I'm designing a Mastermind game, which basically compares 2 lists and marks the similarities. When a colour is found at the right place, a flag making the correct position is added and the item found on the reference list is marked off. The reference list is feeding off an array from another function. The problem is at the mark off, as any changes done to the reference list is changing also the original array, which i don't want it to happen
tempCode = mCode #mCode is the array combination randomly generated from another function
for i in range (len(uCode)): #user input array
for j in range (len(tempCode)): #temp array
if uCode[i] == tempCode[j]: # compare individual chars
if i == j: #compare position
flagMark = "*"
tempCode.insert(j+1, "x") #problem starts here
tempCode.remove(tempCode[j])
fCode.append(flagMark)
When the insert is reached both the tempCode and mCode change which it is not intended.
The code is written in a way should the user enter a combination of the same colours, thus checking the chras(the colours are just letters) and the position, and then mark them of with "x"
As it stands, when it gets to
tempCode.insert(j+1, "x")
the arrays will change to
mCode = ["B","R","x","G","Y"]
tempCode = ["B","R","x","G","Y"]
when I would just want
mCode = ["B","R","G","Y"]
tempCode = ["B","R","x","G","Y"]
See also this answer, which is a different presentation of the same problem.
Essentially, when you do tempCode = mCode, you're not making a copy of mCode, you're actually making another reference to it. Anything you do to tempCode thereafter affects the original as well, so at any given time the condition tempCode == mCode will be true (as they're the same object).
You probably want to make a copy of mCode, which could be done in either of the following ways:
tempCode = mCode.copy()
tempCode = mCode[:]
which produces a different list with the same elements, rather than the same list
Related
first post / total Python novice so be patient with my slow understanding!
I have a dataframe containing a list of transactions by order of transaction date.
I've appended an additional new field/column called ["DB/CR"], that dependant on the presence of "-" in the ["Amount"] field populates 'Debit', else 'Credit' in the absence of "-".
Noting the transactions are in date order, I've included another new field/column called [Top x]. The output of which is I want to populate and incremental independent number (starting at 1) for both debits and credits on a segregated basis.
As such, I have created a simple loop with a associated 'if' / 'elif' (prob could use else as it's binary) statement that loops through the data sent row 0 to the last row in the df and using an if statement 1) "Debit" or 2) "Credit" increments the number for each independently by "Debit" 'i' integer, and "Credit" 'ii' integer.
The code works as expected in terms of output of the 'Top x'; however, I always receive a warning "A value is trying to be set on a copy of a slice from a DataFrame".
Trying to perfect my script, without any warnings I've been trying to understand what I'm doing incorrect but not getting it in terms of my use case scenario.
Appreciate if someone can kindly shed light on / propose how the code needs to be refactored to avoid receiving this error.
Code (the df source data is an imported csv):
#top x debits/credits
i = 0
ii = 0
for ind in df.index:
if df["DB/CR"][ind] == "Debit":
i = i+1
df["Top x"][ind] = i
elif df["DB/CR"][ind] == "Credit":
ii = ii+1
df["Top x"][ind] = ii
Interpreter
df["Top x"][ind] = i
G:\Finances Backup\venv\Statementsv.03.py:173: SettingWithCopyWarning:
A value is trying to be set on a copy of a slice from a DataFrame
See the caveats in the documentation: https://pandas.pydata.org/pandas-docs/stable/user_guide/indexing.html#returning-a-view-versus-a-copy
df["Top x"][ind] = ii
Many thanks :)
You should use df.loc["DB/CR", ind] = "Debit"
Use iterrows() to iterate over the DF. However, updating DF while iterating is not preferable
see documentation here
Refer to the documentation here Iterrows()
You should never modify something you are iterating over. This is not
guaranteed to work in all cases. Depending on the data types, the
iterator returns a copy and not a view, and writing to it will have no
effect.
I'm making a game of hangman. I use a list to keep track of the word that you are guessing for, and a list of blanks that you fill in. But I can't figure out what to do if for example someone's word was apple, and I guessed p.
My immediate thought was to just find if a letter is in the word twice, then figure out where it is, and when they guess that letter put it in both the first and second spot where that letter is. But I can't find
How to test if two STRINGS are duplicates in a list, and
If I were to use list.index to test where the duplicate letters are how to I find both positions instead of just one.
Create a string for your word
Create a string for user input
Cut your string into letters and keep it on a list/array
Get input
Cut input into letters and keep it on another array
Create a string = "--------" as displayed message
Using a for loop check every position in both array lists and compare them
If yourArray[i] == inputArray[i]
Then change displayedString[i] = inputArray[i] and display message then get another input
If it doesnt match leave "-" sings
Displayed the "---a--b" string
One way to do it would be to go through the list one by one and check if something comes up twice.
def isDuplicate(myList):
a = []
index = 0
for item in myList:
if type(item) == str:
if item in a:
return index
else:
a.append(item)
index += 1
return False
This function goes through the list and adds what it has seen so far into another list. Each time it also checks if the item it is looking at is already in that list, meaning it has already been seen before. If it gets through the whole list without any duplicates, it returns False.
