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I'm out of idea how I could format consecutive same (respectively only even) values in Excel tables without using VBA.
The conditional formatting shall color only consecutive values and only
all 0s or all even values, when there are not more than 2.
A: ID
B: binary
C: counting
1
1
1
2
0
2
3
0
2
4
1
3
5
0
4
6
0
4
7
0
4
8
1
5
9
1
5
I tried to format with: =COUNTIF(C1:C9, C1) < 3, but then it also colors the 1s and C6:C7, eventho there are more than 2.
I also tried =AND( COUNTIF(C1:C9,C1) < 3, ISEVEN(C1:C9) ) but then it colors nothing.
I could replace the 0s with empty cells so I could check ISEMPTY(B1:B9) but it again colors nothing. Using $ to set absolute changes nothing as well.
Formating duplicates also colors triplets, which also doesn't work for me.
=OR(COUNTIF($C$1:$C$9,C1) = 1, COUNTIF($C$1:$C$6,C1) = 2) works so far, but also colors the 1s (uneven).
=AND(OR(COUNTIF($C$1:$C$9,C1) = 1, COUNTIF($C$1:$C$6,C1) = 2), ISEVEN($C$1:$C$9)) doesn't work.
=AND(OR(COUNTIF($C$1:$C$9,C1) = 1, COUNTIF($C$1:$C$6,C1) = 2), $B$1:$B$9 <> 1) doesn't work as well.
My only solution so far is using 2 formating rules:
color =OR(COUNTIF($C$1:$C$9,C1) = 1, COUNTIF($C$1:$C$6,C1) = 2)
do not color =$B$1:$B$9 = 1
but I think it is terrible.
I worked on it for some hours, maybe I'm missing something really obvious.
I'm not allowed to use VBA, therefore this is ot an option.
EDIT: My 2.rule-solution can be simplificed with:
color =COUNTIF($C$1:$C$9,C1) < 3
do not color =$B$1:$B$9 = 1
I'm still confused why combining both doesn't work:
AND(COUNTIF($C$1:$C$9,C1) < 3; $B$1:$B$9 <> 1)
EDIT2: I know why it didn't work. Don't check <>1 with absolute value-range $B$1$:$B$9
Solution: B1 <> 1 then it loops through.
Now combining both works:
=AND( COUNTIF($C$1:$C$9, C1) < 3, B1 <> 1)
I can't see an easy answer for the binary numbers. You have two cases:
(1) Current cell is zero, previous cell is 1, next cell is zero and next cell but one is 1.
(2) Current cell is zero, previous cell is zero, previous cell but one is 1, next cell is 1.
But then the first pair of numbers is a special case because there is no previous cell.
Strictly speaking the last pair of numbers is a special case as well because there is no following cell.
=OR(AND(ROW()=1,B$1=0,B$2=0,B$3=1),AND(ROW()=2,B$1=0,B$2=0,B$3=1),AND(B1=0,B1048576=1,B2=0,B3=1),AND(B1=0,B1048576=0,B1048575=1,B2=1))
where I have used the fact that you are allowed to wrap ranges to the end of the sheet (B1048576) in conditional formatting.
Adding the condition for the case where there there are two zeroes at the end of the range:
=OR(AND(ROW()=1,B$1=0,B$2=0,B$3=1),
AND(ROW()=2,B$1=0,B$2=0,B$3=1),
AND(B1=0,B1048576=1,B2=0,OR(B3=1,B3="")),
AND(B1=0,B1048576=0,B1048575=1,OR(B2=1,B2="")))
Even this could go wrong if there was something in the very last couple of rows of the sheet, so I suppose to be absolutely safe:
=OR(AND(ROW()=1,B$1=0,B$2=0,B$3=1),
AND(ROW()=2,B$1=0,B$2=0,B$3=1),
AND(Row()>1,B1=0,B1048576=1,B2=0,OR(B3=1,B3="")),
AND(Row()>2,B1=0,B1048576=0,B1048575=1,OR(B2=1,B2="")))
Shorter:
=OR(AND(ROW()<=2,B$1+B$2=0,B$3=1),
AND(B1+B2=0,B1048576=1,OR(B3=1,B3="")),
AND(B1+B1048576=0,B1048575=1,OR(B2=1,B2="")))
Not the cleanest wat but it works. You only need to move your data 1 row below, so headers would be in row 2 and data in row 3 for this formula to work:
=IF(AND(B3=B4,B3<>B5),IF(AND(B4=B3,B4<>B2),TRUE,FALSE),IF(AND(B3=B2,B3<>B1),IF(AND(B3=B4,B3<>B5),FALSE,TRUE),FALSE))
How about this approach (Office 365):
=LET(range,B$1:B$9,
s,IFERROR(TRANSPOSE(INDEX(range,ROW()+SEQUENCE(5,,-2))),1),
t,TEXTJOIN("",,(s=INDEX(range,ROW()))*ISEVEN(s)),
IFERROR(SEARCH("0110",t)<4,IFERROR(SEARCH("010",t)=2,FALSE)))
It creates an array s of 5 values starting point is the current row of the range, adding the 2 values above and below. If the value is out of range it will replace the error with a 1.
