What command can I run to remove blank lines in Vim?
:g/^$/d
:g will execute a command on lines which match a regex. The regex is 'blank line' and the command is :d (delete)
Found it, it's:
g/^\s*$/d
Source: Power of g at vim wikia
Brief explanation of :g
:[range]g/pattern/cmd
This acts on the specified [range] (default whole file), by executing the Ex command cmd for each line matching pattern (an Ex command is one starting with a colon such as :d for delete). Before executing cmd, "." is set to the current line.
:v/./d
or
:g/^$/d
or
:%!cat -s
The following can be used to remove only multi blank lines (reduce them to a single blank line) and leaving single blank lines intact:
:g/^\_$\n\_^$/d
how to remove all the blanks lines
:%s,\n\n,^M,g
(do this multiple times util all the empty lines went gone)
how to remove all the blanks lines leaving SINGLE empty line
:%s,\n\n\n,^M^M,g
(do this multiple times)
how to remove all the blanks lines leaving TWO empty lines AT MAXIMUM,
:%s,\n\n\n\n,^M^M^M,g
(do this multiple times)
in order to input ^M, I have to control-Q and control-M in windows
How about:
:g/^[ \t]*$/d
This works for me
:%s/^\s*$\n//gc
work with perl in vim:
:%!perl -pi -e s/^\s*$//g
I tried a few of the answers on this page, but a lot of them didn't work for me. Maybe because I'm using Vim on Windows 7 (don't mock, just have pity on me :p)?
Here's the easiest one that I found that works on Vim in Windows 7:
:v/\S/d
Here's a longer answer on the Vim Wikia: http://vim.wikia.com/wiki/Remove_unwanted_empty_lines
Press delete key in insert mode to remove blank lines.
This function only remove two or more blank lines, put the lines below in your vimrc, then use \d to call function
fun! DelBlank()
let _s=#/
let l = line(".")
let c = col(".")
:g/^\n\{2,}/d
let #/=_s
call cursor(l, c)
endfun
map <special> <leader>d :keepjumps call DelBlank()<cr>
:g/^\s*$/d
^ begin of a line
\s* at least 0 spaces and as many as possible (greedy)
$ end of a line
paste
:command -range=% DBL :<line1>,<line2>g/^\s*$/d
in your .vimrc,then restart your vim.
if you use command :5,12DBL
it will delete all blank lines between 5th row and 12th row.
I think my answer is the best answer!
If something has double linespaced your text then this command will remove the double spacing and merge pre-existing repeating blank lines into a single blank line. It uses a temporary delimiter of ^^^ at the start of a line so if this clashes with your content choose something else. Lines containing only whitespace are treated as blank.
%s/^\s*\n\n\+/^^^\r/g | g/^\s*$/d | %s/^^^^.*
This worked for me:
:%s/^[^a-zA-Z0-9]$\n//ig
It basically deletes all the lines that don't have a number or letter. Since all the items in my list had letters, it deleted all the blank lines.
Related
I have a text file with about 2,000 lines of text and I want to remove a large portion of each line of text.
The text is in this format:
Important Text that I care about. Stuff I want to delete
I am unsure as to how to delete all of the text after the . in each line.
Can someone give me a quick command that would do this?
With substitutions:
:%s/\..*/./
With :normal command:
:%norm f.lD
Various additional :normal solutions:
:%norm )Dx
:%norm $T.D
:%norm f.C.
:%norm 0/\. /e<C-v><CR>D
Use the Substitution Ex Command to Trim All Lines
This is very similar to both answers, yet I think there is value in presenting it.
Like the other answers, I just used the ex substitution command:
:%s/[^.]*$//
Explanation of substitution:
% indicates a range for all lines.
[^.] is a character class of all non-period characters
* is a quantifier indicating 0 or more matches.
$ is an anchor which communicates to VIM that we want this pattern to match at the end of the line.
Addendum
The solution assumes each line will have a period, otherwise the command will not work as expected as #Qeole has indicated. Qeole's solution addresses non-periods lines appropriately.
