I have my data in a file store by lines like this :
3.172704445659,50.011996744997,3.1821975358417,50.012335988197,3.2174797791605,50.023182479597
And I would like 2 columns :
3.172704445659 50.011996744997
3.1821975358417 50.012335988197
3.2174797791605 50.023182479597
I know sed command for delete ','(sed "s/,/ /") but I don't know how to "back to line" every two digits ?
Do you have any ideas ?
One in awk:
$ awk -F, '{for(i=1;i<=NF;i++)printf "%s%s",$i,(i%2&&i!=NF?OFS:ORS)}' file
Output:
3.172704445659 50.011996744997
3.1821975358417 50.012335988197
3.2174797791605 50.023182479597
Solution viable for those without knowledge of awk command - simple for loop over an array of numbers.
IFS=',' read -ra NUMBERS < file
NUMBERS_ON_LINE=2
INDEX=0
for NUMBER in "${NUMBERS[#]}"; do
if (($INDEX==$NUMBERS_ON_LINE-1)); then
INDEX=0
echo "$NUMBER"
else
((INDEX++))
echo -n "$NUMBER "
fi
done
Since you already tried sed, here is a solution using sed:
sed -r "s/(([^,]*,){2})/\1\n/g; s/,\n/\n/g" YOURFILE
-r uses sed extended regexp
there are two substitutions used:
the first substitution, with the (([^,]*,){2}) part, captures two comma separated numbers at once and store them into \1 for reuse: \1 holds in your example at the first match: 3.172704445659,50.011996744997,. Notice: both commas are present.
(([^,]*,){2}) means capture a sequence consisting of NOT comma - that is the [^,]* part followed by a ,
we want two such sequences - that is the (...){2} part
and we want to capture it for reuse in \1 - that is the outer pair of parentheses
then substitute with \1\n - that just inserts the newline after the match, in other words a newline after each second comma
as we have now a comma before the newline that we need to get rid of, we do a second substitution to achieve that:
s/,\n/\n/g
a comma followed by newline is replace with only newline - in other words the comma is deleted
awk and sed are powerful tools, and in fact constitute programming languages in their own right. So, they can, of course, handle this task with ease.
But so can bash, which will have the benefits of being more portable (no outside dependencies), and executing faster (as it uses only built-in functions):
IFS=$', \n'
values=($(</path/to/file))
printf '%.13f %.13f\n' "${values[#]}"
Related
i have the file virt.txt contains:
0302 000000 23071SOCIETY 117
0602 000000000000000001 PAYMENT BANK
I want to remove 3 whitespaces from 6th to 8th column to the first line only.
I do:
sed '1s/[[:blank:]]+[[:blank:]]+[[:blank:]]//6' virt.txt
it'KO
please help
Your regex would consume all the available blanks from a sequence of three or more (in a quite inefficient way) and replace the sixth occurrence of that. Because your first input line does not contain six or more separate stretches of three or more whitespace characters, it actually did nothing. But you can in fact use sed to do exactly what you say you want:
sed '1s/^\(.....\) /\1/' virt.txt
(or for convenience, if you have sed -E or the variant sed -r which works on some platforms, but neither of these is standard):
sed -E '1s/^(.{5}) {3}/\1/' virt.txt # -E is not portable
The parentheses capture the first five characters into a back reference, and we then use the first back reference \1 as the replacement string, effectively replacing only the text which matched outside the parentheses.
If your sed supports the -i option, you can use that to modify the file directly; but this is also not standard, so the most portable solution is to write the result to a new file, then move it back on top of the original file if you want to replace it.
sed is convenient if you are familiar with it, but as you are clearly not, perhaps a better approach would be to use a different language, ideally one which is not write-only for many users, like sed.
If you know the three characters will always be spaces, just do a static replacement.
awk 'NR==1 { $0 = substr($0, 1, 5) substr($0, 9) } 1' virt.txt
On the first line (NR is the current input line number) replace the input line $0 with a catenation of the substrings on both sides of the part you want to cut.
For a simple replacement like that, you can also use basic Unix text manipulation utilities, though it's rather inefficient and inelegant:
head -n 1 virt.txt | cut -c1-5,9- >newfile.txt
tail -n +2 virt.txt >>newfile.txt
If you need to check that the three characters are spaces, the Awk script only needs a minor tweak.
awk 'NR==1 && /^.{5} {3}/ { $0 = substr($0, 1, 5) substr($0, 9) } 1' virt.txt
You should vaguely recognize the regex from above. Awk is less succinct, but as a consequence also quite a lot more readable, than sed.
