When I am running below command in unix terminal , its working fine
grep 'ND logistics' /Test/testdir
/asbced/some text/ND logistics Excel/new text
but when I am running same command inside a script, its not working
cat Test.txt
#!/bin/bash
filename = $1
echo "$filename"
grep "$filename" /Test/testdir >> test2.txt
Related
I've placed a bash file inside .zshrc and tried all different ways to run it every time I open a new terminal window or source .zshrc but no luck.
FYI: it was working fine on .bashrc
here is .zshrc script:
#Check if ampps is running
bash ~/ampps_runner.sh & disown
Different approach:
#Check if ampps is running
sh ~/ampps_runner.sh & disown
Another approach:
#Check if ampps is running
% ~/ampps_runner.sh & disown
All the above approaches didn't work (meaning it supposes to run an app named ampps but it doesn't in zsh.
Note: It was working fine before switching to zsh from bash. so it does not have permission or syntax problems.
Update: content of ampps_runner.sh
#! /usr/bin/env
echo "########################"
echo "Checking for ampps server to be running:"
check=$(pgrep -f "/usr/local/ampps" )
#[ -z "$check" ] && echo "Empty: Yes" || echo "Empty: No"
if [ -z "$check" ]; then
echo "It's not running!"
cd /usr/local/ampps
echo password | sudo -S ./Ampps
else
echo "It's running ..."
fi
(1) I believe ~/.ampps_runner.sh is a bash script, so, its first line should be
#!/bin/bash
or
#!/usr/bin/bash
not
#! /usr/bin/env
(2) Then, the call in zsh script (~/.zshrc) should be:
~/ampps_runner.sh
(3) Note: ~/.ampps_runner.sh should be executable. Change it to executable:
$ chmod +x ~/ampps_runner.sh
The easiest way to run bash temporarily from a zsh terminal is to
exec bash
or just
bash
Then you can run commands you previously could only run in bash. An example
help exec
To exit
exit
Now you are back in your original shell
If you want to know your default shell
echo $SHELL
or
set | grep SHELL=
If you want to reliably know your current shell
ps -p $$
Or if you want just the shell name you might use
ps -p $$ | awk "NR==2" | awk '{ print $4 }' | tr -d '-'
And you might just put that last one in a function for later, just know that it is only available if it was sourced in a current shell.
whichShell(){
local defaultShell=$(echo $SHELL | tr -d '/bin/')
echo "Default: $defaultShell"
local currentShell=$(ps -p $$ | awk "NR==2" | awk '{ print $4 }' | tr -d '-')
echo "Current: $currentShell"
}
Call the method to see your results
whichShell
The following commands work on my terminal but not in my shell script. I later found out that my terminal was /bin/tcsh. Can somebody tell me what changes I need to do for /bin/sh. Here are the commands I need to change:
cp source_dir/*/dir1/*.xml destination_dir/
Error in sh-> cp: cannot stat `source_dir/*/dir1/*.xml': No such file or directory
sed -i "s+${initial_name}+${final_name}+" $file_name
This one does not complain but does not work as well.
I am adding an example for testing. The code tends to rename the names of xml files and also the contents of xml files. For example-
The file name crr.ya.na.aa.xml should be changed to aa.xml
The same name inside crr.ya.na.aa.xml should also be changed from crr.ya.na.aa to aa
Here is the code:
#!/bin/sh
# Create dir structure for testing
rm -rf audience
mkdir audience
mkdir audience/dir1 audience/dir2 audience/dir3
mkdir audience/dir1/ipxact audience/dir2/ipxact audience/dir3/ipxact
touch audience/dir1/ipxact/crr.ya.na.aa.xml
echo "<spirit:name>crr.ya.na.aa</spirit:name>" > audience/dir1/ipxact/crr.ya.na.aa.xml
touch audience/dir2/ipxact/crr.ya.na.bb.xml
echo "<spirit:name>crr.ya.na.bb</spirit:name>" > audience/dir2/ipxact/crr.ya.na.bb.xml
touch audience/dir3/ipxact/crr.ya.na.cc.xml
echo "<spirit:name>crr.ya.na.cc</spirit:name>" > audience/dir3/ipxact/crr.ya.na.cc.xml
# Create a dir for ipxact_drop files if it does not exist
mkdir -p ipxact_drop
rm -rf ipxact_drop/*
cp audience/*/ipxact/*.xml ipxact_drop/
ls ipxact_drop/ > ipxact_drop_files.log
cat ipxact_drop_files.log | \
awk '{ split($0,a,"."); print a[length(a)-1] "." a[length(a)] }' ipxact_drop_files.log > file_names.log
cat ipxact_drop_files.log | \
awk '{ split($0,a,"."); print "mv ipxact_drop/" $0 " ipxact_drop/" a[length(a)-1] "." a[length(a)] }' ipxact_drop_files.log > command.log
chmod +x command.log
./command.log
while read line
do
echo ipxact_drop/$line
initial_name=`grep -m 1 crr ipxact_drop/$line | sed -e 's/<spirit:name>//' | sed -e 's/<\/spirit:name>//' `
final_name="${line%.*}"
echo $initial_name
echo $final_name
sed -i "s+${initial_name}+${final_name}+" ipxact_drop/$line
done < file_names.log
echo " ***** SCRIPT RUN FINISHED *****"
Only the sed command at the end is not working
I was reading some other posts and understood that xml files can have problems with scripts. Here is what that worked for me upto now.
