Subsonic Compare Two Objects - subsonic

I would like to use this generic CompareObjects class but it seems that the Subsonic record objects don't implement IComparable.
User userFromDB = User.SingleOrDefault(x => x.UserName == "CmdrTallen");
User modifiedUser = new User();
TryUpdateModel(modifiedUser);
if(CompareOjbects<User>(userFromDB, modifiedUser) != 0)
{
this.log("User was modified")
//+ Add modified columns collection to log here
}
Am I re-inventing the wheel? Perhaps a easier way?

What I ended up doing is using this Generic Serializer to take both DB stored record (userFromDB) and modified user (modifiedUser). Serializing them to XML and then using this to create a diffgram. Exactly what I needed.
woot!

By default the AR template overrides Equals() to compare primary keys instead of base Object comparison. You can change this by changing the ActiveRecord.tt file.

Related

Use JOOQ Multiset with custom RecordMapper - How to create Field<List<String>>?

Suppose I have two tables USER_GROUP and USER_GROUP_DATASOURCE. I have a classic relation where one userGroup can have multiple dataSources and one DataSource simply is a String.
Due to some reasons, I have a custom RecordMapper creating a Java UserGroup POJO. (Mainly compatibility with the other code in the codebase, always being explicit on whats happening). This mapper sometimes creates simply POJOs containing data only from the USER_GROUP table, sometimes also the left joined dataSources.
Currently, I am trying to write the Multiset query along with the custom record mapper. My query thus far looks like this:
List<UserGroup> = ctx
.select(
asterisk(),
multiset(select(USER_GROUP_DATASOURCE.DATASOURCE_ID)
.from(USER_GROUP_DATASOURCE)
.where(USER_GROUP.ID.eq(USER_GROUP_DATASOURCE.USER_GROUP_ID))
).as("datasources").convertFrom(r -> r.map(Record1::value1))
)
.from(USER_GROUP)
.where(condition)
.fetch(new UserGroupMapper()))
Now my question is: How to create the UserGroupMapper? I am stuck right here:
public class UserGroupMapper implements RecordMapper<Record, UserGroup> {
#Override
public UserGroup map(Record rec) {
UserGroup grp = new UserGroup(rec.getValue(USER_GROUP.ID),
rec.getValue(USER_GROUP.NAME),
rec.getValue(USER_GROUP.DESCRIPTION)
javaParseTags(USER_GROUP.TAGS)
);
// Convention: if we have an additional field "datasources", we assume it to be a list of dataSources to be filled in
if (rec.indexOf("datasources") >= 0) {
// How to make `rec.getValue` return my List<String>????
List<String> dataSources = ?????
grp.dataSources.addAll(dataSources);
}
}
My guess is to have something like List<String> dataSources = rec.getValue(..) where I pass in a Field<List<String>> but I have no clue how I could create such Field<List<String>> with something like DSL.field().
How to get a type safe reference to your field from your RecordMapper
There are mostly two ways to do this:
Keep a reference to your multiset() field definition somewhere, and reuse that. Keep in mind that every jOOQ query is a dynamic SQL query, so you can use this feature of jOOQ to assign arbitrary query fragments to local variables (or return them from methods), in order to improve code reuse
You can just raw type cast the value, and not care about type safety. It's always an option, evne if not the cleanest one.
How to improve your query
Unless you're re-using that RecordMapper several times for different types of queries, why not do use Java's type inference instead? The main reason why you're not getting type information in your output is because of your asterisk() usage. But what if you did this instead:
List<UserGroup> = ctx
.select(
USER_GROUP, // Instead of asterisk()
multiset(
select(USER_GROUP_DATASOURCE.DATASOURCE_ID)
.from(USER_GROUP_DATASOURCE)
.where(USER_GROUP.ID.eq(USER_GROUP_DATASOURCE.USER_GROUP_ID))
).as("datasources").convertFrom(r -> r.map(Record1::value1))
)
.from(USER_GROUP)
.where(condition)
.fetch(r -> {
UserGroupRecord ug = r.value1();
List<String> list = r.value2(); // Type information available now
// ...
})
There are other ways than the above, which is using jOOQ 3.17+'s support for Table as SelectField. E.g. in jOOQ 3.16+, you can use row(USER_GROUP.fields()).
The important part is that you avoid the asterisk() expression, which removes type safety. You could even convert the USER_GROUP to your UserGroup type using USER_GROUP.convertFrom(r -> ...) when you project it:
List<UserGroup> = ctx
.select(
USER_GROUP.convertFrom(r -> ...),
// ...

Is it possibile to update an entity saved into my database with Graph?

i am using the Graph library in order to save my data correctly.
I was wondering, if there's a way to update an existing Entity, without duplicate the entity 2 times: user will be allowed to update just two values of the entity.
Also, i would like to know if there's a proper save method
I give you an example
let person = Entity(type: "Person")
person["name"] = //not editable
person["work"] = //editable
person["age"] = //editable
graph.sync() //or something like graph.update
Writing this, i am just creating a new entity, which is not what i want. Maybe, i have to search for the entity, delete that every time, and insert the new one?Hope not.
Thank you for any help you could give!
yes, you can update Entities.
You need to search for the one you want to update first. For example:
let graph = Graph()
let search = Search<Entity>(graph: graph).for(types: "Person")
for entity in search.sync() {
// do something
}
Once you have the entity you want to update, you can set any property, group, or tag as per usual.
entity["name"] = "Daniel"
From there you need to call graph.sync() or graph.async() so that all is saved.
Thats it :)

How can I ensure CassandraOperations.selectOneById() initializes all fields in the POJO?

