Single formula with Multiple Countifs and where data table contains duplicate values in more than one column - excel

The excel file contains a structure table. (which I find difficult to work with but I can't alter the file structure, I am just adding a summary tab with various counts from the data table.)
Item
Month
1
2
2
2
2
2
2
3
3
3
3
4
The item number itself can repeat and be repeated within the same month.
I was able to get a count of total number of unique items using this formula.
=SUMPRODUCT((Item_tab[Item]<>"")/COUNTIF(Item_tab[Item],Item_tab[Item]&""))
Looking for how to count the number of unique items within a specific month.?
Example of Desired output.
Edit/Set formula for Month 2 , output should be 2
Edit/Set formula for Month 3 , output should be 2
Edit/Set formula for Month 4 , output should be 1
I cannot figure out how to apply countifs to something that needs to avoid duplicates in multiple columns.
Tried this but returns #VALUE!
=SUMPRODUCT((Item_tab[Item]<>"")/COUNTIFS(Item_tab[Item],Item_tab[Item]&"",'Item'!M:M,6))
The month column was added later and I don't know how why or how to get that column to have the structured table column Header like everything else.
The sheet name is Item
The Table Name is Item_tab
I can find where to rename the table but not the columns. Not sure the variance is causing an issue. The month column is absolutely part of the table in every way that I can see.

You can try the following in cell D2:
=LET(A, A2:A7, B, B2:B7, uxB, UNIQUE(B), cnts, BYROW(uxB, LAMBDA(u,
ROWS(UNIQUE(FILTER(A, B=u))))), HSTACK(uxB, cnts))
Here is the output:
If you want to get the result repeated instead of consolidating the result by unique months, you can try the following:
=LET(A, A2:A7, B, B2:B7, uxB, UNIQUE(B), BYROW(B, LAMBDA(u,
ROWS(UNIQUE(FILTER(A, B=u))))))
If you don't have such function available, you can try the following formula in D2, it produces the same result as the first formula:
=CHOOSE({1,2}, UNIQUE(B2:B7),
MMULT(N(MMULT(TRANSPOSE(N(B2:B7=TRANSPOSE(UNIQUE(B2:B7)))),
N(A2:A7=TRANSPOSE(UNIQUE(A2:A7))))>0), SEQUENCE(ROWS(UNIQUE(A2:A7)),,1,0)))
or using LET for a better reading and maintenance:
=LET(A, A2:A7, B, B2:B7, CHOOSE({1,2}, UNIQUE(B),
MMULT(N(MMULT(TRANSPOSE(N(B=TRANSPOSE(UNIQUE(B)))),
N(A=TRANSPOSE(UNIQUE(A))))>0), SEQUENCE(ROWS(UNIQUE(A)),,1,0))))

Related

Number occurrences in another cell (Excell) [duplicate]

I have simple problem, but I've not be able to get an answer from searching. I require a column to calculate the number of the nth occurrence of a value. It's best explained in this picture
I require a method to calculate column B.
I'd be very grateful for any help.
Are you looking to merely provide a count of the distinct entries of column A in column B? Or merely add a formula to come up with the table in your link?
If the latter, then the formula to write in cell B2 is:
=COUNTIF(A$2:A2,A2)
then copy/paste it down column B. Note - if your data is both a Date and Time, but the cell is formatted to only display a date, you may not get the results you want. You'd need to interject a new column with a "floor" calculation to round the date/time value to a date (Excel date times are decimal, with integer part dictating the date, and remaining 0.0 -> 1.0 dictating the time of day)
If you just want to derive a table of the counts of distinct entries in column A, then a pivot table will do this for you - simple add a pivot table to cover the data in column A, then select column A into the rows category, and then also drag it into the values category, ensuring the field is set to "Count of". You should then have a table with the distinct entries in your data set in one column, and the count of their occurrences in the other column.
You can use the COUNTIF worksheet function, with a relative address.
Eg. In cell B2, enter this formula:
=COUNTIF(A$2:A2,A2)
And then fill-down.
Use the following formula to generate the required series:
=COUNTIF($A$1:A1,A1) and strech(copy) it in all the cells
This will generate result like this:
A 1 COUNTIF($A$1:A1,A1)
A 2 COUNTIF($A$1:A2,A2)
C 1 COUNTIF($A$1:A3,A3)
C 2 COUNTIF($A$1:A4,A4)
B 1 COUNTIF($A$1:A5,A5)
B 2 COUNTIF($A$1:A6,A6)
A 3 COUNTIF($A$1:A7,A7)
C 3 COUNTIF($A$1:A8,A8)
D 1 COUNTIF($A$1:A9,A9)
D 2 COUNTIF($A$1:A10,A10)
D 3 COUNTIF($A$1:A11,A11)
D 4 COUNTIF($A$1:A12,A12)

How to create a dynamic formula to find the average of a set of values for a given vector

