I'm writing a PHP script that downloads a series of generated files (using wget) into a directory, and then zips then up, using the zip command.
The downloads work perfectly, and the zipping mostly works. I run the command:
zip -r /var/www/oraviewer/rgn_download/download/fcst_20100318_0319.zip /var/www/oraviewer/rgn_download/download/fcst_20100318_0319
which yields a zip file with all the downloaded files, but it contains the full /var/www/oraviewer/rgn_download/download/ directories, before reaching the fcst_20100318_0319/ directory.
I'm probably just missing a flag, or something small, from the zip command, but how do I get it to use fcst_20100318_0319/ as the root directory?
I don't think zip has a flag to do that. I think the only way is something like:
cd /var/www/oraviewer/rgn_download/download/ && \
zip -r fcst_20100318_0319.zip fcst_20100318_0319
(The backslash is just for clarity, you can remove it and put everything on one line.)
Since PHP is executing the command in a subshell, it won't change your current directory.
I have also get it worked by using this command
exec('cd '.$_SERVER['DOCUMENT_ROOT'].' && zip -r com.zip "./"');
cd /home/public_html/site/upload/ && zip -r sub_upload.zip sub_upload/
Use the -j or --junk-paths option in your zip command.
From the zip man page:
-j
--junk-paths
Store just the name of a saved file (junk the path), and do not store
directory names. By default, zip will store the full path (relative
to the current directory).
Related
I have a shell script myautoappupgrade.sh where I automate a process of application upgrade. The script has to be run on few different servers. Unfortunately, the application is located in slightly different directory on each server - the number for parent directory varies between 1-20. How I can modify the script, so that the directory can be replaced by some sort of variable? I don't want to edit the script for each server because there are many directory queries in the automation script.
example:
cd /ae1/apps/myapp/upgradefiles/
unzip file.zip
./install.sh
the directory slightly changes on another server:
cd /ae2/apps/myapp/upgradefiles/
unzip file.zip
./install.sh
and another..
cd /ae3/apps/myapp/upgradefiles/
unzip file.zip
./install.sh
Try something like this:
#!/bin/bash
num=$1
cd /ae${num}/apps/myapp/upgradefiles/file.zip
unzip file.zip
./install.sh
Then call the script with the number as first argument:
myautoappupgrade.sh 1
The simple and obvious solution is to not hard-code the directory at all. Modify the script so it accepts the parent directory as an argument, or just cd into the parent directory before running the script.
Perhaps something like this:
while read server dir; do
ssh "$server" "cd '$dir' && unzip apps/myapp/upgradefiles/file.zip/file.zip && ./install.sh"
done <<\:
ernie /ae1
bert /ae2
cookiemonster /home/cmonster/anN
:
It would probably be even better if you unzipped into a temporary directory, but hopefully this should get you moving in the right direction.
Of course, if you can be sure that /ae[0-1] is always there and there is only one match,
cd /ae[0-9]/apps/myapp/upgradefiles/file.zip
would do what you are asking.
(Do you really have a file named file.zip inside a directory also named file.zip? I'm guessing actually take away the file.zip from the end of the cd path.)
By simply using:
cd /ae*/apps/myapp/upgradefiles/
The * will expand any character.
I used command zip in linux (RedHat), this is my command:
zip -r /home/username/folder/compress/zip.zip /home/username/folder/compressed/*
Then, i open file zip.zip, i see architecture as path folder compress.
I want to in folder zip only consist list file *.txt
Because i used this command in script crontab hence i can't use command cd to path folder before run command zip
Please help me
I skimmed the zip man page and this is what I have found. There is not an option archive files relative to a different directory. The closest I have found is zip -j which removes the entire path and stores the files directly in the zip rather than sub directories. I do not know what happens in the case of file name conflicts such as if /home/username/folder/compressed/a.txt and /home/username/folder/compressed/subdir/a.txt both exist. If this is not a problem for you, you can use this option, but I am concerned because you did specify the -r option indicating that you expect zip to traverse sub folders.
I also thought of the possibility that your script could somehow call zip with a different working directory, but I took a look at this unix stack exchange page and it looks like their options use cd.
I have to admit I do not understand why you cannot use cd and I am very curious about it. You said something about using crontab, but I have never heard of anything wrong with changing directories in a crontab script.
I used option -j in command zip
zip -jr /home/username/folder/compress/zip.zip /home/username/folder/compressed/*
and i was yet settled this problem, thanks
I have a directory containing a set of subdirectories and files. I need to recursively copy all the content of this directory to all the subdirectories of another directory, also recursively.
