I'm not sure if this can be accomplished with regex, so here goes and hoping for the best.
If in vim I do,
:g/function
I get a list of all function rows.
Now, I'd like that but with comments (!) below until the first non comment row, so I get something like:
3 function MyFunction()
4 !This is a comment
5 !This is also a comment
23 function MyOtherFunction()
24 !This is a comment
25 !This is also a comment
Something like that possible ?
Yes
:g/^func/.;/^[^!]/-1 print
Update
An explanation was suggested...so here goes... vi(1) is powerful in part because it is a cursor-addressing extension to Ken Thompson's original line-oriented ed(1) editor. (ed(1) and its spinoff ex is still available on Linux after all these years, albeit in clone form like vi itself.) ed and its early-unix siblings were the first programs anywhere to use regular expressions.
Ok, create a file with 26 or so lines, one for each letter of your alphabet and start vi, ed, or ex. (For ed or ex, leave out the : characters.) Try:
:1;/m/p
The general form of a vi command is: addr, addr2 commmand
In my example the command is just p for print. addr1 and addr2 are usually a line number or a regular expression using /re/ to search downward or ?re? to search upward. Try /c/;/g/p which prompts me to explain: the ; causes the editor to switch to the line found by the first address before it evaluates the second address. It doesn't always matter in the default wrapscan mode but if you type :set nows (not in ed) then search patterns won't wrap and the difference between , and ; becomes bigger.
The most important line mode command wasn't used in my example but it should be mentioned here: :s/pattern/replacement/ or :s/pattern/replacement/g. This command can of course take addresses so a typical command is 1,$s/old/new/g The $ identifies the last line. The default address for most commands is the current line but for the global or g command it defaults to 1,$ and has the general form
addr1, addr2 g /pattern/ any_linemode_command
For example, say I'm Jeff but I want to blame Joel for different types of critical errors in the logs. I need to be stealthy and not change the Jeff's on mere warning lines, so I need:
g/critical.*error/s/Jeff/Joel/
That will run the substitute command on every line of the file that has the pattern "critical anything error" and then just change Jeff to Joel.
So now the answer should be fairly clear. The command works as follows: on every line of the file, check to see if the line begins with /^func/ (func at the beginning of the line) and if it does, start with . (the current line) then, resetting the current address to that line (;) search for a line that does NOT begin with !, and if it's found, subtract one from the line number found (back up slightly to the last actual comment) and then just run the print command.
Related
Apologies if this has been posted already, for I cannot find an answer, even on the vim wiki.
Is there a way I can run multiple commands in vim command-line mode off of a single :g search?
For example,
:%g/foo/ s/bar/\=#a/g | exe "norm /cat\<enter>\"ayiw"
Which (for what I intend it to do) should, on every line matching foo, replace bar with the contents of register a, and then find the next iteration of cat (even if it is many lines ahead), and put the surrounding word into register a.
Instead, this specific syntax completes the subsitution command using the current contents of the initial a register, and then executes the normal mode command on a single line (after the substitution has been completed).
This example is not my specific use-case but shows one instance where this functionality is useful. I realize I could put it all into a single exe, i.e., %g/foo/exe "norm :s/bar/\\=#a/g\<enter>/cat\<enter>\"ayiw", but I would like to do it the first way, as I feel it is more flexible.
I would prefer to do this using vanilla vim, but if a plugin exists for this, that is an okay alternative. Does anybody know if there is syntax to do such a thing?
Okay a "little bit" dirty, but does this work for you?
:let list = split(execute('g/cat/p'), '\n') | g/foo/ s/bar/\=matchstr(remove(list, 0), '\s\d\+\s\zs.*')/g
It first reads all occurences of cat save them in a list.
Then replace the first bar with the first cat... and so on.
The dirty part ist the matchstr command. the g//p also returns a number for the result so the list looks like this:
1 cat
2 cat
3 cat
...
that's why we have to remove a bit from the front. I would love to hear if someone knows a clean solution for that (I am also interested in a clean vimscript solution, does not have to be a oneliner).
You can do this (at least for multiple :s commands applied to a single :g). Example:
" SHORT STORY TITLES to single word of CapitalizedWords within <h3>s
.,$g/^\L\+$/s/[^A-Z0-9 ]\+//ge|s/\u\+/\L&/ge|s/\<\l\+\>/\u&/ge|s/ \+//ge|s/.*/<h3>&<\/h3>/
Let's say I have the following line of code:
something:somethingElse:anotherThing:woahYetAnotherThing
And I want to replace each : with a ; except the first one, such that the line looks like this:
something:somethingElse;anotherThing;woahYetAnotherThing
Is there a way to do this with the :[range]s/[search]/[replace]/[options] command without using the c option to confirm each replace operation?
As far as I can tell, the smallest range that s acts on is a single line. If this is true, then what is the fastest way to do the above task?