I am trying to split gps coordinates into two separate fields in a CSV file. The coordinates are currently combined. Here is a few examples:
+40.71427-074.00597/
-42+174/
+33.20984-087.56917/
+39.76-098.5/
+39.76-098.5/
+42.27756-083.74088/
I was thinking of splitting this using:
sed -r 's/-/,-/g'
but this would only work for the strings that contain a "-", some of these begin the string with a - or have a + in the middle. The +/- signs are important to keep as they determine direction, so I cannot afford to lose them.
Any advice or suggestions would be greatly appreciated and thank you for taking the time!
With any sed:
$ sed 's:\(.*\)\([+-].*\)/:\1,\2:' file
+40.71427,-074.00597
-42,+174
+33.20984,-087.56917
+39.76,-098.5
+39.76,-098.5
+42.27756,-083.74088
This might work for you (GNU sed):
sed 's/[+-]/,&/2' file
This replaces the second occurrence of either + or - by ,+ or ,-.
You may use
sed -E 's/(.+)([-+])/\1,\2/' file > newfile # POSIX ERE syntax
sed 's/\(.*\)\([-+]\)/\1,\2/' file > newfile # POSIX BRE syntax
See the online sed demo
The (.+)([-+]) pattern matches and captures into Group 1 any one or more chars and then captures a - or + in Group 2 and then \1,\2 replacement inserts a comma in between the groups.
You may make the pattern a bit more efficient with a negated bracket expression:
's/([^-+]+)([-+])/\1,\2/' # POSIX ERE
's/\([^-+]*\)\([-+]\)/\1,\2/' # POSIX BRE
where [^-+]+ matches 1 or more chars other than - and +.
Im trying to replace numbers in my textfile by adding one to them. i.e.
sed 's/3/4/g' path.txt
sed 's/2/3/g' path.txt
sed 's/1/2/g' path.txt
Instead of this, Can i automate it, i.e. find a /d and add one to it in the replace.
Something like
sed 's/\([0-8]\)/\1+1/g' path.txt
Also wanted to capture more than one digit i.e. ([0-9])\t([0-9]) and change each one keeping the tab inbetween
Thanks
edited #2
Using the perl example,
I also would like it to work with more digits i.e.
perl -pi~ -e 's/(\d+)\.(\d+)\.(\d+)\.(\d+)/ ($1+1)\.($2+1)\.($3+1)\.($4+1) /ge' output.txt
Any tips on making the above work?
There is no support for arithmetic in sed, but you can easily do this in Perl.
perl -pe 's/(\d+)/ $1+1 /ge'
With the /e option, the replacement expression needs to be valid Perl code. So to handle your final updated example, you need
perl -pi~ -e 's/(\d+)\.(\d+)\.(\d+)\.(\d+)/ $1+1 . "." $2+1 . "." . $3+1 . "." . $4+1 /ge'
where strings are properly quoted and adjacent strings are concatenated together with the . Perl string concatenation operator. (The arithmetic numbers are coerced into strings as well when they are concatenated with a string.)
... Though of course, the first script already does that more elegantly, since with the /g flag it already increments every sequence of digits with one, anywhere in the string.
Triplee's perl solution is the more generic answer, but Michal's sed solution works well for this particular case. However, Michal's sed solution is more easily written:
sed y/12345678/23456789/ path.txt
and is better implemented as
tr 12345678 23456789 < path.txt
This utterly fails to handle 2 digit numbers (as in the edited question).
You can do it with sed but it's not easy, see this thread.
And it's hard with awk too, see this.
I'd rather use perl for this (something like this can be seen in action # ideone):
perl -pe 's/([0-8])/$1+1/e'
(The ideone.com example must have some looping as ideone does not sets -pe by default.)
