I have a device which outputs the time in the format hh:mm:ss.000, e.g., 00:04:58.727 and I need to convert these to milliseconds.
I can't change the way the device outputs the times so I have to do it in Excel, but I don't know VB so am looking for a cell-by-cell solution.
Let's say that your time value is in cell A1 then in A2 you can put:
=A1*1000*60*60*24
or simply:
=A1*86400000
What I am doing is taking the decimal value of the time and multiply it by 1000 (milliseconds) and 60 (seconds) and 60 (minutes) and 24 (hours).
You will then need to format cell A2 as General for it to be in milliseconds format.
If your time is a text value then use:
=TIMEVALUE(A1)*86400000
UPDATE
Per #dandfra's comment this solution may not work in the Italian version of Excel.
Using some text manipulation we can separate each unit of time and then sum them together with their millisecond coefficients.
To show the formulas in the cells use CTRL + `
Use
=LEFT(B2, 2)*3600000 + MID(B2,4,2) * 60000 + MID(B2,7,2)*1000 + RIGHT(B2,3)
you can do it like this:
cell[B1]: 0:04:58.727
cell[B2]: =FIND(".";B1)
cell[B3]: =LEFT(B1;B2-7)
cell[B4]: =MID(B1;11-8;2)
cell[B5]: =RIGHT(B1;6)
cell[B6]: =B3*3600000+B4*60000+B5
maybe you have to multiply B5 also with 1000.
=FIND(".";B1) is only necessary because you might have inputs like '0:04:58.727' or '10:04:58.727' with different length.
Rather than doing string manipulation, you can use the HOUR, MINUTE, SECOND functions to break apart the time. You can then multiply by 60*60*1000, 60*1000, and 1000 respectively to get milliseconds.
Here it is as a single formula:
=(RIGHT(D2,3))+(MID(D2,7,2)*1000)+(MID(D2,4,2)*60000)+(LEFT(D2,2)*3600000)
try this:
=(RIGHT(E9;3))+(MID(E9;7;2)*1000)+(MID(E9;5;2)*3600000)+(LEFT(E9;2)*216000000)
Maybe you need to change semi-colon by coma...
Related
I have a dataset which is amount (parts per million) against time (every minute)
I need to find the peak for each day, so that I can plot that against other data, I can manually do this using =MAX( but I have a lot of data points and I am sure there is a better way
Many Thanks for the help
I don't know where and how you want show this data, but, if you want get a max value amount per day, you can try add an array formula, like that:
=MAX(IF($COL_DATES = $DAY, $COL_VALUE, 0))
Replace $COL_DATES to your column of day date, replace $DAY to value of day what you want get max value and replace $COL_VALUE to your column of values.
After press CTRL + SHIFT + Enter
Can we put up a OR command for custom time in one column?
I have multiple time formats in one column of excel. For eg:
Timing
30 min
31 sec
4 min 20 sec
1 hr 2 min
3 hr
1 hr 23 min 30 sec
I want to convert it to time format: hh:mm:ss so that i can calculate average from all times. How can I achieve it?
Here's a shorter formula:
=TIME(IF(IFERROR(FIND("hr";$A2);0)=0;0;IFERROR(MID($A2;IFERROR(FIND("hr";$A2);0)-3;2);MID($A2;IFERROR(FIND("hr";$A2);0)-2;1)));IF(IFERROR(FIND("min";$A2);0)=0;0;IFERROR(MID($A2;IFERROR(FIND("min";$A2);0)-3;2);MID($A2;IFERROR(FIND("min";$A2);0)-2;1)));IF(IFERROR(FIND("sec";$A2);0)=0;0;IFERROR(MID($A2;IFERROR(FIND("sec";$A2);0)-3;2);MID($A2;IFERROR(FIND("sec";$A2);0)-2;1))))
Note: the above formula contains semicolon (;) as a separator. Replace with coma (,), in case this is your system separator.
To be honest I did not try to decipher #Foxfire's formula.