I'm fairly new to vim myself; I think you're right about range being lines-only (not 100% certain), but for this specific example you might try replacing all of the instances with a global flag, and then putting back the first one by omitting the global -- something like :s/:/;/g|s/;/:/.
Note: if the line contains a ; before the first : then this will not work.
Here you go...
:%s/\(:.*\):/\1;/|&|&|&|&
This is a simple regex substitute that takes care of one single not-the-first :.
The & command repeats the last substitute.
The | syntax separates multiple commands on one line. So, each substitute is repeated as many times as there are |& things.
Here is how you could use a single keystroke to do what you want (by mapping capital Q):
map Q :s/:/;/g\|:s/;/:<Enter>j
Every time you press Q the current line will be modified and the cursor will move to the next line.
In other words, you could just keep hitting Q multiple times to edit each successive line.
Explanation:
This will operate globally on the current line:
:s/:/;/g
This will switch the first semi-colon back to a colon:
:s/;/:
The answer by #AlliedEnvy combines these into one statement.
My map command assigns #AlliedEnvy's answer to the capital Q character.
Another approach (what I would probably do if I only had to do this once):
f:;r;;.
Then you can repeatedly press ;. until you reach the end of the line.
(Your choice to replace a semi-colon makes this somewhat comfusing)
Explanation:
f: - go to the first colon
; - go to the next colon (repeat in-line search)
r; - replace the current character with a semi-colon
; - repeat the last in-line search (again)
. - repeat the last command (replace current character with a semi-colon)
Long story short:
fx - moves to the next occurrence of x on the current line
; repeats the last inline search
While the other answers work well for this particular case, here's a more general solution:
Create a visual selection starting from the second element to the end of the line. Then, limit the substitution to the visual area by including \%V:
:'<,'>s/\%V:/;/g
Alternatively, you can use the vis.vim plugin
:'<,'>B s/:/;/g
I usually have the tw=80 option set when I edit files, especially LaTeX sources. However, say, I want to compose an email in Vim with the tw=80 option, and then copy and paste it to a web browser. Before I copy and paste, I want to unwrap the text so that there isn't a line break every 80 characters or so. I have tried tw=0 and then gq, but that just wraps the text to the default width of 80 characters. My question is: How do I unwrap text, so that each paragraph of my email appears as a single line? Is there an easy command for that?
Go to the beginning of you paragraph and enter:
v
i
p
J
(The J is a capital letter in case that's not clear)
For whole document combine it with norm:
:%norm vipJ
This command will only unwrap paragraphs. I guess this is the behaviour you want.
Since joining paragraph lines using Normal mode commands is already
covered by another answer, let us consider solving the same issue by
means of line-oriented Ex commands.
Suppose that the cursor is located at the first line of a paragraph.
Then, to unwrap it, one can simply join the following lines up until
the last line of that paragraph. A convenient way of doing that is to
run the :join command designed exactly for the purpose. To define
the line range for the command to operate on, besides the obvious
starting line which is the current one, it is necessary to specify
the ending line. It can be found using the pattern matching the very
end of a paragraph, that is, two newline characters in a row or,
equivalently, a newline character followed by an empty line. Thus,
translating the said definition to Ex-command syntax, we obtain:
:,-/\n$/j
For all paragraphs to be unwrapped, run this command on the first line
of every paragraph. A useful tool to jump through them, repeating
a given sequence of actions, is the :global command (or :g for
short). As :global scans lines from top to bottom, the first line
of the next paragraph is just the first non-empty line among those
remaining unprocessed. This observation gives us the command
:g/./,-/\n$/j
which is more efficient than its straightforward Normal-mode
counterparts.
The problem with :%norm vipJ is that if you have consecutive lines shorter than 80 characters it will also join them, even if they're separated by a blank line. For instance the following example:
# Title 1
## Title 2
Will become:
# Title 1 ## Title 2
With ib's answer, the problem is with lists:
- item1
- item2
Becomes:
- item1 - item2
Thanks to this forum post I discovered another method of achieving this which I wrapped in a function that works much better for me since it doesn't do any of that:
function! SoftWrap()
let s:old_fo = &formatoptions
let s:old_tw = &textwidth
set fo=
set tw=999999 " works for paragraphs up to 12k lines
normal gggqG
let &fo = s:old_fo
let &tw = s:old_tw
endfunction
Edit: Updated the method because I realized it wasn't working on a Linux setup. Remove the lines containing fo if this newer version doesn't work with MacVim (I have no way to test).
So oftentimes, while editing with Vim, I'll get into a variety of situations where whitespace gives me hassle. For example, say I have a comment like this:
#This program was featured on the Today show, it is an algorithm for promoting world peace in third-world countries
#given the name of that country and the name of a celebrity to endorse its cause
If I want to, for example, trim the lines so they go to X characters, I end up putting a newline somewhere in the middle of the top line to get this (after hitting the newline and auto-indenting):
#This program was featured on the Today show, it is an algorithm for promoting
world peace in third-world countries
#given the name of that country and the name of a celebrity to endorse its cause
I then add a # to the beginning of the line, and that's all well and good, but then I want that line to line up, too. To do so, I have to delete the newline, all the whitespace for the indent on the next line, and then the commenting # mark. It doesn't take an awfully long amount of time to do that, but this and similar situations all add up over a day's worth of coding.