The array s is checked for being even (TRUE/FALSE, IFERROR created values are uneven) and the values to equal the value of the current row of the range (TRUE/FALSE).
These two booleans are multiplied creating 1 for both values being TRUE, else 0.
These values are joined and checked for 2 consecutive 1's (surrounded by 0) to be found in the 2nd or 3rd position of the range (this would be the case if two even consecutive equal numbers are found),
if it errors it will look if a unique even number is found (1 surrounded by 0 in 2nd position).
PS I'm unable to test if conditional formatting allows you to type the range as B:B instead of B$1:B$9 (working from a mobile) but that would make it more dynamical, because that way you can easily expand the conditional range.
apologies for my ignorance, I'm brand new to VBA - I'm sure this is a simple problem...
I'm trying to write a fn. for up/down side capture in VBA. This is the problem:
There are two columns. One has fund performance in % (I've labelled 'returns'). The other has index performance in % (labelled 'index'). Both are same length / same number of rows. I need both to be variables to enter to the fn.
For UpsideCapture fn., for all nos. in the index column >0, I want to find the corresponding number in the returns column (which will be on the same row). Once I have those numbers I can compound them.
I've tried using Offset, assuming the returns column is 15 columns to the left of the index column but it doesn't return anything, and I don't really want to rely on it always being 15 columns apart (it arbitrary).
Many thanks!
One of my rubbish attempts is below. Any help is much appreciated. Its really just a case of finding the correct corresponding row based on the value in the index column...
Function UpsideCapture(returns As Range, index As Range) As Variant
Dim n As Integer
Dim m As Integer
Dim i As Integer
n = returns.Rows.Count
m = index.Rows.Count
For i = 1 To m
If index(i) > 0 Then
Upsidecap = ((1 + Upsidecap) * (1 + Offset(returns(i), -15))) - 1
End If
Next
UpsideCapture = Upsidecap
End Function
example
I've got a matrix, with two coordinates [i;j]
I'm trying to automatize a lookup:
As an example, this would have the coordinates of [1;2]
Here's a table of all the coordinates:
So here, obviously [1;2] would equate to 143,33
To simplify the issue:
I'll try to go step by step over what I'm trying to do to make the question bit less confusing.
Think of what I'm trying to do as a function, lookup(i, j) => value
Now, refer to the second picture (table)
I find all rows containing index [i] (inside column C) and then
only for those rows find row containing index [j] (inside column D ∩ for rows from previous step)
Return [i;j] value
So if u invoked lookup(2, 4)
Find all rows matching i = 2
Row 5: i = 2 ; j = 3
Row 6: i = 2 ; j = 4
Row 7: i = 2 ; j = 5
Lookup column j for j=4 from found rows
Found row 6: i = 2 ; j = 4.
Return value (offset for yij column = 143,33)
Now this isn't an issue algorhitmically speaking, but I have no idea how to go about doing this with excel formulas.
PS: I know this is reltively simple vba issue but I would prefer formulas
PSS: I removed what I tried to make the question more readable.