You can't do addition directly in sed - you could do it in awk by matching numbers using a regex in each line and increasing the value, but it's quite complicated. If do not need to handle arbitrary numbers but a limited set, like only single-digit numbers from 0 to 8, you can just put several replacement commands on a single sed command line by separating them with semicolons:
sed 's/8/9/g ; s/7/8/g; s/6/7/g; s/5/6/g; s/4/5/g; s/3/4/g; s/2/3/g; s/1/2/g; s/0/1/g' path.txt
This might work for you (GNU sed & Bash):
sed 's/[0-9]/$((&+1))/g;s/.*/echo "&"/e' file
This will add one to every individual digit, to increment numbers:
sed 's/[0-9]\+/$((&+1))/g;s/.*/echo "&"/e' file
N.B. This method is fraught with problems and may cause unexpected results.
I have a string separated by dot in Linux Shell,
$example=This.is.My.String
I want to
1.Add some string before the last dot, for example, I want to add "Good.Long" before the last dot, so I get:
This.is.My.Goood.Long.String
2.Get the part after the last dot, so I will get
String
3.Turn the dot into underscore except the last dot, so I will get
This_is_My.String
If you have time, please explain a little bit, I am still learning Regular Expression.
Thanks a lot!
I don't know what you mean by 'Linux Shell' so I will assume bash. This solution will also work in zsh, etcetera:
example=This.is.My.String
before_last_dot=${example%.*}
after_last_dot=${example##*.}
echo ${before_last_dot}.Goood.Long.${after_last_dot}
This.is.My.Goood.Long.String
echo ${before_last_dot//./_}.${after_last_dot}
This_is_My.String
The interim variables before_last_dot and after_last_dot should explain my usage of the % and ## operators. The //, I also think is self-explanatory but I'd be happy to clarify if you have any questions.
This doesn't use sed (or even regular expressions), but bash's inbuilt parameter substitution. I prefer to stick to just one language per script, with as few forks as possible :-)
Other users have given good answers for #1 and #2. There are some disadvantages to some of the answers for #3. In one case, you have to run the substitution twice. In another, if your string has other underscores they might get clobbered. This command works in one go and only affects dots:
sed 's/\(.*\)\./\1\n./;h;s/[^\n]*\n//;x;s/\n.*//;s/\./_/g;G;s/\n//'
It splits the line before the last dot by inserting a newline and copies the result into hold space:
s/\(.*\)\./\1\n./;h
removes everything up to and including the newline from the copy in pattern space and swaps hold space and pattern space:
s/[^\n]*\n//;x
removes everything after and including the newline from the copy that's now in pattern space
s/\n.*//
changes all dots into underscores in the copy in pattern space and appends hold space onto the end of pattern space
s/\./_/g;G
removes the newline that the append operation adds
s/\n//
Then the sed script is finished and the pattern space is output.
At the end of each numbered step (some consist of two actual steps):
Step Pattern Space Hold Space
This.is.My\n.String This.is.My\n.String
This.is.My\n.String .String
This.is.My .String
This_is_My\n.String .String
This_is_My.String .String
Solution
Two versions of this, too:
Complex: sed 's/\(.*\)\([.][^.]*$\)/\1.Goood.Long\2/'
Simple: sed 's/.*\./&Goood.Long./' - thanks Dennis Williamson
What do you want?
Complex: sed 's/.*[.]\([^.]*\)$/\1/'
Simpler: sed 's/.*\.//' - thanks, glenn jackman.
sed 's/\([^.]*\)[.]\([^.]*[.]\)/\1_\2/g'
With 3, you probably need to run the substitute (in its entirety) at least twice, in general.
Explanation
Remember, in sed, the notation \(...\) is a 'capture' that can be referenced as '\1' or similar in the replacement text.
Capture everything up to a string starting with a dot followed by a sequence of non-dots (which you also capture); replace by what came before the last dot, the new material, and the last dot and what came after it.
Ignore everything up to the last dot followed by a capture of a sequence of non-dots; replace with the capture only.
Find and capture a sequence of non-dots, a dot (not captured), followed by a sequence of non-dots and a dot; replace the first dot with an underscore. This is done globally, but the second and subsequent matches won't touch anything already matched. Therefore, I think you need ceil(log2N) passes, where N is the number of dots to be replaced. One pass deals with 1 dot to replace; two passes deals with 2 or 3; three passes deals with 4-7, and so on.
Here's a version that uses Bash's regex matching (Bash 3.2 or greater).