Now the example above is pretty specific, but my question isn't. What's a good way in Vim to delete all whitespace INCLUDING NEWLINES up until the next non-whitespace character? If Vim already has movements that do that, that would be awesome, but if not, does anyone have a favorite Vim function they use to do the above that could be mapped to a key? At the very least, am I missing some Vim usage idiom that prevents me from even having to worry about this case?
EDIT: Formatting to width, while useful and applicable to the case above, isn't the focus of this question. I'm concerned more with whitespace removal that doesn't stop at the end of a line, but instead carries on to the first non-whitespace character of the next line.
You really just want to reformat that comment to fit the current 'textwidth'. If the comment is a paragraph (i.e., separated by a line of whitespace above and below), then you can just use gqip (gq is the reformat command, ip is the "inner-paragraph" text object) to reformat it. If it's not a standalone paragraph, you can visually select those lines and then use gq.
This likely also relies on having 'formatoptions' set correctly to make sure the comment characters are handled properly, but in many cases the ftplugin has already done that.
This is a while later, but I found that there is a command that does what I need to in 90% of circumstances:
J -- join line below to the current one
This command seems to work:
:.s/\W*$\n\W*//g
it uses a replace to remove whitespace up to end of line and the new line at the end.
In this example:
testting aad $
asdjkasdjsdaksddjk$
(to see meta characters in vim use the command :set list)
if you place the cursor on the first line and use the first command it will delete everything from aad to $ (not including aad but including $ and a newline.)
Also, note for what you are doing it is far more efficient to use an external program to format comments for you. In particular, par is a great small C program that edits text and wraps it to desired lengths.
If you have par in your path, to do what you are trying to do is as easy as selecting the block of comment with Shift+v and running the command
:!par 40pgr
where 40 is the desired width in columns.
If you are feeling hackish, write your own program in C/perl/C++/python that edits comments however you like, then put it in path and use the external filter command :! to process blocks of text through it.
I want to search for a string and find the number of occurrences in a file using the vi editor.
THE way is
:%s/pattern//gn
You need the n flag. To count words use:
:%s/\i\+/&/gn
and a particular word:
:%s/the/&/gn
See count-items documentation section.
If you simply type in:
%s/pattern/pattern/g
then the status line will give you the number of matches in vi as well.
:%s/string/string/g
will give the answer.
(similar as Gustavo said, but additionally: )
For any previously search, you can do simply:
:%s///gn
A pattern is not needed, because it is already in the search-register (#/).
"%" - do s/ in the whole file
"g" - search global (with multiple hits in one line)
"n" - prevents any replacement of s/ -- nothing is deleted! nothing must be undone!
(see: :help s_flag for more informations)
(This way, it works perfectly with "Search for visually selected text", as described in vim-wikia tip171)
:g/xxxx/d
This will delete all the lines with pattern, and report how many deleted. Undo to get them back after.
Short answer:
:%s/string-to-be-searched//gn
For learning:
There are 3 modes in VI editor as below
: you are entering from Command to Command-line mode. Now, whatever you write after : is on CLI(Command Line Interface)
%s specifies all lines. Specifying the range as % means do substitution in the entire file. Syntax for all occurrences substitution is :%s/old-text/new-text/g
g specifies all occurrences in the line. With the g flag , you can make the whole line to be substituted. If this g flag is not used then only first occurrence in the line only will be substituted.
n specifies to output number of occurrences
//double slash represents omission of replacement text. Because we just want to find.
Once got the number of occurrences, you can Press N Key to see occurrences one-by-one.
For finding and counting in particular range of line number 1 to 10:
:1,10s/hello//gn
Please note, % for whole file is repleaced by , separated line numbers.
For finding and replacing in particular range of line number 1 to 10:
:1,10s/helo/hello/gn
use
:%s/pattern/\0/g
when pattern string is too long and you don't like to type it all again.
I suggest doing:
Search either with * to do a "bounded search" for what's under the cursor, or do a standard /pattern search.
Use :%s///gn to get the number of occurrences. Or you can use :%s///n to get the number of lines with occurrences.
** I really with I could find a plug-in that would giving messaging of "match N of N1 on N2 lines" with every search, but alas.
Note:
Don't be confused by the tricky wording of the output. The former command might give you something like 4 matches on 3 lines where the latter might give you 3 matches on 3 lines. While technically accurate, the latter is misleading and should say '3 lines match'. So, as you can see, there really is never any need to use the latter ('n' only) form. You get the same info, more clearly, and more by using the 'gn' form.