while that IO job, be it disk read, DB query, etc, runs.
My question is, after the IO is done, how is that event/callback picked up for further processing? I'm assuming in a synchronous operation, there is a thread right there waiting. But in an asynchronous environment, what picks up the completion of the IO, along with the response data? Does the worker thread periodically check for completion? Or does something register the completion event somehow with Node or Netty?
Sorry for lumping Netty and Node together, I'm assuming they do this similarly.
In Netty, any IO operation is asynchronous,and the read or write method will return a Future Object which can add Listener, after future is done , the listener will call back. In listener, you can do anything you would like.

Will select() block if called while there is still data to be read?

If a socket has data to be read and the select() function is called, will select():
Return immediately, indicating the socket is ready for reading, or
Block until more data is received on the socket
??
It can easily be tested, but I assure you select() will never block if there is data already available to read on one of the readfds. If it did block in that case, it wouldn't be very useful for programming with non-blocking I/O. Take the example where you are looping on select(), you see that there is data to be read, and you read it. Then while you are processing the data read, more data comes in. When you return to select() it blocks, waiting for more data. However your peer on the other side of the connection is waiting for a response to the data already sent. Your program ends up blocking forever. You could work around it with timeouts and such, but the whole point is to make non-blocking I/O efficient.
If an fd is at EOF, select() will never block even if called multiple times.
man 2 select seems to answer this question pretty directly:
select() and pselect() allow a program to monitor multiple file descriptors, waiting until one or more of the file descriptors become "ready" for some class of I/O operation (e.g., input possible). A file descriptor is considered ready if it is possible to perform the corresponding I/O operation (e.g., read(2)) without blocking.
So at least according to the manual, it would return immediately if there is any data available.

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