Remember to apply custom time format to the result cell: [h]:mm:ss
For explanatory reasons see breakdown of the long formula:
This huge formula worked for me:
=IF(AND(IFERROR(FIND("hr";A1;1);0)>0;IFERROR(FIND("min";A1;1);0)>0;IFERROR(FIND("sec";A1;1);0)>0);TEXT(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(A1;" ";"");"hr";":");"min";":");"sec";"");"hh:mm:ss");IF(AND(IFERROR(FIND("hr";A1;1);0)>0;IFERROR(FIND("min";A1;1);0)>0;IFERROR(FIND("sec";A1;1);0)=0);TEXT(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(TRIM(A1)&" 00 sec";" ";"");"hr";":");"min";":");"sec";"");"hh:mm:ss");IF(AND(IFERROR(FIND("hr";A1;1);0)=0;IFERROR(FIND("min";A1;1);0)>0;IFERROR(FIND("sec";A1;1);0)>0);TEXT(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE("00 hr " & TRIM(A1);" ";"");"hr";":");"min";":");"sec";"");"hh:mm:ss");IF(AND(IFERROR(FIND("hr";A1;1);0)>0;IFERROR(FIND("min";A1;1);0)=0;IFERROR(FIND("sec";A1;1);0)=0);TEXT(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(TRIM(A1)&"00 min 00 sec";" ";"");"hr";":");"min";":");"sec";"");"hh:mm:ss");IF(AND(IFERROR(FIND("hr";A1;1);0)=0;IFERROR(FIND("min";A1;1);0)>0;IFERROR(FIND("sec";A1;1);0)=0);TEXT(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE("00 hr " & TRIM(A1)&" 00 sec";" ";"");"hr";":");"min";":");"sec";"");"hh:mm:ss");IF(AND(IFERROR(FIND("hr";A1;1);0)=0;IFERROR(FIND("min";A1;1);0)=0;IFERROR(FIND("sec";A1;1);0)>0);TEXT(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE("00 hr 00 min "&TRIM(A1);" ";"");"hr";":");"min";":");"sec";"");"hh:mm:ss");"Formula needs to be updated"))))))
As I said, you need to check every string in your text. Depending if it contains hr,min,sec, you need to calculate the time and then convert it to time. Also, you need to take care of those annoying blanks at end of some strings. This formula does all this.
Hope you can adapt this to your needs. My Excel is in spanish, but I translated formulas manually. Just in case I typed wrong, I uploaded a file example to Gdrive for you to download and check the formulas (they should autotranslate if you open it).
https://drive.google.com/open?id=13J5IWLOFFZpzvIp1oqPwqkE3eHDk7EeH
I am facing a problem with excel.How can I convert DD:HH:MM to HH:MM in excel?
Here is an exmaple showcasing what I need.
1:02:49(1day, 2hours, 49 mins) should come as 26:49(26 hours, 49 min)
I'm guessing that your 1:02:49 cell is formatted as text; otherwise, you could just change the cell format from DD:HH:MM to HH:MM.
I've opted to output as text, but could change it to an actual Time value if needbe.
Yes, the formula is a bit long but it can cope with any number of digits between each :. So, for example, 100:3:4 (100 days, 3 hours, 4 minutes) would correctly evaluate to 2403:04
=24*LEFT(A1,FIND(":",A1)-1)+MID(A1,FIND(":",A1)+1,LEN(A1)-2-LEN(RIGHT(A1,LEN(A1)-FIND("#",SUBSTITUTE(A1,":","#",2))))-LEN(LEFT(A1,FIND(":",A1)-1)))&":"&TEXT(RIGHT(A1,LEN(A1)-FIND("#",SUBSTITUTE(A1,":","#",2))),"00")
i need to know how can i exclude 0 from rows and get the MIN Value.
But also i need to exlude the F1 Cell.
Ex:
A B C D E F
1 0 18 20 0 150 = 18
but if i do this In excel with =MIN(A1,B1,C1,D1,E1) return 0.