You can use SUMPRODUCT, which return 0 for not found values:
=SUMPRODUCT(($C$4:$C$18=$I4)*($D$4:$D$18=J$3)*$E$4:$E$18)
or AGGREGATE, which returns an error that can be hidden by the IFERROR function:
=IFERROR(AGGREGATE(15,6,(1/(($C$4:$C$18=$I12)*($D$4:$D$18=J$3)))*$E$4:$E$18,1),"")
You can use SUMIFS here assuming you will not have exact duplicate combinations of [i, j]. If you did have a duplicate combination, the amounts will be summed and placed in the corresponding cell
In cell B2 place this equation: =SUMIFS($Q$2:$Q$16,$P$2:$P$16,B$1,$O$2:$O$16,$A2) and drag across and over as needed
IF you want to convert the 0's to blanks you can nest the above formula inside a text formatter like so:
=TEXT([formula], "0;-0;;#")
I am looking to make a list of heading type 1, sub-heading type 2 and sub-sub-heading type 3, and each subsequent instance of a heading increments in excel. e.g.
Outcome 1
Output 1.1
Activity 1.1.1
Activity 1.1.2
Output 1.2
Activity 1.2.1
Activity 1.2.2
Activity 1.2.3
Outcome 2
Output 2.1
Activity 2.1.1
etc
Here is my formula - getting to be a complicated nested IF statement:
IF([#Column1]="","",
IF([#Column1]="Outcome", "Outcome " & COUNTIF(tbOOA[[#Headers],[Column1]]:[#Column1], [#Column1]),
IF([#Column1]="Output","Output "& COUNTIF(tbOOA[[#Headers],[Column1]]:[#Column1],"Outcome") ***&"."&*** COUNTIF(tbOOA[[#Headers],[Column1]]:[#Column1],[#Column1]),
"Activity " & "serious help")))
In Column 1, choose from a list of 'Outcome', 'Output', or 'Activity'.
In column 2, calculate the appropriate number, e.g. Output 1.2
If the row is empty, then nothing. - Fine
If it is "Outcome", count from the header until current row for the number of instances of "Outcome". - Fine
Else if it is "Output", count the number of "Outcome"s there are. - Fine
This is where it falls apart. Trying to calculate the number after the "." (bold and italic)
I need to count the # of instances of "Output", but then this has to reset to 1 each time there is a new 'Outcome'.
The logic I'm trying to follow is:
(# of "Outputs" from the table header until the current row) minus
(# of "Outputs" from the table header until the last instance of "Outcome")
I've tried several attempts at calculating row number, but everything has been problematic.
The logic is the same for activities, though will complicate the formula even more and I haven't bothered to start on that until I can get level 2 sorted.
Does anyone know of a similar problem/solution?
If you are open to using hidden helper columns, the formulas become much more manageable. Use Column A to hold your "Outcome", "Output", and "Activity" data.
Then use column B to deal with Outcome numbers, column C to deal with Output numbers, and column D to deal with Activity numbers. Merge the final results together in Column E.
In B1, C1, and D1, manually write in the first values (1, 0, and 0).
Then, fill down starting from B2 with the following:
=IF(A2="Outcome",B1+1,B1)
This works by incrementing only if you have found your next Outcome.
Fill down from C2 with the following:
=IF(A2="Outcome",0,IF(A2="Output",C1+1,C1))
This works by incrementing only if you have found your next Output. It resets to 0 if you have a new Outcome.
Then fill down from D2 with
=IF(OR(A3="Outcome",A3="Output"),0,IF(A3="Activity",D2+1,D2))
It's very similar to the prior formula, but resets on an Outcome or an Output.
Finally, in D4, merge it all together with
=B1&IF(C1>0,"."&C1&IF(D1>0,"."&D1,""),"")
& is a string concatenate operation. By checking if the inner values are 0, we only concatenate . and the next number if the next number is non-zero.
I had a similar problem, where I wanted to create the multi-level heading numbers based on the indentation of list of texts. So the numbers must be generated automatically with a user-defined formula (UDF) like below:
For this to work, you must type ="1" in cell A2. The same formula in A3 (below) must be copied down to A4:A14.
=NextLevelNum(A2;IndentLevel(B3))
Function IndentLevel I took from https://professor-excel.com/how-to-return-the-indentation-of-a-cell-in-excel/
Function NextLevelNum I did myself. All code below.
