I have a list of 4 values in Sheet1 and 4 values in Sheet2.
In Sheet3 I will combine a random selection of these numbers and return the value in a column. (edit: no random selection from Excel, its a part picked from a bucket)
(A fifth column in Sheet3 will be used to do calculations with ValueS1 and ValueS2)
Sheet1
NumberS1
ValueS1
1
17.10
2
17.20
3
17.12
4
17.15
Sheet2
NumberS2
ValueS2
1
16.10
2
16.20
3
16.12
4
16.15
Sheet3
NumberS1
NumberS2
ValueS1
ValueS2
1
3
17.10
16.12
2
2
17.20
16.20
4
1
17.15
16.10
3
4
17.12
16.15
What kind of function can give the desired return?
I have looked into examples using "Indirect" but cannot see how they will solve my problem.
for the randomization: =ROUNDUP(RAND()*4,0)
rand() gives you a number between 0 and 1, so rand()*4 gives you a number between 0 and 4.
roundup(x,y) round up the number x with y digits you want to round the number up to (in our case 0).
for import the right number from sheet 1 or 2: =VLOOKUP(A1,Sheet1!A1:B2,2,0)
A1 - The value you look for in sheet 1 or 2.
Sheet1!A1:B4 - The array he look for your value on the firs column, always on the first column.
2 - The column you want to import the value from. (because we write an array of tow columns. we can write here only 1 or 2)
0 - it's an Optionally index (0 or 1). o is if you want an exact match of the return value.
Regular Lookup could do:
=LOOKUP(A2:A5,Sheet1!A2:A5,Sheet1!B2:B5) in Sheet3!C2
And
=LOOKUP(B2:B5,Sheet2!A2:A5,Sheet2!B2:B5) in Sheet3!D2
Note that LOOKUP will give the result to the closest match smaller than the search value.
Or VLOOKUP:
=VLOOKUP(A2:A5,Sheet1!A2:B5,2,0) / =VLOOKUP(B2:B5,Sheet2!A2:B5,2,0)
VLOOKUP will error if the value is not found (the way used above). It uses arguments like this:
=VLOOKUP(What you want to look up, where you want to look for it, the column number in the range containing the value to return, return an Approximate or Exact match – indicated as 1/TRUE, or 0/FALSE)
Office 365 has XLOOKUP which combines the logic of the two above and some more:
=XLOOKUP(A2:A5,Sheet1!A2:A5,Sheet1!B2:B5,"value not found",0)
XLOOKUP uses the following arguments:
=XLOOKUP(lookup_value, lookup_array, return_array, [if_not_found], [match_mode], [search_mode])
Related
Consider the sheet below:
A
B
1
4
3
5
2
2
5
0
4
1
I want to find if there is a match for each row of column 1 with any row of column 2. So ideally this would give me:
A
B
C
1
4
Yes
3
5
No
2
2
Yes
5
0
Yes
4
1
Yes
As a first and simple step, I am using =MATCH(A2,B2:B6) to get the index of the match and then manually calling this across the rows to get something like this:
A
B
C
1
4
6
3
5
-
2
2
3
5
0
2
4
1
1
I am now having a problem:
I want to apply this for a row of 500 in A and 2000 in B. I was thinking of manually filling in the first few rows and then select and drag over the first 500 rows. This however does not work as for each subsequent cell, it just changes the formula to =MATCH(A(N +1),B2 + N:B6 + N) which gives me wrong values and at worst, just repeats the older pattern ahead.
Can anyone help me with how I can just use the MATCH function to find all the values in A that are present in B?
Let me continue where you arrived:
=MATCH(A2,B2:B6,0)
(You forgot the last zero)
This formula is correct, but it is also wrong.
???
Well, when you drag it down, you get:
=MATCH(A3,B3:B7,0)
This is not what you want: you want the search term (A2) to change into A3 but you want the search array (B2:B6) not to change. In order to get this done, you need to work with absolute references. This looks like this:
=MATCH(A2,B$2:B$6,0)
When you drag this down, this is what you get:
=MATCH(A3,B$2:B$6,0)
=> ok so far.