Any help is appreciated.
Try this formula
=SMALL((A1,C1,E1),INDEX(FREQUENCY((A1,C1,E1),0),1)+1)
Both SMALL and FREQUENCY functions accept "unions" as arguments, i.e. single cell references separated by commas and enclosed in brackets like (A1,C1,E1).
So the formula uses FREQUENCY and INDEX to find the number of zeroes in a range and if you add 1 to that you get the k value such that the kth smallest is always the minimum value excluding zero.
I'm assuming you don't have negative numbers.....
Enter the following into the result cell and then press Ctrl & Shift while pushing ENTER:
=MIN(If(A1:E1>0,A1:E1))
Not entirely sure what you want here, but if you want to discount blank cells in the range and pass over zeros then this would do it; if a little contrived:
=MIN(IF(A1:E1=0,MAX(A1:E1),A1:E1))
With Ctrl+Shift+Enter as an array.
What I'm doing here is replacing zeros with the maximum value in the list.
if all your value are positive, you can do -max(-n)
Solutions listed did not exactly work for me. The closest was Chief Wiggum - I wanted to add a comment on his answer but lack the reputation to do so. So I post as separate answer:
=MIN(IF(A1:E1>0;A1:E1))
Then instead of pressing ENTER, press CTRL+SHIFT+ENTER and watch Excel add { and } to respectively the beginning and the end of the formula (to activate the formula on array).
The comma "," and "If" statement as proposed by Chief Wiggum did not work on Excel Home and Student 2013. Need a semicolon ";" as well as full cap "IF" did the trick. Small syntax difference but took me 1.5 hour to figure out why I was getting an error and #VALUE.
Throwing my hat in the ring:
1) First we execute the NOT function on a set of integers,
evaluating non-zeros to 0 and zeros to 1
2) Then we search for the MAX in our original set of integers
3) Then we multiply each number in the set generated in step 1 by the MAX found in step 2, setting ones as 0 and zeros as MAX
4) Then we add the set generated in step 3 to our original set
5) Lastly we look for the MIN in the set generated in step 4
{=MIN((NOT(A1:A5000)* MAX(A1:A5000))+ A1:A5000)}
If you know the rough range of numbers, you can replace the MAX(RANGE) with a constant. This speeds things up slightly, still not enough to compete with the faster functions.
Also did a quick test run on data set of 5000 integers with formula being executed 5000 times.
{=SMALL(A1:A5000,COUNTIF(A1:A5000,0)+1)}
1.700859 Seconds Elapsed |
5,301,902 Ticks Elapsed
{=SMALL(A1:A5000,INDEX(FREQUENCY(A1:A5000,0),1)+1)}
1.935807 Seconds Elapsed |
6,034,279 Ticks Elapsed
{=MIN((NOT(A1:A5000)* MAX(A1:A5000))+ A1:A5000)}
3.127774 Seconds Elapsed |
9,749,865 Ticks Elapsed
{=MIN(If(A1:A5000>0,A1:A5000))}
3.287850 Seconds Elapsed |
10,248,852 Ticks Elapsed
{"=MIN(((A1:A5000=0)* MAX(A1:A5000))+ A1:A5000)"}
3.328824 Seconds Elapsed |
10,376,576 Ticks Elapsed
{=MIN(IF(A1:A5000=0,MAX(A1:A5000),A1:A5000))}
3.394730 Seconds Elapsed |
10,582,017 Ticks Elapsed
min() fuction exlude BOOLEAN and STRING values.
if you replace your zeroes with "" (empty string) - min() function will do its job as you like!
In Microsoft 365 you can use the new function MINIFS
=MINIFS(A1:E1;A1:E1;">0")
gives 1
=MINIFS(A1:E1;A1:E1;">1")
gives 18
*replace ; with , if using english version
All you have to do is to delete the "0" in the cells that contain just that and try again. That should work.