I'm using Spring Data Cassandra 1.3.4.RELEASE to persist instances of a class that I have. The class is written in Groovy, but I don't think that really matters. I have implemented a CrudRepository, and I'm injecting an instance of CassandraOperations into the repo implementation class. I can insert, delete, and do most of the other operations successfully. However, there's a scenario I'm running into which breaks my test case. My entity class looks something like this:
#Table("foo")
class FooData {
#PrimaryKey("id")
long id
#Column("created")
long updated
#Column("name")
String name
#Column("user_data")
String userData
#Column("numbers")
List numberList = []
}
In my test case, I happened to only set a few fields like 'id' and 'updated' before calling CassandraOperations.insert(entity), so most of them were null in the entity instance at the time of insertion. But the numberList field was not null, it was an empty List. Directly after the insert(), I'm calling CassandraOperations.selectOneById(FooData.class, id). I get a FooData instance back, and the fields that were initialized when I saved it are populated with data. However, I was checking content equality in my test, and it failed because the empty list was not returned as an empty list in the POJO coming back from CassandraOperations.selectOneById(). It's actually null. I assume this may be some sort of Cassandra optimization. It seems to happen in the CGLIB code that instantiates the POJO/entity. Is this a known "feature"? Is there some annotation I can mark the 'numberList' field with to indicate that it cannot be null? Any leads are appreciated. Thanks.
In short
Cassandra stores empty collections as null and Spring Data Cassandra overwrites initialized fields.
Explanation
Cassandra list/set typed columns represent an empty collection as null. It does not matter whether the list/set (as viewed from Java/Groovy) was empty or null. Storing an empty list yields therefore in null. From here one can't tell whether the state was null or empty at the time saving the value.
Spring Data Cassandra overwrites all fields with values retrieved from the result set and so your pre-initialized fields is set to null.
I created a ticket DATACASS-266 to track the state of this issue.
Workaround
Spring Data uses setters if possible so you have a chance to intervene. A very simple null guard could be:
public void setMyList(List<Long> myList) {
if(myList == null){
this.myList = new ArrayList<>();
return;
}
this.myList = myList;
}
As important addition to mp911de answer you have to set #org.springframework.data.annotation.AccessType(AccessType.Type.PROPERTY) to make this solution work.

Retrieving Properties from DbSqlQuery

Background: Project is a Data Import utility for importing data from tsv files into a EF5 DB through DbContext.
Problem: I need to do a lookup for ForeignKeys while doing the import. I have a way to do that but the retrieval if the ID is not functioning.
So I have a TSV file example will be
Code Name MyFKTableId
codevalue namevalue select * from MyFKTable where Code = 'SE'
So when I process the file and Find a '...Id' column I know I need to do a lookup to find the FK The '...' is always the entity type so this is super simple. The problem I have is that I don't have access to the properties of the results of foundEntity
string childEntity = column.Substring(0, column.Length - 2);
DbEntityEntry recordType = myContext.Entry(childEntity.GetEntityOfReflectedType());
DbSqlQuery foundEntity = myContext.Set(recordType.Entity.GetType()).SqlQuery(dr[column])
Any suggestion would be appreciated. I need to keep this generic so we can't use known type casting. The Id Property accessible from IBaseEntity so I can cast that, but all other entity types must be not be fixed
Note: The SQL in the MyFKTableId value is not a requirement. If there is a better option allowing to get away from SqlQuery() I would be open to suggestions.
SOLVED:
Ok What I did was create a Class called IdClass that only has a Guid Property for Id. Modified my sql to only return the Id. Then implemented the SqlQuery(sql) call on the Database rather than the Set([Type]).SqlQuery(sql) like so.
IdClass x = ImportFactory.AuthoringContext.Database.SqlQuery<IdClass>(sql).FirstOrDefault();
SOLVED:
Ok What I did was create a Class called IdClass that only has a Guid Property for Id. Modified my sql to only return the Id. Then implemented the SqlQuery(sql) call on the Database rather than the Set([Type]).SqlQuery(sql) like so.
IdClass x = ImportFactory.AuthoringContext.Database.SqlQuery<IdClass>(sql).FirstOrDefault();

Entity Framework 4.1 & existing database

Hi I have an existing database with a table with 30 fields, I want to split the table into many models so I could retrieve/save fields that I need and not every time retrieve/save the whole object from the db. using c#.
I think I should be using Code-First. Could someone provide an example or a tutorial link?
thanks,
You don't need to split table to be able to load a subset of field or persist subset of fields. Both operations are available with the whole table mapped to single entity as well.
For selection you simply have to use projection:
var data = from x in context.HugeEntities
select new { x.Id, x.Name };
You can use either anonymous type in projection or any non-mapped class.
For updates you can simply use:
var data = new HugeEntity { Id = existingId, Name = newName };
context.HugeEntities.Attach(data);
var dataEntry = context.Entry(data);
dataEntry.Property(d => d.Name).IsModified = true; // Only this property will be updated
context.SaveChanges();
Or:
var data = new HugeEntity { Id = existingId };
context.HugeEntities.Attach(data);
data.Name = newName;
context.SaveChanges(); // Now EF detected change of Name property and updated it
Mapping multiple entities to single table must follows very strict rules and it is possible only with table splitting were all entities must be related with one-to-one relation (and there are some problems with more than two entities per split table in code first) or with table-per-hierarchy inheritance. I don't think that you want to use any of them for this case.

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