Why won't my "finally" run? - c#-4.0

Question

I assume I'm missing something really trivial here but for reason it's not obvious to me. I've always assumed that "finally" always executes, regardless of an exception or not.
Anyway, this code failed to run and I'm not sure why. It gets to i = i/j and throws an DivideByZero exception but I would've thought it would continue and execute the finally statement before stopping.
static void Main(string[] args)
{
int i = 1;
try
{
int j = 0;
i = i / j;
Console.WriteLine("can't get");
}
finally
{
Console.WriteLine("finally ran");
}
}

Answer 1

Take a look at this MSDN try-finally (C# Reference)
From above link:
Usually, when an unhandled exception ends an application, whether or
not the finally block is run is not important. However, if you have
statements in a finally block that must be run even in that situation,
one solution is to add a catch block to the try-finally statement.

Answer 2

Works for me - at least somewhat. When I run this as a console app from the command line, the "Test.exe has stopped working. Windows is looking for a solution" dialog comes up immediately, but then if I hit the "cancel" button, I see "finally ran". If I let the initial dialog run to completion and just get left with Debug or Close, then hitting Close will terminate the process immediately, and hitting Debug obviously brings up a debugger.
EDIT: Mark Hall's answer explains the behaviour in more detail. I'll leave this answer up as it contains experimental results, but look at Mark's answer :)

Answer 3

Mark's answer says what happens, but I thought I'd mention why:
I believe this is to allow for any external handlers to handler the exception to be handled before the finally block is executed. (For example, when a debugger is attached, it can try to break at the point of exception, allowing you to continue before the finally block starts running.)
If the finally block was executed beforehand, then you couldn't handle the exception in a debugger.

Answer 4

try this:
static void Main(string[] args)
{
int i = 1;
try
{
int j = 0;
i = i / j;
Console.WriteLine("can't get");
}
catch(Exception ex){
Console.WriteLine(ex.Message);
}
finally
{
Console.WriteLine("finally ran");
}
Console.WriteLine("Press enter to exit...");
Console.ReadLine();
}

Answer 5

I think you might need a catch to catch the exception before finally will run.