It also keeps track of the index it is on, so it can return that index if it does find a duplicate.
Alternately, If you want to find multiple occurrences of a given string, you would use the same structure with some modifications.
def isDuplicate(myList, query):
index = 0
foundIndexes = []
for item in myList:
if item == query:
foundIndexes.append(index)
index += 1
return foundIndexes
This would return a list of the indexes of all instances of query in myList.
I am currently attempting to parse data that is sent from an outside source serially. An example is as such:
DATA|0|4|7x5|1|25|174-24|7x5|1|17|TERW|7x5|1|9|08MN|7x5|1|1|_
This data can come in many different lengths, but the first few pieces are all the same. Each "piece" originally comes in with CRLF after, so I've replaced them with string.gsub(input,"\r\n","|") so that is why my input looks the way it does.
The part I would like to parse is:
4|7x5|1|25|174-24|7x5|1|17|TERW|7x5|1|9|08MN|7x5|1|1|_
The "4" tells me that there will be four lines total to create this file. I'm using this as a means to set the amount of passes in the loop.
The 7x5 is the font height.
The 1 is the xpos.
The 25 is the ypos.
The variable data (172-24 in this case) is the text at these parameters.
As you can see, it should continue to loop this pattern throughout the input string received. Now the "4" can actually be any variable > 0; with each number equaling a set of four variables to capture.
Here is what I have so far. Please excuse the loop variable, start variable, and print commands. I'm using Linux to run this function to try to troubleshoot.
function loop_input(input)
var = tonumber(string.match(val, "DATA|0|(%d*).*"))
loop = string.match(val, "DATA|0|")
start = string.match(val, loop.."(%d*)|.*")
for obj = 1, var do
for i = 1, 4 do
if i == 1 then
i = "font" -- want the first group to be set to font
elseif i == 2 then
i = "xpos" -- want the second group to be set to xpos
elseif i == 3 then
i = "ypos" -- want the third group to be set to ypos
else
i = "txt" -- want the fourth group to be set to text
end
obj = font..xpos..ypos..txt
--print (i)
end
objects = objects..obj -- concatenate newly created obj variables with each pass
end
end
val = "DATA|0|4|7x5|1|25|174-24|7x5|1|17|TERW|7x5|1|9|08MN|7x5|1|1|_"
print(loop_input(val))
Ideally, I want to create a loop that, depending on the var variable, will plug in the captured variables between the pipe deliminators and then I can use them freely as I wish. When trying to troubleshoot with parenthesis around my four variables (like I have above), I receive the full list of four variables four times in a row. Now I'm having difficulty actually cycling through the input string and actually grabbing them out as the loop moves down the data string. I was thinking that using the pipes as a means to delineate variables from one another would help. Am I wrong? If it doesn't matter and I can keep the [/r/n]+ instead of each "|" then I am definitely all for that.
I've searched around and found some threads that I thought would help but I'm not sure if tables or splitting the inputs would be advisable. Like these threads:
Setting a variable in a for loop (with temporary variable) Lua
How do I make a dynamic variable name in Lua?
Most efficient way to parse a file in Lua
I'm fairly new to programming and trying to teach myself. So please excuse my beginner thread. I have both the "Lua Reference Manual" and "Programming in Lua" books in paperback which is how I've tried to mock my function(s) off of. But I'm having a problem making the connection.
I thank you all for any input or guidance you can offer!
Cheers.
Try this:
val = "DATA|0|4|7x5|1|25|174-24|7x5|1|17|TERW|7x5|1|9|08MN|7x5|1|1|_"
val = val .. "|"
data = val:match("DATA|0|%d+|(.*)$")
for fh,xpos,ypos,text in data:gmatch("(.-)|(.-)|(.-)|(.-)|") do
print(fh,xpos,ypos,text)
end
I have a variable that is created by a loop. The variable is large enough and in a complicated enough form that I want to save the variable each time it comes out of the loop with a different name.
PM25 is my variable. But I want to save it as PM25_year in which the year changes based on `str = fname(13:end)'
PM25 = permute(reshape(E',[c,r/nlay,nlay]),[2,1,3]); % Reshape and permute to achieve the right shape. Each face of the 3D should be one day
str = fname(13:end); % The year
% Third dimension is organized so that the data for each site is on a face
save('PM25_str', 'PM25_Daily_US.mat', '-append')
The str would be a year, like 2008. So the variable saved would be PM25_2008, then PM25_2009, etc. as it is created.
Defining new variables based on data isn't considered best practice, but you can store your data more efficiently using a cell array. You can store even a large, complicated variable like your PM25 variable within a single cell. Here's how you could go about doing it:
Place your PM25 data for each year into the cell array C using your loop:
for i = 1:numberOfYears
C{i} = PM25;
end
Resulting in something like this:
C = { PM25_2005, PM25_2006, PM25_2007 };
Now let's say you want to obtain your variable for the year 2006. This is easy (assuming you aren't skipping years). The first year of your data will correspond to position 1, the second year to position 2, etc. So to find the index of the year you want:
minYear = 2005;
yearDesired = 2006;
index = yearDesired - minYear + 1;
PM25_2006 = C{index};
You can do this using eval, but note that it's often not considered good practice. eval may be a security risk, as it allows user input to be executed as code. A better way to do this may be to use a cell array or an array of objects.
