realloc function gives SIGABRT due to limited heap size - linux

Question

I am trying to reproduc a problem .
My c code giving SIGABRT , i traced it back to this line number :3174
https://elixir.bootlin.com/glibc/glibc-2.27/source/malloc/malloc.c
/* Little security check which won't hurt performance: the allocator
never wrapps around at the end of the address space. Therefore
we can exclude some size values which might appear here by
accident or by "design" from some intruder. We need to bypass
this check for dumped fake mmap chunks from the old main arena
because the new malloc may provide additional alignment. */
if ((__builtin_expect ((uintptr_t) oldp > (uintptr_t) -oldsize, 0)
|| __builtin_expect (misaligned_chunk (oldp), 0))
&& !DUMPED_MAIN_ARENA_CHUNK (oldp))
malloc_printerr ("realloc(): invalid pointer");
My understanding is that when i call calloc function memory get allocated when I call realloc function and try to increase memory area ,heap is not available for some reason giving SIGABRT
My another question is, How can I limit the heap area to some bytes say, 10 bytes to replicate the problem. In stackoverflow RSLIMIT and srlimit is mentioned but no sample code is mentioned. Can you provide sample code where heap size is 10 Bytes ?

Answer 1

How can I limit the heap area to some bytes say, 10 bytes
Can you provide sample code where heap size is 10 Bytes ?
From How to limit heap size for a c code in linux , you could do:
You could use (inside your program) setrlimit(2), probably with RLIMIT_AS (as cited by Ouah's answer).
#include <sys/resource.h>
int main() {
setrlimit(RLIMIT_AS, &(struct rlimit){10,10});
}
Better yet, make your shell do it. With bash it is the ulimit builtin.
$ ulimit -v 10
$ ./your_program.out
to replicate the problem
Most probably, limiting heap size will result in a different problem related to heap size limit. Most probably it is unrelated, and will not help you to debug the problem. Instead, I would suggest to research address sanitizer and valgrind.