In Excel, how can I create a counter to increment based on a condition? - excel

Lets say in Excel, that I have this in a column. When the number in column N is greater than 3, then the number in the Counter column increases. I have tried if statements, but the count never works.
N Counter
1 1
2 1
3 1
1 2
2 2
3 2
1 3
2 3
3 3

Try this simple COUNTIFS() function.
=COUNTIFS($A$2:$A2,A2)

Related

Is there a way to convert my column of incrementing integers separated by zero to the number of intervals encountered so far in a pandas datafram?

I'm working in pandas and I have a column in my dataframe filled by 0s and incrementing integers starting at one. I would like to add another column of integers but that column would be a counter of how many intervals separated by zero we have encountered to this point. For example my data would like like
Index
1
2
3
0
1
2
0
1
and I would like it to look like
Index IntervalCount
1 1
2 1
3 1
0 1
1 2
2 2
0 2
1 2
Is it possible to do this with vectorized operation or do I have to do this iteratively? Note, it's not important that it be a new column could also overwrite the old one.
You can use cumsum function.
df["IntervalCount"] = (df["Index"] == 1).cumsum()

Increment a column if string appears in dataframe

I want to increment the s_number column if the word "LIVE" appears in another column. The first column will always be "LIVE", and then any occurrence of "LIVE" will always be in a group of 2. I want to increment the s_number column after the second occurrence, I'm not sure how to go about this
Electric s_number
LIVE 1
EARTH 1
NEUTRAL 1
NEUTRAL 1
LIVE 1
LIVE 2
EARTH 2
NEUTRAL 2
Using shift and the column itself to create the bool , then do cumsum
((df.Electric=='LIVE')&(df.Electric.shift()=='LIVE')).cumsum()+1
Out[278]:
0 1
1 1
2 1
3 1
4 1
5 2
6 2
7 2
Name: Electric, dtype: int32

Repeat X in seven rows before incrementing X

Like so:
1
1
1
1
1
1
1
2
2
2
2
2
2
2
...
Something like =IF(A1=4,1,A1+1) would work if the sequence wasn't all the same value.
I believe you are looking for division:
=INT((ROW()-1)/7)
NOTE: You will have to play with the 1 and 7 in the formula above to adapt to your needs. -1 is like an offset, and 7 is the number of times for the repeat. Use -2 if the numbers should start on row 2 for example. Lastly, if you want to start with 1 instead of zero, simply add 1.
=(the previous row's value) + IF(the previous 7 rows all have the same value, 1, 0 )
Obviously(?) this will not work for the first 7 rows; the first row could be the starting value, the next 6 just a straight copy of that.

Find summation and count only if they are EQUAL in Excel

In EXCEL sheet I have 1728 rows and 2 columns (L and O). I am doing addition of these 2 columns in column P. Further I want to count the occurrence in this column if addition is EQUAL to 2 or 4 or 6 or 8 BUT condition here is that The COUNT should be such that BOTH the columns L and O are EQUAL and Their addition is either 2 or 4 or 6 or 8.
This means that only the columns in L and O with values "1+1" , "2+2", "3+3", "4+4" should be counted. The addition of "1+3", "4+2" should not be counted.
=COUNTIF(P:P,4)
does not work.
L O P M
===========================
1 1 2 1 (NO OF 2'S)
2 2 4 1 (NO OF 4'S)
3 3 6 1 (NO OF 6'S)
1 3 4* NO TO BE COUNTED
4 4 8 1 (NO OF 8'S)
2 4 6* NOT TO BE COUNTED
4 2 6*
AS SEEN ABOVE RESULT OF COUNTING IS STORED IN M. Let me know the formula
=IF(L29=M29,SUMPRODUCT(--($L$29:$L$35=$M$29:$M$35)*(L29=$L$29:$L$35)),"Not Counted")
My data started in row 29 so you will need to adjust the references. It counts the entire table in 1 shot. So if you added a row to the bottom that had 1 and 1 and 2, the results in column M in your first row would become 2 and the same for the row you just added.
Will this formula help...?
=IF(AND(A1=B1,OR(SUM(A1,B1)=2,SUM(A1,B1)=4,SUM(A1,B1)=6,SUM(A1,B1)=8)),SUM(A1,B1),"NOT TO BE COUNTED")
Just drag the formula till you have data. You will need to adjust the references.
Here is the reference data.

How to compute the maximum series of a specific condition returning true

i have a slight issue to count the MAX frequency of where the third colmn is bigger than the second. This is just a statistic with scores.
The issue is that i want to have it in one single formula without a macro.
B C
------
2 0
1 2
2 1
2 3
0 1
1 2
0 1
3 3
0 2
0 2
i have tried it with:
{=MAX(FREQUENCY(B3:B100;B3:B100>=C3:C100))} to get 1 for B
{=MAX(FREQUENCY(C3:C100;C3:C100>=B3:B100))} to get 7 for C
I excpected it to deliver me the longest series where the value in the one column was bigger than in the other one, but i failed hard...
Try this version to get 7
=MAX(FREQUENCY(IF(C3:C100>=B3:B100,IF(B3:B100<>"",ROW(B3:B100))),IF(C3:C100<B3:B100,ROW(B3:B100))))
confirmed with CTRL+SHIFT+ENTER
obviously reverse the ranges to get your other result
See example here

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