That said, I think this will do what you want:
for year = 2008:2014
eval(sprintf('PM25_%d = permute(reshape(E',[c,r/nlay,nlay]),[2,1,3]);',year));
save('PM25_Daily_US.mat',sprintf('PM25_%d',year),'-append');
end
I do not recommend to set variables like this since there is no way to track these variables and completely prevents all kind of error checking that MATLAB does beforehand. This kind of code is handled completely in runtime.
Anyway in case you have a really good reason for doing this I recommend that you use the function assignin for this.
assignin('caller', ['myvar',num2str(1)], 63);
I'm trying to use get() to access a list element in R, but am getting an error.
example.list <- list()
example.list$attribute <- c("test")
get("example.list") # Works just fine
get("example.list$attribute") # breaks
## Error in get("example.list$attribute") :
## object 'example.list$attribute' not found
Any tips? I am looping over a vector of strings which identify the list names, and this would be really useful.
Here's the incantation that you are probably looking for:
get("attribute", example.list)
# [1] "test"
Or perhaps, for your situation, this:
get("attribute", eval(as.symbol("example.list")))
# [1] "test"
# Applied to your situation, as I understand it...
example.list2 <- example.list
listNames <- c("example.list", "example.list2")
sapply(listNames, function(X) get("attribute", eval(as.symbol(X))))
# example.list example.list2
# "test" "test"
Why not simply:
example.list <- list(attribute="test")
listName <- "example.list"
get(listName)$attribute
# or, if both the list name and the element name are given as arguments:
elementName <- "attribute"
get(listName)[[elementName]]
If your strings contain more than just object names, e.g. operators like here, you can evaluate them as expressions as follows:
> string <- "example.list$attribute"
> eval(parse(text = string))
[1] "test"
If your strings are all of the type "object$attribute", you could also parse them into object/attribute, so you can still get the object, then extract the attribute with [[:
> parsed <- unlist(strsplit(string, "\\$"))
> get(parsed[1])[[parsed[2]]]
[1] "test"
flodel's answer worked for my application, so I'm gonna post what I built on it, even though this is pretty uninspired. You can access each list element with a for loop, like so:
#============== List with five elements of non-uniform length ================#
example.list=
list(letters[1:5], letters[6:10], letters[11:15], letters[16:20], letters[21:26])
#===============================================================================#
#====== for loop that names and concatenates each consecutive element ========#
derp=c(); for(i in 1:length(example.list))
{derp=append(derp,eval(parse(text=example.list[i])))}
derp #Not a particularly useful application here, but it proves the point.
I'm using code like this for a function that calls certain sets of columns from a data frame by the column names. The user enters a list with elements that each represent different sets of column names (each set is a group of items belonging to one measure), and the big data frame containing all those columns. The for loop applies each consecutive list element as the set of column names for an internal function* applied only to the currently named set of columns of the big data frame. It then populates one column per loop of a matrix with the output for the subset of the big data frame that corresponds to the names in the element of the list corresponding to that loop's number. After the for loop, the function ends by outputting that matrix it produced.
Not sure if you're looking to do something similar with your list elements, but I'm happy I picked up this trick. Thanks to everyone for the ideas!
"Second example" / tangential info regarding application in graded response model factor scoring:
Here's the function I described above, just in case anyone wants to calculate graded response model factor scores* in large batches...Each column of the output matrix corresponds to an element of the list (i.e., a latent trait with ordinal indicator items specified by column name in the list element), and the rows correspond to the rows of the data frame used as input. Each row should presumably contain mutually dependent observations, as from a given individual, to whom the factor scores in the same row of the ouput matrix belong. Also, I feel I should add that if all the items in a given list element use the exact same Likert scale rating options, the graded response model may be less appropriate for factor scoring than a rating scale model (cf. http://www.rasch.org/rmt/rmt143k.htm).
'grmscores'=function(ColumnNameList,DataFrame) {require(ltm) #(Rizopoulos,2006)
x = matrix ( NA , nrow = nrow ( DataFrame ), ncol = length ( ColumnNameList ))
for(i in 1:length(ColumnNameList)) #flodel's magic featured below!#
{x[,i]=factor.scores(grm(DataFrame[, eval(parse(text= ColumnNameList[i]))]),
resp.patterns=DataFrame[,eval(parse(text= ColumnNameList[i]))])$score.dat$z1}; x}
Reference
*Rizopoulos, D. (2006). ltm: An R package for latent variable modelling and item response theory analyses, Journal of Statistical Software, 17(5), 1-25. URL: http://www.jstatsoft.org/v17/i05/