This question already has answers here:
how to find files containing a string using egrep
(7 answers)
Closed 8 years ago.
I am trying to search All .PHP files or ALL .SH files for any reference that contains:
'into tbl_free_minutes_mar'
I have command line access to the server but the files may be scattered in different directories.
For all directories everywhere,
find / -type f \( -name '*.php' -o -name '*.sh' \) \
-exec fgrep 'into tbl_free_minutes_mar' {} \+
For fewer directories elsewhere, just give a list of paths instead of /. To just list the matching files, try fgrep -l. If your file names might not always match the wildcards in the -name conditions, maybe scan all files.
find / -type f \( -name \*.php -o -name \*.sh \) -exec grep 'into tbl_free_minutes_mar' {} /dev/null \;
Change find / ... to to something less all-encompassing if you know the general area that you want to look in, e.g. find /home ...
Provided /base/path is the path where you want to start looking this will get you a list of files:
find /base/path -type f -iregex '.*\.\(php\|sh\)$' -exec grep -l 'into tbl_free_minutes_mar' '{}' \;
Related
The find command is really useful to identify files with a given name that also contain a string somewhere inside of them.
For instance lets say I'm looking for the string "pacf(" in an R markdown file somewhere in my current directory.
find . -name "*.Rmd" -exec grep -ls "pacf(" {} \;
I get useful results.
However, sometimes, I'm not sure if the file I am looking for is an .R file or a .Rmd file so I might also run.
find . -name "*.R" -exec grep -ls "pacf(" {} \;
And lets say there are no R files containing this string so that returns nothing.
One think I'd like to do is look in both .R and .Rmd files for this string. I would think that I could run
find . -name "*.Rmd" -o -name "*.R" -exec grep -ls "pacf(" {} \
But that returns no results.
However if I run
find . -name "*.R" -o -name "*.Rmd" -exec grep -ls "pacf(" {} \
I get the same results as just searching the .Rmd files. So it seems like it is only running the stuff in exec for the second set of files.
Is there a way I could change these commands to look through both the .R and .Rmd files at once?
Add parentheses '()'
find . \( -name '*.R' -o -name '*.Rmd' \) -exec grep -ls "pacf(" {} \;
you can pass "*[.Rmd]" for -name
like this
find . -name "*[.Rmd]" -exec grep -ls "pacf(" {} \;
This question already has answers here:
How do I exclude a directory when using `find`?
(46 answers)
Closed 1 year ago.
Searching whole system using:
find / -type f -size +100M -exec ls -lh {} \; | awk '{ print $9 "|| Size : " $5 }'
How can I omit a directory? I see -prune -o, but I am not sure how to format the option.
find / -path /path/to/ommit -prune -o -type f -size +100M -exec ...
# ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
From man:
To ignore a whole directory tree, use -prune rather
than checking every file in the tree. For example, to skip the
directory src/emacs and all files and directories under it,
and print the names of the other files found, do something like
this:
find . -path ./src/emacs -prune -o -print
Note that the pattern match test applies to the whole file name,
starting from one of the start points named on the command line.
find /home/imk-prac/ \( -type f -size -13c -name '*\?plik\?*' \) -o\( -type d -name '\[Kolo1\]*' \)2> /dev/nul;
This command counts normal files which has less than 13 symbols and contains a sequence of symbols ?plik?.
I want to add looking for files which were modified less than 30 days and I wrote this command:
find /home/imk-prac/ -type f -mtime -30 -exec ls -l {} \; > /dev/null
I don't know how to combine this two commands in to one.
I wanted to add looking for files with specified quantity of symbols and I found this command:
grep -Po '(^|\s)\S{64}(\s|$)' file
But there is the same problem or even worse, because of grep command.
Thanks for your time and I hope you will help me to figure it out ;)
This question already has answers here:
How to insert strings containing slashes with sed? [duplicate]
(11 answers)
Closed 5 years ago.
i need a quick command (linux or windows) to replace every \\ with a /, and all tries with sed failed because of the /.
(I already tried find . -name '*.*' -exec sed -i 's/\\///g' {} \;, but i think it failed with the "/".
find . -name '*.*' -type f -exec sed -i 's:\\\\:/:g' {} \;
You need to escape each backslash, and using a colon or comma as separators is generally recommended when making replacements with forward-slash. However, escaping the forward slash works too:
find . -name '*.*' -type f -exec sed -i 's/\\\\/\//g' {} \;
As pointed out in comments the OS module is probably what you really need to look at.
Edit: thanks to #tripleee for reminding me of the -type f line, which limits it to files, rather than including the current directory.
Also, I copied the syntax *.* from the OP but in general it isn't helpful. * alone is usually what you want, since files aren't guaranteed to have a dot in their name. Assuming you were happy to include files not containing a dot, the simplest thing to do here is have no -name at all:
find . -type f -exec sed -i 's:\\\\:/:g' {} \;
I would like to recursively find all files contained into a directory that has name “name1” or name “name2”
for instance:
structure/of/dir/name1/file1.a
structure/of/dir/name1/file2.b
structure/of/dir/name1/file3.c
structure/of/dir/name1/subfolder/file1s.a
structure/of/dir/name1/subfolder/file2s.b
structure/of/dir/name2/file1.a
structure/of/dir/name2/file2.b
structure/of/dir/name2/file3.c
structure/of/dir/name2/subfolder/file1s.a
structure/of/dir/name2/subfolder/file2s.b
structure/of/dir/name3/name1.a ←this should not show up in the result
structure/of/dir/name3/name2.a ←this should not show up in the result
so when I start my magic command the expected output should be this and only this:
structure/of/dir/name1/file1.a
structure/of/dir/name1/file2.b
structure/of/dir/name1/file3.c
structure/of/dir/name2/file1.a
structure/of/dir/name2/file2.b
structure/of/dir/name2/file3.c
I scripted something but it does not work because it search within the files and not only folder names:
for entry in $(find $SEARCH_DIR -type f | grep 'name1\|name2');
do
echo "FileName: $(basename $entry)"
done
If you can use the -regex option, avoiding subfolders with [^/]:
~$ find . -type f -regex ".*name1/[^/]*" -o -regex ".*name2/[^/]*"
./structure/of/dir/name2/file1.a
./structure/of/dir/name2/file3.c
./structure/of/dir/name2/subfolder
./structure/of/dir/name2/file2.b
./structure/of/dir/name1/file1.a
./structure/of/dir/name1/file3.c
./structure/of/dir/name1/file2.b
I'd use -path and -prune for this, since it's standard (unlike -regex which is GNU specific).
find . \( -path "*/name1/*" -o -path "*/name2/*" \) -prune -type f -print
But more importantly, never do for file in $(find...). Use finds -exec or a while read loop instead, depending on what you really need to with the matching files. See UsingFind and BashFAQ 20 for more on how to handle find safely.