To remove cp error: replace #!/bin/sh -f with #!/bin/sh
To remove sed error for the test input: replace sed -i ...... with sed -i.back ....
The cronjob does not pipe the output from another script to a file but it works I execute it (not same user, chmod for both files is set to 777).
#! /bin/sh
. /disk2/etc/env_cron
SUBJ="Test"
TEXT=/disk2/home/user/mailtxt
ADDR="mail#domain.com"
echo -e `date` > $TEXT
echo -e "1\n\n\nq" | menu >> $TEXT
mutt -s "$SUBJ" -i $TEXT -- $ADDR < /dev/null
I want it to pipe "echo -e 1\n\n\nq" to the script Menu and in turn get the output in a file. The output from Menu will just be text.
The problem (as suggested) was that the cronjob did not have the script 'menu' in it's path. Changing "menu" in the script to the absolute path fixed it.
echo -e "1\n\n\nq" | /folder/folder/menu >> $TEXT
EDIT: Do not forget to set the correct permissions on the textfile if the cronjob is run by another user.
I have written shell script which reads commands from input file and execute commands. I have command like:
cat linux_unit_test_commands | grep "dmesg"
in the input file. I am getting below error message while executing shell script:
cat: |: No such file or directory
cat: grep: No such file or directory
cat: "dmesg": No such file or directory
Script:
#!/bin/bash
while read line
do
output=`$line`
echo $output >> logs
done < $1
Below is input file(example_commands):
ls
date
cat linux_unit_test_commands | grep "dmesg"
Execute: ./linux_unit_tests.sh example_commands
Please help me to resolve this issue.
Special characters like | and " are not parsed after expanding variables; the only processing done after variable expansion is word splitting and wildcard expansions. If you want the line to be parsed fully, you need to use eval:
while read line
do
output=`eval "$line"`
echo "$output" >> logs
done < $1
You might be wondering why its not working with cat command.
Then here is the answer for your question.
output=`$line` i.e. output=`cat linux_unit_test_commands | grep "dmesg"`
here the cat command will take (linux_unit_test_commands | grep "dmesg") all these as arguments i.e. fileNames.
From Man page:
SYNTAX : cat [OPTION]... [FILE]...
++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
Script is OK!
#!/bin/bash
while read line;
do
output=`$line`
echo $output >> logs
done < $1
To make it work you need to change 'cat: "dmesg": No such file or directory' to 'grep "dmesg" linux_unit_test_commands'. It will work!
cat linux_unit_test_commands
ls
date
grep "dmesg" linux_unit_test_commands
I have a file "atest.txt" that have some text..
I want to print this text at files "asdasd.txt asgfaya.txt asdjfusfdgh.txt asyeiuyhavujh.txt"
This files is not exist on my server..
I'm running Debian.. What can i do?
Use the tee(1) command, which duplicates its standard input to standard output and any files specified on the command line. E.g.
printf "Hello\nthis is a test\nthank you\n"
| tee test1.txt test2.txt $OTHER_FILES >/dev/null
Using your example:
cat atest.txt
| tee asdasd.txt asgfaya.txt asdjfusfdgh.txt asyeiuyhavujh.txt >/dev/null
From your bash prompt:
for f in test1.txt test2.txt test3.txt; do echo -e "hello\nworld" >> $f; done
If the text lives in atest.txt then do:
for f in test1.txt test2.txt test3.txt; do cat atest.txt >> $f; done
Isn't it simply:
cp atest.txt asdasd.txt
cp atest.txt asgfaya.txt
cp atest.txt asdjfusfdgh.txt
cp atest.txt asyeiuyhavujh.txt
?
In bash you can write
#!/bin/bash
$TEXT="hello\nthis is a test\nthank you"
for i in `seq 1 $1`; do echo -e $TEXT >text$i.txt; done
EDIT (in response of question change)
If you can't determine programmatically the names of the target files then you can use this script it:
#!/bin/bash
ORIGIN=$1;
shift
for i in `seq $#`; do cp "$ORIGIN" "$1"; shift; done
you can use it this way:
script_name origin_file dest_file1 second_dest_file 'third file' ...
If you are wondering why there are the double quotes into the cp command, it is for cope with filename containing spaces
If anyone would like to write same thing to all files in dir:
printf 'your_text' | tee *