Use search and replace "vim feature" combined with regex:
:%s/\..*$//g
with the cursor at the first character of first line.
fS<Ctrl-V>G$d
I'm reviewing some logs with Java exception spam. The spam is getting is making it hard to see the other errors.
Is is possible in vim to select a block of text, using visual mode. Delete that block every place it occurs in the file.
If vim can't do it, I know silly question, vim can do everything. What other Unix tools might do it?
Sounds like you are looking for the :global command
:g/pattern/d
The :global command takes the form :g/{pat}/{cmd}. Read it as: run command, {cmd}, on every line matching pattern, {pat}.
You can even supply a range to the :delete (:d for short) command. examples:
:,+3d
:,/end_pattern/d
Put this togehter with the :global command and you can accomplish a bunch. e.g. :g/pat/,/end_pat/d
For more help see:
:h :g
:h :d
:h :range
Vim
To delete all matching lines:
:g/regex/d
To only delete the matches themselves:
:%s/regex//g
In either case, you can copy the visual selection to the command line by yanking it and then inserting it with <C-r>". For example, if your cursor (|) is positioned as follows:
hello wo|rld
Then you can select world with viw, yank the selection with y, and then :g/<C-r>"/d.
sed
To delete all matching lines:
$ sed '/regex/d' file
To only delete the matches themselves:
$ sed 's/regex//g' file
grep
To delete all matching lines:
$ grep -v 'regex' file
grep only operates line-wise, so it's not possible to only delete matches within lines.
you can try this in vim
:g/yourText/ d
Based on our discussion in the comments, I guess a "block" means several complete lines. If the first and last lines are distinctive, then the method you gave in the comments should work. (By "distinctive" I mean that there is no danger that these lines occur anywhere else in your log file.)
For simplifications, I would use "ay$ to yank the first line into register a and "by$ to yank the last line into register b instead of using Visual mode. (I was going to suggest "ayy and "byy, but that wold capture the newlines)
To be on the safe side, I would anchor the patterns: /^{text}$/ just in case the log file contains a line like "Note that {text} marks the start of the Java exception." On the command line, I would use <C-R>a and <C-R>b to paste in the contents of the two registers, as you suggested.
:g/^<C-R>a$/,/^<C-R>b$/d
What if the yanked text includes characters with special meaning for search patterns? To be on the really safe side, I would use the \V (very non-magic) modifier and escape any slashes and backslashes:
:g/\V\^<C-R>=escape(#a, '/\')<CR>\$/,/\V\^<C-R>=escape(#b, '/\')<CR>\$/d
Note that <C-R>= puts you on a fresh command line, and you return to the main one with <CR>.
It is too bad that \V was not available when matchit was written. It has to deal with text from the buffer in a search pattern, much like this.
Suppose I'm editing the following document (* = cursor):
Lions
Tigers
Kittens
Puppies
*
Humans
What sequence can I use to delete the surrounding white space so that I'm left with:
Lions
Tigers
Kittens
Puppies
*
Humans
Note: I'm looking for an answer that handles any number of empty lines, not just this exact case.
EDIT 1: Line numbers are unknown and I only want to effect the span my cursor is in.
EDIT 2: Edited example to show I need to preserve leading whitespace on edges
Thanks
Easy. In normal mode, dipO<Esc> should do it.
Explanation:
dip on a blank line deletes it and all adjacent blank lines.
O<Esc> opens a new empty line, then goes back to normal mode.
Even more concise, cip<Esc> would roll these two steps into one, as suggested by #Lorkenpeist.
A possible solution is to use the :join command with a range:
:?.?+1,/./-1join!
Explanation:
[range]join! will join together a [range] of lines. The ! means with out inserting any extra space.
The starting point is to search backwards to the first character then down 1 line, ?.?+1
As the 1 in +1 can be assumed this can be abbreviated ?.?+
The ending point is to search forwards to the next character then up 1 line, /./-1
Same as before the 1 can be assumed so, /./-
As we are using the same pattern only searching forward the pattern can be omitted. //-
The command :join can be shorted to just :j
Final shortened command:
:?.?+,//-j!