Option Explicit
Public Function IndentLevel(Ref As Range) As Long
Application.Volatile
IndentLevel = Ref.IndentLevel
End Function
Public Function NextLevelNum(prevNumRef As Range, level As Integer) As String
Dim prevNum As String
Dim nums() As String
Dim prevLevel As Integer
prevNum = prevNumRef.Value
nums = Split(prevNum, ".")
prevLevel = UBound(nums) + 1
' Ensure 1 <= level <= prevLevel +1
level = WorksheetFunction.Max(level, 1)
level = WorksheetFunction.Min(level, prevLevel + 1)
ReDim Preserve nums(0 To level - 1)
If level = prevLevel + 1 Then
nums(level - 1) = "1"
Else
nums(level - 1) = CStr(CInt(nums(level - 1)) + 1)
End If
NextLevelNum = Join(nums, ".")
End Function
I want to do an INDEX-MATCH-like lookup between two documents, except my MATCH's index array doesn't stay in one column.
In Vague-English: I want a value from a known column that matches another value that may be found in any column.
Refer to the image below. Let's call everything to the left of the bold vertical line on column H doc1, and the right side will be doc2.
Doc2 has a column "Find This", which will be the INDEX's array. It is compared with "ID1" from doc1 (Note that the values in "Find This" will not be in the same order as column ID1, but it's easier to undertsand this way).
The "[Result]" column in doc2 will be the value from doc1's "Want This" column from the row that matches "FIND THIS" ...However, sometimes the value from "FIND THIS" is not in the "ID1" column, and is instead in "ID2","ID3", etc.
So, I'm trying to generate Col K from Col J. This would be like pressing Ctrl+F and searching for a value in Col J, then taking the value from Col D in that row and copying it to Col K.
I made identical values from a column the same color in the other doc to make it easier to visualize where they are coming from.
Note also that in column F of doc1, the same value from doc2's "Find This" can be found after some other text.
Also note that the column headers are only there as examples, the ID columns are not actually numbered.
I would simply hard-code the correct column to search from, but I'm not in control of doc1, and I'm worried that future versions may have new "ID" columns, with other's being removed.
I'd prefer this to be a solution in the form of a formula, but VB will do.
To generate column K based on given values of column J then you could use the following:
=INDEX(doc1!$D$2:$D$14,SUMPRODUCT((doc1!$B$2:$H$14=J2)*ROW(doc1!$B$2:$H$14))-1)
Copy that formula down as far as you need to go.
It basically only returns the row of the where a matching column J is found. we then find that row in the index of your D range to get your value in K.
Proof of concept:
UPDATE:
If you are working with non unique entities n column J. That is the value on its own can be found in multiple rows and columns. Consider using the following to return the Last row where there J value is found:
=INDEX(doc1!$D$2:$D$14,AGGREGATE(14,6,(doc1!$B$2:$H$14=J2)*ROW(doc1!$B$2:$H$14),1)-1)
UPDATE 2:
And to return the first row where what you are looking in column J is found use:
=INDEX($D$2:$D$14,AGGREGATE(15,6,1/($B$2:$H$14=J2)*ROW($B$2:$H$14)-1,1))
Thanks to Scott Craner for the hint on the minimum formula.
To determine if you have UNIQUE data from column J in your range B2:H14 you can enter this array formula. In order to enter an array formula you need to press CTRL+SHFT+ENTER at the same time and not just ENTER. You will know you have done it right when you see {} around your formula in the formula bar. You cannot at the {} manually.
=IF(MAX(COUNTIF($B$2:$H$14,J2:J14))>1,"DUPLICATES","UNIQUE")
UPDATE 3
AGGREGATE - A relatively new function to me but goes back to Excel 2010. Aggregate is 19 functions rolled into 1. It would be nice if they all worked the same way but they do not. I think it is functions numbered 14 and up that will perform the same way an array formula or a CSE formula if you prefer. The nice thing is you do not need to use CSE when entering or editing them. SUMPRODUCT is another example of a regular formula that performs array formula calculations.
The meat of this explanation I believe is what is happening inside of the AGGREGATE brackets. If you click on the link you will get an idea of what the first two arguments are. The first defines which function you are using, and the second tell AGGREGATE how to deal with Errors, hidden rows, and some other nested functions. That is the relatively easy part. What I believe you want to know is what is happening with this:
(doc1!$B$2:$H$14=J2)*ROW(doc1!$B$2:$H$14)
For illustrative purpose lets reduce this formula to something a little smaller in scale that does the same thing. I'll avoid starting in A1 as that can make life a little easier when counting since it the 1st row and first column. So by placing the example range outside of it you can see some more special considerations potentially.
