I'd like to create a find which delete a files older than 30 days, but I have 1 directory where the retention should be 6 months.
How would that be possible?
This one would delete all files in all subdirectories which is older than 30 days if I'm correct.
/bin/find /root/script/* -type f -ctime +30 -exec rm {} \;
Bu how I can set that this directory needs different retention:
/root/script/owner
You can exclude the /root/script/owner from the find output using -path or -regex, combined with '!' to negate the test
find /root/script -type f -ctime +30 '!' -path '/root/script/owner/*' -exec rm {} \;
OR
find /root/script -type f -ctime +30 '!' -regex '/root/script/owner/.*' -exec rm {} \;
Then execute the custom delete on the special folder
find /root/script/owner -type f -ctime +180 -exec rm {} \;
You can combine multiple operators so that they restrict what is included. You actually already do this because you have a -type and -ctime, joined with an implicit AND.
The one you need to add is regex, and you can do something like:
/bin/find /root/script/* -type f ! -regex '/root/script/owner/.*' -ctime +30 -exec rm {} \;
This should exclude files in that particular tree since the ! -regex will be false for them. The basic idea is that only those that pass all the conditions will be subject to further operations.
In this case, any non-regular files will be excluded. Of the others, any that don't match the regex will be excluded. Of those remaining ones, we'll throw away any that don't match the 30-day requirement. Whatever's left will be actioned by the rm.
The remaining directory, of course, is done with the greater time:
/bin/find /root/script/owner -type f -ctime +186 -exec rm {} \;
Related
Suppose the following call in a script:
find $dir/$CACHE_DIR_SUBPATH -type f -mtime +$RETENTION_DAYS -delete
Is there a neat way to print the file names that are going to be deleted or is the best option to call find twice like so:
find $dir/$CACHE_DIR_SUBPATH -type f -mtime +$RETENTION_DAYS
find $dir/$CACHE_DIR_SUBPATH -type f -mtime +$RETENTION_DAYS -delete
You should simply introduce into the find command line the -print option.
In others words:
find $dir/$CACHE_DIR_SUBPATH -type f -mtime +$RETENTION_DAYS -print -delete
The alternative way maybe:
find $dir/$CACHE_DIR_SUBPATH -type f -mtime +$RETENTION_DAYS -exec echo "Deleting file '{}'..."; rm {} \;
I am using the following command to delete the files that are older than 10 days, but I also want to store(log) the list of files that are being deleted using the below command.
find ./path/delete -type f -name '*' -mtime +10 -exec rm {} \;
If you create a file to log to (touch ./path/to/logfile), just add another -exec to your command. Below is a very basic example, but you can add to it:
find ./path/delete -type f -name '*' -mtime +10 -exec rm {} \; -exec echo {} >> ./path/to/logfile \;
I have a dir that is full of many htm reports that I keep around for 30 days and delete old ones via a cron, but there is one sub-dir I would like to keep longer. So this is the line I made in the cron, but how do I tell it to leave one sub-dir alone.
5 0 * * * find /var/www -name "*.htm*" -type f -mtime +30 -exec rm -f {} \;
Any help is greatly appreciated!
Use -prune to prevent going into a directory that matches some conditions.
find /var/www -type d -name 'excluded-directory' -prune -o -name "*.htm*" -type f -mtime +30 -exec rm -f {} \;
In addition to suggestion below, suggesting to use full path in cron.
Also to use find option -delete in-place of -exec rm -f {} \;. It is somewhat safer.
-delete
Delete found files and/or directories. Always returns true.
This executes from the current working directory as find recurses
down the tree. It will not attempt to delete a filename with a
"/" character in its pathname relative to "." for security
reasons. Depth-first traversal processing is implied by this
option. The -delete primary will fail to delete a directory if
it is not empty. Following symlinks is incompatible with this
option.
5 0 * * * /usr/bin/find /var/www -type d -name 'excluded-directory' -prune -o -name "*.htm*" -type f -mtime +30 -delete
I am honestly nowhere near to be a decent bash scripter, but I made a little research and found a command that seems to be useful
find /path/to/files* -mtime +1 -exec rm {} \;
The question is if this line will remove directories? Because I want to only remove files that are images (actually in a *.jpeg format)
No, rm without the -r flag does not remove directories.
It looks like you want to add some more filters:
-type f to match only files
-name '*.jpeg' to match only files ending with .jpeg
Lastly, instead of -exec rm {} \;, you could use the much simpler -delete.
Putting it together, this looks more appropriate for you:
find /path/to/files* -mtime +1 -type f -name '*.jpeg' -delete
Then narrow your search results to *.jpeg files:
find /path/to/files* -mtime +1 -type f -name "*.jpeg" -exec rm {} \;
It's always better to remove the exec parameter to do a dry run before delete:
find /path/to/files* -mtime +1 -type f -name "*.jpeg"
Each line will be passed to rm command, and nothing more.
I am able to delete lets say all regular files in a folder older than 7 days via:
find /path/to/dir -type f -mtime +7 -exec rm {} \;
with a single problem. There is a file here (.gitignore) which I want to keep. I tried using regex but apparently findutils regex does not have support for negative lookahead (?!gitignore)
Any other ideas?
Use ! -name .gitignore
find /path/to/dir ! -name .gitignore -type f -mtime +7 -exec rm {} \;
You can group multiple arguments within escaped parentheses. Example, to remove all files except .gitignore and javascript files (ending in .js):
find /path/to/dir ! \( -name ".gitignore" -o -name "*.js" \) -type f -mtime +7 -exec rm {} \;
-o means or