Here are some related commands that might be handy:
1) to delete all empty lines:
:g/^$/d
:v/./d
2) Squeeze all empty lines into just 1 empty line:
:v/./,//-j
For more help see:
:h :j
:h [range]
:h :g
:h :v
Short Answer: ()V)kc<esc>
In normal mode, if you type () your cursor will move to the first blank line. ( moves the cursor to the beginning of the previous block of non-blank lines, and ) moves the cursor to the end (specifically, to the first blank line after said block). Then a simple d) will delete all text until the beginning of the next non-blank line. So the complete sequence is ()d).
EDIT: You're right, that deletes the whitespace at the beginning of the next non-blank line. Instead of d) try V)kd. V puts you in visual line mode, ) jumps to the first non-blank line (skipping the whitespace at the beginning of the line), k moves the cursor up one line. At this point you've selected all the blank lines, so d deletes the selection.
Finally, type O (capital O) followed by escape to crate a new blank line to replace the ones you deleted. Alternatively, replacing dO<Escape> with c<Escape> does the same thing with one less keystroke, so the entire sequence would be ()V)kc<Esc>.
These answers are irrelevant after the updated question:
This may not be the answer you want to hear, but I would make use of ranges. Take a look at the line number for the first empty line (let's say 55 for example) and the second to last empty line (perhaps 67). Then just do :55,67d.
Or, perhaps you only want there to ever be one empty line in your whole file. In that case you can match any occurrence of one or more empty lines and replace them with one empty line.
:%s/\(^$\n\)\+/\r/
This answer works:
If you just want to use normal mode you could search for the last line with something on it. For instance,
/.<Enter>kkVNjd
I didn't test so much, but it should work for your examples. There maybe more elegant solutions.
function! DelWrapLines()
while match(getline('.'),'^\s*$')>=0
exe 'normal kJ'
endwhile
exe 'silent +|+,/./-1d|noh'
exe 'normal k'
endfunction
source it and try :call DelWrapLines()
I know this question has already been resolved, but I just found a great solution in "sed & awk, 2nd Ed." (O'Reilly) that I thought was worth sharing. It does not use vim at all, but instead uses sed. This script will replace all instances of one or more blank lines (assuming there is no whitespace in those lines) with a single blank line. On the command line:
sed '/ˆ$/{
N
/ˆ\n$/D
}' myfile
Keep in mind that sed does not actually edit the file, but instead prints the edited lines to standard output. You can redirect this input to a file:
sed '/ˆ$/{
N
/ˆ\n$/D
}' myfile > tempfile
Be careful though, if you try to write it directly to myfile, it will just delete the entire contents of the file, which is clearly not what you want! After you write the output to tempfile, you can just mv tempfile myfile and tada! All instances of multiple blank lines are replaced by a single blank line.
Even better:
cat -s myfile > temp
mv temp myfile
cat is awesome, yes?
Bestest:
If you want to do it inside vim, you can replace all instances of multiple blank lines with a single blank line by using vim's handy feature of executing shell commands on a range of lines within vim.
:%!cat -s
That's all it takes, and your entire file is reformatted all nice!
Is there a command to delete a line (or several lines) that is immediately below current line?
Currently I'm doing it as:
jdd and then . to repeat as needed.
Is there a command that would combine all these?
UPDATE: The reason I would like to have such command is that I don't like to move away from current position, yet be able to delete lines below.
The delete ex command will work nicely.
:+,$d
This will delete all the lines from current +1 till the end ($)
To delete the next 2 lines the follow range would work, +1,+2 or shorthand +,+2
:+,+2d
As #ib mentioned the :delete or :d command will move the cursor to the start of the line next to the deleted text. (Even with nostartofline set). To overcome this we can issue the `` normal mode command. `` will jump back to the exact position before the last jump, in this case the :d command. Our command is now
:+,+2denter``
Or as one ex command
:+,+2d|norm! ``
To make this easier we wrap this all up in a command:
command! -count=1 -register D :+,+<count>d <reg><bar>norm! ``
Now to delete the next following 3 lines:
:3D
This command can also take a {reg} like :delete and :yank do. So deleting the next 4 lines into register a would be:
:4D a
For more information
:h :d
:h :command
:h :command-register
:h :command-count
:h ``
dG should work.