[[ $example =~ ^(.*)\.(.*)$ ]]
echo ${BASH_REMATCH[1]//./_}.${BASH_REMATCH[2]}
Here's a Bash version that uses IFS (Internal Field Separator).
saveIFS=$IFS
IFS=.
array=($e) # * split the string at each dot
lastword=${array[#]: -1}
unset "array[${#array}-1]" # *
IFS=_
echo "${array[*]}.$lastword" # The asterisk as a subscript when inside quotes causes IFS (an underscore in this case) to be inserted between each element of the array
IFS=$saveIFS
* use declare -p array after these steps to see what the array looks like.
1.
$ echo 'This.is.my.string' | sed 's}[^\.][^\.]*$}Good Long.&}'
This.is.my.Good Long.string
before: a dot, then no dot until the end. after: obvious, & is what matched the first part
2.
$ echo 'This.is.my.string' | sed 's}.*\.}}'
string
sed greedy matches, so it will extend the first closure (.*) as far as possible i.e. to the last dot.
3.
$ echo 'This.is.my.string' | tr . _ | sed 's/_\([^_]*\)$/\.\1/'
This_is_my.string
convert all dots to _, then turn the last _ to a dot.
(caveat: this will turn 'This.is.my.string_foo' to 'This_is_my_string.foo', not 'This_is_my.string_foo')
You don't need regular expressions at all (those complex things hurt my eyes!) if you use Awk and are a little creative.
1. echo $example| awk -v ins="Good.long" -F . '{OFS="."; $NF = ins"."$NF;print}'
What this does:
-v ins="Good.long" tells awk to create a variable called 'ins' with "Good.long" as content,
-F . tells awk to use the dot as a separator for your fields for input,
-OFS tells awk to use the dot as a separator for your fields as output,
NF is the number of fields, so $NF represents the last field,
the $NF=... part replaces the last field, it appends the current last string to what you want to insert (the variable called "ins" declared earlier).
2. echo $example| awk -F . '{print $NF}'
$NF is the last field, so that's all!
3. echo $example| awk -F . '{OFS="_"; $(NF-1) = $(NF-1)"."$NF; NF=NF-1; print}'
Here we have to be creative, as Awk AFAIK doesn't allow deleting fields. Of course, we set the output field separateor to underscore.
$(NF-1) = $(NF-1)"."$NF: First, we replace the second last field with the last glued to the second last, with a dot between.
Then, we fool awk to make it think the Number of fields is equal to the number of fields minus one, hence deleting the last field!
Note you can't say $NF="", because then it would display two underscores.
Wow, this one has really got me. Gonna need some tricky sed skill here I think. Here is the output value of command text I'm trying to replace:
...
fast
n : abstaining from food
The value I'd like to replace it with, is:
...
Noun
: abstaining from food
This turns out to be tricker that I thought. Because 'fast' is listed a number of times and because it is listed in other places at the beginning of the line. So I came up with this to define the range:
sed '/fast/,/^ n : / s/fast/Noun/'
Which I thought would do, but... Unfortunately, this doesn't end the replacement and the rest of the output following this match are replaced with Noun. How to get sed to stop replacement after the match? Even better, can I find a two line pattern match and replace it?
Try this:
sed "h; :b; \$b ; N; /^${1}\n n/ {h;x;s//Noun\n/; bb}; \$b ; P; D"
Unfortunately, Paul's answer reads the whole file in which makes any additional processing you might want to do difficult. This version reads the lines in pairs.
By enclosing the sed script in double quotes instead of single quotes, you can include shell variables such as positional parameters. I would recommend surrounding them with curly braces so they are set apart from the adjacent characters. When using double quotes, you'll have to be careful of the shell wanting to do its various expansions. In this example, I've escaped the dollar signs that signify the last line of the input file for the branch commands. Otherwise the shell will try to substitute the value of a variable $b which is likely to be null thus making sed unhappy.
Another technique would be to use single quotes and close and open them each time you have a shell variable:
sed 'h; :b; $b ; N; /^'${1}'\n n/ {h;x;s//Noun\n/; bb}; $b ; P; D'
# ↑open close↑ ↑open close↑
I'm assuming that the "[/code]" in your expected result is a typo. Let me know if it's not.
This seems to do what you want:
sed -e ':a;N;$!ba;s/fast\n n/Noun\n/'
I essentially stole the answer from here.
This might work for you:
sed '$!N;s/^fast\n\s*n :/Noun\n :/;P;D' file
...
Noun
: abstaining from food