I have 2 sheets in a workbook (Sheet1, Sheet2).
Sheet 2 contains a table (Named Table1) with 5 columns:
Takeaways
Household
Clothing
Fuel
Groceries
On sheet one, I have 2 columns:
Expense Name
Expense Total
Now, what I am trying to do is:
Set the range for the Expense Name (Range 1)
Set the range for the Expense Total (Range 2)
Compare Range 1 with the respective column in the table and only add up the values for matches
For example, in Range 1 (B6:B16):
BP
Caltex
McDonalds
KFC
In Range 2 (C6:C16):
300
400
200
150
Now, all I want to do is add up the values for the Takeaways (McDonalds, KFC) and exclude anything that DOES NOT match the criteria.
So my sum total will be all occurrences of Takeaways - provided they are listed in my table - 350 in this case.
But I cannot seem to get the formula to work.
I used these sources:
https://exceljet.net/excel-functions/excel-sumifs-function
Selecting a Specific Column of a Named Range for the SUMIF Function
and ended up with this formula:
=SUMIF($B$6:$B$16;Table1[Takeaways];C6:C16)
This source:
https://excelchamps.com/blog/sumif-sumifs-or-logic/
and ended up with this formula:
=SUM(SUMIFS(C6:C16;B6:B16;Table1[Takeaways]))
Both formulae return 0.
BUT, with BOTH of them, if I change Table1[Takeaways] to "McDonalds", then it correctly identifies every occurrence of the word "McDonalds" in Range 1.
EDIT:
I have updated the formulae above to match the images below.
This is the table that contains the references:
This table contains the data:
Formula:
Cell C4 (Next to Takeaways): =SUMIF($B$6:B$16;Table1[Takeaways];C6:C16)
Cell C5 (Next to Fuel): =SUM(SUMIFS(C6:C16;B6:B16;Table1[Fuel]))
It appears that ONLY BP is being detected in the formula.
This is a an output table when I use the formulae with a single cell reference and not a table or used range:
Formula:
Cell F4 (Next to BP): =SUMIF($B$6:B$16;"BP";C6:C16)
Cell F5 (Next to Caltex): =SUM(SUMIFS(C6:C16;B6:B16;"Caltex"))
Cell F6 (Next to McDonalds): =SUMIF($B$6:B$16;"McDonalds";C6:C16)
Cell F7 (Next to KFC): =SUM(SUMIFS(C6:C16;B6:B16;"KFC"))
If I understand correctly what you're trying to achieve, I think your setup is not right conceptually.
It looks like you're trying to track expenses, and each expense (or payee) is allocated to a category ("Takeaways", "Household" etc.). From a relational-model point of view, your second table (which defines the category for each expense/payee) should only have two columns (or variables): Expense Name and Expense Category.
The table you set up ('Sheet 2') uses the categories (i.e., possible values) as different columns (i.e., variables). But there's only variable, namely the "Expense Category", and the categories themselves are the possible values.
If you set it up like that, the problem changes: you can add a dependent column to your first table that shows the category for each payee (or "Expense Name"), using a VLOOKUP() from the second table.
You can then sum the expenses for all payees matching that category.
Note: I've created the illustration using LibreOffice Calc, so there might be some small differences, but the logic is the same.
Without seeing the data in L and K I can't give you a full answer - but likely it's to do with the way you're pulling your Array
Try something similar to this
=SUMPRODUCT(SUMIFS($L$11:$L$43,$K$11:$K$43,CHOOSE({1,2},Takeaways,"anything else you wanted to sum")))
Remember SUMIFS is for multiple criteria, so if you're only calculating one, you'll need =SUMPRODUCT(SUMIF(
The way the above works is with vertical vectors only, but changing your named ranges so the table of 2 columns is 2 named ranges instead should be okay - unless it's part of your requirements
Table 2 would become expense_Name and expense_Total etc
I was about to close this as a duplicate of my own question here but there is a bit of a difference in using a named range I think. However the logic behind this follows more or less the same approach.
Working further on my partial solution below I derived the following formula:
=SUMPRODUCT(COUNTIF(Table1[Takeaways];Range1)*Range2)
The COUNTIF() part counts the number of occurrences of the cell value in your table. Therefore make sure there are no duplicates in your table. If the value is present in the table the result of COUNTIF() will be 0. This way we create a matrix of 1's and 0's. By multiplying and the use of SUMPRODUCT() we force excel to perform matrix calculations and return the correct result.
