I'm trying to find a better understanding of Qt signals and slots in conjunction with threads. So I tried this minimal application:
foo.h:
#include <QObject>
class A : public QObject {
Q_OBJECT
public:
void doit();
signals:
void x();
};
class B : public QObject {
Q_OBJECT
public slots:
void h();
};
foo.cpp:
#include "foo.h"
#include <QThread>
#include <QCoreApplication>
void B::h() {
qDebug("[%d] B::h() here!", (int) QThread::currentThreadId());
QCoreApplication::instance()->quit();
}
void A::doit() {
qDebug("[%d] emitting...", (int) QThread::currentThreadId());
emit x();
}
int main(int argc, char* argv[]) {
QCoreApplication app(argc, argv);
A a;
B b;
QObject::connect(&a, SIGNAL(x()), &b, SLOT(h()));
QThread t;
t.start();
b.moveToThread(&t);
a.doit();
t.wait();
return 0;
}
Everything is fine, only the t.wait() at the end never returns. My understanding is calling quit() should stop the event loop, which means exec() should return and so should run() and thread execution should stop. Am I missing something?
QCoreApplication::quit () is not stated as thread-safe method so you can't call it from another thread. Your application can crash or get an undefined behavior(UB).
t.wait() will never return because the running thread is constantly waiting for events. To stop the thread you must call QThread::quit () [slot]
If you want to quit the application after the work is done you have to emit a signal, which is connected to QCoreApplication::quit () [static slot]
If you want to stop the worker thread after the work is done you also have to emit a signal, connected to void QThread::quit () [slot]
Added: Threads, Events and QObjects for further reading
Important notice: You must call QCoreApplication::exec() in order to be able to use signal & slot mechanism between threads, queued connections.
From Qt QThread doc:
Each QThread can have its own event loop. You can start the event loop
by calling exec(); you can stop it by calling exit() or quit(). Having
an event loop in a thread makes it possible to connect signals from
other threads to slots in this thread, using a mechanism called queued
connections. It also makes it possible to use classes that require the
event loop, such as QTimer and QTcpSocket, in the thread. Note,
however, that it is not possible to use any widget classes in the
thread.
Doc for Qt::QueuedConnection:
The slot is invoked when control returns to the
event loop of the receiver's thread. The slot is executed in the
receiver's thread.
It seems that there are many things wrong with your code.
You don't call app.exec(). Meaning that there is no main event loop. The x signal of A will not be emitted.
By default, a thread has it's own even loop in Qt (at least since few years). Then starting a thread call Qthread::run(), and the event loop is started. That's where your thread is, not in t.wait().
What is the purpose of t.wait()? I believe you are misusing it.
(If everything else was fine), in B::h() you are stopping the main thread from the other thread. Is that what you wanted to do?
So my first advice will be to add app.exec(), see how it behaves. Explain what your are trying to do, and rewrite something else. Because you're doing it wrong
Related
Using C++11 STL with VS2013 to implementing a asynchronous print class.
Failing to get thread.join() returns with no deadlocking.
I am trying to debug and finally find this issue may caused by global/local class variable declaration. Here is the details and I dont know why it happened?
#include <iostream>
#include <string>
#include <chrono>
#include <mutex>
#include <thread>
#include <condition_variable>
#include "tbb/concurrent_queue.h"
using namespace std;
class logger
{
public:
~logger()
{
fin();
}
void init()
{
m_quit = false;
m_thd = thread(bind(&logger::printer, this));
//thread printer(bind(&logger::printer, this));
//m_thd.swap(printer);
}
void fin()
{
//not needed
//unique_lock<mutex> locker(m_mtx);
if (m_thd.joinable())
{
m_quit = true;
write("fin");
//locker.unlock();
m_thd.join();
}
}
void write(const char *msg)
{
m_queue.push(msg);
m_cond.notify_one();
}
void printer()
{
string msgstr;
unique_lock<mutex> locker(m_mtx);
while (1)
{
if (m_queue.try_pop(msgstr))
cout << msgstr << endl;
else if (m_quit)
break;
else
m_cond.wait(locker);
}
cout << "printer quit" <<endl;
}
bool m_quit;
mutex m_mtx;
condition_variable m_cond;
thread m_thd;
tbb::concurrent_queue<string> m_queue;
};
For more convenience I placed thread.join into class's destructor in order to ensure the m_thread can be quit normally.
