Split zip code in a column into 2 columns - excel

Question

This is what my end result should look like. If there is not the four digits to move over to the second column then fill with 4 zeros.
How can I split zip code in a column into 2 columns and fill empty cells in column 2 if first column has only 5 digits?
Here is what I have been working with
Dim ws As Worksheet
Dim cell As Range
Set ws = Worksheets("sheet1")
For Each cell In ws.Range("K2:K500").Cells
cell.Offset(0, 1).Value = Left(cell.Value, 5)
Next cell
Dim cel As Range, rngC As Range, rngB As Range
Dim lastRowA As Long, lastRowB As Long
With ws
lastRowK = .Cells(.Rows.Count, "K").End(xlUp).Row 'last row of column A
lastRowL = .Cells(.Rows.Count, "L").End(xlUp).Row 'last row of column B
For Each cel In .Range("K2:K" & lastRowL) 'loop through column L
'check if cell in column A exists in column B
If WorksheetFunction.CountIf(.Range("K2:K" & lastRowL), cel) = 0 Then
cel.Offset(0, 3).Value = Right(cel.Value, 4)
'.Range("M" & cel.Row) = Right(cell.Value, 4)
Else
.Range("M" & cel.Row) = "0000"
End If
Next
End With

Answer 1

In case you want to bypass VBA and use formulas, you can do this.
Cell B2:
=LEFT(A2,5)
Cell C2:
=IF(LEN(A2)=9,RIGHT(A2,4),"0000")

Answer 2

One of the simplest ways to solve this problem is to supplement the original string with a large number of zeros and take the values ​​of the first and second five characters for two cells:
Sub setZIPandZeros()
Const TEN_ZEROS = "0000000000" ' 10 times
Dim ws As Worksheet
Dim cell As Range
Dim sLongString As String
Set ws = Worksheets("Sheet1")
For Each cell In ws.Range("K2:K" & ws.Cells(ws.Rows.Count, "K").End(xlUp).Row).Cells
sLongString = Trim(cell.Text) & TEN_ZEROS
cell.Offset(0, 1).Resize(1, 2).NumberFormat = "#"
cell.Offset(0, 1).Resize(1, 2).Value = Array(Left(sLongString, 5), _
Mid(sLongString, 6, 5))
Next cell
End Sub
Update The modified code is much faster and gives a result that more closely matches the description of the task:
Sub setZipZeros()
Dim ws As Worksheet
Dim rResult As Range
Set ws = Worksheets("Sheet1")
' Addressing R1C1 is used in the formulas - If the original range
' is shifted to another column, you will need to change the letter
' of the column "K" only in this line
Set rResult = ws.Range("K2", ws.Cells(ws.Rows.Count, "K").End(xlUp)).Offset(0, 1)
' If the columns L:M are already in text format, then instead of
' the results we will get the texts of formulas
rResult.Resize(, 2).NumberFormat = "General"
' These two lines do most of the work:
rResult.Formula2R1C1 = "=LEFT(TRIM(RC[-1])&""00000"",5)"
rResult.Offset(0, 1).Formula2R1C1 = "=MID(TRIM(RC[-2])&""000000000"",6,4)"
' We don't know if auto-recalculation mode is on now
' Application.Calculation = xlAutomatic
ActiveSheet.Calculate
Set rResult = rResult.Resize(, 2)
' Set the text format for the cells of the result
' to prevent conversions "00123" to "123"
rResult.NumberFormat = "#"
' Replace formulas with their values
rResult.Value = rResult.Value
End Sub