Partial solution
I used the following formula:
=SUMPRODUCT(ISNUMBER(MATCH(Range1;Table1[Takeaways]))*Range2)
The formula does the following:
The MATCH()checks if the value in Range1 is present in your table and returns the position of the matching value in your table.
The ISNUMBER() checks if a match is found by checking if the MATCH() fucntion returned a number
Multiplying this with Range2 forces matrix calculation, using the SUMPRODUCT() function
EDIT:
This worked for a really limited sample. As soon as I added the fourth row to my data the formula stopped working as intended. See screenshot:
It took the first two values into the sum correctly, the fourth is not taken into account.
I have an Excel worksheet (Sheet 1) with a list of People's named and their responsible training groups... basically numbers assigned to different handlers.
I need to:
On Sheet 2, I need an IF statement that checks Sheet 1, Column B and if a certain person's name appears, it returns the value to the immediate left.
I have something like this on Sheet 1:
Group Name
101 Fred
102 Wilma
103 Fred
104 Fred
105 Barney
106 Wilma
On Sheet 2, I need this:
Barney Fred Wilma
105 101 102
   103 106
 104
The equation I am trying to use in each cell on sheet 2 is"
=IF('Sheet 1'!B:B="Barney",relative position one cell to the left of name,"")
Thanks in advance.
No array formula needed:
MINIFS($A$2:$A$7,$B$2:$B$7,D$1,$A$2:$A$7,">" & MAX(D$1:D1))
Just a simple MINIFS. Then wrap it in an IF to remove the zeros:
EDIT: Further clarification in response to comment.
I have put both tables on the same sheet for ease, however, one could easily be moved onto a separate sheet if needed.
The formula works by selecting the group with the lowest value, which has the name which appears at the top of the column AND which has not already been listed.
So:
MINIFS($A$2:$A$7,$B$2:$B$7,D$1,$A$2:$A$7,">" & MAX(D$1:D1))
The first argument in the MINIFS formula is $A$2:$A$7. This is the column containing all the groups, which we want to split out and list against each name.
The 2nd and 3rd argument ($B$2:$B$7,D$1) is a criteria range and it's value. This is used to filter out any name we dont want to return in this particular cell (any that are not "Barney" in the case of D2). Notice that the D$1 in the formula does not start with a $, this means that we can just drag the formula across the other name columns and it will filter out the correct names automatically.
The 4th and 5th Arguments ($A$2:$A$7,">" & MAX(D$1:D1)) are also a criteria range and its value. Howevever, in the case of the value this time, we are looking for the max value within a range. We are looking at all the groups which have already been listed against a name and using MAX to select the highest one.Notice that there is a $ before the first "1" in the formula but not before the second. This means that as we drag the formula down, the range that it is looking for the MAX in, will automatically expand to include the cell just above the current one. Also note that there is no $before either of the "D"s, this is so that when you drag the formula to the right, the range it is checking also moves to the right. Once we have the MAX group which has already been listed against a name, we tell the MINIFS formula to only look at groups which are greater than that.
Once there are no groups for a name which are greater than the previously listed group, the MINIFS formula will return 0. To prevent the table from showing lot's of 0's, we simply say "If the MINIFS formula returns 0, then return an empty string instead:
=IF(<the result of the MINIFS>=0, "",<the result of the MINIFS>)
So the final formula would be:
=IF(MINIFS($A$2:$A$7,$B$2:$B$7,D$1,$A$2:$A$7,">" & MAX(D$1:D1))=0,"",MINIFS($A$2:$A$7,$B$2:$B$7,D$1,$A$2:$A$7,">" & MAX(D$1:D1)))
I hope that makes more sense for you. I am sorry if the explanation is a bit long winded, but as you didn't give me a specific area that you didn't understand, I just tried to expand my explanation generally. If there is any specific part you need me to explain further, please let me know.
This was taken and improved slightly from Question that has since been deleted
For those who can see deleted posts, it was taken from here: https://stackoverflow.com/questions/39793322/three-dimensional-lookup-no-concatenate-or-named-ranges-excel
I'm trying to do a three dimensional lookup without named ranges or concatenates. Simplified, my data is on the form:
Column1 Column2 Column3
Scott
P 1 2 3
M 4 5 6
N 7 8 9
George
P 10 11 12
M 13 14 15
N 16 17 18
I now want to search for a specific Name and then for a specific letter within that names table, I then want to match this row number with a specific column.