This means delete all rows until end of file from current cursor.
This will delete ALL lines below the current one:
jdG
Unfortunately that will move the cursor to the beginning of current line after the deletion is made.
well, to do it simply you could use the xxdd command. Most of the time I know (at least have an idea) the size of the script I am editing. So, the command as below is usually more than enough :
99dd
999dd to remove 999lines starting at the cursor position.
9999dd
99999dd for very long script ;)
The other solutions are informative, but I feel it'd be simpler to use a macro for this:
qq (begins recording)
jddk (go down, delete the line, and go back up - i.e. the thing you want to do)
q (end recording)
Now you can do #q to perform this action, maintaining the cursor at the current position. You could also do something like 5#q to delete 5 lines below the cursor.
And finally, if you're repeating the action more than once, you could just type ## after the first time you run #q (this repeats the last used macro - in this case q)
This is a job for marks!
Try maj20dd`a
ma sets the file-specific mark 'a', j20dd does the deletion you want (20 lines in this case), and `a restores you to the mark's position (line and column).
Obviously this pattern can be extended to do anything you want before returning to the mark. If you use mA (or any other capital letter) the mark will actually be unique across files, so you can even edit elsewhere before returning. If you have a very frequent usage you could make it a macro as suggested above.
You could enter the number of lines to delete: j 20 dd k.
Just for the fun of it, you can define a little function that does
exactly what you described: deletes the next n lines below the
current line and restores the initial cursor position.
function! DeleteNextLines(n, reg)
let l = line('.')
let m = min([a:n, line('$')-l])
if m > 0
let c = col('.')
exe '+,+'.m 'd' a:reg
call cursor(l, c)
endif
endfunction
Also, you can define a command that accepts the number of lines
to delete (one, if omitted) and the register name to use as an
optional argument (just like the :delete command).
:command! -range=1 -register -bar D call DeleteNextLines(<count>, <q-reg>)
Additionally, you can define a mapping for triggering the above
:D command, if it is necessary.
How do I delete first word of each line in Vim?
How about a pattern on each line?
:normal to the rescue:
:%norm dw
It basically replays the arguments as if you were typing them in normal ('non-edit') mode.
From :help :
:norm[al][!] {commands}
Execute Normal mode commands {commands}.
This makes it possible to execute Normal mode commands typed on the
command-line. {commands} is executed like it is typed.
Going for cryptic here, in true vi style:
1Gq10dwjq100000#1
Randy fixed this up in the comments to work on more than 100000 lines:
ggqqdwj#qq#q
For those starting out with Vim, this breaks down to:
gg - Go to first line
qq - Record a macro into register 'q'
dwj#q - The macro:
dw - delete word at cursor
j - go down one line
#q - run the macro in register 'q'
q - Stop recording the macro
#q - Execute the macro in register 'q'
In essence, the macro is recursive - it deletes a word, moves down a line, then calls itself again, repeating for each line until end of file. The final '#q' is the initial (manual) call needed to set the macro off on every line.
I would use something like the following:
:%s/^\w+\s+//
The regular expression will match one or more "word" characters starting at the beginning of the line followed by at least one whitespace character. It will remove the word and any following whitespace. If a line can contain only a single word -- and you still want it removed -- you could use alternation to match either whitespace or the end of line.
:%s/^\w+(\s+|$)//
First word (where word is defined as no whitespace)
:%s/^\s*[^ ]* //g
Delete pattern:
:%s/< insert pattern here >//g
What about this?
:%!cut -s -d' ' -f2-
:%s,^[^ ]*,,
From the beginning of the line match anything, but not a space and replace with none.
Although this is an old question, if someone else is looking to do this you could do use visual block.
press ctrl+v
select all the lines you would want to edit
now use arrow keys to select the entire word
press 'x'
That would delete the first word in all the lines. This method is especially very handy to edit log files