I am trying to create a formula that gives me the average of the last 12 entries in a given dataset depending on the associated vector.
Let's make an example:
I have in column F2,G2,H2 and I2 dates, Company1, Company2 and Company3 respectively. Then from row3 to row 33 I have months dates starting from May 2016.
Date Company1 Company2 Company3
May-16 2,453,845
Jun-16 13,099,823
Jul-16 14,159,037
Aug-16 38,589,050 8,866,101
Sep-16 63,290,285 13,242,522
Oct-16 94,005,364 14,841,793
Nov-16 123,774,792 7,903,600 41,489,883
Dec-16 93,355,037 12,449,604 69,117,105
Jan-17 47,869,982 13,830,712 83,913,764
Feb-17 77,109,905 10,361,555 68,176,643
The goal is to create a formula that, when I drag it down, correctly calculates the average of the last 12 values for a given company.
So for example i would have, say in table "B2:C5":
Company1 76,856,345
Company2 11,120,859
Company3 65,674,349
And, if a new Company4 is added to the list, then I just have to drag it down the formula, to calculate the average of the last 12 months for Company4.
Until now, I have came up with this formula:
=AVERAGE(LOOKUP(LARGE(IF(ISNUMBER(G:G),ROW(G:G)),ROW(INDIRECT("1:"&MIN(12,COUNT(G:G))))),ROW(G:G),G:G ))
This formula correctly calculates the average of a given column, considering only the last 12 values. The last step would be to come up with a formula that includes all the columns and then calculates the average for the given company.
Thanks!
I recommend that you use a named range to define your data in columns G:I. When a company is added, just modify the named range's specs. I used the name Target. Of course, you can replace it with $G:$I if you feel so inclined but I would rather recommend reducing the number of rows in the range, which is easier to manage when it is named.
Use the formula below to extract the company names from the first row of Target into the first column of your averages table. This is to ensure that the names are spelled identically in both locations.
=INDEX(Target,1,ROW()-2)
The number 2 indicates the number of rows above the row containing the formula. it is copied here from cell M3. There, ROW()-2 creates the number 1, counting sequentially as the formula is copied down.
Now I have the formula below in my cell N3 and copied down.
=SUM(INDEX(Target,0,MATCH($M3,INDEX(Target,1,0),0)))
The formula simply sums up the columns G, H, and I in 3 consecutive rows.
In the final step I inserted the range definition established above, meaning excluding the SUM() function, into your existing formula.
=AVERAGE(LOOKUP(LARGE(IF(ISNUMBER(INDEX(Target,0,MATCH($M3,INDEX(Target,1,0),0))),ROW(INDEX(Target,0,MATCH($M3,INDEX(Target,1,0),0)))),ROW(INDIRECT("1:"&MIN(12,COUNT(INDEX(Target,0,MATCH($M3,INDEX(Target,1,0),0))))))),ROW(INDEX(Target,0,MATCH($M3,INDEX(Target,1,0),0))),INDEX(Target,0,MATCH($M3,INDEX(Target,1,0),0))))

Calculate Occurrence Number - Excel

I have simple problem, but I've not be able to get an answer from searching. I require a column to calculate the number of the nth occurrence of a value. It's best explained in this picture
I require a method to calculate column B.
I'd be very grateful for any help.
Are you looking to merely provide a count of the distinct entries of column A in column B? Or merely add a formula to come up with the table in your link?
If the latter, then the formula to write in cell B2 is:
=COUNTIF(A$2:A2,A2)
then copy/paste it down column B. Note - if your data is both a Date and Time, but the cell is formatted to only display a date, you may not get the results you want. You'd need to interject a new column with a "floor" calculation to round the date/time value to a date (Excel date times are decimal, with integer part dictating the date, and remaining 0.0 -> 1.0 dictating the time of day)
If you just want to derive a table of the counts of distinct entries in column A, then a pivot table will do this for you - simple add a pivot table to cover the data in column A, then select column A into the rows category, and then also drag it into the values category, ensuring the field is set to "Count of". You should then have a table with the distinct entries in your data set in one column, and the count of their occurrences in the other column.
You can use the COUNTIF worksheet function, with a relative address.
Eg. In cell B2, enter this formula:
=COUNTIF(A$2:A2,A2)
And then fill-down.
Use the following formula to generate the required series:
=COUNTIF($A$1:A1,A1) and strech(copy) it in all the cells
This will generate result like this:
A 1 COUNTIF($A$1:A1,A1)
A 2 COUNTIF($A$1:A2,A2)
C 1 COUNTIF($A$1:A3,A3)
C 2 COUNTIF($A$1:A4,A4)
B 1 COUNTIF($A$1:A5,A5)
B 2 COUNTIF($A$1:A6,A6)
A 3 COUNTIF($A$1:A7,A7)
C 3 COUNTIF($A$1:A8,A8)
D 1 COUNTIF($A$1:A9,A9)
D 2 COUNTIF($A$1:A10,A10)
D 3 COUNTIF($A$1:A11,A11)
D 4 COUNTIF($A$1:A12,A12)