I tried a simple INDEX/MATCH:
=INDEX(A:D,MATCH("M",A:A,0),MATCH("Column1",1:1,0))
And that works for the fist name but not any others as it finds the first instance of M.
How do I modify it to look for a different name?
I have answered below, but want to see if someone has a better solution.
I used an IF() statement array formula to find what the P row number was after the George row... I also needed to use the MIN() function to get the first P row number after the name.
Beyond that, it's a simple INDEX() function.... that racked my brain for over an hour :).
=INDEX($A$1:$D$9,MIN(IF((ROW(A1:A9)>MATCH($F$4,A1:A9,0))*(A1:A9=$F$5),ROW(A1:A9),"")),MATCH($F$6,$A$1:$D$1,0))
Don't Forget!
Use Ctrl+Shift+Enter when finishing the formula, so it gets evaluated as an array formula.
You can use two other INDEX/MATCH's inside the first MATCH to set the lookup range. Then you simply need to add the MATCH() to find the absolute position of the name.
=INDEX(A:D,MATCH($H$4,INDEX(A:A,MATCH($H$3,A:A,0)):INDEX(A:A,MATCH($H$3,A:A,0)+4),0)+MATCH($H$3,A:A,0)-1,MATCH($H$5,$1:$1,0))
This one works better and does not have a size constraint:
=INDEX(A:D,MATCH(F4,INDEX(A:A,MATCH(F3,A:A,0)):A1040000,0)+MATCH(F3,A:A,0)-1,MATCH(F5,A1:D1,0))
You can do this just by adding the results of two matches together. One match for the names plus one match for the letter equals the total row.
=INDEX(A:D,MATCH(G5,A3:A5,0)+MATCH(G3,A:A,0),MATCH(G4,1:1,0))
In other words: Index(All of the Data, Match(Name, In name column, exact) + Match(Letter, In letter column, exact), Match(Column name, in Column row, exact)
Screen capture of working sheet
My answer attempts the general case with only one caveat:
That a letter is single character text, and a name is more than 1 character. Otherwise i feel there is no difference logically between letters and names, and it is then impossible to really do...
RE-EDIT for better function construction:
{=INDEX($A$1:$D$17, MATCH($H$3,$A1:$A17, 0)+MATCH($H$4, INDEX($A1:$A17, MATCH($H$3,$A1:$A17, 0)):INDEX($A:$A, SMALL(IFERROR(MATCH($H$3,$A1:$A17, 0)+POWER(SQRT(IF(LEN($A$1:$A$17)>1, ROW($A$1:$A$17), 0)-MATCH($H$3,$A$1:$A$17, 0)), 2)-1, ROWS($A$1:$A$17)), 2)), 0)-1, MATCH($H$5, $A$1:$D$1, 0))}
This uses an array formula along column A, and checks if the length is > 1 and throws the row nums into an array, with letters given a 0.
Then match row of unique name(e.g. George) is subtracted from each.
We then use a min(of all other name rows, with the last data row as the final default - SMALL function with 2 parameter) to find the next name row(or last data row if there is no following name).
Rest is standard index/match etc.
It will correctly return #N/A if there is no such letter under the chosen name...
My dataset is A1:A17, and the formula could use A:A instead each time, but the array calc inside the IF needs the A1:A17 for speed.
EDIT for better function construction:
If we wanted to avoid editing the formula when the data length changes, then we could let full column references of A:A go through the entire construction(and lose speed/efficiency) with the last data row in colA calculated via ROWS(A:A):
Re-edit:
{=INDEX($A:$D, MATCH($H$3,$A:$A, 0)+MATCH($H$4, INDEX($A:$A, MATCH($H$3,$A:$A, 0)):INDEX($A:$A, SMALL(IFERROR(MATCH($H$3,$A:$A, 0)+POWER(SQRT(IF(LEN($A:$A)>1, ROW($A:$A), 0)-MATCH($H$3,$A:$A, 0)), 2)-1, ROWS($A:$A)), 2)), 0)-1, MATCH($H$5,1:1, 0))}
It really depends on the setup...