I test the whole class and something wrong occured.
m_thd.join() never return when class logger declared as a global var
like this:
logger lgg;
void main()
{
lgg.init();
for (int i = 0; i < 100; ++i)
{
char s[8];
sprintf_s(s, 8, "%d", i);
lgg.write(s);
}
//if first call lgg.fin() here, m_thd can be joined normally
//lgg.fin();
system("pause");
//dead&blocked here and I observed that printer() finished successfully
}
If class logger declared as a local variable, it seems everything works well.
void main()
{
logger lgg;
lgg.init();
for (int i = 0; i < 100; ++i)
{
char s[8];
sprintf_s(s, 8, "%d", i);
lgg.write(s);
}
system("pause");
}
update 2015/02/27
I tried to delete std::cout in printer(), but program still blocked at same place, seems it is not the std::cout problem?
Deleting supernumerary lock in fin()
Globals and statics are constructed and destructed just prior or post to DllMain getting called respectively for DLL_PROCESS_ATTACH and DLL_PROCESS_DETACH. The problem with this is that it occurs inside the loader lock. Which is the most dangerous place on the planet to be if dealing with kernel objects as it may cause deadlock, or the application to randomly crash. As such you should never use thread primitives as statics on windows EVER. Thus dealing with threading in a destructor of a global object is basically doing the exact things we're warned not to do in DllMain.
To quote Raymond Chen
The building is being demolished. Don't bother sweeping the floor and emptying the trash cans and erasing the whiteboards. And don't line up at the exit to the building so everybody can move their in/out magnet to out. All you're doing is making the demolition team wait for you to finish these pointless housecleaning tasks.
and again:
If your DllMain function creates a thread and then waits for the thread to do something (e.g., waits for the thread to signal an event that says that it has finished initializing, then you've created a deadlock. The DLL_PROCESS_ATTACH notification handler inside DllMain is waiting for the new thread to run, but the new thread can't run until the DllMain function returns so that it can send a new DLL_THREAD_ATTACH notification.
This deadlock is much more commonly seen in DLL_PROCESS_DETACH, where a DLL wants to shut down its worker threads and wait for them to clean up before it unloads itself. You can't wait for a thread inside DLL_PROCESS_DETACH because that thread needs to send out the DLL_THREAD_DETACH notifications before it exits, which it can't do until your DLL_PROCESS_DETACH handler returns.
This also occurs even when using an EXE because the visual C++ runtime cheats and registers its constructors and destructors with the C runtime to be run when the runtime is loaded or unloaded, thus ending up with the same issue:
The answer is that the C runtime library hires a lackey. The hired lackey is the C runtime library DLL (for example, MSVCR80.DLL). The C runtime startup code in the EXE registers all the destructors with the C runtime library DLL, and when the C runtime library DLL gets its DLL_PROCESS_DETACH, it calls all the destructors requested by the EXE.
I'm wondering how you're using m_mtx. The normal pattern is that both thread lock it and both threads unlock it. But fin() fails to lock it.
Similarly unexpected is m_cond.wait(m_mtx). This would release the mutex, except that it isn't locked in the first place!
Finally, as m_mtx isn't locked, I don't see how m_quit = true should become visible in m_thd.
One problem you have is that std::condition_variable::notify_one is called while the same std::mutex that the waiting thread is holding, is held (happens when logger::write is called by logger::fin).
This causes the notified thread to immediately block again, and hence the printer thread will block possibly indefinitely upon destruction (or until spurious wakeup).
You should never notify while holding the same mutex as the waiting thread(s).