How do I achieve this, preferably without using a script and only with the cp command?
You can write this in a script but you don't have to. Just write it line by line in the terminal:
# $TARGET is the directory containing subdirectories where you want to STORE the copies
# $SOURCE is the directory containing the subdirectories you want to COPY
for dir in $(ls $TARGET); do
cp -r $SOURCE/* $TARGET/$dir
done
Only uses cp and runs on both bash and zsh.
You can't. cp can copy multiple sources but will only copy to a single destination. You need to arrange to invoke cp multiple times - once per destination - for what you want to do; using, as you say, a loop or some other tool.
The first part of the command before the pipe instruct tar to create an archive of everything in the current directory and write it to standard output (the – in place of a file-name frequently indicates stdout).
tar cf - * | ( cd /target; tar xfp -)
The commands within parentheses cause the shell to change directory to the target directory and untar data from standard input. Since the cd and tar commands are contained within parentheses, their actions are performed together.
The -p option in the tar extraction command directs tar to preserve permission and ownership information, if possible given the user executing the command. If you are running the command as superuser, this option is turned on by default and can be omitted.
Also you can use the following command, but it seems to be quite slower than tar;
cp -a * /target
Right now to create an extension with Google Chrome Extensions page we select a directory that contains created extension and it generates .crx file.
The problem is that it contains all files from this directory - for example, all docs, asset drafts, etc.
Is it possible to create some blacklist to ignore specified files like *.psd, *.pdf, docs/* ... ?
The Chromium team decided not to implement a manifest (or similar mechanism) for including only the desired files in a .CRX.
The recommended workflow is to have a build step that outputs only the needed files in a dist directory, and to create the CRX from that directory. This is common practice for JavaScript libraries.
My solution
I have created a .crxignore custom ignore file, like this:
.*
Makefile
*.md
bin
It is made for zip command! It is different than .gitignore. You can't add comments eg! See documentation: https://linux.die.net/man/1/zip , look for --exclude word.
Now you can create a zip without ignred files:
$ zip -qr -9 -X .out/out.zip . -x#.crxignore
# ^^^^^^^^^^^^^ using ignore file
After that I can convert zip to crx file with this go script: https://github.com/mmadfox/go-crx3 You have to build it with go build -o out/crx3 crx3/main.go command (you may get missing mod errors, but there will be the commands what you have to run). --> you can move your out/crx3 to where you want. Eg: [project]/bin/crx3.
I haven't tried, maybe chrome command also can convert zip to crx.
You have to generate a private key:
$ bin/crx3 keygen .out/key.pem
Final Makefile
build:
rm -f .out/out.zip
zip -qr -9 -X .out/out.zip . -x#.crxignore
bin/crx3 pack .out/out.zip -p .out/key.pem -o .out/out.crx
Build process:
$ make build
# --> build the .out/out.crx file
Try the command line program "zip", which could be found in cygwin if you're on windows, or is likely present on OSX, and easy to install if you're using linux.
zip package.zip -r * -x package.sh -x *.git* -x "*.*~" -x "*.pdf" docs/* "*.psd"
I need to compress certain files and a directory. Suppose they're placed in /root/project.
The thing is that i need to compress them in a gzip-tarball format with certain name (name.tar.gz) and in the "root" directory, i mean, that as soon as i opened the .tar.gz all the files and directories i want to compress are there.
I have tried using the following commands:
tar czfv name.tar.gz /root/project
tar czfv name.tar.gz /root/project/*
but then the whole substructure gets compress (i mean, when i open the .tar.gz i have to navigate through the directories root/project.. which i dont, i need that the files were as soon as i opened in "/" i suppose)
I hope i've explained myself... excuse me for my bad english and thanks in advance!
If you are using GNU tar you can use the following command:
tar -C /root/project -zcvf /root/name.tar.gz .
The -C causes tar to change to the /root/project directory before adding the . directory to the archive. Make sure the destination directory for your archive is not in the directory you are archiving (/root/project). This example creates the archive in /root.
If you want the filenames in the tarball to all have a project/ prefix (which is often advisable), do
(cd /root && tar czvf `pwd`/name.tar.gz project)
If you don't want a prefix at all, do
(cd /root/project && tar czvf `pwd`/name.tar.gz .)
(The pwd captures the present working directory prior to doing the cd; the parentheses execute the command in a subshell so your current shell stays in the same directory.)