Edit again for version which takes blanks as separators for names
If you want to use blanks as the separator for names, where no blanks are in the data results, but blanks appear in columns B to D where there is a name, then a tiny change in the above formulae will result in this:
=INDEX($A$1:$D$17, MATCH($H$3,$A$1:$A$17, 0)+MATCH($H$4, INDEX($A:$A, MATCH($H$3,$A:$A, 0)):INDEX($A:$A, SMALL(IFERROR(MATCH($H$3,$A:$A, 0)+POWER(SQRT(IF($B$1:$B$17="", ROW($A$1:$A$17), 0)-MATCH($H$3,$A$1:$A$17, 0)), 2)-1, ROWS($A$1:$A$17)), 2)), 0)-1, MATCH($H$5, $A$1:$D$1, 0))
This means that the names and letters do not have to be any specified length, but just one proviso is that blanks appear in the row with the name.
A small amendment to the condition to find the end range to search for the letter by replacing this: SQRT(IF(LEN($A$1:$A$17)>1, with this:
SQRT(IF($B$1:$B$17="",
I would use the area (4th parameter) of Index(). Below is a screenshot of test data. This example assumes the same columns and keys are sorted and consistent.
This works by using (Range1,Range2) as the first parameter of index. For the 4th parameter of index, use N for which area in the () you want Index to return.
I think this may be slightly tidier, and a little easier to modify maybe.
=INDEX(OFFSET(INDIRECT("A"&MATCH($H$3,$A:$A,0),TRUE),0,0,4,4),MATCH($H$4,$A:$A,0),MATCH(H5,$1:$1,0))
Using offset to create the range first, we're able to use the name from H3 to set that up, and then beyond that we are just indexing within that new range.
Now this is still dependendent on staying in Column A for the names.
Assuming the format of the data is always Name then P, M and N this formula does the work:
=INDEX($A:$D,
MATCH($H$3,$A:$A,0)
+LOOKUP($H$4,{"P",1;"M",2;"N",3}),
MATCH($H$5,$1:$1,0))
This solution works on almost all conditions. One restriction I found is when one of the subjects (Names) does no have data for any of the details (letters), but as of now the same occurs with all the other answers.
The formula assumes the data is located at B6:F30 (in order to ensure it can be applied regardless of the source range location).
The formula uses the Index\Match functions:
First, a MATCH to retrieve the position of the Name:
MATCH($H8,$B$6:$B$30,0)
With that info it uses INDEX to build a range that is used to obtain the position of the Detail (letter) using a second MATCH Function:
+ MATCH($I8,INDEX($B$6:$B$30, 1 + MATCH($H8,$B$6:$B$30,0))
:INDEX($B$6:$B$30,ROWS($B$6:$B$30)),0),
Adding the results of the first and second MATCH functions obtains the position of the Name`Detail` combination and uses it in an Index to the entire data. The position of the Data Column required is obtained with a Match:
INDEX($B$6:$F$30, 1st.MATCH + 2nd.MATCH,
MATCH(J$6,$B$6:$F$6,0))
With the results located at G6:L30 enter this formula in J8 then copy to J8:L30:
= INDEX( $B$6:$F$30,
MATCH( $H8, $B$6:$B$30, 0)
+MATCH( $I8, INDEX( $B$6:$B$30 , 1 + MATCH( $H8, $B$6:$B$30 ,0))
: INDEX( $B$6:$B$30, ROWS($B$6:$B$30) ),0),
MATCH( J$6, $B$6:$F$6, 0)),"")
This solution works in all conditions discussed so far (let me know of any condition that it does not work and I’ll try to cover it).
I’m posting this as a separated answer as the formulas applied in prior answer rightly apply to the conditions stated in them, as such they will be useful to users with those specific scenarios, so they don’t need to apply these long formulas.
This formula assumes the data is located at B6:E30 (in order to ensure it can be applied regardless of the source range location).
This formula uses the Index\Match functions and it’s a Formula Array.
FormulaArrays are entered pressing [Ctrl] + [Shift] + [Enter] simultaneously, you shall see { and } around the formula if entered correctly
Syntax:
=IFERROR(INDEX(DataRng,
MATCH(Value1,NamesRng,0)
+IFERROR(MATCH(Value2,INDEX(NamesRng,
1+MATCH(Value1,NamesRng,0))
:INDEX(NamesRng, IFERROR(MATCH(Value1,NamesRng,0)
+MATCH("#",IF((INDEX(Col1Rng,1+MATCH(Value1,NamesRng,0))
:INDEX(Col1Rng,ROWS(NamesRng)))="","#","!"),0),
ROWS(NamesRng))),0),NA()),MATCH(ValCol,DataHdr,0)),"")
Arguments:
Assuming the data is located at B6:E30.
Value1= Name to be found in Data, i.e. George, Scott, etc.