Quote from en.cppreference.com:
The notifying thread does not need to hold the lock on the same mutex as the one held by the waiting thread(s); in fact doing so is a pessimization, since the notified thread would immediately block again, waiting for the notifying thread to release the lock.
I am not sure if my question is correct, but I have the following example, where the main thread creates two additional threads.
Since I am not using join command at the end of the main, it will continue execution and in the same time, the two created threads will work in parallel. But since the main is terminated before they finish their execution, I am getting the following output:
terminate called without an active exception
Aborted (core dumped)
Here's the code:
#include <iostream> // std::cout
#include <thread> // std::thread
#include <chrono>
void foo()
{
std::chrono::milliseconds dura( 2000 );
std::this_thread::sleep_for( dura );
std::cout << "Waited for 2Sec\n";
}
void bar(int x)
{
std::chrono::milliseconds dura( 4000 );
std::this_thread::sleep_for( dura );
std::cout << "Waited for 4Sec\n";
}
int main()
{
std::thread first (foo);
std::thread second (bar,0);
return 0;
}
So my question is how to keep these two threads working even if the main thread terminated?
I am asking this because in my main program, I have an event handler ,and for each event I create a corresponding thread. But the main problem when the handler creates a new thread, the handler will continue execution. Until it is destroyed which will cause also the newly created thread to be destroyed. So my question is how to keep the thread alive in this case?
Also if I use a join it will convert back to serialization.
void ho_commit_indication_handler(message &msg, const boost::system::error_code &ec)
{
.....
}
void event_handler(message &msg, const boost::system::error_code &ec)
{
if (ec)
{
log_(0, __FUNCTION__, " error: ", ec.message());
return;
}
switch (msg.mid())
{
case n2n_ho_commit:
{
boost::thread thrd(&ho_commit_indication_handler, boost::ref(msg), boost::ref(ec));
}
break
}
};
Thanks a lot.
Keeping the threads alive is a bad idea, because it causes a call to std::terminate. You should definitively join the threads:
int main()
{
std::thread first (foo);
std::thread second (bar, 0);
first.join();
second.join();
}
An alternative is to detach the threads. However you still need to assert that the main thread lives longer (by e.g. using a mutex / condition_variable).
This excerpt from the C++11 standard is relevant here:
15.5.1 The std::terminate() function [except.terminate]
1 In some situations exception handling must be abandoned for less subtle error
handling techniques. [ Note: These situations are:
[...]
-- when the destructor or the copy assignment operator is invoked on an
object of type std::thread that refers to a joinable thread
Hence, you have to call either join or detach on threads before scope exit.
Concerning your edit: You have to store the threads in a list (or similar) and wait for every one of them before main is done. A better idea would be to use a thread pool (because this limits the total number of threads created).
I'm trying to use a C++11 std::condition_variable, but when I try to lock the unique_lock associated with it from a second thread I get an exception "Resource deadlock avoided". The thread that created it can lock and unlock it, but not the second thread, even though I'm pretty sure the unique_lock shouldn't be locked already at the point the second thread tries to lock it.
FWIW I'm using gcc 4.8.1 in Linux with -std=gnu++11.
I've written a wrapper class around the condition_variable, unique_lock and mutex, so nothing else in my code has direct access to them. Note the use of std::defer_lock, I already fell in to that trap :-).
