I need to display with no decimal, but retaining the numbers that
appear after the last decimal. For example, given `03.1037.190
I tried roundup and trunct but not sure how it works.
Try this on a string where . could be on a dynamic spot
=SUBSTITUTE(A1,".","",LEN(A1)-LEN(SUBSTITUTE(A1,".","")))
Or when your string always follows the same pattern ##.####.####.## you could try:
=REPLACE(A1,13,1,"")
The question is quite unclear as you have a value with the same thousand and decimal delimiter and also 4 numbers between the delimiters. It would help a lot if you specified the actual number without thousand delimiters.
Assuming there are no decimals (31.037.190.301): remove "." using:
=SUBSTITUTE(A1,".","")
and Excel will recognize it as a number
Related
I have a text string which reflects thousand separators as a dot but also the decimal.
I want to convert this to a number but retain the decimal.
1.056.865.39 should be 1056865.39
6.685.3 should be 6685.3
I've tried substitute and replace but I can't work out how to retain the last decimal.
Any ideas how to do this in excel?
Try:
=SUBSTITUTE(TEXTBEFORE(A1,".",-1),".",)+TEXTAFTER(A1,".",-1)/100
Old Excel versions:
=NUMBERVALUE(SUBSTITUTE(D13,".",",",LEN(D13)-LEN(SUBSTITUTE(D13,".",))),",",".")
Excel 2013:
=SUBSTITUTE(A1,".","")/10^(1+(LEFT(RIGHT(A1,3))="."))
I'm trying to make a rounding function in Python to make proper significant figures but I don't know how to remove the quotes from the answer, an ex. is '156.70', I want to have the number with 2 decimal place precision, and
round(156.70,2) returns 156.7.
I have tried this: format(round(156.70,2),'.2f'), but it places the answer in single quotes like I stated above. Is there a way to round directly with the floating point zero, or is there a way to remove the quotes?
I have also tried the strip command which does not remove the quotes.
I also tried converting the answer (156.70) to a numpy array to remove the quotes the following way:
ares1 = np.array(format(round(ans,2),".2f"))
values = ares1.item().split(' ')
ares = np.asarray(values, dtype='float')
Where 'ans' is the value 156.7 I want to round to two precision points. Thanks for any help.
Precision doesn't work in programming as it works in real life. By default, numbers have infinite precision, and any decimal places after the defined decimal places will be zeroes. So, your number 156.7 is the same as 156.70 and 156.7000, as they will all be stored identically in memory.
Now with that out of the way, you can definitely "format" the number when outputting it. That will not edit the actual stored value, but will give you a String representation of the number for display purposes only. For that, I'll refer you to this StackOverflow question.
I looking for a number format that is locale-independent.
Let's say that I want that my Excel file use an a character as a thousand separator and a b character as a decimal separator on every computer (so this question is not about local Excel settings). The second wish is that the number has always two decimal places.
Can I do this only with a number format without VB code?
After some attempts, I came to this format: ###\a###\a##0\b.00.
1234567.89 > 1a234a567b.89
The problems are:
I must repeat ###\a section and I can not get rid of dot decimal separator (the decimal places are not taken into account without the dot character).
Can I do this only with a number format without VB code?
No.
Even if you can get your separator characters inserted, you will not be able to remove the decimal separator.
The decimal separator is displayed in the cell whenever it is included in custom number display format settings.
I'm working with a dataset that has really terrible ID numbers that are an integer followed by a 13 digit decimal. However, the first 6-7 decimal places are zeroes. For example:
10.0000000960554
This is making my life difficult. So I want to parse the IDs apart at the decimal into two integers, drop the leading zeros, and put them back together as one giant integer. However, everything I find for how to do this in Excel keeps the numbers after the decimal after the decimal. For Stata, I've tried to convert the numeric into a string so I can then parse it, but Stata won't let me because it's a decimal:
encode ScrambledID, generate StringID
Here's the error:
not possible with numeric variable
r(107);
An added issue, I can't just split the decimal in Excel and then multiply by 1e+12 because it messes with the values (long story with how they were derived).
Like I said, I'm fine with doing this in either Stata or Excel. Either way this is driving me nuts.
In Excel:
In one column put:
=int(A1)
In the next put:
=--MID(A1,FIND(".",A1)+1,999)
As #Grade'Eh'Bacon stated, I have use a few shortcuts in the above formula. The -- at the beginning change text that are numbers into numbers. It replaces the VALUE() function.
The 999 is a superfluous number in that it is assumed the length of the string being split is not longer than 999 characters. It can be replaced with the LEN() function which would return the actual length of the string.
So putting the two together:
=VALUE(MID(A1,FIND(".",A1)+1,LEN(A1))
Where A1 is the location of the number
Your story is truly shocking.
I'd advise extreme caution in any software. For a start, numbers with decimal parts will be rendered differently depending on whether they are imported as 4-byte or 8-byte reals, in Stata terms as floats or doubles. The underlying problem is that many decimal numbers have no exact binary representation.
In Stata terms, encode is indeed out of the question for a numeric variable (and your example would also fail for other reasons). But ideally you should import the identifiers as strings in the first place. Otherwise you should try a conversion such as generate stringID = string(numid, "%16.13f").
. di %21s string(10.0000000960554, "%16.13f")
10.0000000960554
. di %21s string(10.00000009605539, "%16.13f")
10.0000000960554
. di %21s string(10.00000009605544, "%16.13f")
10.0000000960554
. di %21s string(10.00000009605535, "%16.13f")
10.0000000960554
I have this number
111100000000000010001000
I want to extend it to 32 bits with leading zeros. In other words:
00000000111100000000000010001000
So I found this suggestion here:
Add leading zeroes/0's to existing Excel values to certain length
is to use the Right function. So I do:
=RIGHT("00000000000000000000000000000000"+A1,32)
I end up getting a number in Engineering notation. So as suggested somewhere else I add:
=TEXT(RIGHT("00000000000000000000000000000000"+A1,32), "0")
I still get
111100000000000000000000
Not 32-bit and the trailing 10001000 has become zeros.
Any idea what's happening here??
Excel takes that as a decimal number, not a binary number.
111100000000000010001000 as a decimal number is too much for the number precision Excel has to offer, so that is rounded to 111100000000000000000000 before you apply your zeros (which you can see yourself if you apply a numeric format to A1 that disallows scientific notation).
The solution is the same, treat all numbers as string. Prefix the source number in A1 with an apostrophe to make it a string, the RIGHT will then work as you expect.
Well, it actually won't, because I used + when I should have used &, so Excel will try to convert to numbers and actually make the addition. So correct the formula:
=RIGHT("00000000000000000000000000000000"&A1,32)