Value2= Detail to be found in Data, i.e. Detail1, Detalle2, etc.
ValCol = Column to be found in Data i.e. Column1, Column2, etc.
DataRng= $B$6:$E$30
DataHdr= $B$6:$E$6
NamesRng= $B$6:$B$30
Col1Rng= $C$6:$C$30
1st MATCH: Retrieves the position of the Name:
MATCH(Value1,NamesRng,0)
2nd MATCH: Retrieves the end position of the Name’s corresponding Details, which is determined by a blank value in column C or the end of the data range:
MATCH("#",IF((INDEX(Col1Rng, 1 + 1stMATCH)
:INDEX(Col1Rng,ROWS(NamesRng)))="","#","!"),0),
Builds a Range (vRange): With the Names's Details using the 1st and 2nd match functions. If 2nd Match returns an error then it uses the last row of the Data range:
INDEX(NamesRng, 1 + 1stMATCH )
:INDEX(NamesRng, IFERROR( 1stMATCH + 2ndMATCH, ROWS(NamesRng)))
3rd MATCH: Retrieves the position of the Detail within the vRange. It returns #NA if the combination is not present.
IFERROR(MATCH(Value2, vRange,0), NA())
Adding the results of the 1st and 3rd match functions obtains the Row index of the Name`Detailcombination or#NAif no found.
The Column index is obtained with a Match from the Header of the Data.
It then applying the INDEX function to the Data Range returns the value of theName\Detail\Columncombination.
If theName\Detail` combination is not found it returns blank.
=IFERROR( INDEX( DataRng, 1stMATCH + 3rdMATCH, MATCH(Column,DataHdr,0)),"")
With the results located at H6:L37 enter this Formula Array in J8 then copy to K8:L37 and to J9:L37:
=IFERROR( INDEX($B$6:$E$30,
MATCH($H8,$B$6:$B$30,0)
+IFERROR( MATCH($I8, INDEX($B$6:$B$30,
1+MATCH($H8,$B$6:$B$30,0))
:INDEX($B$6:$B$30, IFERROR(MATCH($H8,$B$6:$B$30,0)
+MATCH("#", IF((INDEX($C$6:$C$30,1+MATCH($H8,$B$6:$B$30,0))
:INDEX($C$6:$C$30,ROWS($B$6:$B$30)))="","#","!"),0),
ROWS($B$6:$B$30))),0),NA()),
MATCH(J$6,$B$6:$E$6,0)), "")
Wow... So many solutions already.
I think a simpler solution could be using offset to get a more generic answer.
=INDEX($A$1:$D$9, MATCH($G$3,OFFSET($A$1,MATCH($G$2,$A$1:$A$9,0),0,3,1),0)+MATCH($G$2,$A$1:$A$9,0), MATCH($G$4,$B$1:$D$1,0)+1)
The only variable to look for is 3 which is the number of M/N/P options present because that will affect the number of rows. Otherwise, the solution works fine in all possible scenarios and different orders.
When I have more than two inpunts for a data search I prefer to have the data organized as shown in the figure, so that I can use a pivot table and get it to organize the data in rows and columns as I like.
Then I use GETPIVOTDATA to search for a value.
Cell G9 contains this formula:
=GETPIVOTDATA("Value";$F$3;"Name";G15;"Letter";G16;"Column";G17)
I have two different sheets with 300,000 data in Excel.
First sheet contains:
S2_Symbol Start_Pos End Position
STE 254857 267891
PRI 748578 758962
ILA 852741 963369
VIS 789456 796325
Second:
S1_Location
789460
852898
748678
My output should be like this:
S1_Location Symbol
789460 VIS
852898 ILA
748678 PRI
I have to find that S1_location falls in which S2_location and its corresponding Symbol. I have used INDEX formula in Excel but for each cell, I have to change the reference cell manually. I couldn't do it 300,000 data.
How can I do in an in Excel or should I use a script?
This solution assumes the following:
Start and End Positions for each S2 Symbol are unique (i.e. there is no intersection between the ranges allocated to each symbol)
Data in first sheet is located at A1:D17 (adjust ranges in formulas as needed)
Data in second sheet is locate at A1:B300010 (adjust ranges in formulas as needed)
The solution requires:
To add a working column in worksheet one. Enter this formula in D2 and copy till last record.
=ROWS($A$1:$A2)
Fig. 1
Then in second worksheet enter this formula at B2 and copy till last record.