Consolidate two or more columns of data into one column using formula

I need to collect Sch Code from different columns into one column as shown below.
First priority is by formula or UDF Function if possible.
My Data:
Column A Column B Column C Column D Column E Column F Column G
SCH Code Value SCH Code Value Rating SCH Code Value
C01-3-1 4 C01-4-1 8 300 C02-3-1 8
300 C02-3-5 9
C01-3-2 5 C01-4-2 12 300 C02-3-2 12
C01-3-3 6 C01-4-3 21 300 C02-3-3 21
300 C02-3-6 10
C01-3-4 7 C01-4-4 4 300 C02-3-4 4
Required Result (Only Sch Code required in summary sheet but it is required by formula or VBA UDF function) :
Column A
C01-3-1
C01-3-2
C01-3-3
C01-3-4
C01-4-1
C01-4-2
C01-4-3
C01-4-4
C02-3-1
C02-3-5
C02-3-2
C02-3-3
C02-3-6
C02-3-4
You can collect unique non-blank values from column A with an array formula e.g. =INDEX($A$2:$A$99,MATCH(0, IF(LEN($A$2:$A$99),COUNTIF(I$1:I1,$A$2:$A$99),1),0)). Since this returns #N/A where it has no more values to return from its column, you can pass control over to a similar formula that references another column with IFERROR.
    
To choose from your three columns of SCH Codes, you would need to stack this 3 deep. The formula in I2 is:
=IF(LEN(I1),IFERROR(INDEX($A$2:$A$99,MATCH(0, IF(LEN($A$2:$A$99),COUNTIF(I$1:I1,$A$2:$A$99),1),0)),IFERROR(INDEX($C$2:$C$99,MATCH(0, IF(LEN($C$2:$C$99),COUNTIF(I$1:I1,$C$2:$C$99),1),0)),IFERROR(INDEX($F$2:$F$99,MATCH(0, IF(LEN($F$2:$F$99),COUNTIF(I$1:I1,$F$2:$F$99),1),0)),""))),"")
This array formula requires Ctrl+Shift+Enter, not just Enter. Once entered correctly, it can be filled down to catch all possible values. I would fill down for at least three times as many rows as you have in order that the blanks would have a place if they were filled in at a later date.
In theory, you could stack this much deeper but for practical purposes, I wouldn't go much deeper than this. Array formulas eat up calculation resources at a logarithmic rate so the size of your data is going to be a key factor on whether this is a suitable solution.
One solution:
Copy and paste all values in column C below column A data. Highlight column A and go to Data>Remove duplicates then Data>Sort.

Excel: Match\Index specific column based on multiple criteria

I have two Tables, Table 1 Column A is a rolling date column. Table 2 consists of four columns of differing "Trigger Dates". Table 2, Column 1 contains an Annual trigger, ie occurs once a year. Table 2 Column 2 contains Bi-Annual Triggers, and occurs twice yearly. Table 2 Column 3 contains Monthly Triggers, "12 dates" and Table 2 Column 4 contains Weekly Triggers, "52 dates".
Ok, so what I'm looking for is to a formula that will return the date trigger, where Table 1 Column 1 matches a condition (Annually, Bi-Annually, Monthly, Weekly) selected in a cell "we'll say F1, outside of any ranges that may be created.
Example: If Table 1 Col 2 = "01/02/2013" and I select "Weekly" in F1, the formula will look in the weekly Column in Table 2 to determine if "01/02/2013" exists.
I've allocated a named range to each column in Table 2
I've allocated a named range to the condition in F1 which is a drop down list
Any suggestions?
You might try:
=IFERROR(VLOOKUP(B2,INDIRECT(CHAR(72+MATCH(F$1,$I$1:$L$1,0))&":"&CHAR(72+MATCH(F$1,$I$1:$L$1,0))),1,0),"")
Ok, so supposing your Range Name is in F1, your formula to find the match would look as follows:
=If(IsError(Match(LookupVal,Indirect(F1),0)),"No Match", "Match")
...Something along those lines
Hope this helps point you in the right direction.
INDIRECT and VLOOKUP will be your friends here.
I constructed Table2 just as you had described, with the Annual,Bi-annual,Monthly,Weekly labels for the columns in the table - this will avoid having to keep named ranges up to date, as it's looking directly at the table in the formula
For the function, I then used VLOOKUP to find the date, in the column referenced by F1.
Column Reference: INDIRECT("Table2["&$F$1&"]")
Find Value: VLOOKUP([#Col2],INDIRECT("Table2["&$F$1&"]"),1,FALSE) (looking at column 1 in the return values, as I don't really care what value is returned.
This will return the date if found, and an error if not. I can then wrap the result in the IF(ISERROR( so I can return Yes or No if the date is found.
This produces the entire formula of
=IF(ISERROR(VLOOKUP([#Col2],INDIRECT("Table2["&$F$1&"]"),1,FALSE)),"No","Yes")
for the next column in Table1, so that when I change the value in F1, it will look for that column name in Table2, and let me know if it is found.

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