What I want to know is what row each of the items list in Column C occurs in column B
| B | C
3 | DOG | PLATYPUS
4 | CAT | DOG
5 | PLATYPUS |
The full formula for our mini example would be:
{=($B$3:$B$5=C2)*ROW($B$3:$B$5)}
And we are going to look at the following as an array
=INDEX($B$3:$B$5,AGGREGATE(14,6,($B$3:$B$5=C2)*ROW($B$3:$B$5),1)-2)
So the first brackets is going to be a Boolean array as you noted. Every cell that is TRUE will TRUE until its forced into a math calculation. When that happens, True becomes 1 and False becomes 0.I that formula was entered as a CSE formula and place in D2, it would break down as follows:
FALSE X 3
FALSE X 4
TRUE X 5
The 3, 4 and 5 come from ROW() returning the value of the row number that it is dealing with at the time of the array math operation. Little trick, we could have had ROW(1:3). Just need to make sure the size of the array matches! This is not matrix math is just straight across multiplication. And since the Boolean is now experiencing a math operation we are now looking at:
0 X 3 = 0
0 X 4 = 0
1 X 5 = 5
So the array of {0,0,5} gets handed back to the aggregate for more processing. The important thing to note here is that it contains ONLY 0 and the individual row numbers where we had a match. So with the first aggregate formula, formula 14 was chosen which is the LARGE function. And we also told it to ignore errors, which in this particular case does not matter. So after providing the array to the aggregate function, there was a ,1) to finish off the aggregate function. The 1 tells the aggregate function that we want the 1st larges number when the array is sorted from smallest to largest. If that number was 2 it would be the 2nd largest number and so on. So the last row or the only row that something is found on is returned. So in our small example it would be 5.
But wait that 5 was buried inside another function called Index. and in our small example that INDEX formula would be:
=INDEX($B$3:$B$5,AGGREGATE(...)-2)
Well we know that the range is only 3 rows long, so asking for the 5th row, would have excel smacking you up side the head with an error because your index number is out of range. So in comes the header row correction of -1 in the original formula or -2 for the small example and what we really see for the small example is:
=INDEX($B$3:$B$5,5-2)
=INDEX($B$3:$B$5,3)
and here is a weird bit of info, That last one does not become PLATYPUS...it becomes the cell reference to =B5 which pulls PLATYPUS. But that little nuance is a story for another time.
Now in the comments Scott essentially told me to invert for the error to get the first row. And this is important step for the aggregate and it had me running in circles for awhile. So the full equation for the first row option in our mini example is
=INDEX($B$3:$B$5,AGGREGATE(15,6,1/($B$3:$B$5=C2)*ROW($B$3:$B$5),1)-2)
And what Scott Craner was actually suggesting which Skips one math step is:
=INDEX($B$3:$B$5,AGGREGATE(15,6,ROW($B$3:$B$5)/($B$3:$B$5=C2),1)-2)
However since I only realized this after writing this all up the explanation will continue with the first of these two equations
So the important thing to note here is the change from function 14 to function 15 which is SMALL. Think of it a finding the minimum. And this time that 6 plays a huge factor along with the 1/. So our array in the middle this time equates to:
1/FALSE X 3
1/FALSE X 4
1/TRUE X 5
Which then becomes:
1/0 X 3
1/0 X 4
1/1 X 5
Which then has excel slapping you up side the head again because you are trying to divide by 0:
#div/0 X 3
#div/0 X 4
1/1 X 5
But you were smart and you protected yourself from that slap upside the head when you told AGGREGATE to ignore error when you used 6 as the second argument/reference! Therefore what is above becomes:
{5}
Since we are performing a SMALL, and we passed ,1) as the closing part of the AGGREGATE, we have essentially said give me the minimum row number or the 1st smallest number of the resulting array when sorted in ascending order.
The rest plays out the same as it did for the LARGE AGGREGATE method. The pitfall I fell into originally is I did not use the 1/ to force an error. As a result, every time I tried getting the SMALL of the array I was getting 0 from all the false results.
SUMPRODUCT works in a very similar fashion, but only works when your result array in the middle only returns 1 non zero answer. The reason being is the last step of the SUMPRODUCT function is to all the individual elements of the resulting array. So if you only have 1 non zero, you get that non zero number. If you had two rows that matched for instance 12 and 31, then the SUMPRODUCT method would return 43 which is not any of the row numbers you wanted, where as aggregate large would have told you 31 and aggregate small would have told you 12.