=INDEX( Sheet1!$A$1:$A$17,
SUMIFS( Sheet1!$D$1:$D$17,
Sheet1!$B$1:$B$17, "<=" & $A2, Sheet1!$C$1:$C$17, ">=" & $A2 ) )
Fig. 2
It took aprox. less than 14 seconds to copy downwards and calculate the formulas in sheet 2.
As it can be seen in figures 1 and 2 none of the tables need to be sorted.
Assuming both sheets start in A1, and First sheet ColumnB is sorted ascending, in Second sheet B2 please try:
=INDEX(First!A:A,MATCH(A2,First!B:B))
copied down to suit. It relies on inexact matching.
Assuming we have a Sheet1 like this:
note, the Sheet1is sorted by Start_Pos, End_Pos in ascending order.
and a Sheet2 like this:
Then the formula in Sheet2!B2 downwards could be:
=INDEX(Sheet1!A:A,IF(MATCH(A2,Sheet1!B:B)>IFERROR(MATCH(A2-(10^-10),Sheet1!C:C),0),MATCH(A2,Sheet1!B:B),NA()))
See MATCH: https://support.office.com/en-us/article/MATCH-function-e8dffd45-c762-47d6-bf89-533f4a37673a
The idea is: MATCH without exact matching (without parameter match_type) gets the row of the largest value which is smaller or equal the search value. So in the Start_Pos column it will get the row from which we can get the S2_Symbol. But from the End_Pos column it should get one row beforehand if the value is not outside the given ranges.
There is only one exception. If the value is exact the value in the End_Pos column, then it will return the same row as in the Start_Pos column. Considering this exception, we can search in the End_Pos column with a little bit smaller value. Thanks to Tom Sharpe for his comment.
The formula in Sheet2!D2 downwards is:
{=INDEX(Sheet1!A:A,MIN(IF($A2>=Sheet1!$B$2:$B$300000,IF($A2<=Sheet1!$C$2:$C$300000,ROW(Sheet1!$A$2:$A$300000),2^20+1))))}
this is an array formula which is exactly formulated respecting the requirements. But this is very bad in performance for using in much many cells. But using this, the Sheet1 is not required to be sorted.
Benchmark test:
Have the following Sheet1:
Formulas:
A2:A300002: ="S"&(ROW(A1)-1)*10&"-"&(ROW(A1)-1)*10+7
B2:B300002: =(ROW(A1)-1)*10
C2:C300002: =B2+7
and the following Sheet2:
Formulas:
A2:A300002: =RANDBETWEEN(0,3000007)
B2:B300002: =INDEX(Sheet1!A:A,IF(MATCH(A2,Sheet1!B:B)>IFERROR(MATCH(A2-10^-9,Sheet1!C:C),0),MATCH(A2,Sheet1!B:B),NA()))
Note the -10^-9 instead of -10^-10 in previous version. This is because we have only 16 digits precision. In previous version this was maximum 6 digits integer part and then 10 digits decimal part. Now it is maximum 7 digits integer part and then 9 digits decimal part.
Calculation after pressing F9 in Sheet2 takes ca. 2 s. (Excel 2007, Windows 7, 4 core processor).
I would have gone for something like this which gives you the first match if there is one:-
=INDEX(First!A:A,MATCH(1,(First!B:B<=A2)*(First!C:C>=A2),0))
assuming keys and start and end values are in a sheet called First and lookup values start in A2.
Array formula which must be entered with CtrlShiftEnter
In response to the question from #pnuts about how long it will take, I have set up a similar benchmark with 300,000 rows in each sheet and it has reached 1% after 90 minutes, so it should take about 150 hours to reach 100% or roughly one week. This is to be expected as the number of computations required is (rows in sheet 1) X (rows in sheet 2)
300,000 X 300,000
but in fact because the multiplication applies to complete columns, I believe it is more correctly
300,000 X 1,048,576
i.e. > 300 billion.
A practical version which gives good response for smaller ranges is as follows:-
I define three named ranges Range1, Range2 and Range3
=First!$A$1:INDEX(First!$A:$A,MATCH("ZZZ",First!$A:$A))
=First!$B$1:INDEX(First!$B:$B,MATCH(9.9E+307,First!$B:$B))
=First!$C$1:INDEX(First!$C:$C,MATCH(9.9E+307,First!$C:$C))
and the modified formula is
=INDEX(Range1,MATCH(1,(Range2<=A2)*(Range3>=A2),0))
I was thinking of deleting this answer, but would rather it stood as a counter-example.