class Cond {
private:
std::condition_variable cCond;
std::mutex cMutex;
std::unique_lock<std::mutex> cULock;
public:
Cond() : cULock(cMutex, std::defer_lock)
{}
void wait()
{
std::ostringstream id;
id << std::this_thread::get_id();
H_LOG_D("Cond %p waiting in thread %s", this, id.str().c_str());
cCond.wait(cULock);
H_LOG_D("Cond %p woke up in thread %s", this, id.str().c_str());
}
// Returns false on timeout
bool waitTimeout(unsigned int ms)
{
std::ostringstream id;
id << std::this_thread::get_id();
H_LOG_D("Cond %p waiting (timed) in thread %s", this, id.str().c_str());
bool result = cCond.wait_for(cULock, std::chrono::milliseconds(ms))
== std::cv_status::no_timeout;
H_LOG_D("Cond %p woke up in thread %s", this, id.str().c_str());
return result;
}
void notify()
{
cCond.notify_one();
}
void notifyAll()
{
cCond.notify_all();
}
void lock()
{
std::ostringstream id;
id << std::this_thread::get_id();
H_LOG_D("Locking Cond %p in thread %s", this, id.str().c_str());
cULock.lock();
}
void release()
{
std::ostringstream id;
id << std::this_thread::get_id();
H_LOG_D("Releasing Cond %p in thread %s", this, id.str().c_str());
cULock.unlock();
}
};
My main thread creates a RenderContext, which has a thread associated with it. From the main thread's point of view, it uses the Cond to signal the rendering thread to perform an action and can also wait on the COnd for the rendering thread to complete that action. The rendering thread waits on the Cond for the main thread to send rendering requests, and uses the same Cond to tell the main thread it's completed an action if necessary. The error I'm getting occurs when the rendering thread tries to lock the Cond to check/wait for render requests, at which point it shouldn't be locked at all (because the main thread is waiting on it), let alone by the same thread. Here's the output:
DEBUG: Created window
DEBUG: OpenGL 3.0 Mesa 9.1.4, GLSL 1.30
DEBUG: setScreen locking from thread 140564696819520
DEBUG: Locking Cond 0x13ec1e0 in thread 140564696819520
DEBUG: Releasing Cond 0x13ec1e0 in thread 140564696819520
DEBUG: Entering GLFW main loop
DEBUG: requestRender locking from thread 140564696819520
DEBUG: Locking Cond 0x13ec1e0 in thread 140564696819520
DEBUG: requestRender waiting
DEBUG: Cond 0x13ec1e0 waiting in thread 140564696819520
DEBUG: Running thread 'RenderThread' with id 140564575180544
DEBUG: render thread::run locking from thread 140564575180544
DEBUG: Locking Cond 0x13ec1e0 in thread 140564575180544
terminate called after throwing an instance of 'std::system_error'
what(): Resource deadlock avoided
To be honest I don't really understand what a unique_lock is for and why condition_variable needs one instead of using a mutex directly, so that's probably the cause of the problem. I can't find a good explanation of it online.
Foreword: An important thing to understand with condition variables is that they can be subject to random, spurious wake ups. In other words, a CV can exit from wait() without anyone having called notify_*() first. Unfortunately there is no way to distinguish such a spurious wake up from a legitimate one, so the only solution is to have an additional resource (at the very least a boolean) so that you can tell whether the wake up condition is actually met.
This additional resource should be guarded by a mutex too, usually the very same you use as a companion for the CV.
The typical usage of a CV/mutex pair is as follows:
std::mutex mutex;
std::condition_variable cv;
Resource resource;
void produce() {
// note how the lock only protects the resource, not the notify() call
// in practice this makes little difference, you just get to release the
// lock a bit earlier which slightly improves concurrency
{
std::lock_guard<std::mutex> lock(mutex); // use the lightweight lock_guard
make_ready(resource);
}
// the point is: notify_*() don't require a locked mutex
cv.notify_one(); // or notify_all()
}
void consume() {
std::unique_lock<std::mutex> lock(mutex);
while (!is_ready(resource))
cv.wait(lock);
// note how the lock still protects the resource, in order to exclude other threads
use(resource);
}
Compared to your code, notice how several threads can call produce()/consume() simultaneously without worrying about a shared unique_lock: the only shared things are mutex/cv/resource and each thread gets its own unique_lock that forces the thread to wait its turn if the mutex is already locked by something else.
As you can see, the resource can't really be separated from the CV/mutex pair, which is why I said in a comment that your wrapper class wasn't really fitting IMHO, since it indeed tries to separate them.
The usual approach is not to make a wrapper for the CV/mutex pair as you tried to, but for the whole CV/mutex/resource trio. Eg. a thread-safe message queue where the consumer threads will wait on the CV until the queue has messages ready to be consumed.
