I have long section titles in my document like:
Lorem ipsum dolor sit amet, consectetur adipisicing elit. Proin nibh augue, suscipit a, scelerisque sed, lacinia in, mi.
Now I want to place it in page header but it is to long for it. Is there any way to cut text in LaTeX? I want to have it like that:
Lorem ipsum dolor sit amet, consectetur...
Is that possible?
https://tex.stackexchange.com/questions/6862/how-can-i-display-a-short-chapter-name-in-the-header-and-a-long-chapter-name-in-t
Related
I have a .txt file that contains text that is formatted like so:
Neque porro, quisquam est qui
dolorem ipsum quia, dolor (sit amet)
consectetur, adipisci velit,Lorem Ipsum
dolor sit amet, consectetur adipiscing elit
tempor ipsum quia, minim (sit minim)
consectetur, adipisci velit,Lorem Ipsum
There are multiple text items like this. I wish to make it so that they are all one liners each so I can paste them into excel like so
Neque porro, quisquam est qui dolorem ipsum quia, dolor (sit amet) consectetur, adipisci velit, Lorem Ipsum
dolor sit amet, consectetur adipiscing elit tempor ipsum quia, minim (sit minim) consectetur, adipisci velit,Lorem Ipsum
Would there be any way to do this for files with a lot of text that are like this?
If you did want to use Excel (as your question indicates) this formula work if you had all text in a single cell
=SUBSTITUTE(SUBSTITUTE(A1,CHAR(10)&" "," "),char(10),REPT(char(10),2))
Im looking for a fast way to get a word in a huge text which starts with "TEST-"
Lorem ipsum dolor sit amet, consectetur adipisici elit "TEST-12345"
Lorem ipsum dolor sit amet, consectetur adipisici elit 'TEST-12345'
Lorem ipsum dolor sit amet, consectetur adipisici elit " TEST-12345 "
Lorem ipsum dolor sit amet, consectetur adipisici elit "TEST-12345" sed diam nonumy eirmod tempor invidunt
Lorem ipsum dolor sit amet, consectetur adipisici elit " TEST-12345 "
I have tried to archive this with different loops, but im getting Unexpected identifier everytime
Lorem ipsum dolor sit amet, consectetur adipisici elit "TEST-12345"
Lorem ipsum dolor sit amet, consectetur adipisici elit 'TEST-12345'
Lorem ipsum dolor sit amet, consectetur adipisici elit " TEST-12345 "
Lorem ipsum dolor sit amet, consectetur adipisici elit "TEST-12345" sed diam nonumy eirmod tempor invidunt
Lorem ipsum dolor sit amet, consectetur adipisici elit " TEST-12345 "
var text = 'Lorem ipsum dolor sit amet, consectetur adipisici elit "TEST-12345"\
Lorem ipsum dolor sit amet, consectetur adipisici elit \'TEST-12345\'\
Lorem ipsum dolor sit amet, consectetur adipisici elit " TEST-12345 "\
Lorem ipsum dolor sit amet, consectetur adipisici elit "TEST-12345" sed diam nonumy eirmod tempor invidunt\
Lorem ipsum dolor sit amet, consectetur adipisici elit " TEST-12345 "'.split("\\")
for (var x in text) {
console.log(text[x])
}
Use .match method.
text.match(/TEST-\d{5}/g)
st = 'Lorem ipsum dolor sit amet, consectetur adipis.cing elit. Aliquam sem odio...'
n = []
for i in st:
n.append(i)
for i in n:
if i in [',','.']:
n.remove(i)
string = ''
for i in n:
string += i
print(string)
input string :
Lorem ipsum dolor sit amet, consectetur adipis.cing elit. Aliquam sem odio...
output :
Lorem ipsum dolor sit amet consectetur adipiscing elit Aliquam sem odio.
expected output :
Lorem ipsum dolor sit amet consectetur adipiscing elit Aliquam sem odio
There is one dot . at the end of the sentence that is not getting removed.
You can use str.join for the task:
st = "Lorem ipsum dolor sit amet, consectetur adipis.cing elit. Aliquam sem odio..."
print("".join(ch for ch in st if ch not in {*",."}))
Prints:
Lorem ipsum dolor sit amet consectetur adipiscing elit Aliquam sem odio
How about using replace() for both commas and periods?
>>> st.replace(",", "").replace(".", "")
'Lorem ipsum dolor sit amet consectetur adipiscing elit Aliquam sem odio'
Calling some_list.remove(something) while iterating over some_list changes the length of list and introduces the potential to skip elements. The solution is to copy the list first. See this thread.
Also, remove() removes the first occurrence, not the current index, so you may get unusual results using it. Best case scenario, iterating over the list repeatedly from the front is harmful to time complexity. I don't find remove() useful often in practice.
I'd write this using a simple regex:
>>> import re
>>> st = 'Lorem ipsum dolor sit amet, consectetur adipis.cing elit. Aliquam sem odio...'
>>> re.sub(r"[.,]", "", st)
'Lorem ipsum dolor sit amet consectetur adipiscing elit Aliquam sem odio'
Other remarks:
This is Shlemiel the painter's algorithm:
for i in n:
string += i
Better is "".join(n)
n is usually reserved for "number". Prefer lst or L for a generic list.
Allocating a list inside a loop adds unnecessary overhead: if i in [',','.']:.
The code:
n = []
for i in st:
n.append(i)
can be better expressed as list(st).
When writing a long footnote with LilyPond 2.17.25, the text is not breaking into several lines or respecting the margin limits. I would love to have it set to justified alignment as well, if that is possible.
Here is a tiny example:
\version "2.17.25"
{
\footnote #'(-1 . 1)
\markup{Lorem ipsum dolor sit amet, consectetur adipiscing elit. Ut eget ante venenatis mi consectetur ornare. Cras facilisis dictum venenatis. Donec.}
a'4 b' c'' d''
}
Thanks a lot!
The solution is to simply add \justify or \wordwrap to the \markup command, as:
\version "2.17.25"
{
\footnote #'(-1 . 1)
\markup\justify{Lorem ipsum dolor sit amet, consectetur adipiscing elit. Ut eget ante venenatis mi consectetur ornare. Cras facilisis dictum venenatis. Donec.}
a'4 b' c'' d''
}
I need to insert the line number before each line of text using Vim, and there has to be a space after the line number. For example, if this was TestFile:
Lorem ipsum dolor sit amet, consectetuer adipiscing elit.
Morbi nunc enim, vehicula eget, ultricies vel, nonummy in, turpis.
It should look like this
1 Lorem ipsum dolor sit amet, consectetuer adipiscing elit.
2 Morbi nunc enim, vehicula eget, ultricies vel, nonummy in, turpis.
I have been using the command :%s/^/\line('.')/ with a number of variations, but I cannot figure out how to get the space at the end.
Any ideas?
You were very close!
This substitution will do the job by concatenating the string ' ' to the line number:
%s!^!\=line('.').' '!
This is probably easiest with an external tool:
:%!nl -ba -w1 -s' '
You can use a macro. First make sure you have a 0 before the first line and have your cursor placed on it:
0 Lorem ipsum dolor sit amet, consectetuer adipiscing elit.
Morbi nunc enim, vehicula eget, ultricies vel, nonummy in, turpis.
foo
bar
etc...
Then perform this key sequence to store the right macro in register a: qaywjP0<C-A>q.
Now press #a to execute the macro. Use a quantifier to execute it multiple times.
Type :help q to find out more about recording macro's.