I have an Excel 2010 workbook which contains a cell with the value of, say, 9876:54:32 (manually entered) representing 9876 hours, 54 minutes and 32 seconds of, say, phone talk time.
Then I have a cell with the value of, say, 1000 (manually entered) representing 1000 calls.
I want to divide the values to get the average talk time of 592.615 minutes per call.
I'm doing a regular =A1/B1 and it gives me an error.
* EDITED *
Thanks Brain Webster for correcting my math. I mean 9.876 hours. But the point is that Excel gives me an error, not my manual math. Playing around with it I discovered that Excel is fine with me with values up to 9999:59:59. Once I try with 10000:00:00 and up, it doesn't recognize it as a time value.
I love these seemingly easy riddles, so here is my solution as a formula and as a VBA attempt:
my original:
= (LINKS(A38;FINDEN(":";A38)-1)/24)+ZEITWERT("0"&RECHTS(A38;LÄNGE(A38)-FINDEN(":";A38)+1))
translated:
= (LEFT(A38,FIND(":",A38)-1)/24)+TIMEVALUE("0"&RIGHT(A38,LEN(A38)-FIND(":",A38)+1))
This will get you the right value to a given 10k text of a time duration. You would only have to setup the format of the cell to [h]:mm:ss. Then those values will look the same, but one would be a string and the other a number - and that is a major difference ;)
In vba it looks much more easier, and once defined, you can use it as a worksheetfunction.
Public Function GetDurationValue(ByVal strInput As String) As Double
Dim arrResult As Variant
arrResult = Split(strInput, ":") 'saves you parsing
GetDurationValue = (arrResult(0) / 24) + _
TimeSerial(0, arrResult(1), arrResult(2))
End Function
A38 = "10971:12:14"
=GetDurationValue(A38)
=457.13349537037
You can use LEFT and RIGHT function to retreive parts of the time value and then sum and multiply these values by 60 [minutes] (resp. 3600 [hours]).
Something like this for the hours, minutes, seconds (A1 is the cell with time value):
B1=VALUE(LEFT(A1;FIND(":";A1)))*3600
B2=VALUE(LEFT(A1;FIND(":";A1; FIND(":";A1))))*60
B3=VALUE(LEFT(A1;FIND(":";A1; FIND(":";A1; FIND(":";A1)))))
Now you can sum that:
C1=SUM(B1;B2;B3)
Then divede by calls count (A2 is the cell with the calls count):
D1=C1/A2
Finally format it like time:
E1=TEXT(D1/(24*3600);"d \day\s hh:mm:ss")
BTW: I tried that in Excel 2013 and when I enter 111:22:33 into a cell it automatically converts to a time. So then I can divide it like you try...
It appears that hours > 10000 are not recognised as such by Excel. Therefore we need to introduce an IF() to see whether this is the case and determined the alternative formula for the case where hours >10000
=IF(ISERROR(FIND(":",A2)),A2/B2, <SCRIPT IN CASE OF >10000>)
<SCRIPT IN CASE OF >10000> will now be:
VALUE(LEFT(A2,FIND(":",A2)))/24+VALUE(LEFT(A2,FIND(":",A2, FIND(":",A2))))/(24*60)+VALUE(LEFT(A2,FIND(":",A2, FIND(":",A2,FIND(":",A2)))))*(24*60*60)
combine and enjoy!
Assuming you don't exceed 100,000 hours in A1, and you always display hours, minutes and seconds then this formula should suffice
=IFERROR(A1/B1,(LEFT(A1)*10000/24+RIGHT(A1,10))/B1)
format result cell as [h]:mm:ss to get the result as a time value
With 10971:12:14 in A1 and 1000 in B1 that should give a result of 10:58:16 [or format result cell as [m]:ss to get minutes and seconds like 658:16]
This version will work with any number of hours and with or without seconds
=IFERROR(A1/B1,(LEFT(A1,FIND(":",A1)-1)/24+RIGHT(A1&IF(COUNTIF(A1,":*:"),"",":00"),5)/60)/B1)