Something like this maybe, starting in K2 and copied down:
=IFERROR(INDEX(D:D,MAX(IFERROR(MATCH(J2,B:B,0),-1),IFERROR(MATCH(J2,E:E,0),-1),IFERROR(MATCH(J2,G:G,0),-1),IFERROR(MATCH(J2,H:H,0),-1))),"")
If you want to keep the positions of the columns for the Match variable, consider creating generic range names for each column you want to check, like "Col1", "Col2", "Col3". Create a few more range names than you think you will need and reference them to =$B:$B, =$E:$E etc. Plug all range names into Match functions inside the Max() statement as above.
When columns are added or removed from the table, adjust the range name definitions to the columns you want to check.
For example, if you set up the formula with five Matches inside the Max(), and the table changes so you only want to check three columns, point three of the range names to the same column. The Max() will only return one result and one lookup, even if the same column is matched several times.
I came up with a vba solution if I understood correctly:
Sub DisplayActiveRange()
Dim sheetToSearch As Worksheet
Set sheetToSearch = Sheet2
Dim sheetToOutput As Worksheet
Set sheetToOutput = Sheet1
Dim search As Range
Dim output As Range
Dim searchCol As String
searchCol = "J"
Dim outputCol As String
outputCol = "K"
Dim valueCol As String
valueCol = "D"
Dim r As Range
Dim currentRow As Integer
currentRow = 1
Dim maxRow As Integer
maxRow = sheetToOutput.UsedRange.Rows.Count
For currentRow = 1 To maxRow
Set search = Range("J" & currentRow)
For Each r In sheetToSearch.UsedRange
If r.Value <> "" Then
If r.Value = search.Value Then
Set output = sheetToOutput.Range(outputCol & currentRow)
output.Value = sheetToSearch.Range(valueCol & currentRow).Value
currentRow = currentRow + 1
Set search = sheetToOutput.Range(searchCol & currentRow)
End If
End If
Next
Next currentRow
End Sub
There might be better ways of doing it, but this will give you what you want. We assume headers in both "source" and "destination" sheets. You will need to adapt the "Const" declarations according to how your sheets are named. Press Control & G in Excel to bring up the VBA window and copy and paste this code into "This Workbook" under the "VBA Project" group, then select "Run" from the menu:
Option Explicit
Private Const sourceSheet = "Source"
Private Const destSheet = "Destination"
Public Sub FindColumns()
Dim rowCount As Long
Dim foundValue As String
Sheets(destSheet).Select
rowCount = 1 'Assume a header row
Do While Range("J" & rowCount + 1).value <> ""
rowCount = rowCount + 1
foundValue = FncFindText(Range("J" & rowCount).value)
Sheets(destSheet).Select
Range("K" & rowCount).value = foundValue
Loop
End Sub
Private Function FncFindText(value As String) As String
Dim rowLoop As Long
Dim colLoop As Integer
Dim found As Boolean
Dim pos As Long
Sheets(sourceSheet).Select
rowLoop = 1
colLoop = 0
Do While Range(alphaCon(colLoop + 1) & rowLoop + 1).value <> "" And found = False
rowLoop = rowLoop + 1
Do While Range(alphaCon(colLoop + 1) & rowLoop).value <> "" And found = False
colLoop = colLoop + 1
pos = InStr(Range(alphaCon(colLoop) & rowLoop).value, value)
If pos > 0 Then
FncFindText = Mid(Range(alphaCon(colLoop) & rowLoop).value, pos, Len(value))
found = True
End If
Loop
colLoop = 0
Loop
End Function
Private Function alphaCon(aNumber As Integer) As String
Dim letterArray As String
Dim iterations As Integer
letterArray = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
If aNumber <= 26 Then
alphaCon = (Mid$(letterArray, aNumber, 1))
Else
If aNumber Mod 26 = 0 Then
iterations = Int(aNumber / 26)
alphaCon = (Mid$(letterArray, iterations - 1, 1)) & (Mid$(letterArray, 26, 1))
Else
'we deliberately round down using 'Int' as anything with decimal places is not a full iteration.
iterations = Int(aNumber / 26)
alphaCon = (Mid$(letterArray, iterations, 1)) & (Mid$(letterArray, (aNumber - (26 * iterations)), 1))
End If
End If
End Function