I am looking for a formula where I can put a 5 digit Modified Julian Date and have it convert it to today's date for me.
I did it in a way where I have a separate sheet with a table but although it works, I am looking for a way without the need of a separate table. Here is some information:
00000 should translate to 11-17-1858
58890 should translate to 02-11-2020
Every time the number goes up 1, it should go up 1 day. This needs to have leap years in consideration as well. Any help will be appreciated.
Here is a website that currently does the conversions:
http://www.csgnetwork.com/julianmodifdateconv.html
This has to be done without macros, literally need it in formula format.
Just subtract 15018 and format the result as a date.
Why 15018 and not 15020?
In Excel, 1-Jan-1900 value is 1
In your date scheme 15020 = 1-Jan-1900
But, if you had the number 15020 to convert and subtracted 15020 it would --> 0, not the desired 1.
Therefore we reduce the 15020 by 1 to 15019.
Next, there is a deliberate "bug" in Excel, widely discussed both on SO and the internet, whereby the year 1900 is erroneously classified as a leap year.
So for any date equivalent that is after 28-Feb-1900, we have to subtract an extra 1.
If you might be dealing with dates between 1/1/1900 and 2/28/1900 you will need to modify the formula to take that into account.
Minor thing and not sure if on the right place to ask.. but; I have a large dataset with dates, some of then have the correct date stamp, others are just a string of numbers and time which forms an optical date, but isn't. I figured out it has something today with a double space.
12/12/2016 13:01:32 PM
12/12/2016 12:33:46 PM (this one has 2 spaced between 2016 and 12)
the last one is the correct format for a date stamp
research:
http://www.mrexcel.com/forum/excel-questions/502863-extract-am-pm-text-date-time.html
Got it, the problem was in the data set.. with text to column I separated the date time and PM/AM.. then I can get the date and time separate and delete the last column.. thanks for your interest
Got input such as in the topic title.
Trying to figure out how to convert this into UK date and time to be used in calculations.
I've looked at some methods on Google such as using text to columns, but I don't think this is what I'm looking for...
Thanks!
Edit: month is always in abbreviated format.
Edit 2: I should mention that I'm in the UK, and it doesn't seem to convert US date automagically.
Edit 3: Data:
Jun 05 2016 08:00:00 to dd/mm/yyyy hh:mm:ss
Assuming that your source date is a string and it is in the cell D10, the first thing you need to do is convert it to an excel date time serial. In the Excel Date Time serial there are a few things to note.
The integer portion of the number represents the number of days since Jan 1 1900 in windows and I think 1904 on mac
The decimal portion of the number represents the time in fraction of a day. 0.5 would represent noon. Valid Excel times for VBA are 00:00 to 23:59:59. 24:00 is not a valid time, though it will work with some excel formulas
So in order to convert your string to an Excel date serial we will need to rip out the components and dump them into the DATE() function. The date function consists of three arguments:
DATE(year,month,day)
Pretty straight forward with the exception that those values need to be numbers. Why dont we start pulling your information going from the largest unit to the smallest unit.
Thankfully your string is of consistent length. You have leading 0 for your single digits so they will occupy the same space as double digits. So this method will work until the year 9999, but I don't think we are too worried about that right now.
In order to pull the year we look at where it is in your string and how long it is. So by simply counting we know it starts in the 8th character position and its 4 characters long. We use this information with the MID() function
=MID(D10,8,4)
In order to pull the month it get a little more complicated since we need to convert it from an abbreviation to a number. There are several ways of doing this. You could go for a long IF statement which would wind up repeating the pull of the month a 11 times. Instead I decided to use the MATCH() function and built an array of month abbreviations inside it. The MATCH() function will return the number/position of what you are searching for in the provided search list. So as long as we enter the months in chronological order, their position will correspond to their numeric values. As such our formula will look like:
MATCH(LEFT(D10,3),{"JAN","FEB","MAR","APR","MAY","JUN","JUL","AUG","SEP","OCT","NOV","DEC"},0)
The LEFT() function was used to pull the month abbreviation from your string. The 0 at the end tell match to look for an exact match. Important to note, this match method is not case sensitive.
Now to get the day we employ the same principals that we did for pulling the year and we wind up with:
=MID(D10,5,2)
We can now substitute each of the formulas for Year Month and Day into the DATE() function and we will get the date portion of the excel date serial. The formula should look like the following:
=DATE(MID(D10,8,4),MATCH(LEFT(D10,3),{"JAN","FEB","MAR","APR","MAY","JUN","JUL","AUG","SEP","OCT","NOV","DEC"},0),MID(D10,5,2))
Now you need to tack on your time portion or figure out the decimal portion. In order to do this I would first recommend trying the TIMEVALUE() function. Since time formats tend to be a lot more standard in format than dates, there is a much higher probability that it will work for you. In order to use TIMEVALUE(), the time portion needs to be ripped from the string. This can easily be done with the RIGHT() function as follows:
=RIGHT(D10,8)
That will give you just the time portion which can then be substituted into the TIMEVALUE() function and looks like:
=TIMEVALUE(RIGHT(D10,8))
If the TIMEVALUE() function does not work for you, then you will need to strip out the hour minutes and seconds and dump their results in to the TIME() function. Do this in the same way you pulled the year and the day for the DATE() function. Just update your character counts. TIME() uses three arguments as follows:
TIME(HOUR,MINUTES,SECONDS)
Now that you have figured out your date portion and your time portion all you need to do is add them together to get all the information into one cell. The resulting formula will look like:
=DATE(MID(D10,8,4),MATCH(LEFT(D10,3),{"JAN","FEB","MAR","APR","MAY","JUN","JUL","AUG","SEP","OCT","NOV","DEC"},0),MID(D10,5,2))+TIMEVALUE(RIGHT(D10,8))
Where ever you windup placing that formula, remember to change the formatting on the cell to a custom date. Enter the cell custom format as in the image below.