Problem now: you need to translate your current results (a number or #N/A) into "yes" or "no". This can be done in numerous ways, let me give you an example:
=IF(ISERROR(MATCH(A2,B$2:B$6,0)),"No","Yes")
One remark: there exists an IFERROR() function in Excel, but this does not have an "else"-clause, hence the choice for the IF(ISERROR( combination.
Within Sheets you may try this out:
=index(if(len(A2:A),if(ifna(xmatch(A2:A,B2:B)),"Yes","No"),))
If you want to separate those matching values then could use FILTER() function.
=FILTER(A1:A5,COUNTIFS(B1:B9,A1:A5))
And for YES, NO dynamically, try MAP() function.
=MAP(A1:A5,LAMBDA(x,ISNUMBER(XMATCH(x,B:B))))
I have a list of part numbers that are used in 4 different top level assemblies. The parts can be used in 1 to 4 of the top level assemblies. I'm trying to write a formula that will count how many unique top level assemblies a part number occurs in. I had previously written a formula that worked, but it uses UNIQUE and FILTER, and my coworkers don't have Excel 365, so those formulas aren't supported for them. I've been trying to come up with a workaround and would really appreciate any help :)
I have an example (I can't provide any real data) section of our spreadsheet and an image of the formula I had that was working
Top Level Assy
Part Number
Qty
Number of times used
02554
01622
4
3
89975
01622
4
3
95665
01622
4
3
98886
01723
4
1
98886
01723
10
1
98886
01723
4
1
02554
01734
4
3
89975
01734
4
3
95665
01734
4
3
02554
01740
6
3
89975
01740
6
3
95665
01740
6
3
02554
01746
5
3
89975
01746
5
3
95665
01746
5
3
02554
01835
2
3
89975
01835
2
3
95665
01835
2
3
02554
51205
4
3
=SUM(--(LEN(UNIQUE(FILTER(A:A, C:C=C2, "")))>0))
Picture of the excel sheet
Picture of working formula
Use the following formula in row 2: =SUMPRODUCT(--(FREQUENCY(IF($B$2:$B$20=$B2,$A$2:$A$20),$A$2:$A$20)>0))
*I think it doesn't require ctrl+shift-enter in older Excel versions, since SUMPRODUCT is an array formula by default.
The formula checks the frequency of values in column A where column B matches the value in the current row. It returns the count per unique value meeting the condition. Wrapping it in -- & >0 returns 1 for each unique value. SUMPRODUCT sums them.
Edit:
I realized that the top level assembly values are actual text, not numeric values. In that case (since it's all numeric values stored as text) you can use this workaround:
=SUMPRODUCT(--(FREQUENCY(IF($B$2:$B$20=$B2,--($A$2:$A$20)),--($A$2:$A$20))>0))
It converts the text to numbers.
Sidenotes to this workaround:
If any value would contain a character other than numeric it will not get counted.
If you have both values like 02554 and 2554 they'll both get converted to 2554 and counted likewise.
Edit 2:
For text use the following:
=SUMPRODUCT(IF($B$2:$B$20=$B2, 1/(COUNTIFS($B$2:$B$20, $B2, $A$2:$A$20, $A$2:$A$20)), 0))
Hello I have a table shown below where I have letters in column 1, and min and max ranges for column 2 and 3. I am trying to retrieve the final number in column 4.
I know I can use a VLOOKUP and set the range as TRUE to get the last column. However, how would I factor in multiple columns/criteria to find match the correct range with the correct letter.
For example, I can would like to get value 4 from the last column. I would have to match with "B" and it would be between 0 and $50,000.
A 0 $50,000 1
A $50,001 $100,000 2
A $100,001 $250,000 3
B 0 $50,000 4
B $50,001 $100,000 5
B $100,001 $250,000 6
C 0 $50,000 7
C $50,001 $100,000 8
C $100,001 $250,000 9
Thank you!
