When doing
echo "some stuff" >> file.txt
I can append to my file some stuff
But when trying to do
echo ls >> file.txt
I append ls instead of listing all my items in the current path. How can I fix this? Sorry I'm new to linux
just redirect the ls output
ls >> file.txt
echo ls >> file.txt
This is interpreted as echo the term ls to file.txt. This isn't what you want.
>> redirects the output of a command, which can be ls.
So you could do:
ls >> file.txt
Related
The following commands work on my terminal but not in my shell script. I later found out that my terminal was /bin/tcsh. Can somebody tell me what changes I need to do for /bin/sh. Here are the commands I need to change:
cp source_dir/*/dir1/*.xml destination_dir/
Error in sh-> cp: cannot stat `source_dir/*/dir1/*.xml': No such file or directory
sed -i "s+${initial_name}+${final_name}+" $file_name
This one does not complain but does not work as well.
I am adding an example for testing. The code tends to rename the names of xml files and also the contents of xml files. For example-
The file name crr.ya.na.aa.xml should be changed to aa.xml
The same name inside crr.ya.na.aa.xml should also be changed from crr.ya.na.aa to aa
Here is the code:
#!/bin/sh
# Create dir structure for testing
rm -rf audience
mkdir audience
mkdir audience/dir1 audience/dir2 audience/dir3
mkdir audience/dir1/ipxact audience/dir2/ipxact audience/dir3/ipxact
touch audience/dir1/ipxact/crr.ya.na.aa.xml
echo "<spirit:name>crr.ya.na.aa</spirit:name>" > audience/dir1/ipxact/crr.ya.na.aa.xml
touch audience/dir2/ipxact/crr.ya.na.bb.xml
echo "<spirit:name>crr.ya.na.bb</spirit:name>" > audience/dir2/ipxact/crr.ya.na.bb.xml
touch audience/dir3/ipxact/crr.ya.na.cc.xml
echo "<spirit:name>crr.ya.na.cc</spirit:name>" > audience/dir3/ipxact/crr.ya.na.cc.xml
# Create a dir for ipxact_drop files if it does not exist
mkdir -p ipxact_drop
rm -rf ipxact_drop/*
cp audience/*/ipxact/*.xml ipxact_drop/
ls ipxact_drop/ > ipxact_drop_files.log
cat ipxact_drop_files.log | \
awk '{ split($0,a,"."); print a[length(a)-1] "." a[length(a)] }' ipxact_drop_files.log > file_names.log
cat ipxact_drop_files.log | \
awk '{ split($0,a,"."); print "mv ipxact_drop/" $0 " ipxact_drop/" a[length(a)-1] "." a[length(a)] }' ipxact_drop_files.log > command.log
chmod +x command.log
./command.log
while read line
do
echo ipxact_drop/$line
initial_name=`grep -m 1 crr ipxact_drop/$line | sed -e 's/<spirit:name>//' | sed -e 's/<\/spirit:name>//' `
final_name="${line%.*}"
echo $initial_name
echo $final_name
sed -i "s+${initial_name}+${final_name}+" ipxact_drop/$line
done < file_names.log
echo " ***** SCRIPT RUN FINISHED *****"
Only the sed command at the end is not working
I was reading some other posts and understood that xml files can have problems with scripts. Here is what that worked for me upto now.
To remove cp error: replace #!/bin/sh -f with #!/bin/sh
To remove sed error for the test input: replace sed -i ...... with sed -i.back ....
When I am running below command in unix terminal , its working fine
grep 'ND logistics' /Test/testdir
/asbced/some text/ND logistics Excel/new text
but when I am running same command inside a script, its not working
cat Test.txt
#!/bin/bash
filename = $1
echo "$filename"
grep "$filename" /Test/testdir >> test2.txt
How can I suppress error messages for a shell command?
For example, if there are only jpg files in a directory, running ls *.zip gives an error message:
$ ls *.zip
ls: cannot access '*.zip': No such file or directory
Is there an option to suppress such error messages? I want to use this command in a Bash script, but I want to hide all errors.
Most Unix commands, including ls, will write regular output to standard output and error messages to standard error, so you can use Bash redirection to throw away the error messages while leaving the regular output in place:
ls *.zip 2> /dev/null
$ ls *.zip 2>/dev/null
will redirect any error messages on stderr to /dev/null (i.e. you won't see them)
Note the return value (given by $?) will still reflect that an error occurred.