If you have a list of date times to convert in a column, simply copy your formula and formatted cell down as far as you need to go.
Proof of Concept
Formulas used
For more information on the functions used in the formulas above, follow the links below:
MATCH
DATE
TIMEVALUE
RIGHT
MID
LEFT
{"JAN","FEB","MAR","APR","MAY","JUN","JUL","AUG","SEP","OCT","NOV","DEC"}
The { } are used to build a custom list or static array.
If you don't want to write a macro in VBA, a cell formula would work if the format is as you specified:
I am assuming the data is in cell B3
=MID(B3,5,2) & "/" & IF(LEFT(B3,3)="Jan","01",IF(LEFT(B3,3)="Feb","02",IF(LEFT(B3,3)="Mar","03",IF(LEFT(B3,3)="Apr","04",IF(LEFT(B3,3)="May","05",IF(LEFT(B3,3)="Jun","06",IF(LEFT(B3,3)="Jul","07",IF(LEFT(B3,3)="Aug","08",IF(LEFT(B3,3)="Sep","09",IF(LEFT(B3,3)="Oct","10",IF(LEFT(B3,3)="Nov","11","12"))))))))))) & "/" & RIGHT(B3,13)
The DATEVALUE function expects a comma between the day and year; the REPLACE function can add that in. The TIMEVALUE function should be able to read that time without modification.
=DATEVALUE(REPLACE(LEFT(A1, 11), 7, 0, ","))+TIMEVALUE(RIGHT(A1, 8))
Note that the original in A1 is left-aligned; this indicates a text value. The converted date/time in B1 is right-aligned; this indicates a true date/time value.
Column B was formatted as dd/mm/yyyy hh:mm:ss. As General it would show as 42526.33333.
Got formulas for figuring my differences between date periods in days as follows:
=IF(F7="","0",DAYS360(F6,F7)+1)
This gives the days result for each period that I am interested in, but I then need to add each period of days together and subtract them from a current date (like doing service computation). The issue is that I need to do this second calculation within a 360-day calendar as well. If I just try to do a days360() formula with one value being the current date and the other being the total number of days that I need to backtrack, then the "original" date that it comes up with is drastically off.
This seems to be the equivalent of the difference between NETWORKDAYS and WORKDAY functions. The former counts working days between two dates, the latter adds working days to a date, you essentially want the WORKDAY equivalent for DAYS360, which I don't think exists.
You can manipulate DAYS360, though, e.g. with a date in A2 and number of days to subtract (in 360 day mode) in B2 you can use this formula for the date
=A2-B2-MATCH(B2,INDEX(DAYS360(A2-B2-ROW(INDIRECT("1:"&CEILING(B2/30,1))),A2),0),0)
I am doing some work in Excel and am running into a bit of a problem. The instruments I am working with save the date and the time of the measurements and I can read this data into Excel with the following format:
A B
1 Date: Time:
2 12/11/12 2:36:25
3 12/12/12 1:46:14
What I am looking to do is find the difference in the two date/time stamps in mins so that I can create a decay curve from the data. So In Excel, I am looking to Make this (if the number of mins in this example is wrong I just calculated it by hand quickly):
A B C
1 Date: Time: Time Elapsed (Minutes)
2 12/11/12 2:36:25 -
3 12/12/12 1:46:14 1436.82
I Have looked around for a bit and found several methods for the difference in time but they always assume that the dates are the same. I exaggerated the time between my measurements some but that roll over of days is what is causing me grief. Any suggestions or hints as to how to go about this would be great. Even If I could find the difference between the date and times in hrs or days in a decimal format, I could just multiple by a constant to get my answer. Please note, I do have experience with programming and Excel but please explain in details. I sometimes get lost in steps.
time and date are both stored as numerical, decimal values (floating point actually). Dates are the whole numbers and time is the decimal part (1/24 = 1 hour, 1/24*1/60 is one minute etc...)
Date-time difference is calculated as:
date2-date1
time2-time1
which will give you the answer in days, now multiply by 24 (hours in day) and then by 60 (minutes in hour) and you are there:
time elapsed = ((date2-date1) + (time2-time1)) * 24 * 60
or
C3 = ((A3-A2)+(B3-B2))*24*60
To add a bit more perspective, Excel stores date and times as serial numbers.
Here is a Reference material to read up.
I would suggest you to use the following:
Combine date to it's time and then do the difference. So it will not cause you any issues of next day or anything.
Please refer to the image with calculations. You may leave your total minutes cell as general or number format.
MS EXCEL Article: Calculate the difference between two times
Example as per this article
Neat way to do this is:
=MOD(end-start,1)*24
where start and end are formatted as "09:00" and "17:00"
Midnight shift
If start and end time are on the same day the MOD function does not affect anything. If the end time crosses midnight, and the end is earlier then start (say you start 23PM and finish 1AM, so result is 2 hours), the MOD function flips the sign of the difference.
Note that this formula calculates the difference between two times (actually two dates) as decimal value. If you want to see the result as time, display the result as time (ctrl+shift+2).
https://exceljet.net/formula/time-difference-in-hours-as-decimal-value
get n day between two dates, by using days360 function =days360(dateA,dateB)
find minute with this formula using timeA as reference =(timeB-$timeA+n*"24:00")*1440
voila you get minutes between two time and dates
I think =TEXT(<cellA> - <cellB>; "[h]:mm:ss") is a more concise answer. This way, you can have your column as a datetime.