Two ways:
If the pattern is the same as to the breaks of the dollar amounts then use this:
=INDEX(D:D,MATCH(G1,A:A,0)+MATCH(H1,$B$1:$B$3)-1)
Where MATCH(G1,A:A,0) returns the first row where the ID is located and MATCH(H1,$B$1:$B$3) finds the relative location of the price in the first pattern. Change $B$1:$B$3 to encompass the whole pattern.
If the patterns are different then you can use this:
=SUMIFS(D:D,A:A,G1,B:B,"<=" & H1,C:C,">=" & H1)
One more for the future when Microsoft releases FILTER():
=FILTER(D:D,(A:A=G1)*(B:B<=H1)*(C:C>=H1))
This is entered normally and does not matter the pattern.
I'm looking for a formula which will give me the date of the last version of the order.
To illustrate, the sheet looks as follows:
A B C
1 Sales Order Version Date
2 SO#12345 1 21/02/2013
2 SO#12345 2 28/04/2013
3 SO#12345 3 04/08/2013
4 SO#12345 4 27/09/2013
5 SO#54321 1 02/03/2014
6 SO#54321 2 31/03/2014
7 SO#54321 3 07/10/2014
8 SO#54321 4 13/12/2014
So I would like to get the date of SO#12345, version 4 (29/09/2013).
I've tried several combinations of INDEX, MATCH, IF and MAX functions, but I can't seem to get the right value.
It either gives me the corresponding date of the highest value in the version column or it gives me the correct version number, but I can't make it show the appropriate date.
I did use CTRL+SHIFT+ENTER for these formulas, so they are executed as a matrix function.
Again, assuming the Order Number is in E2, try:
=LOOKUP(1,0/FREQUENCY(0,1/(1+(A2:A8=E2)*B2:B8)),C2:C8)
Regards
If the versions are listed in order for each Sales Order numberyou can use LOOKUP like this:
=LOOKUP(2,1/(A$2:A$8=E2),C$2:C$8)
Where E2 contains a specific order number
....or you can use the order number directly
=LOOKUP(2,1/(A$2:A$8="SO#12345"),C$2:C$8)
I have an Summary sheet set up data set up as follows-
Cat A Cat B Cat C Cat D
Name 1 0 0 0 0
Name 2 2 3 2 2
Name 3 2 2 2 2
Name 4 3 2 2 3
Name 5 2 3 2 3
I also then have separate tabs for each of Name1 through to Name 5.
The summary sheet contains the maximum values for each category from each tab. So the Cell at Cat A Name 1 should show the maximum value on Sheet(Name1) in the Cat A column.
So far so good. However each tab may not contain the same categories, so therefore I would like teh summary sheet to check the maximum value in each column by doing a search on the Cat name.
So far I have this-
=MATCH(Overview!S$1,Name1!$C$1:$V$1,0)
Which returns the column number with the right Category, in this case 13. So I can find the right column. What I am struggling with is to now find the maximum value in the column.
Can anyone help?
Thanks
IAssuming your search range goes to row 1000:
=MAX(INDEX(Name1!$C$2:$V$1000,0,MATCH(Overview!S$1,Name1!$C$1:$V$1,0)))
The 0 Row argument in Index means to select the entire column.
The Offset function is your key here.
After you've got the value from the match, you can pass it to the offset to get the correct column.
So, for example, you probably want something like:
=Max(Name1!$C1:$C2000)
But you don't know whether you should use the C column or the D column or whatever, in this case, it was 13, so is that the P column? (c=3, the match was 13 so 3+13 = 16 = P?), so I think you want something like this:
=Max(Offset(Name1!$C$1:$C$2000, 0, [result of your match expression] - 1))
Here's an example of what I think you want in GoogleDocs:
https://docs.google.com/spreadsheet/ccc?key=0Ai45AJPc2AWMdGRlZXNIdlZBaHJxc01qVlJWa1N1WXc