Segmentation Fault With Multiple Threads - multithreading

Question

I get error segmentation fault because of the free() at the end of this equation...
don't I have to free the temporary variable *stck? Or since it's a local pointer and
was never assigned a memory space via malloc, the compiler cleans it up for me?
void * push(void * _stck)
{
stack * stck = (stack*)_stck;//temp stack
int task_per_thread = 0; //number of push per thread
pthread_mutex_lock(stck->mutex);
while(stck->head == MAX_STACK -1 )
{
pthread_cond_wait(stck->has_space,stck->mutex);
}
while(task_per_thread <= (MAX_STACK/MAX_THREADS)&&
(stck->head < MAX_STACK) &&
(stck->item < MAX_STACK)//this is the amount of pushes
//we want to execute
)
{ //store actual value into stack
stck->list[stck->head]=stck->item+1;
stck->head = stck->head + 1;
stck->item = stck->item + 1;
task_per_thread = task_per_thread+1;
}
pthread_mutex_unlock(stck->mutex);
pthread_cond_signal(stck->has_element);
free(stck);
return NULL;
}

Answer 1

Edit: You totally changed the question so my old answer doesn't really make sense anymore. I'll try to answer the new one (old answer still below) but for reference, next time please just ask a new question instead of changing an old one.
stck is a pointer that you set to point to the same memory as _stck points to. A pointer does not imply allocating memory, it just points to memory that is already (hopefully) allocated. When you do for example
char* a = malloc(10); // Allocate memory and save the pointer in a.
char* b = a; // Just make b point to the same memory block too.
free(a); // Free the malloc'd memory block.
free(b); // Free the same memory block again.
you free the same memory twice.
-- old answer
In push, you're setting stck to point to the same memory block as _stck, and at the end of the call you free stack (thereby calling free() on your common stack once from each thread)
Remove the free() call and, at least for me, it does not crash anymore. Deallocating the stack should probably be done in main() after joining all the threads.