If you really want to wrap just the CV/mutex pair, you should get rid of your lock()/release() methods which are unsafe (from a RAII point of view) and replace them with a single lock() method returning a unique_ptr:
std::unique_ptr<std::mutex> lock() {
return std::unique_ptr<std::mutex>(cMutex);
}
This way you can use your Cond wrapper class in rather the same way as what I showed above:
Cond cond;
Resource resource;
void produce() {
{
auto lock = cond.lock();
make_ready(resource);
}
cond.notify(); // or notifyAll()
}
void consume() {
auto lock = cond.lock();
while (!is_ready(resource))
cond.wait(lock);
use(resource);
}
But honestly I'm not sure it's worth the trouble: what if you want to use a recursive_mutex instead of a plain mutex? Well, you'd have to make a template out of your class so that you can choose the mutex type (or write a second class altogether, yay for code duplication). And anyway you don't gain much since you still have to write pretty much the same code in order to manage the resource. A wrapper class only for the CV/mutex pair is too thin a wrapper to be really useful IMHO. But as usual, YMMV.
Background
I'm currently developing a program using C++11 for the raspberry pi. The basic design (relevant to this question) is:
I have a main loop that's awaiting commands from an external source.
In the main loop I create an agent (object that's running in a separate thread) which sleeps until something is added to its queue, in which case it awakens, processes this item, and then checks if there are any items in the queue again before going back to sleep (this process repeats if there is more to process)
In the "processing" of the item, I am simply enabling/disabling GPIO pins one at a time for X amount of seconds.
Processing pseudo-code:
for (Pin pin : pins)
{
set_pin(pin, HIGH);
this_thread::sleep_for(chrono::seconds(x))
set_pin(pin, LOW);
this_thread::sleep_for(chrono::seconds(y))
}
Obviously, 99.999% of the time of this thread is going to be spent asleep (the only time it's executing code is when it's setting pin outputs (no data is touched here)
Question
How should I go about canceling the processing of the current item from the main thread? I don't want to kill the thread, ever, I just want it to return to it's run loop to process the next item in the queue (or go back to sleep).
I can think of ways to do this, I would just like to hear several ideas from the community and choose the best solution.
Additional code
This is the class running in a separate thread doing the processing of items in the queue.
schedule->RunSchedule(schedule) is the call to the function described by the pseudo-code above.
ScheduleThread.cpp
#include "ScheduleThread.h"
ScheduleThread::ScheduleThread()
: thread(&ScheduleThread::run, this)
{
}
ScheduleThread::~ScheduleThread() {
// TODO Auto-generated destructor stub
}
void ScheduleThread::QueueSchedule(Schedule *schedule)
{
lock_guard<mutex> lock(m);
schedule_queue.push(schedule);
stateChangedSema.post();
}
bool ScheduleThread::scheduler()
{
if (!schedule_queue.empty())
{
Schedule *schedule = schedule_queue.front();
schedule->RunSchedule();
schedule_queue.pop();
return true;
}
return false;
}
void ScheduleThread::run()
{
for(;;)
{
stateChangedSema.wait();
while (scheduler());
}
}
Thanks in advance for any help.
I don't know if I understood well what you're trying to do, but if you want to communicate with a certain thread from the main thread you may simply set a flag (declared as a global variable) and make the threads consult this flag in order to change their behavior as you desire. For instance, you may add this variable to the while statement that keeps executing your scheduler() function. Other idea may involve the use of condition variables.
Hope it helps.
Look into Condition variables
Instead of "sleeping", the thread blocks on the condition variable, waking up when it's signalled. The blocking can be a time-out - so if the condvar times out, the thread can do one thing (go round the loop again, for instance), and if the condvar is signalled, it can do something else.
Pay attention to the wait_for warnings about spurious waking up.