To suppress error messages and also return the exit status zero, append || true. For example:
$ ls *.zip && echo hello
ls: cannot access *.zip: No such file or directory
$ ls *.zip 2>/dev/null && echo hello
$ ls *.zip 2>/dev/null || true && echo hello
hello
$ touch x.zip
$ ls *.zip 2>/dev/null || true && echo hello
x.zip
hello
I attempted ls -R [existing file] and got an immediate error.
ls: cannot access 'existing file': No such file or directory
So, I used the following:
ls -R 2>dev/null | grep -i [existing file]*
ls -R 2>dev/null | grep -i text*
Or, in your case:
ls -R 2>dev/null | grep -i *.zip
My solution with a raspberry pi3 with buster.
ls -R 2>/dev/null | grep -i [existing file]*
2>/dev/null is very usefull with Bash script to avoid useless warnings or errors.
Do not forget slash caracter
I have written shell script which reads commands from input file and execute commands. I have command like:
cat linux_unit_test_commands | grep "dmesg"
in the input file. I am getting below error message while executing shell script:
cat: |: No such file or directory
cat: grep: No such file or directory
cat: "dmesg": No such file or directory
Script:
#!/bin/bash
while read line
do
output=`$line`
echo $output >> logs
done < $1
Below is input file(example_commands):
ls
date
cat linux_unit_test_commands | grep "dmesg"
Execute: ./linux_unit_tests.sh example_commands
Please help me to resolve this issue.
Special characters like | and " are not parsed after expanding variables; the only processing done after variable expansion is word splitting and wildcard expansions. If you want the line to be parsed fully, you need to use eval:
while read line
do
output=`eval "$line"`
echo "$output" >> logs
done < $1
You might be wondering why its not working with cat command.
Then here is the answer for your question.
output=`$line` i.e. output=`cat linux_unit_test_commands | grep "dmesg"`
here the cat command will take (linux_unit_test_commands | grep "dmesg") all these as arguments i.e. fileNames.
From Man page:
SYNTAX : cat [OPTION]... [FILE]...
++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
Script is OK!
#!/bin/bash
while read line;
do
output=`$line`
echo $output >> logs
done < $1
To make it work you need to change 'cat: "dmesg": No such file or directory' to 'grep "dmesg" linux_unit_test_commands'. It will work!
cat linux_unit_test_commands
ls
date
grep "dmesg" linux_unit_test_commands
I have a file "atest.txt" that have some text..
I want to print this text at files "asdasd.txt asgfaya.txt asdjfusfdgh.txt asyeiuyhavujh.txt"
This files is not exist on my server..
I'm running Debian.. What can i do?
Use the tee(1) command, which duplicates its standard input to standard output and any files specified on the command line. E.g.
printf "Hello\nthis is a test\nthank you\n"
| tee test1.txt test2.txt $OTHER_FILES >/dev/null
Using your example:
cat atest.txt
| tee asdasd.txt asgfaya.txt asdjfusfdgh.txt asyeiuyhavujh.txt >/dev/null
From your bash prompt:
for f in test1.txt test2.txt test3.txt; do echo -e "hello\nworld" >> $f; done
If the text lives in atest.txt then do:
for f in test1.txt test2.txt test3.txt; do cat atest.txt >> $f; done
Isn't it simply:
cp atest.txt asdasd.txt
cp atest.txt asgfaya.txt
cp atest.txt asdjfusfdgh.txt
cp atest.txt asyeiuyhavujh.txt
?
In bash you can write
#!/bin/bash
$TEXT="hello\nthis is a test\nthank you"
for i in `seq 1 $1`; do echo -e $TEXT >text$i.txt; done
EDIT (in response of question change)
If you can't determine programmatically the names of the target files then you can use this script it:
#!/bin/bash
ORIGIN=$1;
shift
for i in `seq $#`; do cp "$ORIGIN" "$1"; shift; done
you can use it this way:
script_name origin_file dest_file1 second_dest_file 'third file' ...
If you are wondering why there are the double quotes into the cp command, it is for cope with filename containing spaces
If anyone would like to write same thing to all files in dir:
printf 'your_text' | tee *