Pseudo-ish code might be:
// assumes the condvar is triggered when cancellation is reqd.
if(condvar.wait_for( lock, std::chrono::seconds( x ) ) != std::cv_status::timeout)
return;
set_pin(pin, HIGH);
if(condvar.wait_for( lock, std::chrono::seconds( y ) ) != std::cv_status::timeout)
return;
set_pin(pin, LOW);
Or have I misunderstood what you're after?
Hi I have an example that will help you understand how condition variable work.
You declare two threads (two infinite loops).
One that takes user input and signals to the other thread that one input is ready to be processed
The other one that processes it and signals that he's done
Here is the code
#include <thread>
#include <chrono>
#include <mutex>
#include <iostream>
#include <string>
#include <condition_variable>
#include <atomic>
using namespace std;
//this simulates any action from the user (use it for your pin for example)
int GetUserName()
{
while (true)
{
cout<<"Enter your name " << endl;
cin>> UserName;
NewName=true;//one new name is ready to be processed
cv.notify_one();
// Wait until the naame has been processed
{
std::unique_lock<std::mutex> lk(m);
cv.wait(lk, []{return (NewName==false);});
}
}
return 0;
}
//this reacts to any action of the user, processes the data and signals that he's done
int ProcessName()
{
while (true)
{
//waiting for one data to be processed
{
std::unique_lock<std::mutex> lk(m);
cv.wait(lk, []{return (NewName==true);});
}
cout<<"Hey "+UserName<<"!"<<endl;
NewName=false;//sets to flase because the data are processed
cv.notify_one();//I have processed the data, the user can input something else
}
return 0;
}
Tell me if that helps, o if you have any questions/remarks
I'm writing a simple application that should be able to receive and process notifications in a background thread using Apple's CoreFoundation framework. Here is what I'm trying to accomplish:
static void DummyCallback(CFNotificationCenterRef center,
void *observer,
CFStringRef name,
const void *object,
CFDictionaryRef userInfo) {
printf("RECEIVED NOTIFICATION\n");
}
void *ThreadStart(void *arg) {
CFNotificationCenterAddObserver(CFNotificationCenterGetDistributedCenter(),
NULL,
&DummyCallback,
NULL,
CFSTR("TEST_OBJECT"),
CFNotificationSuspensionBehaviorDeliverImmediately);
printf("background thread: run run loop (should take 5 sec to exit)\n");
int retval = CFRunLoopRunInMode(kCFRunLoopDefaultMode, 5, true);
printf("background thread: exited from run loop (retval: %d)\n", retval);
return NULL;
}
int main(int argc, char** argv) {
pthread_t thread;
int rc = pthread_create(&thread, NULL, &ThreadStart, NULL);
assert(rc == 0);
printf("main: sleep\n");
sleep(10);
printf("main: done sleeping\n");
return 0;
}
If I run the program I just get
main: sleep
background thread: run run loop (should take 5 sec to exit)
background thread: exited from run loop (retval: 1)
main: done sleeping
The problem is that the background thread's run loop exits immediately (return code kCFRunLoopRunFinished instead of kCFRunLoopRunTimedOut) because there is no source/observer/timer. CFNotificationCenterAddObserver registers itself only with the run loop of the main thread but not the one of my background thread.
I need the main thread for some other stuff and can't use it to run it's run loop. Is there any way to get this working? Maybe by registering CFNotificationCenter with the run loop of the background thread?
Thanks in advance!
As stated in http://developer.apple.com/library/mac/#documentation/CoreFoundation/Reference/CFNotificationCenterRef/Reference/reference.html
The first time an observer is registered with a distributed notification center, the notification center creates a connection with the system-wide notification server and places a listening port into the common modes of the current thread’s run loop. When a notification is delivered, it is processed on this initial thread, even if the observer that is receiving the notification registered for the notification on a different thread.
Because loaded frameworks may potentially spawn threads and add their own observers before your code executes, you cannot know for certain which thread will receive distributed notifications. If you need to control which thread processes a notification, your callback function must be able to forward the notification to the proper thread. You can use a CFMessagePort object or a custom CFRunLoopSource object to send notifications to the correct thread’s run loop.